Multibody System Dynamics (2006) 15: 1–24 DOI: 10.1007/s11044-006-2359-z C Springer 2006 A Modified Implicit Euler Algorithm for Solving Vehicle Dynamic Equations GEORG RILL FH Regensburg, University of Applied Sciences, Galgenbergstr. 30, 93053 Regensburg, Germany; E-mail: [email protected] (Received: 27 May 2005; accepted in revised form: 6 June 2005) Abstract. Vehicle modelling is usually done by Multibody Systems. Very often the overall model consists of several subsystems, like the vehicle framework, the drive train and the steering system. Due to the tire forces and torques and due to small but essential compliances in the axle/wheel suspension systems the resulting differential equations are stiff. To improve the model quality dynamic models for some components like damper, and rubber elements are used. Again these models contain stiff parts. If the implicit Euler Algorithm is adopted to the specific problems in vehicle dynamics a very effective numerical solution can be achieved. Applied to vehicle dynamic equations the algorithm produces good and stable results even for integration step sizes in the magnitude of milliseconds. As it gets along with a minimum number of operations a very good run time performance is guaranteed. Hence, even with very sophisticated vehicle models real time applications are possible. Due to its robustness the presented algorithm is very well suited for co-simulations. The modifications in the implicit Euler Algorithm also make it possible to use a simple model for describing the dry friction in the damper and in the brake disks. A quarter car vehicle model with a longitudinal and a vertical compliancy in the wheel suspension and a dynamic damper model including dry friction is used to explain the algorithm and to show its benefits. Keywords: multibody systems, vehicle dynamics, stiff differential equations, dry friction, implicit integration algorithm, real-time simulation 1. Modelling Aspects 1.1. OVERALL VEHICLE MODEL Vehicle modelling is normally based on Multibody Systems [3]. Usually the overall vehicle model is separated into different subsystems [7]. Figure 1 shows the components of a passenger car model which can be used to investigate the handling and ride properties. The vehicle framework consisting of the vehicle chassis and the wheel/axle suspension system is the kernel of the model. It directly interacts with most of the other subsystems. The equations of motion for the vehicle framework can be derived from Jourdain’s principle [11]. An enhanced vehicle model with an elastically suspended engine, four passengers and complex axle models comes up to n D ≈ 80 degrees of freedom. Due to the tire forces and torques and due to small but essential compliances in the axle/wheel 2 G. RILL Figure 1. Overall vehicle model. suspension systems the resulting differential equations are stiff. To improve the model quality dynamic models for some components like damper, and rubber elements are used. Again these subsystems contain stiff parts. 1.2. ENHANCED QUARTER CAR MODEL To demonstrate the basic structure and the specific properties of vehicle dynamic equations a much simpler but still typical quarter car model is used. Figure 2 shows Figure 2. Quarter car model. A MODIFIED IMPLICIT EULER ALGORITHM FOR SOLVING VEHICLE DYNAMIC EQUATIONS 3 an enhanced quarter car model which consists of the chassis, the knuckle and the wheel. The model describes a modern passenger car rear axle suspension where the compliances in bushing B are taken into account. The momentary position of the model bodies are described by n D = 6 generalized coordinates which are arranged in the 6 × 1-vector y = [u C , wC ; u B , w B , β K ; βW ]T , vehicle: yV axle: y A (1) wheel:yW where u C , wC are the horizontal and vertical chassis motions, u B , w B are the displacements in bushing B, the angle β K describes the rotation of the knuckle relative to the chassis and βW is the absolute wheel rotation. The sub-vectors yV , y A and yW take the structure of the vehicle model into account. The road irregularities are described by ξ = ξ (x Q ), where x Q denotes the xcoordinate of a vector from the inertia frame to the tire contact point Q. 2. Vehicle Dynamic Equations 2.1. BASIC EQUATIONS Figure 3 shows the elements of the enhanced quarter car model. Masses and moments of inertia are given by m C , m K , m W and K , The forces in the bushing, the spring and the damper are denoted by FB , FS and FD . Aerodynamic forces are neglected within this quarter car model. The weight forces of the chassis, the knuckle and the wheel are expressed by G C , G K and G W . The braking torque TB acts between wheel and knuckle whereas the drive torque TD acts between chassis and wheel. According to the standard tire interface (STI) [5], the tire forces FT and torques TT generated in the contact area are transferred from the contact point Q Figure 3. Elements of an enhanced quarter car model. 