Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 DOI 10.1186/s13660-015-0572-0 RESEARCH Open Access Generalized Finsler-Hadwiger type inequalities for simplices and applications Shiguo Yang1,2 and Wen Wang1* * Correspondence: [email protected] 1 School of Mathematics and Statistics, Hefei Normal University, Hefei, Anhui 230601, P.R. China Full list of author information is available at the end of the article Abstract For an n-dimensional simplex in the Euclidean space E n , we establish some generalized Finsler-Hadwiger inequalities. By using these inequalities, generalizations of some well-known important inequalities for simplices are obtained. MSC: 51M20; 52A40 Keywords: simplex; volume; circumradius; inradius; inequality 1 Introduction Let ABC be a triangle (in the Euclidean plane) of area S and sides a, b, c. The following inequality [, ] is well known: √ a + b + c ≥ S + (a – b) + (b – c) + (c – a) . (.) Equality holds iff this triangle is regular. Let n be an n-dimensional simplex (in the n-dimensional Euclidean space En ) of volume V and edge lengths ai (i = , , . . . , n(n + )). Let Ai (i = , , . . . , n) be the vertices of n , Fi be the (n – )-dimensional volume of the ith face fi = A · · · Ai– Ai+ · · · An+ ((n – )dimensional simplex) for i = , , . . . , n. In , Chen and Ma extended the inequality (.) to an n-simplex and established Finsler-Hadwiger type inequality for the edge length and the volume of an n-simplex as follows [, ]: n(n+) ai ≥ n(n + ) i= (n!) n+ n Vn + n(n – ) (ai – aj ) . (.) ≤i<j≤ n(n+) Equality holds iff n is regular. In , Leng and Tang established another kind of Finsler-Hadwiger type inequality for the face areas and the volume of an n-simplex as follows [, ]: n i= Fi ≥ n (n + ) n (n!) n V (n–) n + (Fi – Fj ) . n – ≤i<j≤n (.) Equality holds iff n is regular. In this paper, we will discuss problem for generalized Finsler-Hadwiger type inequalities for k-dimensional face areas and the volume of an n-simplex, and establish generalized © 2015 Yang and Wang; licensee Springer. This is an Open Access article distributed under the terms of the Creative Commons Attribution License (http://creativecommons.org/licenses/by/4.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly credited. Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 Page 2 of 14 Finsler-Hadwiger type inequalities for an n-simplex. From these inequalities, generalizations of some inequalities for an n-simplex are obtained. 2 Main results Let R and r be the circumradius and the inradius of the simplex n , respectively. Let V denote the volume of the n-dimensional regular simplex with circumradius R. For (n+)! k = , , . . . , n – , we put μn,k = n+ = (k+)!(n–k)! . Let Vi (k) (i = , , . . . , μn,k ) denote the k+ k-dimensional volumes of the k-dimensional subsimplices of n . Our main results are the following theorems. Theorem Let n be an n-simplex, nature number k ∈ [, n – ], real numbers α ∈ (, ] and λ ∈ (, n + – k]. Then we have μn,k Viα (k) ≥ i= + R nr kα n(n+)(n–) k k + (n!) n α kα · μn,k · V n (k!) n + μn,k – λ ≤i<j≤μ α Vi (k) – Vjα (k) . (.) n,k Equality holds iff n is regular. Theorem Let n be an n-simplex, nature number k ∈ [, n – ], real numbers α ∈ (, ] and λ ∈ (, n + – k]. Then we have μn,k Viα (k) ≥ i= + V V kα n(n+)(n–) k k + (n!) n α kα · μn,k · V n (k!) n + μn,k – λ ≤i<j≤μ α Vi (k) – Vjα (k) . (.) n,k Equality holds iff n is regular. R ≥ and VV ≥ , respecNotice From the inequality R ≥ nr and Lemma , we have nr tively. Further, according to the conditions of equalities hold, we now consider a class of n-simplices ϕ inscribed in an (n – )-dimensional sphere of radius R (where R is constant R number). If the radius r of an n-simplex in ϕ is sufficiently small, then nr is large enough. Similarly, if the volume V of an n-simplex in ϕ is sufficiently small, then VV is sufficiently large. Take λ = n + – k, from Theorem or Theorem we derive an inequality for a simplex as follows. Corollary Let n be an n-simplex and real number α ∈ (, ]. Then μn,k k k + (n!) n α kα · V n (k!) n + Viα (k) ≥ μn,k i= + Viα (k) – Vjα (k) . μn,k – (n + – k) ≤i<j≤μ n,k Equality holds iff n is regular. (.) Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 Page 3 of 14 By taking k = and α = in the inequality (.) we can obtain the inequality (.). Take k = n – and α = in the inequality (.) we can obtain the inequality (.). Take k = , α = and λ = n in Theorem and Theorem , we get generalizations of the inequality (.) as follows. Corollary For an n-simplex n , we have n(n+) ai ≥ i= ai ≥ i= V V + n(n+)(n–) n(n – ) + n(n+) R nr (n!) · n(n + ) · n+ Vn (ai – aj ) , (.) ≤i<j≤ n(n+) n(n+)(n–) n(n – ) n · n(n + ) · (n!) n+ n Vn (ai – aj ) . (.) ≤i<j≤ n(n+) Equality holds iff n is regular. Take k = n – , α = , and λ = in Theorem and Theorem ; we get generalizations of the inequality (.) as follows. Corollary Let n be an n-simplex. Then we have n Fi ≥ i= n Fi i= ≥ R nr V V n(n –) n(n –) V (n–) n + (Fi – Fj ) , n – ≤i<j≤n (.) V (n–) n + (Fi – Fj ) . n – ≤i<j≤n (.) · n (n + ) n (n!) n · n (n + ) n (n!) n Equality holds iff n is regular. To prove the above theorems, we need some lemmas as follows. Lemma [, ] For an n-simplex n , we have n i= n– Fi n(n–) ≥ (n + )n– (n!) n+ V n –n– n(n+) n ai , (.) i= with equality iff n is regular. Lemma [, ] Let n be an n-simplex with edge lengths aij = |Ai Aj | ( ≤ i < j ≤ n), then we have n+ n n n aij ≥ (n!) (VR) , (.) n ≤i<j≤n with equality iff n is regular. Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 Page 4 of 14 Lemma [, ] For an n-simplex n , we have V≤ (n + )n+ (n!) nn Rn , (.) with equality iff n is regular. Lemma [, ] For an n-simplex n , we have n n– Fi ≥ nn – (n + )–(n+)(n–) (n!)–n V n –n– R. (.) i= Equality holds iff n is regular. Lemma [, ] Let n be an n-simplex and natural number k ∈ [, n – ). Then √ μn,k k! k+ μ n,k Vi (k) i= k n n+ n– (n – )! ≥ Fi , √ n i= (.) with equality iff n is regular. Lemma For an n-simplex n , we have n+ (n + ) n V≥ n! n – n r n – n Rn , (.) with equality iff n is regular. Proof Let P be an interior point of n and di the distance from the point P to the ith face fi of n for i = , , . . . , n. Obviously, we have ni= di Fi = nV . Then n di Fi i= nV = . Using the arithmetic-geometric means inequality we get n di Fi i= nV ≤ di Fi n + i= nV n n+ = , (n + )n+ namely n n– ≤ di i= (nV )n – . (n + )n – ( ni= Fi )n– (.) Substituting (.) into (.) we get n i= n– di n – V . ≤ (n!)n (n + )n(n+) nn – R (.) Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 Page 5 of 14 We now take the point P is the incenter of n , then di = r for i = , , . . . , n. Thus from (.) we can obtain the inequality (.). It is easy to see that equality holds in (.) iff n is regular. Lemma For an n-simplex n and k = , , . . . , n – , we have μn,k μ n,k Vi (k) ≥ i= μn,k μ n,k Vi (k) ≥ i= R nr V V √ k n(n+)(n–) k n(n+)(n–) nk k+ n! V , √ k! n+ √ nk n! k+ V . √ k! n+ (.) (.) Equality holds iff n is regular. Proof We have the well-known inequality [, , ] V≤ (n + ) n n– n+ Rn– r. (.) n! Equality holds iff n is regular. Using (.) and (.) we get n n– Fi i= nn – ≥ (n + )n –n– V (n –)(n–) n (n!n )V R n . (.) From (.) and (.) we have n n+ ≥ Fi i= R nr n(n –) n n (n!) (n + ) n– n V n– n . (.) Thus, inequality (.) is valid for k = n – . We now prove that inequality (.) is valid for ≤ k < n – . Substituting (.) into (.) we can obtain inequality (.). So the inequality (.) is valid for ≤ k < n – . It is easy to see that equality holds in (.) iff n is regular. By Lemma we have V = (n + )n+ (n!) nn Rn . (.) Substituting (.) into the right of (.) we get n(n+) ai ≥ i= V V n n+ n+ (n!V ) n+ . (.) From (.) and (.) we have n i= n+ Fi ≥ V V n(n –) n n (n!) (n + ) n– n V n– n . (.) Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 Page 6 of 14 Thus the equality (.) is valid for k = n – . Now we prove that inequality (.) is valid for ≤ k < n – . Substituting (.) into the right of (.) we can obtain inequality (.). So the inequality (.) is valid for ≤ k < n – . It is easy to see that equality holds in (.) iff n is regular. Lemma [, ] Let n be an n-simplex and real number α ∈ (, ]. Then Fiα Fjα – ≤i<j≤n n Fiα i= n n + n α (n–)α ≥ n – V n , n + (n!) (.) with equality iff n is regular. Proof of Theorem and Theorem The inequality (.) can be written as μn,k Viα (k) + Viα (k)Vjα (k) – λ ≤i<j≤μn,k i= ≥ R nr μn,k i= √ kα n(n+)(n–) Viα (k) · μn,k (μn,k – λ) · nk α n! k+ kα V n . √ k! n+ (.) Now we prove that the inequality (.) is valid. Let p(k, α, δ) denote the left of the inequality (.). Then p(k, α, δ) = Viα (k)Vjα (k) – (n – k) ≤i<j≤μn,k μn,k Viα (k) i= Viαp (k)Viαq (k) – k+ Viα (k) p p= ≤p<q≤k+ (i ,i ,...,ik+ )∈σ + Viα (k) + (n + – k – λ) i= = μn,k Viαp (k)Viαq (k) + (n + – k – λ) ip ,iq ∈τ μn,k Viα (k), (.) i= where σ = {(i , i , . . . , ik+ )| there exists a (k + )-subsimplex Ai Ai · · · Aik+ of n , such that its k + side areas are Vi (k), Vi (k), . . . , Vik+ (k) ( ≤ i < i < · · · < ik+ μn,k )}, and τ = {(ip , iq )| there is not a (k + )-subsimplex of n , such that its two side areas are Vip (k), Viq (k)}. On the other hand, we easily get n+ μn,k n+ |σ | = , |τ | = – = μn,k – (n – k)(k + ) – . k+ k+ n+ n–k We put m = |σ |, then m = k+ = k+ · μn,k . If (i , i , . . . , ik+ ) ∈ σ , we use Vi (k + ) to denote the volume of k + -subsimplex with side areas Vi (k), Vi (k), . . . , Vik+ (k). By Lemma we have Viαp (k)Viαq (k) – k+ Viα (k) p p= ≤p<q≤k+ (k + ) ≥ k(k + ) k+ k+ (k + )! k+ α Vi (k + ) kα Equality holds iff the simplex Ai Ai · · · Aik+ is regular. k+ . (.) Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 Page 7 of 14 Using the arithmetic-geometric means inequality, (.), and (.) we get I = Viαp (k)Viαq (k) – k(k + ) (i , ,...,ik+ )∈σ k+ Viα (k) p p= ≤p<q≤k+ (i ,i ,...,ik+ )∈σ ≥ α k+ kα k+ (k + ) Vi (k + ) k+ k + (k + )! kα α μ n,k+ (k+)μn,k+ k+ k+ (k + ) ≥ μn,k+ k(k + ) V (k + ) i k + (k + )! i= α k+ (k + ) k+ ≥ k(k + ) k + (k + )! √ k+ kα n k+ n! k+ kα · μn,k+ V n √ (k + )! n+ kα √ nk α R n(n+)(n–) n! k+ kα = μn,k+ k(n – k) V n . √ nr (k)! n+ R nr kα n(n+)(n–) (.) By the arithmetic-geometric