1250 F 14 Lecture 5-3 Assessment Problem Why is inductance, L, proportional to the number of turns squared in an inductor? ANS: The voltage across each turn, vturn, is the same and is proportional to the change in the magnetic flux, , through that turn: vturn = dL dt (1) The turns are in series, so the total voltage drop, v, across the inductor is the number of turns, N, times the voltage per turn, vturn: v = Nvturn = N dL dt (2) The turns are close together, so the magnetic flux created by each turn, turn, is felt by all the turns, and the total flux, , is N times the flux created by one turn: L = NLturn (3) Substituting for in (2) gives a formula in which N2 appears: v=N dL dNLturn dL =N = N 2 turn dt dt dt (4) Finally, we note that the flux created by one turn is proportional to the current, i, in that turn: Lturn = ki (5) where k is a constant. (5) into (4) yields v = kN 2 di dt (2) From (6), we identify the inductance, L, as follows (since v = Ldi/dt): L = kN 2 Thus, L is proportional to N2. (2)
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