Hindawi Publishing Corporation Abstract and Applied Analysis Volume 2013, Article ID 214123, 8 pages http://dx.doi.org/10.1155/2013/214123 Research Article Further Refinements of Jensen’s Type Inequalities for the Function Defined on the Rectangle M. Adil Khan,1 G. Ali Khan,1 T. Ali,1 T. Batbold,2 and A. Kiliçman3 1 Department of Mathematics, University of Peshawar, Peshawar 25000, Pakistan Institute of Mathematics, National University of Mongolia, P.O. Box 46A/104, 14201 Ulaanbaatar, Mongolia 3 Department of Mathematics and Institute of Mathematical Research, Universiti Putra Malaysia (UPM), 43400 Serdang, Selangor, Malaysia 2 Correspondence should be addressed to A. Kiliçman; [email protected] Received 26 September 2013; Accepted 10 November 2013 Academic Editor: Abdullah Alotaibi Copyright © 2013 M. Adil Khan et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. We give refinement of Jensen’s type inequalities given by Bakula and Pečarić (2006) for the co-ordinate convex function. Also we establish improvement of Jensen’s inequality for the convex function of two variables. 1. Introduction Jensen’s inequality for convex functions plays a crucial role in the theory of inequalities due to the fact that other inequalities such as the arithmetic mean-geometric mean inequality, the Hölder and Minkowski inequalities, and the Ky Fan inequality, can be obtained as particular cases of it. Therefore, it is worth studying it thoroughly and refining it from different point of view. There are many refinements of Jensen’s inequality; see, for example, [1–14] and the references in them. A function 𝑓 : [𝑎, 𝑏] × [𝑐, 𝑑] → R, [𝑎, 𝑏] × [𝑐, 𝑑] ⊂ R2 with 𝑎 < 𝑏 and 𝑐 < 𝑑 is called convex on the co-ordinates if the partial mappings 𝑓𝑦 : [𝑎, 𝑏] → R defined as 𝑓𝑦 (𝑡) = 𝑓(𝑡, 𝑦) and 𝑓𝑥 : [𝑐, 𝑑] → Rdefined as 𝑓𝑥 (𝑠) = 𝑓(𝑥, 𝑠) are convex for all 𝑥 ∈ [𝑎, 𝑏], 𝑦 ∈ [𝑐, 𝑑]. Note that every convex function 𝑓 : [𝑎, 𝑏] × [𝑐, 𝑑] → R is co-ordinate convex, but the converse is not generally true [8]. The following theorem has been given in [4]. Theorem 1. Let 𝑓 : [𝑎, 𝑏] × [𝑐, 𝑑] → R be a convex function on the co-ordinates on [𝑎, 𝑏] × [𝑐, 𝑑]. If x is an n-tuple in [𝑎, 𝑏], y is m-tuple in [𝑐, 𝑑], p is a nonnegative n-tuple, and w is a nonnegative m-tuple such that 𝑃𝑛 = ∑𝑛𝑖=1 𝑝𝑖 > 0 and 𝑊𝑚 = ∑𝑚 𝑖=1 𝑤𝑗 > 0, then 𝑓( 1 𝑛 1 𝑚 ∑𝑝𝑖 𝑥𝑖 , ∑𝑤 𝑦 ) 𝑃𝑛 𝑖=1 𝑊𝑚 