4 G. RILL to the wheel center R. Finally FKCW describes the constraint force between wheel and knuckle. Linear and angular momentum applied to each body yield m C r̈0C,0 = −FB,0 − FS,0 − FD,0 + G C,0 ; m K r̈0K ,0 = FB,0 + FS,0 + FD,0 + G K ,0 + (2) FKCW,0 , K ω̇0K ,0 = r K B,0 × FB,0 + r K S,0 × FS,0 + r K D,0 × FD,0 −TB,0 + r K R,0 × FKCW,0 ; m W r̈0R,0 = FT,0 + G K ,0 − FKCW,0 (3) , W ω̇0W,0 = TD,0 + TT,0 + TB,0 (4) where all vectors are expressed in the fixed frame 0 indicated by the comma separated subscript 0. 2.2. KINEMATICS The momentary position of the chassis center C with respect to the fixed frame 0 is given by ⎡ ⎤ uC ⎢ ⎥ I r0C,0 = r0C,0 + ⎣ 0 ⎦, (5) wC I where r0C,0 denotes the initial position of the chassis center. The momentary position of the knuckle center K with respect to a fixed frame 0 is described by ⎡ ⎤ ⎡ ⎤ uB xBK ⎢ ⎥ ⎢ ⎥ r0K ,0 = r0C,0 + rCI K ,0 + ⎣ 0 ⎦ + A0K ⎣ 0 ⎦, (6) wB zBK r B K ,0 where the initial position of the knuckle center K relative to the chassis center C is given by the vector rCI K ,0 and the coordinates x B K , z B K are constants fixing the position of K relative to the bushing center B at rotation angle β K = 0. The orientation of the knuckle is given by the rotation matrix ⎡ ⎤ cosβ K 0 sinβ K ⎢ ⎥ 1 0 ⎦. A0K = ⎣ 0 (7) − sinβ K 0 cosβ K A MODIFIED IMPLICIT EULER ALGORITHM FOR SOLVING VEHICLE DYNAMIC EQUATIONS 5 For a perfectly balanced wheel the wheel center R coincides with the center of gravity. Hence, similar to Equation (6) we get ⎡ r0R,0 ⎤ uB ⎢ ⎥ = r0C,0 + rCI B,0 + ⎣ 0 ⎦ + A0K wB ⎡ ⎤ xBR ⎢ ⎥ ⎣ 0 ⎦, zBR (8) r B R,0 where x B R , z B R are constants describing the position of R relative to the bushing center B at rotation angle β K = 0. Finally, the angular velocities of the knuckle and the wheel are given by ⎡ ω0K ,0 2.3. ⎤ 0 ⎢ ⎥ = ⎣β̇ K ⎦, 0 ⎡ ω0W,0 ⎤ 0 ⎢ ⎥ = ⎣β̇W ⎦. 0 (9) JOURDAIN ’S PRINCIPLE Using the principle of Jourdain the constraint forces can be eliminated and the equations of motion can be written as a set of two first order differential equations K (y) ẏ = z, (10) M(y)ż = q(y, z), (11) where K is called kinematic matrix, y is the vector of generalized coordinates, z is the vector of generalized speeds and M denotes the mass matrix. Within three-dimensional vehicle models suitable generalized speeds can be defined by using the components of the vectors of the absolute velocity and the absolute angular velocity expressed in a moving reference frame, c.f. [10]. Due to the simplicity of this quarter car model only trivial generalized speeds ẏ = z (12) are possible. Corresponding to the model structure the 6 × 6 mass matrix ⎡ MV V ⎢ M =⎢ ⎣ MV A MV W MVT A MVT W ⎤ MAA ⎥ T ⎥, M AW ⎦ M AW MW W (13) 6 G. RILL consists of submatrices for the overall vehicle MV V , the axle M A A , the wheel MW W , and the coupling matrices MV A , MV W , M AW . The elements of the submatrices are given by 0 mV MV V = , (14) 0 mV ⎡ ⎡ ⎤ ⎤ mA mA 0 0 rz m A ⎢ ⎢ ⎥ ⎥ m A ⎦, M A A = ⎣ 0 mA −r x m A ⎦, MV A = ⎣ 0 (15) r z m A −r x m A r z m A −r x m A A MV W = [0 0], M AW = [0 0 0], MW W = [W ], (16) where the following abbreviations were used m A = m K + mW , m V = mC + m K + m W , r x m A = r B K x,0 m K + r B Rx,0 m W , r z m A = r B K z,0 m K + r B Rz,0 m W , A = K + r B2 K z +r B2 K x m K + r B2 Rz +r B2 Rx m W (17) and r B K x , r B K z and r B K x,0 , r B Rx,0 are the x and z-coordinates of the vectors r B K ,0 and r B R,0 which are defined in Equation (6) and Equation (8). Within this quarter car model all elements of the submatrices MV W and M AW are equal to zero. In general the mass coupling between the wheel rotation and the vehicle model can be neglected, cf. [9]. Hence, the vehicle framework and the drive train can be described by separate subsystems. 