means inequality, and by (.), we get I = Viαp (k)Viαq (k) + (n + – k – λ) μn,k Viα (k) i= (ip ,iq )∈τ ≥ μn,k μn,k – (n – k)(k + ) – μn,k μα n,k Vi (k) + (n + – k – λ)μn,k μn,k i= ≥ R nr kα n(n+)(n–) μα n,k Vi (k) i= μn,k μn,k – (n – k)k – λ √ k+ n! √ (k)! n+ nk α V kα n . (.) From (.), (.), and (.) we get p(k, α, λ) = I + I ≥ R nr kα n(n+)(n–) √ μn,k [μn,k – λ] nk α k+ n! kα V n . √ (k)! n+ (.) Thus the equality (.) is valid. It is easy to prove that the equality holds iff n is regular. Similarly, we can prove that (.) is true by the same method. 3 Some applications Geometric inequalities for simplices which are the simplest and useful polytopes have been a very attractive subject for a long time. Mitrinović, Pečarić, Volenec, Zhang and Yang and other authors have obtained a great number of elegant results (see []). Specially, we mention the well-known Euler inequality for a simplex, inequalities for the width of a simplex, and inequalities related the interior point of a simplex. In this section we shall improve these inequalities by using the results in the above section. Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 Page 8 of 14 LF Tóth extended the Euler inequality R ≥ r for a triangle to an n-dimensional simplex and obtained the Euler inequality for an n-simplex as follows [, ]: R ≥ nr. (.) Equality holds iff n is regular. Let O and I denote the circumcenter and the incenter of an n-simplex n , respectively. Let G be the barycenter of n . Klamkin [, ] and Yang and Wang obtained the following generalizations of (.): R – |OI| ≥ (nr) , (.) R – |OG| ≥ (nr) . (.) Equality holds iff n is regular. We shall use these results in the above section to study related inequalities, and we obtain a strengthened Euler inequality as follows. Theorem For an n-simplex n and k = , , . . . , n – , we have R – |OG| k ≥ R nr k n(n+)(n–) (nr)k + Vi (k) – Vj (k) , μn,k – (n + – k) ≤i<j≤μ n,k (.) R – |OG| k ≥ V V k n(n+)(n–) (nr)k + Vi (k) – Vj (k) . μn,k – (n + – k) ≤i<j≤μ n,k (.) Equality holds iff n is regular. If take k = and k = n – in (.) and (.), we get two corollaries as follows. Corollary For an n-simplex n and k = , , . . . , n – , we have R – |OG| ≥ R – |OG| ≥ R nr V V n(n+)(n–) n(n+)(n–) (nr) + (nr) + n(n – ) n(n – ) (ai – aj ) , (.) (ai – aj ) , (.) ≤i<j≤ n(n+) ≤i<j≤ n(n+) with equality iff n is regular. Corollary For an n-simplex n and k = , , . . . , n – , we have n– R – |OG| ≥ R nr n(n –) (nr)(n–) + (Fi – Fj ) , n – ≤i<j≤n (.) Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 n– R – |OG| ≥ V V n(n –) Page 9 of 14 (nr)(n–) + (Fi – Fj ) . n – ≤i<j≤n (.) Equality holds iff n is regular. Proof of Theorem If take α = and λ = n + – k in (.) and (.), we obtain μn,k R nr Vi (k) ≥ i= + n(n+)(n–) k k + (n!) n k μn,k · Vn (k!) n + Vi (k) – Vj (k) , μn,k – (n + – k) ≤i<j≤μ (.) n,k μn,k V V Vi (k) ≥ i= + n(n+)(n–) k k + (n!) n k μn,k · Vn (k!) n + Vi (k) – Vj (k) . μn,k – (n + – k) ≤i<j≤μ (.) n,k We use the well-known equality [, ] n(n+) ai = (n + ) R (.) i= and the well-known inequality [, ] μn,k Vi (k) ≤ i= n! k n (k!) (n – k)!