𝑗=1 𝑗 𝑗 ≤ } 1{1 𝑛 1 𝑚 𝑝 𝑓 (𝑥 , 𝑦) + ∑ ∑𝑤 𝑓 (𝑥, 𝑦𝑗 )} 𝑖 𝑖 2 { 𝑃𝑛 𝑖=1 𝑊𝑚 𝑗=1 𝑗 } { ≤ 1 𝑛 𝑚 ∑ ∑𝑝 𝑤 𝑓 (𝑥𝑖 , 𝑦𝑗 ) , 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝑖 𝑗 (1) where 𝑥 = (1/𝑃𝑛 ) ∑𝑛𝑖=1 𝑝𝑖 𝑥𝑖 , and 𝑦 = (1/𝑊𝑚 ) ∑𝑚 𝑗=1 𝑤𝑗 𝑦𝑗 . Recently Dragomir has given new refinement for Jensen inequality in [9]. The purpose of this paper is to give related refinements of Jensen’s type inequalities (1) for the co-ordinate convex function. We will also discuss some particular interesting cases. We establish improvement of Jensen’s inequality for the convex function defined on the rectangles. For related improvements of Jensen’s inequality, 2 Abstract and Applied Analysis see, for example, [1, 2, 9, 13, 14]. For further several related integral inequalities, see [15]. 𝐷𝑘 (𝑓, p, x) := 𝐷 (𝑓, p, x, {𝑘}) 2. Main Results Let 𝑓 : [𝑎, 𝑏] × [𝑐, 𝑑] → R be convex on the co-ordinate on [𝑎, 𝑏] × [𝑐, 𝑑]. If 𝑥𝑖 ∈ [𝑎, 𝑏], 𝑦𝑗 ∈ [𝑐, 𝑑], 𝑝𝑖 , 𝑤𝑗 > 0, 𝑖 ∈ {1, 2, . . . , 𝑛}, 𝑗 ∈ {1, 2, . . . , 𝑚} with 𝑃𝑛 = ∑𝑛𝑖=1 𝑝𝑖 , and 𝑊𝑚 = ∑𝑚 𝑗=1 𝑤𝑗 , then for any subsets 𝐼 ⊂ {1, 2, . . . , 𝑛} and 𝐽 ⊂ {1, 2, . . . , 𝑚}, we assume that 𝐼 := {1, 2, . . . , 𝑛} \ 𝐼 and 𝐽 := {1, 2, . . . , 𝑚} \ 𝐽. Define 𝑃𝐼 = ∑𝑖∈𝐼 𝑝𝑖 , 𝑃𝐼 = ∑𝑖∈𝐼 𝑝𝑖 , 𝑊𝐽 = ∑𝑗∈𝐽 𝑤𝑗 , and 𝑊𝐽 = ∑𝑗∈𝐽 𝑤𝑗 . For the function 𝑓 and the 𝑛-, 𝑚-tuples, x = (𝑥1 , 𝑥2 , . . . , 𝑥𝑛 ), y = (𝑦1 , 𝑦2 , . . . , 𝑦𝑚 ), p = (𝑝1 , 𝑝2 , . . . , 𝑝𝑛 ), and w = (𝑤1 , 𝑤2 , . . . , 𝑤𝑚 ), we define the following functionals: 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 ) = ∑𝑛 𝑝 𝑥 − 𝑝𝑘 𝑥𝑘 𝑃 − 𝑝𝑘 𝑝𝑘 𝑓 (𝑥𝑘 , 𝑦) + 𝑛 𝑓 ( 𝑖=1 𝑖 𝑖 , 𝑦) , 𝑃𝑛 𝑃𝑛 𝑃𝑛 − 𝑝𝑘 𝐷𝑙 (𝑓, w, y) := 𝐷 (𝑓, w, y, {𝑙}) = ∑𝑚 𝑤𝑙 𝑊 − 𝑤𝑙 𝑗=1 𝑤𝑗 𝑦𝑗 − 𝑤𝑙 𝑦𝑙 𝑓 (𝑥, 𝑦𝑙 ) + 𝑚 𝑓 (𝑥, ). 𝑊𝑚 𝑊𝑚 𝑊𝑚 − 𝑤𝑙 (3) The following refinement of (1) holds. Theorem 2. Let 𝑓 : [𝑎, 𝑏] × [𝑐, 𝑑] → R be a co-ordinate convex function on [𝑎, 𝑏] × [𝑐, 𝑑]. If 𝑥𝑖 ∈ [𝑎, 𝑏], 𝑦𝑗 ∈ [𝑐, 𝑑], 𝑝𝑖 , 𝑤𝑗 > 0, 𝑖 ∈ {1, 2, . . . , 𝑛}, 𝑗 ∈ {1, 2, . . . , 𝑚} with 𝑃𝑛 = ∑𝑛𝑖=1 𝑝𝑖 , and 𝑊𝑚 = ∑𝑚 𝑗=1 𝑤𝑗 , then for any subsets 𝐼 ⊂ {1, 2, . . . , 𝑛} and 𝐽 ⊂ {1, 2, . . . , 𝑚}, one has 𝑃 𝑃𝐼 1 1 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦𝑗 ) + 𝐼 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦𝑗 ) , 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝐷 (𝑓, w, y, 𝐽, 𝑥𝑖 ) 𝑊𝐽 𝑊𝐽 1 1 = 𝑓 (𝑥𝑖 , 𝑓 (𝑥𝑖 , ∑𝑤𝑗 𝑦𝑗 ) + ∑𝑤𝑗 𝑦𝑗 ) , 𝑊𝑚 𝑊𝐽 𝑗∈𝐽 𝑊𝑚 𝑊𝐽 𝑗∈𝐽 𝐷 (𝑓, p, x, 𝐼) = = 𝑃 𝑃𝐼 1 1 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦) + 