3.5 Expected Values Ulrich Hoensch MAT310 Rocky Mountain College Billings, MT 59102 Expected Value Definition 3.5.1 Let X be a discrete random variable with probability mass function p(xi ). The expected value of X is defined as X µ = E (X ) = xi p(xi ). i Let X be a continuous random variable with probability density function f (x). The expected value of X is defined as Z ∞ µ = E (X ) = xf (x) dx. −∞ Example 1 Find the expected value of each random variable. 1. X is given by the PMF: x 0 1 2 3 p(x) 1/8 3/8 3/8 1/8 X E (X ) = xi p(xi ) i = (0)(1/8) + (1)(3/8) + (2)(3/8) + (3)(1/8) = 12/8 = 3/2. 2. X is given by the PDF e −x if x ≥ 0 0 if x < 0 Z ∞ Z ∞ E (X ) = xf (x) dx = xe −x dx −∞ Z ∞ 0 Z ∞ ∞ −x −x = −xe 0 + e dx = e −x dx = 1. f (x) = 0 0 Binomial and Hypergeometric Distribution 1. If X ∼ B(n, p), then for k = 0, 1, 2, . . . , n n k p(k) = p (1 − p)n−k , k and E (X ) = np. 2. If X ∼ H(n, K , N), then for k = 0, 1, 2, . . . , n K N−K p(k) = k n−k N n and E (X ) = n K . N , Poisson Random Variable Definition: A random variable X with the PMF p(k) = e −λ λk , k = 0, 1, 2, . . . k! is called a Poisson random variable with parameter λ > 0. We write X ∼ Poisson(λ). The expected value of X is E (X ) = ∞ X k=0 = ... = λ. ke −λ λk k! Standard Normal Random Variable Definition: A random variable Z with the PDF 1 2 f (z) = √ e −z /2 2π is called a standard normal random variable. Since z 7→ ze −z 2 /2 is an odd function, the expected value of Z is Z ∞ 1 2 E (Z ) = z √ e −z /2 dz = 0. 2π −∞ Expected Value of a Function of a Random Variable Theorem 3.5.3 Let X be a random variable, and let g (X ) be a function of X . Then, X g (xi )p(xi ) if X is discrete i Z E [g (X )] = ∞ g (x)f (x) dx if X is continuous −∞ Properties of Expected Values Let c, d ∈ R and g (X ), g1 (X ), g2 (X ), . . . , gn (X ) be functions of the random variable X . Then, 1. E (c) = c 2. E (cg (X ) + d) = cE (g (X )) + d ! n n X X 3. E gi (X ) = E (gi (X )) i=1 i=1 Normal Random Variable Definition: A random variable X is called a normal random variable with parameters µ ∈ R and σ > 0 if X = σZ + µ, where Z is a standard normal random variable. We write X ∼ N(µ, σ 2 ). The expected value of X is E (X ) = E (σZ + µ) = σE (Z ) + µ = µ. Example 2 The speed S of a molecule in a perfect gas has a density function given by r a3 2 −as 2 s e f (s) = 4 , π where s ≥ 0 and a > 0 is a constant. The kinetic energy is 1 W = mS 2 . 2 Thus, the expected value for the kinetic energy is r Z ∞ 1 2 a3 2 −as 2 E (W ) = ms 4 s e ds 2 π 0 = ... 3m = . 4a Median and Quantiles Definition 3.5.2 Suppose X is a continuous random variable and F (x) is its CDF. Then: I The median of X is the value m so that F (m) = 0.5. I The q-quantile of X is the value xq so that F (xq ) = q, where 0 < q < 1. Thus, m = x0.5 . Exponential Random Variable Definition: A random variable X is called an exponential random variable with parameters λ > 0 if it has the PDF f (x) = λe −λx for x ≥ 0. We write X ∼ E (λ). The expected value of X is Z ∞ 1 E (X ) = xλe −λx dx = . λ 0 The CDF is x Z F (x) = λe −λt dt = 1 − e −λx . 0 Thus, the median is obtained by solving the equation 1 − e −λx = 0.5 for x. This gives m= log 2 1 < = E (X ). λ λ Practice Problems for Section 3.5 I p.149: 3.5.9, 3.5.17, 3.5.27; I p.155: 3.5.31, 3.5.33.
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