2.4. GENERALIZED FORCES The generalized force vector can be separated into two parts q = qi + qa . (18) where qi contains the weight and inertia forces and qa collects the applied forces and torques. The generalized weight and inertia force vector is given by FC I x + FK I x + FW I x qi V = , FC I z + FK I z + FW I z ⎤ ⎡ FK I x + FW I x ⎥ ⎢ FK I z + FW I z qi A = ⎣ ⎦, r B K z FK I x −r B K x FK I z + r B Rz FW I x −r B Rx FW I z qi W = [0], (19) A MODIFIED IMPLICIT EULER ALGORITHM FOR SOLVING VEHICLE DYNAMIC EQUATIONS 7 where FC I x = 0, FC I z = −m C g; FK I x = m K r B K x β̇ K2 , FK I z = m K r B K z β̇ K2 −g ; FW I x = m W r B Rx β̇ K2 , (20) FW I z = m W r B Rz β̇ K2 −g and g denotes the constant of gravity. The contribution of each applied force Fi or torque T j to the generalized force vector qa can be calculated via the virtual power. For n F applied forces and n T applied torques we get qa = nF ∂vi T i=1 ∂z + Fi nT ∂ω j T j=1 ∂z Tj , (21) where vi is the velocity in direction of the applied force and ω j is the angular velocity around the acting direction of the applied torque. Finally, z denotes the vector of generalized speeds which is defined by Equation (12). 3. Applied Forces and Torques 3.1. BUSH FORCES In modern axle suspension systems the bush compliances have become design parameters, cf. [4]. As the compliancy of a bushing is limited the forces in bushing B are modelled by nonlinear spring damper elements FBx = FBx (u B , u̇ B ) and FBz = FBz (w B , ẇ B ) (22) where u B , u̇ B and w B , ẇ B are the bush displacements and their derivatives in longitudinal and vertical direction. The contribution of the bush forces to the vector of generalized forces and torques is given by qa FB = 0 0 1 0 ∂ u̇ B /∂z 0 T 0 FBx + 0 0 0 1 ∂ ẇ B /∂z 0 T 0 FBz . (23) As u̇ B /∂z and ẇ B /∂z are generalized speeds the partial derivatives ∂ u̇ B and ∂ ẇ B are quite simple. 8 3.2. G. RILL SPRING FORCE The spring is attached to the knuckle at point S and to the chassis at point P, Figure 3. Neglecting dissipative terms the spring force can be modelled by a pure function of the spring displacement u S FS = FS (u S ) , (24) where the spring displacement is defined by the difference of the actual length and the length of the spring in design position u S = − 0 . The actual spring length follows from T rC P,0 − rC S,0 rC P,0 − rC S,0 , = where the actual position of the attachment points S and P is given by ⎡ ⎡ ⎤ ⎤ xC P xC B + u B + cos β K x B S + sin β K z B S ⎢ ⎢ ⎥ ⎥ 0 rC P,0 = ⎣ 0 ⎦ ; rC S,0 = ⎣ ⎦. zC P z C B + w B − sin β K x B S + cos β K z B S (25) (26) (27) Here xC P , z C P , xC B , z C B and x B S , z B S are constants describing the design position of the attachment points S and P and the bushing center B. According to Equation (21) the contribution of the spring force FS to the generalized force vector qa can be calculated via ∂ u̇ S T FS qa = FS . (28) ∂z As 0 and rC P,0 are both constant, the time derivative of the spring displacement u S results in ∂rC S,0 T 2 (rC P,0 − rC S,0 ) − ẏ ∂rC S,0 ∂y ˙ ẏ, (29) = − e ST P,0 u̇ S = = ∂y 2 (rC P,0 − rC S,0 )T (rC P,0 − rC S,0 ) where ẏ is the time derivative of the vector of generalized coordinates defined in Equation (1) and rC P,0 − rC S,0 e S P,0 = (rC P,0 − rC S,0 )T (rC P,0 − rC S,0 ) (30) A MODIFIED IMPLICIT EULER ALGORITHM FOR SOLVING VEHICLE DYNAMIC EQUATIONS 9 denotes a unit vector into the direction of the spring. From Equation (27) one gets ⎡ ⎤ 0 0 1 0 − sin β K x B S +cos β K z B S 0 ⎥ ∂rC S,0 ⎢ ⎥. =⎢ (31) 0 0 0 0 0 0 ⎣ ⎦ ∂y 0 0 0 1 − cos β K x B S −sin β K z B S 0 In this modelling approach trivial generalized speeds ẏ = z were used. Hence, the time derivative of the spring displacement Equation (29) delivers by simple inspection ∂ u̇ S ∂rC S,0 ∂ u̇ S = = − e ST P,0 . ∂z ∂ ẏ ∂y 3.3. (32) DAMPER TOP - MOUNT COMBINATION The damper top-mount combination represents a dynamic force element which is attached at point D to the knuckle and at point E to the chassis, Figure 3. A simple damper top-mount model which also takes the dry friction in the damper into account is shown in Figure 4. Damper and top-mount are both described by force characteristics, FD = FD (ṡ) and FS = FS (u − s), where u and s are the overall element and the pure