(n + )k– n(n+) k ai . (.) i= Equality holds iff n is regular. When k = , then (.) is the identity. By (.) and (.) we get μn,k Vi (k) ≤ i= (n + )k+ n! k R . (k!) nk (n – k)! (.) We use the well-known inequality in [] n V≥ n (n + ) n! n+ rn , (.) with equality iff n is regular. From (.), (.), and (.) we can obtain (.). By (.), (.), and (.) we can obtain (.). It is easy to see that equality holds in (.) or (.) iff n is regular. Let ω be the width of n . We put βn = n[ n+ ](n + – [ n+ ]) . (n + ) Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 Page 10 of 14 In , Alexander [, ] proved Sallee’s conjecture and obtained the inequality ω– ≥ βn R– . (.) Equality holds iff n is regular. In , Yang and Zhang [, ] improved (.) and established an inequality as follows: ω– ≥ βn (n + ) n+ n n · (n!) n V–n , (.) with equality iff n is regular. In this section, we shall give generalizations of the equalities (.) and (.) by using (.) and (.) in the above section. Theorem For an n-simplex n and k = , , . . . , n – , we have ω– ≥ ω – ≥ R nr V V n(n –) n(n –) βn βn (n + ) n+ n n · (n!) (n + ) n n+ n n · (n!) n V – n + βn V – n + βn (n + )V – (Fi – Fj ) , n (n – ) ≤i<j≤n (.) (n + )V – (Fi – Fj ) . n (n – ) ≤i<j≤n (.) Equality holds iff n is regular. Proof We use the well-known inequality in [] as follows: n (n + ) ω ≤ n+ [ ](n + – [ n+ ]) ( n V i= Fi ) . Equality holds iff n is regular. The above inequality can be written as ω – n+ ≥ βn · n n i= Fi . V (.) By (.) and (.) we can get (.), and from (.) and (.) we can get (.). Substituting (.) into (.) and (.) we obtain generalizations of the inequality (.) as follows. Corollary For an n-simplex n and k = , , . . . , n – , we have ω– ≥ ω – ≥ R nr V V n(n –) n(n –) βn R– + βn (n + )V – (Fi – Fj ) , n (n – ) ≤i<j≤n (.) βn R– + βn (n + )V – (Fi – Fj ) . n (n – ) ≤i<j≤n (.) Equality holds iff n is regular. Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 Page 11 of 14 For i = , , . . . , n, let hi be the altitude of the ith face of the simplex n . The following inequality is well known (see []): n n n+ n n V ≥ hi . (n!) (n + )n– i= (.) Equality holds iff n is regular. By using the results in Section we can obtain generalizations of the inequality (.) as follows. Theorem For an n-simplex n and k = , , . . . , n – , we have V (n –)k R nr ≥ n (n –)k n n+ nn · hi (n!) (n + )n– i= kα n(n+)(n–) (nr)(n –n–)k (n + )n+ (n –)k Vi (k) – Vj (k) , + n μn,k – (n + – k) n · (n!) ≤i<j≤μ (.) n,k V (n –)k V V ≥ + n (n –)k n n+ nn · hi (n!) (n + )n– i= kα n(n+)(n–) (n + )n+ (n –)k (nr)(n –n–)k Vi (k) – Vj (k) . n μn,k – (n + – k) n · (n!) ≤i<j≤μ (.) n,k Equality holds iff n is regular. Proof We take k = n – in (.) and (.), and get n Fi ≥ i= n Fi ≥ i= R nr V V n(n–) (n!) V n+ n n(n–) Using the formula Fi = (n –)k n (n+) (n + ) n (n!) nV hi n+ n n – n (n+) (n + ) n – n V n – n , (.) V n – n . (.) (see []) and (.) we get n (n –)k n n+ nn Rk ≥ hi . (nr)k (n!) (n + )n– i= (.) By Theorem we get Rk ≥ R nr k n(n+)(n–) (nr)k + Vi (k) – Vj (k) . μn,k – (n + – k) ≤i<j≤μ n,k (.) Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 Page 12 of 14 Substituting (.) into (.) we get V (n –)k ≥ R nr kα n(n+)(n–) n (n –)k n n+ nn · hi (n!) (n + )n– i= n (n –)k n n+ nn · + hi (nr)k [μn,k – (n + – k)] (n!) (n + )n– i= Vi (k) – Vj (k) . · (.) ≤i<j≤μn,k We use the well-known inequality in [, ] as follows: n hi ≥ (n + )n+ rn+ , (.) i= with equality holding iff n is regular. From (.) and (.) we can obtain (.). It is easy to see that equality holds iff n is regular. By a similar method we can prove that inequality (.) is also valid. Let P be an interior point of n and di the distance from the point P to the ith face fi of n for i = , , . . . , n. In [], Gerber established the following inequality: n – nn(n+) (n + )(n+) n – (n+) di ≥ V n . (.) (n!)