𝐼 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦) , 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑓 (𝑥, 𝑦) ≤ 1 [𝐷 (𝑓, w, y, 𝐽) + 𝐷 (𝑓, p, x, 𝐼)] 2 ≤ 1 𝑚 1[1 𝑛 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) + ∑ 𝑤 𝑓 (𝑥, 𝑦𝑗 )] 2 𝑃𝑛 𝑖=1 𝑊𝑚 𝑗=1 𝑗 ] [ ≤ 1[1 𝑛 1 𝑚 ∑𝑝𝑖 𝐷 (𝑓, w, y, 𝐽, 𝑥𝑖 ) + ∑ 𝑤 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 )] 2 𝑃𝑛 𝑖=1 𝑊𝑚 𝑗=1 𝑗 ] [ ≤ 1 𝑛 𝑚 ∑ ∑𝑝 𝑤 𝑓 (𝑥𝑖 , 𝑦𝑗 ) , 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝑖 𝑗 𝐷 (𝑓, w, y, 𝐽) 𝑊𝐽 𝑊𝐽 1 1 = 𝑓 (𝑥, 𝑓 (𝑥, ∑𝑤𝑗 𝑦𝑗 ) + ∑𝑤𝑗 𝑦𝑗 ) , 𝑊𝑚 𝑊𝐽 𝑗∈𝐽 𝑊𝑚 𝑊𝐽 𝑗∈𝐽 (4) (2) where 𝑥 = (1/𝑃𝑛 ) ∑𝑛𝑖=1 𝑝𝑖 𝑥𝑖 , and 𝑦 = (1/𝑊𝑚 ) ∑𝑚 𝑗=1 𝑤𝑗 𝑦𝑗 . It is worth to observe that for 𝐼 = {𝑘}, 𝑘 ∈ {1, . . . , 𝑛}, and 𝐽 = {𝑙}, 𝑙 ∈ {1, . . . , 𝑚}, we have the functionals where 𝑥 = (1/𝑃𝑛 ) ∑𝑛𝑖=1 𝑝𝑖 𝑥𝑖 , and 𝑦 = (1/𝑊𝑚 ) ∑𝑚 𝑗=1 𝑤𝑗 𝑦𝑗 . Proof. One-dimensional Jensen’s inequality gives us 𝐷𝑘 (𝑓, p, x, 𝑦𝑗 ) 𝑓 (𝑥𝑖 , 𝑦) ≤ := 𝐷 (𝑓, p, x, {𝑘} , 𝑦𝑗 ) = 1 𝑛 𝑓 (𝑥, 𝑦𝑗 ) ≤ ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦𝑗 ) . 𝑃𝑛 𝑖=1 ∑𝑛 𝑝 𝑥 − 𝑝𝑘 𝑥𝑘 𝑝𝑘 𝑃 − 𝑝𝑘 𝑓 (𝑥𝑘 , 𝑦𝑗 ) + 𝑛 𝑓 ( 𝑖=1 𝑖 𝑖 , 𝑦𝑗 ) , 𝑃𝑛 𝑃𝑛 𝑃𝑛 − 𝑝𝑘 𝐷𝑙 (𝑓, w, y, 𝑥𝑖 ) := 𝐷 (𝑓, w, y, {𝑙} , 𝑥𝑖 ) ∑𝑚 𝑤𝑙 𝑊𝑚 − 𝑤𝑙 𝑗=1 𝑤𝑗 𝑦𝑗 − 𝑤𝑙 𝑦𝑙 = 𝑓 (𝑥𝑖 , 𝑦𝑙 ) + 𝑓 (𝑥𝑖 , ), 𝑊𝑚 𝑊𝑚 𝑊𝑚 − 𝑤𝑙 1 𝑚 ∑𝑤 𝑓 (𝑥𝑖 , 𝑦𝑗 ) , 𝑊𝑚 𝑗=1 𝑗 (5) As we have 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 ) = (6) 𝑃 𝑃𝐼 1 1 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦𝑗 ) + 𝐼 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦𝑗 ) , 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 Abstract and Applied Analysis 3 Multiplying (9) and (10), respectively, by 𝑤𝑗 and 𝑝𝑖 and summing over 𝑖 and 𝑗, we obtain so by Jensen’s inequality, we have 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 ) = 1 𝑚 1 𝑚 ∑ 𝑤𝑗 𝑓 (𝑥, 𝑦𝑗 ) ≤ ∑𝑤 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 ) 𝑊𝑚 𝑗=1 𝑊𝑚 𝑗=1 𝑗 𝑃 𝑃𝐼 1 1 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦𝑗 ) + 𝐼 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦𝑗 ) 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑃𝑛 𝑃𝐼 1 𝑛 𝑚 ≤ ∑∑ 𝑝 𝑤 𝑓 (𝑥𝑖 , 𝑦𝑗 ) , 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝑖 𝑗 𝑖∈𝐼 ≤ 𝑃 1 𝑃𝐼 1 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦𝑗 ) + 𝐼 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦𝑗 ) 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 = 1 1 ∑𝑝 𝑓 (𝑥𝑖 , 𝑦𝑗 ) + ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦𝑗 ) 𝑃𝑛 𝑖∈𝐼 𝑖 𝑃𝑛 (7) 1 𝑛 1 𝑛 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) ≤ ∑𝑝𝑖 𝐷 (𝑓, w, y, 𝐽, 𝑥𝑖 ) 𝑃𝑛 𝑖=1 𝑃𝑛 𝑖=1 1 𝑛 𝑚 ≤ ∑∑𝑝 𝑤 𝑓 (𝑥𝑖 , 𝑦𝑗 ) . 