Introduction to Charm S.Olsen Hawaii & 高能物理研究所 BESIII物理分析讲习班 2008年6月23日-7月4日 中关村教学园区教学楼大厅 S. Olsen’s A brief history of the charmed quark Hadrons in 1963 “stable” hadrons Two “classes” of hadrons “non-strange:” n, p, p, r, … “strange:” L, S, K, K*, … meson resonances baryon resonances “Three quarks for Muster Mark” 3 quarks 夸克 Gell-Mann u+2/3 Zweig d-1/3 u-2/3 s-1/3 non-strange: no s quarks p: p-: u+2/3 u+2/3 d-1/3 u-2/3 d-1/3 (& 3 antiquarks) 反夸克 d+1/3 s+1/3 strange: contains s quark(s) L: K-: u+2/3 s-1/3 d-1/3 S-1/3 u-2//3 Weak decay’s in the 3-quark era 3 quarks: u q=-1/3 d q=+2/3 |DS|=0 4 leptons: Flavorchanging decays |DS|=1 s e ~ e - - (1964—1974) Flavorpreserving decays Problems Problem 1: Different weak decay “charges” for leptons & hadrons: du Gd 0.98GF d n Gd G Fermi Constant - GF F u Flavor preserving decay p K- GF su Gs 0.21GF s Gs GF u Flavor changing decay p0 flavor mixing Cabibbo’s sol’n: N.Cabibbo Weak Int flavor state Flavor mass eigenstates d = a d + b s GF d’ u = W- a=cosqc=0.98 aGF d Unitarity: |a|2 + |b|2 = 1 b=sinqc=0.21 u + W- bGF s u W- a=cosqc; b = sinqc qc=“Cabibbo angle” ≈ 12o Missing neutral currents Problem 2: no flavor-changing “neutral currents” seen. Discovered at CERN s GN d,u d,u K- flavor-preserving neutral currents (e.g. NX) are allowed d p- flavor-changing neutral currents (e.g. Kp l+l-) are strongly suppressed GIM sol’n: Introduce 4th quark 2 quark doublets: charmed quark u c d ' s' u c d s Weak eigenstates GIM: Mass eigenstates Glashow Iliopoulis Maiani d’ & s’ are mixed d & s 4-quark flavor-mixing matrix Weak eigenstates d ' a b d Mass s' s eigenstates Mixing matrix must be Unitary UU† = 1 a U GF a b a 1 0 * * b 0 1 * * b a b cos qC - b a - sin qC |a|2 + |b|2 = 1 & a*b - ab* =0 sin qC cos qC Charged currents (u-quark) 3 |DS|=1 u -1 ad 3 + b s -13 2 d aGF u s W- du: GF modified by a Cabibbo favored (cosqc) bGF u W- (sinqc) su: GF modified by b Cabibbo suppressed N.Cabibbo N.Cabibbo Charged currents (c-quark) 3 |DC|=1 c |DS|=1 - b d -13 + as -13 2 |DC|=1 |DS|=0 -b GF d c W- dc: GF modified by b (sinqc) suppressed N.Cabibbo s aGF c W(cosqc) sc: GF modified by a Favored Flavor preserving Neutral Current |a|2+|b| 2 d,(S) GN d,(s) d a d - b s s a s + b d Z0 d d a d - b s a d - b s * a 2 * d d - a * b d s - b a s d + b * a +b 2 allowed 2 =1 2 s s From Unitarity Flavor changing Neutral Current a*b-ba* GN s(d) Z0 a 2 d a d - b s d(s) s a s + b d s d a * s - b * d a d + b s s d + a * b s s - b a d d + b * a b -b a * * =0 From FCNC forbidden by Unitarity 2 d s Unitarity “GIMmechanism” GIM Mechanism GIM: Glashow Iliopoulis Maiani FCNC forbidden by Unitarity if quarks come in pairs Discovery of the 4th quark (charm) p+Bee+e- + X @ BNL e+e- @ SLAC J/y s(e+e- hadrons) cc bound state Ting (丁) Richter s(e+e- e+e-) 1976 Nobelists PRL 33, 1404 (1974) s(e+e- +-, p+p- & K+K-) M(e+e-) PRL 33, 1406 (1974) Ecm(e+e-) Glashow won the 1979 Physics Nobel prize for predicting the c-quark No prize for Iliopoulis & Maiani Status in 2008 6 quarks (3 doublets) u c t d s b +2/3 e -1/3 e cos qC - sin qC 3x3 flavor-mixing (CKM) matrix d ' VudVusVub d s ' VcdVcsVcb s b' V V V b td ts tb sin qC cos qC Mesons formed from c quarks “charmonium” mesons are cc pairs Charmonium mesons y(4415) y(4150) y(4040) c’c2 y” h’c y’ hc cc0 cc1 cc2 J/y hc Discovered by Ting & Richter The 1-- states are produced directly n e+e- annihilations “Open-charm” mesons contain one c quark +2/3 D+: c d+1/3 +2/3 D0: c u-2/3 +2/3 D+s: c s+1/3 “Ds meson” “D meson” D0 meson discovered at SLAC 1975 c+2/3 u-2/3 G. Goldhaber D0K-p+ Phys Rev Letts 37, 255 (1976) (& D0K+p-) K- p+ 1865 MeV D+ discovered in 1976 c+2/3 d+1/3 “Invariant mass:” 2 M inv ( EK + Ep ) - ( pK + pp ) 2 Ds meson discovered at Cornell c+2/3 s+1/3 Y. Kubota Ds+fp+ (& Ds-fp-) 1970 MeV fp invariant mass Phys Rev Letts 51, 634 (1983) How do D mesons decay? Dominant hadronic decay modes “Cabibbo-allowed” hadronic decays u * ud V c q Vcs d W s q K, K*, etc (=u or d) some D+ Bf’s & D0 Bf’s K0p+ 2.9% K-p+ 3.8% K0r+ 9.6% K-r+ 11% K*0p+ 2.0% K*-p+ 3.4% K*0r+ 1.8% K*-r+ 6.5% Vcs cos q c Vud cos q c “singly” Cabibbo-suppressed hadronic modes Vus -Vcd sin qc 0.21 u * us V Vcs c q W s s q K, K*, etc or (=u or d) V c q Vcd & D0 Bf’s K0K+ 0.6% K-K+ 0.4% K0K*+ 1.2% K-K*+ 0.4% p+p0 0.1% p+p- 0.1% r0p+ 0.1% r+p- ~1% Vus d W (=u or d) some D+ Bf’s u * ud 2 Expected suppression factor ~ V ≈ tan2qC = 0.05 ud d q p, r, etc “doubly” Cabibbo suppressed nodes Vus -Vcd sin qc 0.21 Vcd c q u * us V W s d q p, r, etc (=u or d) some Bf’s D0K+p- 0.014% D0K*+p- 0.01% D+K+p0 <0.04% D+K+p+p- 0.06% “Expected” suppression factor ~ Vus Vud 4 ≈ tan4qC = 0.003 color suppressed nodes Internal W bosons c Vcs c s d W Vud* u u u K0,K*0, etc p0, r0, s d W Vud* u etc c quark colors must match W Vud* The nominal suppression factor is (1/3)2; observed suppression are typically less some Bf’s u u u s d u u color mismatches are not allowed For comparison D0K0p0 2.2% D0K-p+ 3.8% D0K*0p0 1.2% D0K*-p+ 3.4% D0K0r0 1.5% D0K-r+ 11% D0K*0r0 1.5% D0K*-r+ 2.1% The trouble with these simple arguments u d u d c Vcs W q s q We draw diagrams that look like this c W s q q But nature does this Semileptonic decays are “cleaner” Vcs W c s c Vcd W d K, K*, etc q q (=u or d) Vcs p, r, etc q q (=u or d) “Cabibbo-allowed” semileptonic decays “Cabibbo-suppressed” semileptonic decays some Bf’s some Bf’s D0K-e+ 3.5% D0p-e+ 0.3% D0K*-e+ 2.2% D0r-e+ 0.2% D+K0e+ 8.6% D+p0e+ 0.4% D+K*0e+ 5.6% D+r0e+ 0.2% Vcs Vus 2 suppression factor ~ V ≈ tan2qC = 0.05 ud Cleanest modes: purely leptonic D+e+ <0.002% D++ 0.04% D+t+ <0.21% (s) (Vcs) (s) Ds+e+ <0.013% Ds++ 0.64% Ds+t+ 8.0% (s) SM theory calculates this unambiguously to be: Use |Vcd| from elsewhere: measure fD+ Helicity suppression factor detecting D mesons at BES-III y(3770) Run at the y(3770) If a D meson is produced here it must recoil from a D meson & nothing else (not enough energy to make any other particles) 2mD mD+mD* BES-II PLB 660, 315 (2007) Kinematic variables for y(3770)DD Tagged-D ED Ep + EK ECM 2 K e+ recoil-D invariant mass: Beam-constrained mass: D0 D0 e+y(3770)eE=Ecm/2 p e- E=Ecm/2 in CM: 2 minv ( Ep + EK ) - ( pp + pK ) 2 mbc ( ECM 2 2) - ( pp + pK ) 2 Mbc s=6~12 MeV mode-dependent DE 3.57 3.61 3.65 s =1.2~2 Energy difference: DE Ep + EK - ECM 2 Beam-constrained mass: 2 2 mbc ( ECM 2) - ( pp + pK ) 3.69 MeV 3.73 3.77 D meson “beam” E=½Ecm D0 recoil-D Tagged-D D0 p+ K- E=½Ecm Kp+ •its energy E •its 3-momentum: p •flavor (D or D) For the recoil-D we know: •which tracks come from it (no *combinatoric” background) CLEO-c D- Tagging modes Measurements with tagged D mesons • Absolute branching fractions • Semileptonic decays – |Vcs| and |Vcd| CKM matrix elements • Purely leptonic decays – fD and fDs decay constants • D-D oscillations – Exploiting quantum correlations @ the y(3770) • CP violation • … Absolute branching fractions Nj = number of single tags Dfj N DD Br ( D f j )eff f j Njk = number of double tags Dfj and Dfk N DD Br ( D f j )eff f j Br ( D f k )eff fk Absolute branching fractions N jk Nj N DD Br ( D f j )eff f j Br ( D f k )eff fk N DD Br ( D f j )eff f j N jk 1 Br ( D f k ) N j eff fk No dependence on NDD or efffj CLEO-c with 281 pb-1 Factors of 2~4 improvement BES-III should do even better Semileptonic decays (neutrino reconstruction) c ℓ+ Vcs K, K*, etc s c Vcd ℓ+ d p, r, etc K, K*, etc q Vcd q q q (=u or d) Vcs measurements of Vcs and Vcd Goal: precise Why are these important? Wolfenstein parameterization of the CKM matrix - 12qC2 VudVusVub 1cos sin qC 2 1 V V V 1 cd cs cb - sin qC cos qC2 V V V A3 (1 - r - ih ) - A2 td ts tb A3 ( r - ih ) 2 A + (4 ) ≈sinq ≈ 1 C 0.21 4 = 0.002 So, to good precision, SM predicts: World avg Errors: Vcs = Vud Vcd = -Vus ~10% ~5% 0.02% ~1% Checking these relations by improving the Vcs and Vcd precision will provide an important test of the Standard Model. (Needs a combined theory & experimental effort.) Neutrino reconstruction K- K+ pe+ D0 By tagging the meson, we can know p & E for the recoil D0: Ke+ D0 D0 K+ p- p = pD – pK – pp E = ½Ecm – EK – Ep E–| p|= “Umiss” = 0 Umiss in CLEO-c Cabibbo-favored Cabibbo-suppressed D0K-e+ Signal is well separated from background, even in the Cabibbo-suppressed modes |Vcs| and |Vcd| from CLEO-c Expected experimena’l precision from BES-III Purely leptonic D+ & Ds+ decays SM value for fD+ can be calculated by lattice QCD (s) (Vcs) H +? (s) This could be modified by the presence of other heavy particles. (A charged Higgs Would make the value lower than the SM prediction.) New CLEO Measurements arXiv:0806.2112v2 ≈4 % precision 205.8±8.9 MeV Theory seems to get it right 206±4 MeV Does fDs differ from SM predictions? Vcs Ds s Kronfeld & Dobrescu arXiv: 0803.0512 H+as well? a hot (the hottest?) topic for BES-III Talk by at A. Kronfeld Measuring D+ + decays Use charged D+ tagged sample + D+ Single track on the recoil side -identify it as a muon- CLEO-c D- K+ p- L p- p = pD – p E = ½Ecm – E 2 2 E–| p| = MM2= 0 CLEOc doesn’t have a muon detector Systematic errors BES-III statistical error will be ~2% Source of Error (for CLEO-c) Finding the + track Minimum ionization of + in EM cal Particle identification of + MM2 width Extra showers in event > 250 MeV Background Number of single tag D+ Monte Carlo statistics Total % 0.7 1.0 1.0 1.0 0.5 0.6 0.6 0.4 2.1 BES-III precision on fD+ + + ( D ) + + Br ( D ) t D + ( D + + ) tot f D+ 8pBr ( D + + ) t D GF Vcd m M D (1 - M ) + + m2 2 D+ ≈ 2.0% 0.6% 1.5% 1.1% Measuring Br(D+t+) Now there are 2 or 3 ’s on the recoil side. The measurement Is dirtier, but the Bf is larger p+ t+ D+ + D- K+ p- Single track on the recoil side -identify it as a as a pion or muon- p- D+p+KL pmiss = pD – pp Emiss = ½Ecm – Ep 2 2 Emiss–| pmiss| 0< MM2 2 <mK 0 p+ Ds leptonic decays Big question: what energy to run at? Ds production cross section (nanobarns) CLEO-c Here s(e+e-Ds+Ds-)≈0.9nb. A modified tagging technique is needed Here s(e+e-Ds+Ds-)≈0.3nb. The standard tagging