Electronic I (DMT 121)
Laboratory Module
Exp.6
EXPERIMENT 6
Voltage Divider Biasing
1.
OBJECTIVE
1.1
1.2
2.
To analyze the voltage-divider bias circuit
To construct the dc load line
INTRODUCTION
The advantage of using voltage divider bias is that the base current is made
small compared to the currents through the two base (“voltage divider”) resistors.
With this property, transistor beta changes will no longer affect the base voltage
and the collector current.
2.1
Quiescent dc base voltage
VB
2.2
2.7
VB - VBE
(7.2)

VE
( IC  IE for large  )
RE
(7.3)
=
VCC - ICRC
(7.4)
Quiescent dc collector to emitter voltage
VCE
2.6
=
Quiescent collector voltage
VC
2.5
(7.1)
Quiescent dc collector (emitter) current
IC
2.4
 R2 

VCC
 R1  R2 
Quiescent dc emitter voltage
VE
2.3


VCC – IC( RC + RE)
=
VC – VE
(7.5)
Dc load line
IC(sat)

VCE(off)
=
VCC
(saturation)
RC  RE
VCC (cutoff)
(7.6)
(7.7)
In general, make :
R1 || R2  RE
(7.8)
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Electronic I (DMT 121)
Laboratory Module
Exp.6
3.
COMPONENT AND EQUIPMENT
3.1 Resistors:
3.1.1 Two 1 kΩ
3.1.2 4.7 kΩ
3.1.3 10 kΩ
3.2 10 kΩ potentiometer
3.3 2N3904 NPN silicon transistors
3.4 0-15V dc power supply
3.5 Multimeter
4.
PROCEDURE
4.1
Determination of VB, VE, VC and VCE:
4.1.1 Construct the voltage divider bias circuit shown in Figure 7.1.
Figure 7.1 Schematic diagram of circuit
4.1.2
4.1.3
4.2
Calculate the expected values of the quiescent dc base voltage
(VB), emitter voltage (VE), collector voltage (VC), and collector
emitter voltage (VCE) using typical value for the base-emitter voltage
of a silicon transistor (0.7V).
Record these values in Table 7.1.
Measuring of VB, VC, VE,VCE and IC using Multimeter:
4.2.1 At this point, wire the circuit shown in the schematic diagram in
Figure 7.1
4.2.2 Apply power to the breadboard.
(NOTE: The pin diagram for the 2N3904 is given in Figure 7.2)
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Electronic I (DMT 121)
Laboratory Module
Exp.6
Figure 7.2 2N3904 pin diagram
4.2.3
4.2.4
Take your multimeter and measure VB, VC, VE and VCE.
Record your results in Table 7.1 and make comparison between
these measured values with the expected voltages determined
before.
(NOTE: Your results should agree within 10%)
4.2.5
4.2.6
4.3
Now measure the quiescent collector current and compare this
value with the expected value (Equation 7.3).
Record this value in Table 7.1.
Determination of DC Load Line:
4.3.1 Calculate the saturation and cutoff points on the dc load line for this
circuit using the equations 7.6 & 7.7.
4.3.2 Record these values in Table 7.2.
4.3.3 Then, plot the dc load line, using the calculated values of IC(sat) and
VCE(off) as the endpoints of the load line.
4.3.4 On the same graph, plot the Q point based on the measured values
of IC and VCE.
(NOTE: You should find that the measured Q point lies essentially on the dc
load line)
4.4
Measuring voltage and current in ‘cutoff’ condition:
4.4.1 By using the same transistor , disconnect power from the
breadboard.
4.4.2 Replace resistors R1 and R2 with a 10 kΩ potentiometer as shown in
Figure 7.3.
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Electronic I (DMT 121)
Laboratory Module
Exp.6
Figure 7.3
4.4.3
4.4.4
4.4.5
4.4.6
4.4.7
4.5
Schematic diagram from Step 5
Now, connect the power to the breadboard.
Connect a multimeter between the transistor’s collector and emitter
terminals.
Then, slowly vary the 10 kΩ potentiometer until VCE as read by the
multimeter reaches a maximum value, VCE(OFF).
Then measure the corresponding collector current, IC(OFF).
Record both values in Table 7.2.
Measuring voltage and current in ‘saturation’ condition:
4.5.1 Carefully vary the resistance of the 10 kΩ potentiometer until the
collector current reaches a maximum value while continuing to
measure the transistor’s collector current (IC)
(NOTE: This is the collector saturation current IC(sat). )
4.5.2
4.5.3
Now measure the corresponding collector emitter voltage VCE(sat).
Record the values for both IC(sat) and VCE(sat) in Table 7.2.
(NOTE: At saturation, VCE(sat) is ideally zero while at cutoff, IC(off) is zero. )
4.5.4
4.6
Now, plot the values for IC and VCE at cutoff and saturation on the
graph constructed in Step 3
Measuring IC and VCE over the ‘active region’ of the dc load line:
4.6.1 Now, vary the potentiometer so that you are able to measure about
five combinations of IC and VCE .
4.6.2 Record all values in Table 7.2.
4.6.3 Then plot these values on the graph.
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Electronic I (DMT 121)
Laboratory Module
Exp.6
Name
: ______________________________
Date : ______________
Matric No.:______________________________
5.
Course : ______________
RESULT
Table 7.1
Parameter
Dc Values
Measured Values
Expected
Transistor 1
Value
VB
VC
VE
VCE
IC
Table 7.2
Condition
Dc load line
Expected Values
IC
VCE
Measured Values
IC
Cutoff
(Step 5)
Saturation
(Step 6)
Active
Region
(Step 7)
Instructor Approval :
____________________
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Date :_____________
VCE
Electronic I (DMT 121)
Laboratory Module
Exp.6
Name
: ______________________________
Matric No.:______________________________
6.
CALCULATIONS:
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Date : ______________
Course : ______________
Electronic I (DMT 121)
Laboratory Module
Exp.6
Name
: ______________________________
Date : ______________
Matric No.:______________________________
7.
Course : ______________
DISCUSSION
PART A - TROUBLESHOOTING PROBLEM
1.
0.0V
0.0V
Figure 7.4
A student constructs the circuit in Figure 7.4 and measured the voltage as displayed in
above figure. Why the base and emitter voltage is equal to 0V.
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Electronic I (DMT 121)
Laboratory Module
Exp.6
Name
: ______________________________
Date : ______________
Matric No.:______________________________
Course : ______________
RC
2.
+ 12 V
Gnd
R1
Emitter
Base
R2
Collector
RE
Figure 7.5
A pnp transistor is used with voltage divider bias in the circuit shown above. Calculate
the dc parameters listed in below ( R1  10k, R2  56k, RC  2.7k, RE  1.5k ).
1. VB
2. VE
IE
4. VC
5. VCE
3.
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Electronic I (DMT 121)
Laboratory Module
Exp.6
Name
: ______________________________
Matric No.:______________________________
8.
Date : ______________
Course : ______________
CONCLUSION
Based on the DC load line graph, make your conclusion (your answer should be
in a simple note).
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