damper displacement. If the dry friction is modelled by |FF | ≤ FFmx with FFmx as the maximum friction force then, the force balance FS = FD + FF delivers a differential equation for the damper displacement s which is defined in sections FD (ṡ) = FS (u − s) + FFmx , ṡ = 0, FS < −FFmx , |FS | ≤ FFmx , FD (ṡ) = FS (u − s) − FFmx , (33) FS > +FFmx . Here the damper displacement s acts as an internal state variable. Depending on the model complexity of the damper and the top mount additional internal state variables may be added. In general the overall force can be expressed as FD = FD (y, z, s D ) , Figure 4. Damper top-mount combination including dry friction. (34) 10 G. RILL where y, z are the vectors of generalized coordinates and speeds and s D is a vector of damper internal state variables. Similar to Equation (28) and Equation (32) the contribution of the overall damper force to the generalized force vector qa is given by qa FD ∂rC D,0 = − ∂y T e D E,0 FD , (35) where the partial derivative of the vector rC D,0 from the chassis center C to point D and the unit vector e D E,0 into the direction of the damper top-mount combination correspond with Equation (31) and Equation (30). 3.4. TIRE FORCES AND TORQUES Tire forces and torques have a dominant influence on vehicle dynamics. The tire model TMeasy used here is based on a semi-empirical model approach which provides an useful compromise between user-friendliness, model-complexity and efficiency in computation time on the one hand, and precision in representation on the other hand [2]. In a steady state approach the tire forces FT and torques TT are calculated from the position of the rim center r0R,0 , its velocity v0R,0 , the orientation of the knuckle A0K , the angular velocity of the knuckle ω0K ,0 , the angular velocity β̇W = W of the wheel and the road profile ζ FT = FT (r0R,0 , v0R,0 , A0K , ω0K ,0 , W , ζ ) , TT = TT (r0R,0 , v0R,0 , A0K , ω0K ,0 , W , ζ ) . (36) In general the tire forces and torques can be expressed as functions of the generalized coordinates y and generalized speeds z, the road profile ζ and in the case of dynamic tire models of internal tire state variables sT FT = FT (y, z, ζ, sT ) and TT = TT (y, z, ζ, sT ) . (37) According to Equation (21) the contribution of FT and TT follows from qa FT TT = ∂ ṙ0R,0 ∂z T FT,0 + ∂ω0W,0 ∂z T T TT,0 , where the partial derivatives are given by ⎡ 1 0 1 0 − sin β K x B R +cos β K z B R ∂ ṙ0R,0 ⎢ = ⎣0 0 0 0 0 ∂z 0 1 0 1 − cos β K x B R −sin β K z B R (38) ⎤ 0 ⎥ 0⎦ , 0 (39) A MODIFIED IMPLICIT EULER ALGORITHM FOR SOLVING VEHICLE DYNAMIC EQUATIONS ⎡ ∂ω0W,0 ∂z 0 = ⎣0 0 0 0 0 0 0 0 0 0 0 0 0 0 ⎤ 0 1⎦ 0 11 (40) and the constants x B R , z B R describe the design position of the rim center R. 3.5. DRIVING TORQUE In complex vehicle models the drive torque at each wheel is generated by a separate engine model. Here, the drive torque is modelled by a simple time dependent function TD = TD (t). (41) The contribution to the generalized force vector is given by qa TD = 0 0 0 0 0 1 T TD . (42) ∂ β˙W /∂z 3.6. BRAKING TORQUE The brake torque is modelled by an enhanced dry friction model TB = TB (ω) = TBst − d N ω with |TB | ≤ TBmx , (43) where TBst is the static part, d N > 0 is a constant, TBmx denotes the maximum braking torque and ω = β̇W − β̇ K (44) describes the relative angular velocity between wheel and knuckle. The enhanced brake torque model avoids the jump at ω = 0, Figure 5, but via the static part it still provides a locking torque, TB (ω = 0) = TBst . The contribution to the generalized force vector is given by qa TB = 0 0 0 0 −1 ∂ω/∂z 1 T TB . (45) 12 3.7. G. RILL STRUCTURE OF THE GENERALIZED FORCES AND TORQUES For the quarter car model the contribution of the applied forces and torques to the vector of generalized forces and torques is given by the 6 × 1-vector qa = qa FB + qa FS + qa FD + qa FT TT + qa TD + qa TB . (46) According to the model structure it can be split into different parts qa = qaVT qa TA T qaW T , (47) where the 2 × 1-vector qaV and the 3 × 1-vector qa A describe the generalized applied forces and torques for the vehicle framework and qaW is the resulting generalized torque applied to the wheel. 