(n+) i= For any natural number m > , Leng and Ma [] obtained an inequality as follows: (di di )–m – (μn, )–m · · r–m mn n ≥ (μn, )–m (μn, )m – nm R–m m . (.) ≤i<j≤n Equalities hold in (.) and (.) iff n is regular and P is the center of n . By using the results in the Section we can obtain generalizations of (.) and (.) as follows. Theorem For an n-simplex n , we have n – n+ R n(n –) n (n + )(n+) n – (n+) di ≥ · V n nr (n!)(n+) i= + n – di ≥ i= + nn– (n + )n+ V – (Fi – Fj ) , (n!) (n – ) ≤i<j≤n V V n(n –) nn+ (n + )(n+) · (n!)(n+) n V– (.) (n+) n nn– (n + )n+ V – (Fi – Fj ) . (n!) (n – ) ≤i<j≤n Equality holds in (.) or (.) iff n is regular and P is the center of n . (.) Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 Page 13 of 14 Proof By (.), we have n – (n + )(n+) –(n+) V Fi . n(n+) i= n ≥ di i= (.) We use the well-known inequality in [] as follows: n nn (n–) ≥ V Fi . (n!) (n + )n i= n Fi i= (.) Equality holds iff n is regular. Using (.) and (.) we get n Fi ≥ i= + R nr n(n –) n(n+) (n!) (n+) n (n + ) n – n nn V (n–) (n!) (n + )n (n – ) V (n –) n (Fi – Fj ) . (.) ≤i<j≤n From (.) and (.) we can obtain (.). It is easy to see that equality holds in (.) iff n is regular and P is the center of n . By a similar method we can prove that (.) is valid. Theorem Let n be an n-simplex and m > a natural number, then we have (di dj )–m – (μn, )–m r–m mn ≤i<j≤n ≥ R nr n(n+)(n–) n (μn, )–m (μn, )m – nm R–m m · γ (n, m)(Rr)– (ai – aj ) , (.) ≤i<j≤μn, (di dj )–m – (μn, )–m r–m mn ≤i<j≤n ≥ V V n(n+)(n–) n (μn, )–m (μn, )m – nm R–m m · γ (n, m)(Rr)– (ai – aj ) . ≤i<j≤μn, Equality holds iff n is regular and P is the center of n , where n γn,m = (μn, )–m (μn, )m – m · . nn+ (n – ) Proof We use the following well-known inequality (.) in []: ≤i<j≤n (di dj ) –m ≥ (μn, ) –m mn (μn, )m – –m m m n+ + (n + ) n · r , m n! V n (.) Yang and Wang Journal of Inequalities and Applications (2015) 2015:56 Page 14 of 14 i.e. (di dj )–m – (μn, )–m r–m ≤i<j≤n ≥ (μn, ) –m m m (n + ) n m n+ · (μn, )m – n . n! V (.) Equality holds iff n is regular and P is the center of n . From (.) we have n! · nn ≥ R . V (n + )n+ Rn (nr) (.) Substituting (.) into (.) and using (.) we can obtain (.). It is easy to see that equality holds in (.) iff n is regular and P is the center of n . The proof of (.) is similar. In fact, the strengthening of some well-known inequalities for simplices can be derived from Theorem and Theorem . In this paper, we omit the details. Competing interests The authors declare that they have no competing interests. Authors’ contributions The authors co-authored this paper together. All authors read and approved the final manuscript. Author details 1 School of Mathematics and Statistics, Hefei Normal University, Hefei, Anhui 230601, P.R. China. 2 Department of Mathematics and Physics, Anhui Xinhua University, Hefei, 230088, P.R. China. Acknowledgements This work is supported by the Doctoral Programs Foundation of Education Ministry of China (20113401110009) and Foundation of Anhui higher school (KJ2013A220); Natural Science Research Project of Hefei Normal University (2012kj11). The authors are grateful for the help. 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