ANALYTIC GEOMETRY
In order to represent points in space, we first choose a fixed point O (the origin)
and three directed lines through O that are mutually perpendicular. These lines are
called the coordinate axes and are labeled π₯ β ππ₯ππ , π¦ β ππ₯ππ , and π§ β ππ₯ππ .
Usually, we think of the π₯ β and π¦ β ππ₯ππ as being horizontal and π§ β ππ₯ππ being
vertical.
In three dimensional geometry, an equation in x, y and z represents a surface in π
3 .
Example
Describe and sketch the surface in π
3 represented by the equation
(a) π§ = 3
(b) π¦ = π₯
Proposition
The distance |π1 π2 | between the points π1 (π₯1 , π₯2 , π₯3 ) and π2 (π¦1 , π¦2 , π¦3 ) is
|π1 π2 | = β(π¦1 β π₯1 )2 + (π¦2 β π₯2 )2 + (π¦3 β π₯3 )2
VECTORS
Definition
β = [π1 , π2 ] of real numbers. A three
A two-dimensional vector is an ordered pair π
β = [π1 , π2 , π3 ] of real numbers. The
dimensional vector is an ordered triple π
β.
numbers π1 , π2 and π3 are called the components of the vector π
Definition
β = [π1 , π2 ] is given by
a) The length of a two dimensional vector π
β | = βπ12 + π22 .
|π
b) The length of a three dimensional vector βπ= [π1 , π2 , π3 ] is given by
β | = βπ12 + π22 + π32 .
|π
Definition
If βπ = [π1 , π2 ] and βπ = [π1 , π2 ] then the vector βπ + βπ is defined by
β = [π1 + π1 , π2 + π2 ].
β +π
π
Similarly, for three dimensional vectors
β + βπ = [π1 + π1 , π2 + π2 , π3 + π3 ]
π
Definition
β = [π1 , π2 ] and c is a scalar; then the vector cπ
β is defined by cπ
β = [ππ1 , ππ2 ].
If π
β = [ππ1 , ππ2 , cπ3 ].
Similarly, for three dimensional vectors, cπ
There are three vectors in R3 that play a special role. Let π = [1,0,0], π = [0,1,0],
β = [0,0,1]. Then π, πβ and π
β are vectors that have length 1 and point in the
π
direction of the positive π₯ β, π¦ β, and π§ β ππ₯ππ .
β = [π1 , π2 , π3 ] then we can write π
β = [π1 , π2 , π3 ] = [π1 , 0, 0] + [0, π2 , 0] +
If π
β
[0, 0, π3 ] = π1 π + π2 π + π3 π
β are all unit
A unit vector is a vector whose length is 1. For instance π, π, and π
β , then the unit vector that has the same direction as π
β is not equal π
β is
vectors. If π
βπ = πβ .
β|
|π
The dot product
Definition
β = [π1 , π2 , π3 ] and βπ = [π1 , π2 , π3 ], then the dot product of π
β and βπ is the
If π
β β βπ given by
number π
β β βπ = π1 π1 + π2 π2 + π3 π3 .
π
Theorem
β , βπ and π
β are vectors in the three dimensional space, and c a scalar, then
If π
β βπ
β = |π|π
1. π
β β βπ= π β π
β
2. π
β +π
β β (π
β)= π
β β βπ + π
β βπ
β
3. π
β )*b
β ) β βπ = π(π
β β βπ) = π
β β (ππ
4. (cπ
β =0
5. βπ β π
Theorem
β | cos πΌ.
β and βπ, then π
β β βπ = |π
β | β |π
If Ξ± is the angle between the nonzero vectors π
Corollary
β and βπ, then cos πΌ =
If Ξ± is the angle between the nonzero vectors π
β
β βπ
π
β|
|π
β |β|π
Definition
π
Two vectors are perpendicular or orthogonal if the angle between them is .
2
Theorem
β and βπ are orthogonal if and only if π
β β βπ = 0.
Two vectors π
The cross product
Definition
β = [π1 , π2 , π3 ] and βπ = [π1 , π2 , π3 ], then the cross product of π
β and βπ is the
If π
vector
β
β × βπ = (π2 π3 β π3 π2 )π β (π1 π3 β π3 π1 )π + (π1 π2 β π2 π1 )π
π
Theorem
β × βπ is orthogonal to both π
β and βπ.
The vector π
Theorem
β | sin πΌ.
β and βπ (so 0 β€ Ξ± β€ Ο) then |π
β × βπ| = |π
β | |π
If Ξ± is the angle between π
Theorem
β are parallel if and only if π
β =π
β.
β and π
β ×π
Two nonzero vectors π
Theorem
β and π
β ,π
β are vectors and c a scalar, then
If π
β ×π
β × βπ = βπ
β
1. π
β)
β ) × βπ = π(π
β × βπ) = π
β × (ππ
2. (ππ
β +π
β × (π
β)=π
β × βπ + π
β ×π
β
3. π
β + βπ) × π
β =π
β ×π
β + βπ × π
β
4. (π
β ×π
β × (π
β ) = (π
β × βπ) × π
β.
5. π
Lines
A line L in three-dimensional space is determine by a point π0 (π₯0 , π¦0 , π§0 ) on the
ββββπ be the position vector of π0 (π₯0 , π¦0 , π§0 ), then every
line and the its direction. Let π
ββββπ + π‘π
β for some t, where π
β is the direction of L.
point on L can be expressed as π
Therefore the equation
β =π
ββββπ + π‘π
β
(1) π
β = [π, π, π], then tπ
β = [π‘π, π‘π, π‘π].
is a vector equation of L. If the direction vector π
β = [π₯, π¦, π§] and ββββ
We can also write π
π0 = [π₯0 , π¦0 , π§0 ], then the vector equation (1)
becomes
[π₯, π¦, π§] = [π₯0 + π‘π, π¦0 + π‘π, π§0 + π‘π].
Thus
π₯ = π₯0 + ππ‘
(2) {π¦ = π¦0 + ππ‘.
π§ = π§0 + ππ‘
These are called parametric equations of the line L. Another way of writing the
equation of a line L is to eliminate the parameter t from equations (2). If none of a,
b or c is zero, we can obtain
π₯βπ₯0
π¦βπ¦0
π§βπ§0
(3)
=
=
.
π
π
π
These equations are called the symmetric equations of L.
Planes
β that is
A plane is determined by a point π0 (π₯0 , π¦0 , π§0 ) in the plane and a vector π
orthogonal to the plane. This orthogonal vector is called a normal vector. Let
β = [π, π, π]. Then
π(π₯, π¦, π§) be a point on the plane and π
(4) ππ₯ + ππ¦ + ππ§ = π,
where π = ππ₯0 + ππ¦0 + ππ§0 is called the scalar equation of the plane through
β = [π, π, π]. Conversely, if a, b, and c are not
π0 (π₯0 , π¦0 , π§0 ) with normal vector π
all zero, then equation (4) represents a plane with normal vector [π, π, π].
Two planes are parallel if their normal vectors are parallel. If two planes are not
parallel, then they intersect in a straight line and the angle between the two planes
is defined as the acute angle between the two normal vectors.
The distance from the point (π₯1 , π¦1 , π§1 ) to the plane ππ₯ + ππ¦ + ππ§ = π is
|ππ₯1 +ππ¦1 +ππ§1 βπ|
.
2
2
2
βπ +π +π
© Copyright 2026 Paperzz