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝑖 𝑗 𝑖∈𝐼 = 1 ∑ 𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦𝑗 ) 𝑃𝑛 𝑖∈𝐼∪𝐼 ⇒ 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 ) ≤ (12) Adding (11) and (12), we have 𝑛 1 ∑𝑝 𝑓 (𝑥𝑖 , 𝑦𝑗 ) . 𝑃𝑛 𝑖=1 𝑖 As the function 𝑓 is convex on the first co-ordinate, so we have 1[1 𝑛 1 𝑚 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) + ∑𝑤 𝑓 (𝑥, 𝑦𝑗 )] 2 𝑃𝑛 𝑖=1 𝑊𝑚 𝑗=1 𝑗 ] [ 1[1 𝑛 ∑𝑝 𝐷 (𝑓, w, y, 𝐽, 𝑥𝑖 ) 2 𝑃𝑛 𝑖=1 𝑖 [ ≤ 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 ) = (11) 𝑃 𝑃𝐼 1 1 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦𝑗 ) + 𝐼 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦𝑗 ) 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑃𝑛 𝑃𝐼 + 𝑖∈𝐼 1 ∑ 𝑤 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 )] 𝑊𝑚 𝑗=1 𝑗 ] 1 𝑛 𝑚 ∑ ∑𝑝 𝑤 𝑓 (𝑥𝑖 , 𝑦𝑗 ) . 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝑖 𝑗 ≤ 𝑃 1 𝑃 1 ≥ 𝑓 ( 𝐼 ∑𝑝𝑖 𝑥𝑖 + 𝐼 ∑𝑝𝑖 𝑥𝑖 , 𝑦𝑗 ) 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑃𝑛 𝑃𝐼 (13) 𝑚 𝑖∈𝐼 1 1 = 𝑓 ( ∑𝑝𝑖 𝑥𝑖 + ∑𝑝𝑖 𝑥𝑖 , 𝑦𝑗 ) 𝑃𝑛 𝑖∈𝐼 𝑃𝑛 𝑖∈𝐼 = 𝑓( Again by one-dimensional Jensen’s inequality, we have (8) 𝑓 (𝑥, 𝑦) ≤ 1 ∑ 𝑝𝑖 𝑥𝑖 , 𝑦𝑗 ) 𝑃𝑛 (14) 1 𝑚 𝑓 (𝑥, 𝑦) ≤ ∑𝑤 𝑓 (𝑥, 𝑦𝑗 ) . 𝑊𝑚 𝑗=1 𝑗 𝑖∈𝐼∪𝐼 = 𝑓( 1 𝑛 ∑𝑝 𝑓 (𝑥𝑖 , 𝑦) , 𝑃𝑛 𝑖=1 𝑖 1 𝑛 ∑𝑝 𝑥 , 𝑦 ) 𝑃𝑛 𝑖=1 𝑖 𝑖 𝑗 As we have the functional 𝐷 (𝑓, p, x, 𝐼) = 1 𝑛 ⇒ 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 ) ≥ 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦𝑗 ) . 𝑃𝑛 𝑖=1 𝑃 𝑃𝐼 1 1 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦) + 𝐼 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦) , 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 (15) Now, from (7) and (8), we have so by Jensen’s inequality, we get 𝑓 (𝑥, 𝑦𝑗 ) ≤ 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 ) ≤ 1 𝑛 ∑𝑝 𝑓 (𝑥𝑖 , 𝑦𝑗 ) . 𝑃𝑛 𝑖=1 𝑖 (9) 𝐷 (𝑓, p, x, 𝐼) = 𝑃𝐼 1 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦) 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 + Similarly, we can write 𝑃𝐼 1 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦) 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑓 (𝑥𝑖 , 𝑦) ≤ 𝐷 (𝑓, w, y, 𝐽, 𝑥𝑖 ) ≤ 𝑚 1 ∑ 𝑤 𝑓 (𝑥𝑖 , 𝑦𝑗 ) . 