4. Numerical Solution 4.1. STRUCTURE OF THE DYNAMIC EQUATIONS Vehicle models have a typical model structure which in principle can be shown by the quarter car model. At first there is the vehicle framework described by two sets of first order differential equations K (y) ẏ = z, (48) M(y) ż = q(y, z, w, s), (49) where now y= yV yA and z z= V zA (50) denote the generalized coordinates and the generalized speeds for the vehicle framework only. Hence, the kinematic matrix K , the mass matrix M and the vector of generalized forces and torques q also consist of the parts related to the vehicle framework only. In general, the kinematic matrix and the mass matrix are functions of the generalized coordinates, K = K (y), M = M(y). Here, the kinematic matrix is equal to the matrix of identity K = E. The vector of generalized forces and torques q depend on the state y, z of the vehicle framework and on additional states w, s describing the dynamics of subsystems like the drive train and external force elements. A MODIFIED IMPLICIT EULER ALGORITHM FOR SOLVING VEHICLE DYNAMIC EQUATIONS 13 Within the quarter car model the drive train model consists just of the wheel rotation W β̇W = (51) ˙W qW /W ẇ r where W = β̇W is the absolute wheel angular velocity, W is the inertia of wheel and rim and qW = qi W + qaW are the generalized torques for the wheel rotation which are defined in Equation (19) and Equation (47). In Equation (33) the dynamics of the damper top-mount model is described by a first order differential equation for the damper displacement s. It can be written as ṡ = g (y, z, s) . (52) To keep the vehicle model modular the differential equations for the different model parts are not combined in one system of first order differential equations. 4.2. MODEL DATA AND STIFFNESS PROPERTIES According to [12] a set of N linear differential equations ẋ = A x + h(t) is called stiff, if the eigenvalues of A have negative real parts real(λi ) < 0, i = 1, 2, . . . , N and if max (|λi |) 1 min (|λi |) (53) holds. The left side of the equation in Equation (53) is called stiff ratio. In vehicle dynamics the differential equations are nonlinear due to the kinematics and due to nonlinear characteristics of forces and torques. The bush forces in longitudinal and vertical direction are modelled by nonlinear spring characteristics, Figure 6, and linear damping elements, where the constants d Bx = 500.000 N /(m/s) and d Bz = 1200.000 N /(m/s) are used to describe the damping properties. The nonlinear characteristics of the top-mount and the damper are plotted in Figure 7. The combination of a coil spring and stops results in a nonlinear overall spring characteristics, Figure 8a. As usual, the longitudinal tire force Fx is plotted versus the longitudinal slip sx . Figure 8b also shows the influence of the vertical load Fz . All the remaining data of the quarter car model are given in Table I. The stiff ratio of nonlinear systems can only be determined by linearizing the equations of motions with respect to a certain operating point. Driving on a flat road with a speed v = 30 m/s the quarter car model has a stiff ratio of approximately 200 14 G. RILL Figure 5. Coulomb dry friction model and enhanced brake torque model. Figure 6. Spring characteristics of bushing B. Figure 7. Top-mount and damper characteristics. which indicates a mildly stiff system. But running on rough road and or performing hard braking maneuvers the bush forces, the longitudinal tire force and the braking torque show an extreme nonlinear behavior which demand stiff differential equation solvers. A MODIFIED IMPLICIT EULER ALGORITHM FOR SOLVING VEHICLE DYNAMIC EQUATIONS 15 Table I. Quarter car model data. Height of chassis mass center X -pos. of knuckle center rel. to chassis Z -pos. of knuckle center rel. to chassis X -pos. of wheel center rel. to chassis Z -pos. of wheel center rel. to chassis Chassis mass (quarter vehicle) Knuckle mass Wheel mass Knuckle moment of inertia 0.600 m 0.050 m −0.275 m 0.000 m −0.300 m 300.000 kg 30.000 kg 15.000 kg 2.500 kgm2 Wheel moment of inertia X -pos. knuckle bush rel. to chassis Z -pos. knuckle bush rel. to chassis X -pos. spring at knuckle rel. to chassis Z -pos. spring at knuckle rel. to chassis X -pos. spring at chassis Z -pos. spring at chassis Spring preload X -pos. damper at knuckle rel. to chassis Z -pos. damper at knuckle rel. to chassis X -pos. damper at chassis Z -pos. damper at chassis Damper friction 1.200 kgm2 0.400 m −0.310 m 0.075 m −0.250 m 0.100 m −0.050 m 3637.000 N 0.025 m −0.280 m 0.050 m −0.020 m 50.000 N Figure 8. Spring and tire characteristics. 