Discrete Probability Conditional expectation of a random variable R. Inkulu http://www.iitg.ac.in/rinkulu/ (Conditional Expectation) 1/9 Definition • If X and Y are two random variables with the joint distribution, the conditional expectation of Y for a given X = xj , denoted with P E(Y|X = xj ), is yk ∈range(Y) yk p(Y = yk |X = xj ). • Essentially, the expression E(Y|X) is a random variable f (X) that takes on the value E(Y|X = xj ) when X = xj . (Conditional Expectation) 2/9 Example The conditional expectation of rolling a fair die given that the number rolled is ≤ 3: letting X denotes the number rolled, (Conditional Expectation) 3/9 Example The conditional expectation of rolling a fair die given that the number rolled is ≤ 3: letting XPdenotes the number rolled, E(X|X ≤ 3) = 3i=1 ip(X = i|X ≤ 3) = 2. (Conditional Expectation) 3/9 Example Suppose that we independently roll two fair dice. Let X1 be the number that that shows on the first die, X2 the number on the second die, and X the sum of the numbers on the two dice. Then • E(X|X1 ) = (Conditional Expectation) 4/9 Example Suppose that we independently roll two fair dice. Let X1 be the number that that shows on the first die, X2 the number on the second die, and X the sum of the numbers on the two dice. Then PX1 +6 P 7 1 • E(X|X1 ) = i ip(X = i|X1 ) = i=X1 +1 (i)( 6 ) = X1 + 2 — hence, E(X|X1 ) is a function with X1 as its domain (Conditional Expectation) 4/9 Example Suppose that we independently roll two fair dice. Let X1 be the number that that shows on the first die, X2 the number on the second die, and X the sum of the numbers on the two dice. Then PX1 +6 P 7 1 • E(X|X1 ) = i ip(X = i|X1 ) = i=X1 +1 (i)( 6 ) = X1 + 2 — hence, E(X|X1 ) is a function with X1 as its domain E(X|X1 = 2) = (Conditional Expectation) 4/9 Example Suppose that we independently roll two fair dice. Let X1 be the number that that shows on the first die, X2 the number on the second die, and X the sum of the numbers on the two dice. Then PX1 +6 P 7 1 • E(X|X1 ) = i ip(X = i|X1 ) = i=X1 +1 (i)( 6 ) = X1 + 2 — hence, E(X|X1 ) is a function with X1 as its domain E(X|X1 = 2) = (Conditional Expectation) 11 2 4/9 Example Suppose that we independently roll two fair dice. Let X1 be the number that that shows on the first die, X2 the number on the second die, and X the sum of the numbers on the two dice. Then PX1 +6 P 7 1 • E(X|X1 ) = i ip(X = i|X1 ) = i=X1 +1 (i)( 6 ) = X1 + 2 — hence, E(X|X1 ) is a function with X1 as its domain E(X|X1 = 2) = 11 2 • E(X1 |X = 5) = (Conditional Expectation) 4/9 Example Suppose that we independently roll two fair dice. Let X1 be the number that that shows on the first die, X2 the number on the second die, and X the sum of the numbers on the two dice. Then PX1 +6 P 7 1 • E(X|X1 ) = i ip(X = i|X1 ) = i=X1 +1 (i)( 6 ) = X1 + 2 — hence, E(X|X1 ) is a function with X1 as its domain E(X|X1 = 2) = • E(X1 |X = 5) = (Conditional Expectation) 11 2 P4 i=1 ip(X1 = i|X = 5) = 5 2 4/9 Law of total expectations For any random variables X and Y, E(X) = P y∈range(Y) p(Y = y)E(X|Y = y). - conditional expectations are quite useful in dividing the expectation calculation into simpler cases Ex: Supoose that there are m percent of the people are male and the rest are female. Also, suppose that the expected height of male is hm and the expected height of women is hw . Then the expected height of a randomly chosen person is (Conditional Expectation) 5/9 Law of total expectations For any random variables X and Y, E(X) = P y∈range(Y) p(Y = y)E(X|Y = y). - conditional expectations are quite useful in dividing the expectation calculation into simpler cases Ex: Supoose that there are m percent of the people are male and the rest are female. Also, suppose that the expected height of male is hm and the expected height of women is hw . Then the expected height of a randomly chosen m m person is hm 100 + hw (1 − 100 ). (Conditional Expectation) 5/9 Extending linearity of expectations For any finite collection of discrete random variables X1 , X2 , . . . , Xn with finite P expectations andPfor any random variable Y, E[ ni=1 Xi |Y = y] = ni=1 E[Xi |Y = y]. — homework (Conditional Expectation) 6/9 Expectation of E[Y|Z] For random variables Y and Z, E[Y] = E[E[Y|Z]]. Ex. Suppose that we independently roll two fair dice. Let X1 be the number that that shows on the first die, X2 the number on the second die, and X the sum of the numbers on the two dice. We have seen that E(X|X1 ) = X1 + 72 . Thus E(E(X|X1 )) = E(X1 + 27 ) = E(X1 ) + 72 = 7 = E(X). (Conditional Expectation) 7/9 Example: expectation of a sum of a random number of random variables Suppose the number of customers entering the store on a given day is a random variable with mean µ′ . Also, suppose that the amounts of money spent by these customers are independent random variables having a common mean of µ′′ . Assume that the amount of money spent by a customer is also independent of the total number of customers to enter the store. Then the expected amount of money spent in the store on a given day is (Conditional Expectation) 8/9 Example: expectation of a sum of a random number of random variables Suppose the number of customers entering the store on a given day is a random variable with mean µ′ . Also, suppose that the amounts of money spent by these customers are independent random variables having a common mean of µ′′ . Assume that the amount of money spent by a customer is also independent of the total number of customers to enter the store. Then the expected amount of money spent in the store on a given day is µ′ µ′′ . (Conditional Expectation) 8/9 Example: branching process Consider a program that includes one call to a proces S. Assume that each call to process S recursively spawns new copies of the process S, where the number of new copies is a random variable whose expected value is np. Further, assuming that these random variables are independent for each call to S, the expected number of copies of the process S generated by program are (Conditional Expectation) 9/9 Example: branching process Consider a program that includes one call to a proces S. Assume that each call to process S recursively spawns new copies of the process S, where the number of new copies is a random variable whose expected value is np. Further, assuming that these random variables are independent for each call to S, number of copies of the process S generated by program are Pthe expected i. (np) i≥0 (Conditional Expectation) 9/9
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