𝑊𝑚 𝑗=1 𝑗 (10) ≤ 𝑃 1 𝑃𝐼 1 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) + 𝐼 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 4 Abstract and Applied Analysis = 1 1 ∑𝑝 𝑓 (𝑥𝑖 , 𝑦) + ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) 𝑃𝑛 𝑖∈𝐼 𝑖 𝑃𝑛 Combining (13) and (20), we have 1 ∑ 𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) 𝑃𝑛 𝑓 (𝑥, 𝑦) 𝑖∈𝐼 = 𝑖∈𝐼∪𝐼 ≤ 1 [𝐷 (𝑓, w, y, 𝐽) + 𝐷 (𝑓, p, x, 𝐼)] 2 (16) ≤ 1 𝑚 1[1 𝑛 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) + ∑ 𝑤 𝑓 (𝑥, 𝑦𝑗 )] 2 𝑃𝑛 𝑖=1 𝑊𝑚 𝑗=1 𝑗 ] [ and as the function 𝑓 is convex on the first co-ordinate, so we have ≤ 1[1 𝑛 ∑𝑝 𝐷 (𝑓, w, y, 𝐽, 𝑥𝑖 ) 2 𝑃𝑛 𝑖=1 𝑖 [ ⇒ 𝐷 (𝑓, p, x, 𝐼) ≤ 𝐷 (𝑓, p, x, 𝐼) = 𝑛 1 ∑𝑝 𝑓 (𝑥𝑖 , 𝑦) , 𝑃𝑛 𝑖=1 𝑖 𝑃𝐼 1 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦) 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 + + 𝑃𝐼 1 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦) 𝑃𝑛 𝑃𝐼 ≤ 𝑖∈𝐼 ≥ 𝑓( 𝑃 1 𝑃𝐼 1 ∑𝑝𝑖 𝑥𝑖 + 𝐼 ∑𝑝𝑖 𝑥𝑖 , 𝑦) 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑃𝑛 𝑃𝐼 1 1 ∑𝑝 𝑥 + ∑𝑝𝑖 𝑥𝑖 , 𝑦) 𝑃𝑛 𝑖∈𝐼 𝑖 𝑖 𝑃𝑛 1 1 𝑛 ∑ 𝑝𝑖 𝑥𝑖 , 𝑦) = 𝑓 ( ∑𝑝𝑖 𝑥𝑖 , 𝑦) 𝑃𝑛 𝑃𝑛 𝑖=1 𝑖∈𝐼∪𝐼 ⇒ 𝐷 (𝑓, p, x, 𝐼) ≥ 𝑓 (𝑥, 𝑦) . (17) 1 𝑛 ∑𝑝 𝑓 (𝑥𝑖 , 𝑦) . 𝑃𝑛 𝑖=1 𝑖 1[1 𝑛 ∑𝑝 𝐷 (𝑓, w, y, 𝐽, 𝑥𝑖 ) 𝐼⊂{1,...,𝑛} 2 𝑃𝑛 𝑖=1 𝑖 𝐽⊂{1,...,𝑚} [ + (18) 1 𝑚 ∑ 𝑤 𝑓 (𝑥, 𝑦𝑗 ) . 𝑊𝑚 𝑗=1 𝑗 (19) 1 𝑛 ≤ min [ ∑𝑝𝑖 𝐷 (𝑓, w, y, 𝐽, 𝑥𝑖 ) 𝐼⊂{1,...,𝑛} 𝑃𝑛 𝑖=1 𝐽⊂{1,...,𝑚} [ Adding (18) and (19), we get 𝑓 (𝑥, 𝑦) ≤ ≤ 1 𝑚 ∑ 𝑤 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 )] , 𝑊𝑚 𝑗=1 𝑗 ] 1 𝑛 1 𝑚 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) + ∑ 𝑤 𝑓 (𝑥, 𝑦𝑗 ) 𝑃𝑛 𝑖=1 𝑊𝑚 𝑗=1 𝑗 Similarly, we can prove that 𝑓 (𝑥, 𝑦) ≤ 𝐷 (𝑓, w, y, 𝐽) ≤ 1 𝑛 𝑚 ∑∑ 𝑝 𝑤 𝑓 (𝑥𝑖 , 𝑦𝑗 ) 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝑖 𝑗 ≥ max Now from (16) and (17), we have 𝑓 (𝑥, 𝑦) ≤ 𝐷 (𝑓, p, x, 𝐼) ≤ 1 𝑛 𝑚 ∑∑ 𝑝 𝑤 𝑓 (𝑥𝑖 , 𝑦𝑗 ) . 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝑖 𝑗 Remark 3. We observe that the inequalities in (4) can be written equivalently as 𝑖∈𝐼 = 𝑓( 1 𝑚 ∑𝑤 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 )] 𝑊𝑚 𝑗=1 𝑗 ] The following cases from the above inequalities are of interest [6, 7]. 𝑖∈𝐼 = 𝑓( (21) 1 [𝐷 (𝑓, w, y, 𝐽) + 𝐷 (𝑓, p, x, 𝐼)] 2 1 𝑚 1[1 𝑛 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) + ∑ 𝑤 𝑓 (𝑥, 𝑦𝑗 )] . 