4.3. STANDARD IMPLICIT EULER FORMULAS The implicit Euler formula for a system of first order differential equations ẋ = f (x) (54) 16 G. RILL is given by x k+1 = x k + h f (x k+1 ), (55) where h is the integration step size, and x k , x k+1 denote the state vector at time t and t + h. Applying the implicit Euler formalism to each system of the quarter car model results in K (y k+1 ) y k+1 = K (y k+1 ) y k + h z k+1 , M(y k+1 ) z k+1 = M(y k+1 ) z k + h q(y k+1 , z k+1 , k+1 , s k+1 ) k+1 βW W k+1 W k+1 s = k βW + h = W kW k k+1 W (56) , , + h qW y k+1 , z k+1 , k+1 W = s + h g(y k+1 , z k+1 , s k+1 ) . (57) (58) k+1 k+1 , k+1 would Solving this set of nonlinear equations for y k+1 , z k+1 , βW W and s provide an asymptotically stable solution but would cost a large number of operations performing one single integration step. As the Euler approach delivers only solutions with an accuracy in the magnitude of the step size, comparatively small step sizes are needed in order to achieve acceptable results. To make it simple: the implicit Euler approach spends most of its effort to achieve a poor but stable solution for large step sizes. In vehicle dynamics the integration step size is bounded anyway, h ≤ h max . In real time applications for example the maximum integration step size is determined by the communication step size. Usually one millisecond is used, h max = 1 ms. On rough roads the step size is limited by the sample rate of the road irregularities. If for instance the vehicle is driving with a speed of v = 30 m/s and we want to sample the road at least with the length of a passenger car tire contact area, x ≈ 0.12 m then, the maximum step size is given by h max = x/v = 4 ms. Hence, integration algorithms which are developed to run with large step sizes are usually not practical in vehicle dynamic applications. 4.4. A MODIFIED IMPLICIT EULER APPROACH 4.4.1. Integrate and Calculate The dynamics of the wheel rotation k → k+1 and the dynamics of external state variables s k → s k+1 usually is much faster than the dynamics of the vehicle k+1 frame work y k → y k+1 and z k → z k+1 . Then, the generalized torque qW and the function g k+1 can be approximated by a truncated Taylor expansion ∂qW k+1 qW y k+1 , z k+1 , k+1 ≈ qW y k , z k , kW + W − kW + ... , W ∂W ∂g k+1 g(y k+1 , z k+1 , s k+1 ) ≈ g(y k , z k , s k ) + (s − s k ) + ... , (59) ∂s A MODIFIED IMPLICIT EULER ALGORITHM FOR SOLVING VEHICLE DYNAMIC EQUATIONS 17 where small and all higher order terms were neglected. Using this approximation the implicit Euler formulas Equation (57) and Equation (58) can be written as k+1 W = kW ∂qW −1 k k k + h W −h qW y , z , W , ∂W k+1 k = βW + h k+1 βW W , ∂g −1 k k k k+1 k =s +h E −h g(y , z , s ), s ∂s (60) (61) where E denotes a matrix of identity of the same size as the Jacobian ∂g/∂s. If the equations Equation (60) and Equation (61) are solved first, then the new states of the wheel rotation k+1 and the external variables s k+1 are known and can be used to calculate the vector of generalized forces and torques for the vehicle framework. 4.4.2. Displacement Prediction Similar to Equation (59) the implicit state of the vector of generalized forces and torques for the vehicle framework can be approximated by q(y k+1 , z k+1 , k+1 , s k+1 ) ≈ q(y k +h K(y k )−1 z k , z k , k+1 , s k+1 ) ∂q k+1 y − y k − h K(y k )−1 z k + ∂y ∂q k+1 − z k ) + ... , (z + ∂z (62) −1 k where again all higher order terms were neglected and y Ek+1 = y k +h K y k z is the explicit Euler solution of the kinematic differential equation Equation (48) and acts here as a first approximation to the yet unknown implicit position yok+1 . If force elements have strong nonlinearities this displacement prediction improves the stability because the derivatives are taken at the estimated implicit position y Ek+1 instead of the momentary position y k . As the bodies in the vehicle framework do not change their position very rapidly the implicit states of the kinematic and the mass matrix can be approximated by their explicit values K (y k+1 ) ≈ K (y k ) M(y k+1 ) ≈ M(y k ) . (63) If trivial generalized speeds ẏ = z are defined then, the kinematic matrix is equal to the matrix of identity and does not depend on generalized coordinates at all. This is the case within this quarter car model. 