PHYS-2325: University Physics-I
SOLUTION TO SIMILAR PROBLEMS
CHAPTER 11:
Ch-11
ANGULAR MOMENTUM
1.
Given M = 6 î + 2 ĵ – k̂ and N = 2 î – ĵ – 3 k̂ , calculate the vector product M  N .
2.
Two vectors are given by A = –3 î + 4 ĵ and B = 2 î + 3 ĵ . Find the angle between A &
B
3.
Assume A  B = A  B . What is the angle between A and B ?
PHYS-2325: University Physics-I
Ch-11
4.
A 1.50-kg particle moves in the xy plane with a velocity of v = (4.20 î – 3.60 ĵ ) m/s.
Determine the angular momentum of the particle about the origin when its position vector
is r = (1.50 î + 2.20 ĵ ) m.
5.
Heading straight toward the summit of Pikes Peak, an airplane of mass 12 000 kg flies
over the plains of Kansas at nearly constant altitude 4.30 km with constant velocity 175 m/s
west. What is the airplane’s vector angular momentum relative to a wheat farmer on the
ground directly below the airplane?
PHYS-2325: University Physics-I
Ch-11
6.
Model the Earth as a uniform sphere. Calculate
a - the angular momentum of the Earth due to rotation about its axis.
B - the angular momentum of the Earth due to its orbital motion about the Sun.
7.
Big Ben, the Parliament tower clock in London, has hour and minute hands with
lengths of 2.70 m and 4.50 m and masses of 60.0 kg and 100 kg, respectively. Calculate the
total angular momentum of these hands about the center point. Treat the hands as long,
thin, uniform rods.
PHYS-2325: University Physics-I
Ch-11
8.
A playground merry-go-round of radius R = 2.00 m has a moment of inertia I = 250 kg
· m2 and is rotating at 10.0 rev/min about a frictionless vertical axle. Facing the axle, a 25.0kg child hops onto the merry-go-round and manages to sit down on the edge. What is the
new angular speed of the merry-go-round?
9.
Comet Halley moves about the Sun in an elliptical orbit, with its closest approach to
the Sun being about 0.590 AU and its greatest distance 35.0 AU (1 AU = the Earth–Sun
distance). The comet’s speed at closest approach is 54.0 km/s. What is its speed when it is
farthest from the Sun? The angular momentum of the comet about the Sun is conserved
because no torque acts on the comet. The gravitational force exerted by the Sun has zero
moment arm.