techique applies Ds leptonic decays @ 4170 MeV e+e-DsDs* Ds + Ds- The can come from either Ds Ds*p- f Since the Ds and Ds have different energies, the n-reconstruction method we use @ the y(3770) do not work. CLEO-c used two techniques: one required detecting the , the other didn’t Technique -1 (detect the ) First select a tagged-Ds sample: Invariant mass: M inv ( Ei ) 2 - ( p i ) 2 Then compute the + tag-Ds missing mass2: MM 2Ds E + EDs - p 2 + pDs 2 11880±399±504 tags E and p for the recoil Ds is determined For events with 1 + (or p+) on the recoil side, 2 2 2 compute: MM Ecm - ED - E - E - - pD - p - p s s D++ (MC) + Data Ds+ signal D+p+KL D+t+ (MC) p+ Data Dst+ signals? D+p+KL e+ Data MM2 (GeV) Technique-1 systematic errors on Br(Ds+) Mostly from uncertainties in fitting this peak ?? 11880±399±504 tags BES-III will have to figure out how to improve this Technique-2 (for Dst+): Ignore the but require a single e+ on the recoil side Tag-Ds signals with a single recoil electron (or positron) Look at the “extra” EMC energy recoil-Dst+ e+ K e+ p K+ tag-Ds tracks After the EMC signals associated with the e+ and the tag-D trks are removed, only ’s remain. DsKLe+ bkgd looks just like the signal & must be well understood. For CLEOc this is the dominate syst error (~5%) Expected precision (Dsℓ+) CLEOc’s weighted average (281 pb-1): fDs=274±10±5 MeV ~4% ~2% •BES-III can easily improve the statistical error to 1% •>10x more data •good Muon detection •Need to improve systematic error by at least factor of 2 •restrict analyses to cleaner tag modes? particle-antiparticle oscillations First seen in the K0 system Short distance contribution: ≈ 1/MW ≈ 10-3fm K0 K0 long distance contribution: ≈ 1/Mp ≈ 1fm p+ K0 p- K0 This part is most interesting since non-SM heavy particles could occur in the loop Neutral D meson phenomenology SM: CPV is very small: q ≈ p ≈1/2 What happens when two identical systems are coupled? D0D0 D0 D0 Energy transfers …. back-and-forth between the two oscillators •In general, part of x = DM/ originates from short distance terms and is, thus, interesting. • y = D/2 is produced by long distance terns & is less interesting • when mixing occurs, it’s important to sort out x & y Historically, particleantiparticle mixing has been a good indicator of new physics 1st hint of charm came from K0K0 Vus* Dms K0 u u Vud + Si c + Si t Vus* Vud qi qi Vus* K0 + K0 Vus* Vcd u c K0 + K0 u Vcs* Vud Vud Vtd≈0 K0 t Vts*≈0 Dms Vus*Vud f (mu )Vus*Vud + f (mc )Vcs*Vcd in the limit mu=mc (=mq): Dms Vus*Vud f (mq ) Vus*Vud + Vcs*Vcd =0 (GIM mechanism) K0K0 mixing parameter Dm is determined by the difference in mass between the c-quark and u-quark: mc≈150xmu 1st sign of a heavy t-quark came from B0B0 mixing Discovered at DESY B0 B0 B0 H.Schroeder B0 B0 ~20ps a heavy t-quark large Dmb b Dmb B0 Vub* u Vub* Vud b B0 u + Vub* Vcd b B0 u c B0 b Vud +… +… Vub* Vtd + B0 u t b Vud b Vcb* Vud Vts* Dmb Vub* Vud f (mu )Vub* Vud + f (mc )Vcb* Vcd + f (mt )Vtb*Vud Vub* Vud + Vcb* Vcd + Vtb*Vud 0 Unitarity (GIM) Vud* Vcd* Vtd* VudVusVub 1 0 0 * * * VusVcsVts VcdVcsVcb 0 1 0 * * * VubVcbVtb VtdVtsVtb 0 0 1 Dmb is large because of the huge t-quark mass: i.e. f(mt) is very much different than f(mu) & f(mc) B0 mu≈10 MeV mc≈1500 MeV mt≈175,000 MeV x150 x120 The “Flavor Problem” SUSY’s Problem with K0K0 