PROBLEM SITUATION
A
basketball team stopped at a fast food
restaurant after a game. They divided into
two groups.
 One group bought 5 chicken sandwiches
and 7 hamburgers for a cost of $24.90.
 The second group spent $28.80 and
bought 5 chicken sandwiches and 9
hamburgers.
 How much does a hamburger cost?
DEFINE VARIABLES
H
represents the cost of one
hamburger
C represents the cost of one
chicken sandwich
SYSTEM OF EQUATIONS
5C + 7H =
24.90
SOLUTION METHOD
The
system of equations is
going to solved by the method
of elimination.
The
variable c is going to be
eliminated when we subtract
the equations.
STEP _1_ OF SOLUTION
We eliminate the 5C
5C + 7H = 24.90
5C + 9H = 28.80
------------------------------2H = 3.90
STEP _2_ OF SOLUTION

You divide 3.90 by 2

2H = 3.90
H = 3.90 / 2 = 1.95
STEP _3_ OF SOLUTION

Use either equation to find C

5C + 7H = 24.90
5C + 7(1.95) = 24.90
5C + 13.65 = 24.90
5C = 11.25
C = 2.25
SOLUTION TO THE SYSTEM OF EQUATIONS
The solution to the system of equations is
(2.25,1.95)
CHECK OF SOLUTION

5(2.25)+7(1.95)=24.90 true

5(2.25)+9(1.95)=28.80 true
----------------------------
SOLUTION IN THE PROBLEM SITUATION
Each chicken sandwich is $2.25
and each hamburger is $1.95