2 𝑃𝑛 𝑖=1 𝑊𝑚 𝑗=1 𝑗 ] [ (20) + 1 𝑚 ∑𝑤 𝐷 (𝑓, p, x, 𝐼, 𝑦𝑗 )] , 𝑊𝑚 𝑗=1 𝑗 ] 1 𝑛 1 𝑚 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) + ∑ 𝑤 𝑓 (𝑥, 𝑦𝑗 ) 𝑃𝑛 𝑖=1 𝑊𝑚 𝑗=1 𝑗 ≥ max [𝐷 (𝑓, w, y, 𝐽) + 𝐷 (𝑓, p, x, 𝐼)] , 𝐼⊂{1,...,𝑛} 𝐽⊂{1,...,𝑚} Abstract and Applied Analysis 5 𝑓 (𝑥, 𝑦) min 𝐷𝑘 (𝑓, p, x, 𝑦𝑗 ) ≥ min 𝐷 (𝑓, p, x; 𝐼, 𝑦𝑗 ) , 𝐼⊂{1,...,𝑛} 𝑘∈{1,...,𝑛} 1 ≤ min [𝐷 (𝑓, w, y, 𝐽) + 𝐷 (𝑓, p, x, 𝐼)] . 𝐼⊂{1,...,𝑛} 2 min 𝐷𝑙 (𝑓, w, y, 𝑥𝑖 ) ≥ min 𝐷 (𝑓, w, y; 𝐽, 𝑥𝑖 ) . 𝐽⊂{1,...,𝑚} 𝑙∈{1,...,𝑚} 𝐽⊂{1,...,𝑚} (24) (22) These inequalities imply the following results: We discuss the following particular cases of the above inequalities which is of interest [6]. In the case when 𝑝𝑖 = 1 and 𝑤𝑗 = 1 for 𝑖 ∈ {1, . . . , 𝑛} and 𝑗 ∈ {1, . . . , 𝑚}, consider the natural numbers 𝑘, 𝑙 with 1 ≤ 𝑘 ≤ 𝑛 − 1 and 1 ≤ 𝑙 ≤ 𝑚 − 1 and define 𝑛 𝑚 1 ∑ ∑𝑝 𝑤 𝑓 (𝑥𝑖 , 𝑦𝑗 ) 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝑖 𝑗 1[1 𝑛 ∑𝑝 𝐷 (𝑓, w, y, 𝑥𝑖 ) 𝑘∈{1,...,𝑛} 2 𝑃𝑛 𝑖=1 𝑖 𝑙 𝑙∈{1,...,𝑚} [ ≥ max + 𝐷𝑘 (𝑓, x, 𝑦𝑗 ) 𝑚 1 ∑𝑤 𝐷 (𝑓, p, x, 𝑦𝑗 )] , 𝑊𝑚 𝑗=1 𝑗 𝑘 ] 1 𝑛 1 𝑚 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) + ∑𝑤 𝑓 (𝑥, 𝑦𝑗 ) 𝑃𝑛 𝑖=1 𝑊𝑚 𝑗=1 𝑗 𝐷𝑙 (𝑓, y, 𝑥𝑖 ) = 1 𝑛 ≤ min [ ∑𝑝𝑖 𝐷𝑙 (𝑓, w, y, 𝑥𝑖 ) 𝑘∈{1,...,𝑛} 𝑃𝑛 𝑖=1 𝑙∈{1,...,𝑚} [ + 𝐷𝑙 (𝑓, y) = 1 𝑛 1 𝑚 ∑𝑝𝑖 𝑓 (𝑥𝑖 , 𝑦) + ∑𝑤 𝑓 (𝑥, 𝑦𝑗 ) 𝑃𝑛 𝑖=1 𝑊𝑚 𝑗=1 𝑗 𝑘∈{1,...,𝑛} 𝑙∈{1,...,𝑚} 1 𝑛 𝑘 𝑛−𝑘 1 𝑘 1 𝑓 ( ∑𝑥𝑖 , 𝑦) + 𝑓( ∑ 𝑥𝑖 , 𝑦) , 𝑛 𝑘 𝑖=1 𝑛 𝑛 − 𝑘 𝑖=𝑘+1 𝑙 1 𝑙 𝑚−𝑙 1 𝑚 𝑓 (𝑥, ∑𝑦𝑗 ) + 𝑓 (𝑥, ∑ 𝑦 ). 𝑚 𝑙 𝑗=1 𝑚 𝑚 − 𝑙 𝑗=𝑙+1 𝑗 (25) ≥ max [𝐷𝑙 (𝑓, w, y) + 𝐷𝑘 (𝑓, p, x)] , 𝑘∈{1,...,𝑛} 2 𝑙∈{1,...,𝑚} 𝑙 1 𝑙 𝑚−𝑙 1 𝑚 𝑓 (𝑥𝑖 , ∑𝑦𝑗 ) + 𝑓 (𝑥𝑖 , ∑ 𝑦 ), 𝑚 𝑙 𝑗=1 𝑚 𝑚 − 𝑙 𝑗=𝑙+1 𝑗 𝐷𝑘 (𝑓, x) = 1 𝑚 ∑ 𝑤 𝐷 (𝑓, p, x, 𝑦𝑗 )] , 𝑊𝑚 𝑗=1 𝑗 𝑘 ] 𝑓 (𝑥, 𝑦) ≤ min 𝑛 𝑘 𝑛−𝑘 1 𝑘 1 𝑓 ( ∑𝑥𝑖 , 𝑦𝑗 ) + 𝑓( ∑ 𝑥𝑖 , 𝑦𝑗 ) , 𝑛 𝑘 𝑖=1 𝑛 𝑛 − 𝑘 𝑖=𝑘+1 = We can give the following result. Corollary 4. Let 𝑓 : [𝑎, 𝑏] × [𝑐, 𝑑] → R be a co-ordinate convex function on [𝑎, 𝑏]×[𝑐, 𝑑]. If 𝑥𝑖 ∈ [𝑎, 𝑏] and 𝑦𝑗 ∈ [𝑐, 𝑑], then for any 𝑘 ∈ {1, . . . , 𝑛 − 1} and 𝑙 ∈ {1, . . . , 𝑚 − 1}, one has [𝐷𝑙 (𝑓, w, y) + 𝐷𝑘 (𝑓, p, x)] . (23) Moreover, from the above, we also have max 𝐷 (𝑓, p, x; 𝐼) ≥ max 𝐷𝑘 (𝑓, p, x) , 𝐼⊂{1,...,𝑛} 𝑘∈{1,...,𝑛} 1 𝑚 1 𝑛 𝑓 ( ∑𝑥𝑖 , ∑𝑦𝑗 ) 𝑛 𝑖=1 𝑚 𝑗=1 max 𝐷 (𝑓, w, y; 𝐽) ≥ max 𝐷𝑙 (𝑓, w, y) , ≤ 1 [𝐷 (𝑓, y) + 𝐷𝑘 (𝑓, x)] 2 𝑙 max 𝐷 (𝑓, p, x; 𝐼, 𝑦𝑗 ) ≥ max 𝐷𝑘 (𝑓, p, x, y𝑗 ) , ≤ 1 𝑚 1 [1 𝑛 ∑𝑓 (𝑥𝑖 , 𝑦) + ∑𝑓 (𝑥, 𝑦𝑗 )] 2 𝑛 𝑖=1 𝑚 𝑗=1 ] [ ≤ 1 [1 𝑛 1 𝑚 ∑𝐷𝑙 (𝑓, y, 𝑥𝑖 ) + ∑𝐷𝑘 (𝑓, x, 𝑦𝑗 )] 2 𝑛 𝑖=1 𝑚 𝑗=1 ] [ ≤ 1 𝑛 𝑚 ∑∑ 𝑓 (𝑥𝑖 , 𝑦𝑗 ) . 