18 G. RILL By using the first equation in Equation (56) the second term on the right side of the equation Equation (62) can be simplified to ∂q k+1 ∂q − y k − h K(y k )−1 z k = h y K(y k )−1 (z k+1 − z k ) ∂y ∂y (64) and Equation (56) results in z k+1 = z k + h M I−1 q(y k +h K(y k )−1z k , z k , k+1 , s k+1 ) y k+1 k −1 k+1 = y + h K (y ) k z (65) , where the ‘implicit’ mass matrix is given by M I = M(yk ) − h ∂q ∂q − h2 K(y k )−1 ∂z ∂y (66) The modified implicit Euler formulas Equations (60) (61), and (65) are based on first approximations to the implicit state of the right hand side of the differential equations. Hence, the derivatives needed in these formulas can be calculated with a similar or an equal approximation level. 4.5. DERIVATIVES 4.5.1. Approximation Level According to Equation (18) the vector of generalized forces and torques consists of a part qi containing weight and inertia forces and the part qa collecting the applied forces and torques. During normal vehicle motions the weight and inertia forces qi do not change rapidly. Then, the partial derivatives in Equation (66) can be approximated by ∂q ∂qa ∂ ≈ = (qa FB + qa FS + qa FD + qa FT TT + qa TD + qa TB ), (67) ∂z ∂z ∂z ∂qa ∂ ∂q ≈ = (qa FB + qa FS + qa FD + qa FT TT + qa TD + qa TB ). (68) ∂y ∂y ∂y 4.5.2. Standard Force Elements The contribution of force elements to the vector of generalized forces and torques is calculated via the virtual power Equation (21). Using the definition of generalized speeds Equation (10) the contribution of forces like the bush forces and the spring force can be written as T ∂ u̇ ∂ u̇ ∂ ẏ T ∂ u̇ −1 T F qa = K F(u) = F(u) = F(u) , (69) ∂z ∂ ẏ ∂z ∂ ẏ A MODIFIED IMPLICIT EULER ALGORITHM FOR SOLVING VEHICLE DYNAMIC EQUATIONS 19 where u denotes the displacement of the force F, z is the vector of generalized speeds, ẏ is the time derivative of the vector of generalized coordinates and K is the kinematic matrix. For the quarter car model the kinematic matrix is equal to the matrix of identity, K = E. While taking one integration step from y k to y k+1 in vehicle models the kinematic matrix K and the direction vector (∂ u̇/∂ ẏ) will not change very much. Hence, the partial derivative of qa F with respect to y results in ∂qa F = ∂y ∂ u̇ −1 K ∂ ẏ T ∂ F(u) ∂u . ∂u ∂ y (70) The time derivative of the force displacement u̇ = d ∂u (u(y)) = ẏ dt ∂y (71) delivers by simple inspection ∂ u̇ ∂u = . ∂ ẏ ∂y (72) As ∂ u̇/∂ ẏ is given by the kinematics of the force element and K comes from the definition of generalized speeds only the force derivative with respect to the force displacement ∂ F/∂u is needed to calculate the contribution of a force element to the partial derivative of the vector of generalized forces and torques. Usually nonlinear force characteristics are defined by lookup tables which are interpolated by simple lines or cubic splines. Then, calculating the force F(u) and the derivative ∂ F(u)/∂u costs only slightly more than the pure evaluation of the force. 4.5.3. Global Derivatives The brake torque TB = TB (ω) was modelled by an enhanced dry friction model. Its contribution qa TB to the vector of generalized forces and torques is given by Equation (45). To calculate the partial derivative ∂qa TB /∂ y which can be done similar to Equation (70) the derivative dTB /dω is needed. As the braking torque was modelled quite simply in the neighborhood of ω = 0, jumps in the derivative will occur. 20 G. RILL The need for this derivative comes from the truncated Taylor expansion Equation (62) which was applied to generate an approximation to the implicit state qa k+1 of the vector of generalized forces and torques. If we replace the ‘exact’ derivative ⎧ ω < ω1 ⎪ ⎨ 0, dTB = −d N , ω1 ≤ ω ≤ ω2 (73) ⎪ dω ⎩ 0, ω > ω2 by the ‘global’ derivative dTB TB (ω) − TB (0) T − TBst ≈ = B dω ω−0 ω (74) a smooth transition can be achieved, Figure 9. Using the ‘global’ derivative means that instead of a Newton step a secant step is used to get an approximation of qa k+1 . For characteristics with sharp bends a single secant step generates a better approximation than a single Newton step and thus increases the stability of the modified Euler formulas. 