mixing SM: Weak-int vertices 2nd order EW: Δm 3 x 10-12 MeV NP (SUSY): QCD-vertices 6x6 matrix Dm should be huge: but it is not quark-squark “Alignment” Invoke a symmetry that results in small values for the down-type squark mixing This requires up-type squark mixing elements sinqC (~0.2) Expect large effects in D0-D0 mixing e.g. Δm ~ 6x10-11 MeV Nir & Raz PRD 66, 035007 (2002) D0D0 & K0K0 comparison c D0 d,s d,s D0 K0 u,c u,c K0 c charge=-1/3 virtual quarks (d,s,b) md≈10 MeV ms≈150 MeV x15 charge=+2/3 virtual quarks (u,c,t)c mu≈10 MeV mc≈1500 MeV SM: D0D0 mixing is very small (at least the part from short-distance terms) x150 BaBar: study of D0K+p(“wrong-sign” decays) u * ud V D0K-p+ is a Cabibbo-allowed favored decay mode (Br=3.8%) c u Vcs d W s u K- There are 2 ways that a D0 can decay to the opposite combination K+p-: 1) Doubly Cabibbo-suppressed decays (DCS) u * Vus s c 0 D u Vcd W Br ~ 0.014% d u p- 2) D0 D0; D0K+p- decays * cs V u 0 c D mixing c D0 u d Vud u W s u K+ Cabibbo-allowed D0 decay (CA) Distinguish DCS from mixing using t-dependence ws ( D K p ) ADCS + Amix ACA 0 + - 2 2 2 ( x + y ) 2 2 2 -t t * ws ADCS + yADCS ACAt + ACA t e 4 pure mixing DCSD interfence usually use : ADCS re i ACA rs ACA e -t t 2 (" right sign" rate) ws ( x 2 + y 2 ) 2 -t t 1 + y' rt + t e rs 4 y ' y cos + x sin This is what BaBar measures BaBar’s fit y’ = (9.7 4.4 3.1) x 10−3 y ' y cos + x sin long-distance effect? short-distance effect? Dm??? D??? Need to translate y’ into x & y, for this we have to determine Time-dependence of D0K+p- What can BES-III do? We can’t measure t-dependence because our D0 mesons at almost at rest But in y(3770)D0D0 decays, the D0 and D0 are in a coherent Quantum state So, for example: When one D0 decays to a CP=+1 eigenstate (D1K+K- or D1p+p-), the rate for the other DK∓p± is “enhanced” by f=1+(2rcos+y) BES-III can measure f with a ~1% statistical error r≈tan2qc≈0.05 When one D0 decays to a CP=-1 eigenstate (D2KSp0 or D1KSh), the rate for the other D2K∓p± is “reduced” by f=1-(2rcos+y) other quantum correlations @ the y(3770) ℓ + ℓ- CLEO-c Results 1st measurement of Kp •essential input to D-mixing studies •unique to the y(3770) (BES-III) •BES-III will do much better •plus other modes CP violation in c-quark sector? the most exciting quantum correlation Expected to be very small in the SM in y(3770)D0D0, the D0 and D0 are in a coherent CP=-1 Quantum state When one D0 decays to a CP eigenstate, the other D cannot decay to a CP eigen state with the same CP unless CP is violated For example, y(3770) DD CP violation!!! Summary • Charm physics has had an illustrious history • New results (mixing, fDs) have revived interest • Many unique opportunities for BES-III – – – – challenge SM with improved f D+& fDs values Important contributions to D-mixing studies Search for CP violation in D-meson decays … • Many, many thesis topics for PhD students Lots to do 加油 謝謝 Back-up slides SM expectation for Dmc Vcd Dmc c D0 u +… Vud* u d d * ud V Vcd D0 c Vcd c + D0 d u * us V s * ud V Vcd u D0 c Vub* ≈0 u c D0 + d u Vcs b * ud V Vcb≈0 Dmc Vud* Vcd f (md )Vud* Vcd + f (ms )Vus*Vcs +… not so different Expect D0D0 mixing is very small (at least from short-distance terms) D0 c How to make Δm small? PLB 309, 337 (1993)
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