𝑚𝑛 𝑖=1𝑗=1 𝐽⊂{1,...,𝑚} 𝐼⊂{1,...,𝑛} 𝑙∈{1,...,𝑚} 𝑘∈{1,...,𝑛} max 𝐷 (𝑓, w, y; 𝐽, 𝑥𝑖 ) ≥ max 𝐷𝑙 (𝑓, w, y, 𝑥𝑖 ) , 𝐽⊂{1,...,𝑚} 𝑙∈{1,...,𝑚} min 𝐷𝑘 (𝑓, p, x) ≥ min 𝐷 (𝑓, p, x; 𝐼) , 𝑘∈{1,...,𝑛} 𝐼⊂{1,...,𝑛} min 𝐷𝑙 (𝑓, w, y) ≥ min 𝐷 (𝑓, w, y; 𝐽) , 𝑙∈{1,...,𝑚} 𝐽⊂{1,...,𝑚} (26) 6 Abstract and Applied Analysis −𝑞/𝑝 Proof. Using the functions 𝑓(𝑥) = 𝑥𝑝 , 𝑝 > 1, 𝑥𝑖 → 𝑥𝑖 𝑦𝑖 𝑞 and 𝑝𝑖 → 𝑦𝑖 in (28), we get (29). In particular, we have the bounds 𝑛 𝑚 1 ∑∑ 𝑓 (𝑥𝑖 , 𝑦𝑗 ) 𝑚𝑛 𝑖=1𝑗=1 ≥ max Remark 7. As mentioned above from the inequalities in (29), we can write 𝑛 1 [1 ∑𝐷𝑙 (𝑓, y, 𝑥𝑖 ) 𝑛 [ 𝑖=1 𝑘∈{1,...,𝑛} 2 𝑙∈{1,...,𝑚} + 𝑛 𝑝 (∑𝑥𝑖 ) 𝑖=1 1 𝑚 ∑ 𝐷 (𝑓, x, 𝑦𝑗 )] , 𝑚 𝑗=1 𝑘 ] 𝑛 1/𝑝 1/𝑞 𝑞 (∑𝑦𝑖 ) 𝑖=1 𝑛 𝑛 𝑞 ≥ max [(∑𝑦𝑖 ) 𝐼⊂{1,...,𝑛} [ 𝑖=1 𝑚 1 1 ∑𝑓 (𝑥𝑖 , 𝑦) + ∑𝑓 (𝑥, 𝑦𝑗 ) 𝑛 𝑖=1 𝑚 𝑗=1 𝑝/𝑞 −𝑝/𝑞 { 𝑞 {(∑𝑦𝑖 ) { 𝑖∈𝐼 + (27) 𝑛 1 ≤ min [ ∑𝐷𝑙 (𝑓, y, 𝑥𝑖 ) 𝑘∈{1,...,𝑛} 𝑛 𝑙∈{1,...,𝑚} [ 𝑖=1 (∑𝑥𝑖 𝑦𝑖 ) 𝑖∈𝐼 1/𝑝 −𝑝/𝑞 𝑝 } 𝑞 (∑𝑦𝑖 ) (∑𝑥𝑖 𝑦𝑖) }] , 𝑖∈𝐼 𝑖∈𝐼 }] 𝑛 𝑖=1 𝑛 𝑞 ≤ min [(∑𝑦𝑖 ) 𝐼⊂{1,...,𝑛} [ 𝑖=1 𝑝/𝑞 { 𝑞 {(∑𝑦𝑖 ) { 𝑖∈𝐼 −𝑝/𝑞 ≥ max [𝐷𝑙 (𝑓, y) + 𝐷𝑘 (𝑓, x)] , (∑𝑥𝑖 𝑦𝑖 ) 𝑖∈𝐼 𝑞 +(∑𝑦𝑖 ) 𝑖∈𝐼 1 [𝐷𝑙 (𝑓, y) + 𝐷𝑘 (𝑓, x)] . 𝑘∈{1,...,𝑛} 2 𝑓 (𝑥, 𝑦) ≤ min 𝑙∈{1,...,𝑚} Remark 5. Note that if we substitute 𝑚 = 1, 𝑓(𝑥, 𝑦1 ) → 𝑓(𝑥), 𝐷(𝑓, w, y, 𝐽, 𝑥𝑖 ) = 𝑓(𝑥), 𝐷(𝑓, p, x, 𝐼, 𝑦𝑗 ) = 𝐷(𝑓, p, x, 𝐼), and 𝐷(𝑓, w, y, 𝐽) = 𝑓(𝑥) in Theorem 2, we get the following result of Dragomir [9] for convex function defined on the interval and ∑𝑛𝑖=1 𝑝𝑖 = 𝑃𝑛 > 0, 𝑃 𝑃 1 1 1 𝑛 ∑𝑝 𝑥 ) ≤ 𝐼 𝑓 ( ∑𝑝𝑖 𝑥𝑖 ) + 𝐼 𝑓 ( ∑𝑝𝑖 𝑥𝑖 ) 𝑃𝑛 𝑖=1 𝑖 𝑖 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑃𝑛 𝑃𝐼 𝑖∈𝐼 𝑛 1 ≤ ∑𝑝𝑖 𝑓 (𝑥𝑖 ) . 𝑃𝑛 𝑖=1 (28) The following refinement of Hölder inequality holds. Corollary 6. Let x = (𝑥1 , 𝑥2 , . . . , 𝑥𝑛 ) and y = (𝑦1 , 𝑦2 , . . . , 𝑦𝑛 ) be two positive n-tuples. Then for (1/𝑝) + (1/𝑞) = 1, 𝑝, 𝑞 > 1, one has 𝑛 𝑝/𝑞 𝑛 𝑞 ≤ [ ( ∑𝑦 ) [ ≤ 𝑖=1 𝑖 −𝑝/𝑞 { 𝑞 {(∑𝑦𝑖 ) { 𝑖∈𝐼 1/𝑝 } (∑𝑥𝑖 𝑦𝑖) }] . 𝑖∈𝐼 }] (30) Theorem 8. Let 𝑓 : [𝑎, 𝑏] × [𝑐, 𝑑] → R be convex on the coordinates of [𝑎, 𝑏] × [𝑐, 𝑑] ⊆ R2 . If x is an n-tuple in [𝑎, 𝑏], y is an m-tuple in [𝑐, 𝑑], p is a nonnegative n-tuple such that 𝑃𝑛 = ∑𝑛𝑖=1 𝑝𝑖 > 0, and w is a nonnegative m-tuple such that 𝑊𝑚 = ∑𝑚 𝑗=1 𝑤𝑗 > 0, then 1 𝑛 𝑚 ∑ ∑𝑝 𝑤 𝑓 (𝑥𝑖 , 𝑦𝑗 ) − 𝑓 (𝑥, 𝑦) 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝑖 𝑗 1 𝑛 𝑚 ≥ ∑ ∑𝑝𝑖 𝑤𝑗 𝑓 (𝑥𝑖 , 𝑦𝑗 ) − 𝑓 (𝑥, 𝑦) 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝜕𝑓 (𝑥, 𝑦) 1 𝑛 𝑚 − (𝑥𝑖 − 𝑥) ∑ ∑𝑝𝑖 𝑤𝑗 + 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝜕𝑤 (31) 𝜕𝑓+ (𝑥, 𝑦) + (𝑦𝑗 − 𝑦) , 𝜕𝑧 𝑝 (∑𝑥𝑖 𝑦𝑖 ) 𝑖∈𝐼 1/𝑝 −𝑝/𝑞 𝑝 } 𝑞 ] + (∑𝑦𝑖 ) (∑𝑥𝑖 𝑦𝑖 ) } 𝑖∈𝐼 𝑖∈𝐼 }] 1/𝑝 1/𝑞 𝑛 𝑛 𝑝 𝑞 (∑𝑥𝑖 ) (∑𝑦𝑖 ) . 