5. Results 5.1. OVERALL PERFORMANCE To test the performance of the modified Euler algorithm a simple driving and braking manoeuver on a rough road was simulated. The road profile and the time history of the driving and the maximum braking torque are plotted in Figure 10. Some results are shown in Figure 11. The vehicle starts with a speed of v ≈ 70 km/ h. By a ramp shaped drive torque it is accelerated to v ≈ 106 km/ h. A hard braking manoeuver reduces the speed to v ≈ 25 km/ h. The maximum brake Figure 9. Enhanced brake torque model and derivatives. A MODIFIED IMPLICIT EULER ALGORITHM FOR SOLVING VEHICLE DYNAMIC EQUATIONS 21 Figure 10. Road profile ξ (x) and torques TD (t) and TBmx (t). Figure 11. Simulation results: modified euler compared to gear. torque TBmx = 1200 N m is large enough to lock the wheel in an instant. The brake torque model discussed in section 3.6 automatically generates the appropriate brake torque |TB | ≤ TBmx which is needed to keep the wheel locked. The drive torque has nearly no influence to the knuckle rotation. The strong reaction of the knuckle rotation to the brake torque is typical for a trailing arm rear axle suspension and indicates the contribution to the anti-dive reaction of the chassis. Due to the different 22 G. RILL Figure 12. Damper displacement: – with friction, – without friction. bush compliances the bush displacements in the vertical direction are significantly smaller than in the longitudinal direction. The implicit displacement prediction described in Section 4.4.2 improves and stabilizes the stiff parts of the bush motion. The modified implicit Euler algorithm was applied with an integration step size of h = 2 ms. Figure11 also shows the results of a Gear integration where the accuracy was controlled by an absolute and relative error tolerance of abs = rel = 10−6 . Even in critical situations, like applying and releasing the brake, Euler and Gear solutions are in very good conformity. 5.2. DAMPER FRICTION In Figure 12 the displacement of the pure damper element is plotted versus time using a damper element with and without friction. To emphasize the effect of the damper friction the road roughness was switched off and the maximum friction force was increased from FFmx = 50 N to FFmx = 200 N . The modified implicit Euler algorithm perfectly handles the dry friction model developed in section 3.3. During normal driving and accelerating the friction force is large enough to suppress any damper motion. The brake torque generates a large knuckle rotation which results in a significant damper displacement. After finishing the driving and braking maneuver the vehicle quickly returns to the equilibrium position. Due to the dry friction in the damper element the equilibrium positions of the damper displacement at the beginning (t = 0 s) and at the end (t = 8 s) are not the same. 6. Conclusion In this paper the implicit Euler algorithm is tailored to the specific problems in vehicle dynamics. A first version of this approach was already used to achieve real time performance for a full truck model, [8]. In particular the modifications within A MODIFIED IMPLICIT EULER ALGORITHM FOR SOLVING VEHICLE DYNAMIC EQUATIONS 23 the implicit Euler algorithm pay off for large vehicle systems [6]. Since several years the presented algorithm is used successfully within VeDynA a commercial tool in Vehicle Dynamics [13]. VeDynA is embedded into the environment of MATLAB/SIMULINK and it is widely used for off-line and real time applications, c.f. [1]. The enhanced quarter car model used here is simply enough to explain all the modification details but still is representative for complex vehicle models. At first the implicit Euler formulas are applied to each subsystem of the overall vehicle model. Then, the fully implicit Euler is replaced by a first order approximation where only dominant terms in the Jacobian are taken into account. In consequence, all derivatives are calculated in a first approximation level only. An implicit displacement prediction and global derivatives used to smoothen sharp bends in nonlinear force or torque characteristics improve the stability of the algorithm. The latter also simplifies the modelling of dry friction. 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