𝑖=1 𝑖=1 𝑝 The following improvement of Jensen’s inequality is valid. ∑𝑥𝑖 𝑦𝑖 𝑖=1 𝑝 −𝑝/𝑞 𝑘∈{1,...,𝑛} 𝑙∈{1,...,𝑚} 𝑓( 𝑝 ∑𝑥𝑖 𝑦𝑖 𝑚 1 ∑𝐷 (𝑓, x, 𝑦𝑗 )] , 𝑚 𝑗=1 𝑘 ] 1 𝑛 1 𝑚 ∑𝑓 (𝑥𝑖 , 𝑦) + ∑𝑓 (𝑥, 𝑦𝑗 ) 𝑛 𝑖=1 𝑚 𝑗=1 + , (29) where 𝑥 = (1/𝑃𝑛 ) ∑𝑛𝑖=1 𝑝𝑖 𝑥𝑖 , and 𝑦 = (1/𝑊𝑚 ) ∑𝑚 𝑗=1 𝑤𝑗 𝑦𝑗 . Proof. Since 𝑓 is convex on [𝑎, 𝑏] × [𝑐, 𝑑], therefore we have 𝑓 (𝑥, 𝑦) − 𝑓 (𝑤, 𝑧) ≥ 𝜕𝑓+ (𝑤, 𝑧) 𝜕𝑓 (𝑤, 𝑧) (𝑦 − 𝑧) . (𝑥 − 𝑤) + + 𝜕𝑤 𝜕𝑧 (32) Abstract and Applied Analysis 7 One has From the above inequality, we have 𝑛 𝑚 𝑓 (𝑥, 𝑦) − 𝑓 (𝑤, 𝑧) − 𝜕𝑓+ (𝑤, 𝑧) 𝜕𝑓 (𝑤, 𝑧) (𝑦 − 𝑧) (𝑥 − 𝑤) − + 𝜕𝑤 𝜕𝑧 𝜕𝑓 (𝑤, 𝑧) = 𝑓 (𝑥, 𝑦) − 𝑓 (𝑤, 𝑧) − + (𝑥 − 𝑤) 𝜕𝑤 𝜕𝑓 (𝑤, 𝑧) − + (𝑦 − 𝑧) 𝜕𝑧 ≥ 𝑓 (𝑥, 𝑦) − 𝑓 (𝑤, 𝑧) 𝜕𝑓 (𝑤, 𝑧) 𝜕𝑓 (𝑤, 𝑧) − + (𝑦 − 𝑧) . (𝑥 − 𝑤) + + 𝜕𝑤 𝜕𝑧 𝑖=1 𝑗=1 𝜕𝑓+ (𝑥, 𝑦) (𝑥𝑖 − 𝑥) 𝜕𝑤 𝑚 = ∑ 𝑤𝑗 𝑗=1 𝜕𝑓+ (𝑥, 𝑦) 𝑛 1 𝑛 (∑𝑝𝑖 𝑥𝑖 − 𝑃𝑛 ⋅ ∑𝑝𝑖 𝑥𝑖 ) = 0, (36) 𝜕𝑤 𝑃𝑛 𝑖=1 𝑖=1 𝑛 𝑚 ∑∑ 𝑝𝑖 𝑤𝑗 𝑖=1 𝑗=1 𝜕𝑓+ (𝑥, 𝑦) (𝑦𝑗 − 𝑦) = 0. 𝜕𝑧 Therefore (35) becomes 𝑛 𝑚 𝑛 𝑚 𝑖=1 𝑗=1 𝑖=1 𝑗=1 ∑ ∑𝑝𝑖 𝑤𝑗 𝑓 (𝑥𝑖 , 𝑦𝑗 ) − ∑∑ 𝑝𝑖 𝑤𝑗 𝑓 (𝑥, 𝑦) (33) Let 𝑥 → 𝑥𝑖 , 𝑦 → 𝑦𝑗 , 𝑤 → ∑𝑛𝑖=1 𝑝𝑖 𝑥𝑖 /𝑃𝑛 := 𝑥, and 𝑧 → ∑𝑛𝑗=1 𝑤𝑗 𝑦𝑗 /𝑊𝑚 := 𝑦, then (33) becomes 𝑛 𝑚 ≥ ∑ ∑𝑝𝑖 𝑤𝑗 𝑓 (𝑥𝑖 , 𝑦𝑗 ) − 𝑓 (𝑥, 𝑦) 𝑖=1𝑗=1 𝑛 𝑚 𝜕𝑓 (𝑥, 𝑦) − ∑∑ 𝑝𝑖 𝑤𝑗 + (𝑥𝑖 − 𝑥) 𝜕𝑤 𝑖=1 𝑗=1 + 𝜕𝑓 (𝑥, 𝑦) 𝜕𝑓+ (𝑥, 𝑦) (𝑥𝑖 − 𝑥) − + (𝑦𝑗 − 𝑦) 𝜕𝑤 𝜕𝑧 (34) ≥ 𝑓 (𝑥𝑖 , 𝑦𝑗 ) − 𝑓 (𝑥, 𝑦) 𝜕𝑓 (𝑥, 𝑦) 𝜕𝑓 (𝑥, 𝑦) − + (𝑥𝑖 − 𝑥) + + (𝑦𝑗 − 𝑦) . 𝜕𝑧 𝜕𝑤 Multiplying (34) by 𝑝𝑖 and 𝑤𝑗 and summing over 𝑖 and 𝑗, we have 1 𝑛 𝑚 ∑∑ 𝑝 𝑤 𝑓 (𝑥𝑖 , 𝑦𝑗 ) − 𝑓 (𝑥, 𝑦) 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝑖 𝑗 1 𝑛 𝑚 ≥ ∑∑ 𝑝𝑖 𝑤𝑗 𝑓 (𝑥𝑖 , 𝑦𝑗 ) − 𝑓 (𝑥, 𝑦) 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝜕𝑓 (𝑥, 𝑦) 1 𝑛 𝑚 − (𝑥𝑖 − 𝑥) ∑ ∑𝑝𝑖 𝑤𝑗 + 𝑃𝑛 𝑊𝑚 𝑖=1𝑗=1 𝜕𝑤 + 𝑛 𝑚 𝑛 𝑚 𝑖=1 𝑗=1 𝑖=1 𝑗=1 This completes the proof. 𝜕𝑓+ (𝑥, 𝑦) (𝑥𝑖 − 𝑥) 𝜕𝑤 Conflict of Interests ∑∑ 𝑝𝑖 𝑤𝑗 𝑓 (𝑥𝑖 , 𝑦𝑗 ) − ∑ ∑𝑝𝑖 𝑤𝑗 𝑓 (𝑥, 𝑦) 𝑛 𝑚 − ∑ ∑𝑝𝑖 𝑤𝑗 𝑖=1 𝑗=1 (37) 𝜕𝑓+ (𝑥, 𝑦) (𝑦𝑗 − 𝑦) . 𝜕𝑧 Multiplying both hand sides by 1/𝑃𝑛 𝑊𝑚 , we have 𝑓 (𝑥𝑖 , 𝑦𝑗 ) − 𝑓 (𝑥, 𝑦) − ∑∑ 𝑝𝑖 𝑤𝑗 𝜕𝑓 (𝑥, 𝑦) − ∑ ∑𝑝𝑖 𝑤𝑗 + (𝑦𝑗 − 𝑦) 𝜕𝑧 𝑖=1 𝑗=1 𝜕𝑓 (𝑥, 𝑦) + + (𝑦𝑗 − 𝑦) . 𝜕𝑧 𝜕𝑓+ (𝑥, 𝑦) (𝑦𝑗 − 𝑦) . 𝜕𝑧 The authors declare that they have no conflict of interests regarding publication of this paper. 𝑛 𝑚 𝑛 𝑚 ≥ ∑∑ 𝑝𝑖 𝑤𝑗 𝑓 (𝑥𝑖 , 𝑦𝑗 ) − 𝑓 (𝑥, 𝑦) 𝑖=1𝑗=1 𝜕𝑓 (𝑥, 𝑦) 𝑛 𝑚 −∑ ∑𝑝𝑖 𝑤𝑗 + (𝑥𝑖 − 𝑥) 𝜕𝑤 𝑖=1 𝑗=1 (38) (35) Acknowledgments The authors are grateful to the referees for the useful comments regarding presentation in the early version of the paper. 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