A survey of ascending subgraph decomposition 胡維新 1 Abstract A graph G with n 1 2 edges is said to have an ascending subgraph decomposition if its edge set can be decomposed into n sets E1, E2, …, En such that for i=1, 2, …, n and each Ei induces a subgraph Gi such that Gi is isomorphic to a subgraph of Gi+1 for i=1, 2, …, n-1. Here we will introduce some results of the ASD conjecture . 2 In 1987, Paul Erdös and the others posed the following conjecture. Ascending Subgraph Decomposition Conjecture : n 1 t 2 Let G be a graph on edges where 0≤t≤n then E(G) can be partitioned into n set E1, E2, …, En which induce G1, G2, …, Gn such that |E(Gi)| < |E(Gi+1)| and Gi is isomorphic to a subgraph of Gi+1 (denoted by Gi ≤ Gi+1 ) for i=1, 2, …, n-1. G1, G2, …, Gn are the members of the ASD. Usually, we let |E(Gi)|=i for i=1, 2, …, n-1 and |E(Gn)|=n+t, hence only the case n 1 when |E(G)|= 2 is considered except for some special class of graph. 3 5 1 Example: 15= 2 G1 G2 G3 G4 G5 4 Three directions in dealing with the ASD problem (1) |V(G)|≤n+3 (2) (G) (2 2 )n (3) Special classes of graphs : split graphs, complete t-partite graphs, forests, regular graphs 5 Theorem 1.1 The complete graph Kn+1 has an ASD with each member a star (a path or mixed). 6 n 1 edges 2 Theorem 1.2 Let G be a graph on and |V(G)|=n+2 then G has an ASD with each member a star. Proof : n ≤Δ(G) ≤ n+1 Case 1 Δ(G) =n : G=G’ union Sn(n edges) then delete Sn and G’ by induction. G’ . . . Sn 7 Case 2 Δ(G) =n+1 : G=G’union Sn+1(n+1 edges) then delete the star and union by induction. . . . . . . G’ Sn+1 Let the member Gi containing the red edge receive an edge of the Sn+1 to form a star then we have an ASD with each member a star. 8 Example 9 n 1 2 edges Theorem 1.3 Let G be a graph on and |V(G)|=n+3 then G has an ASD with each member a Ti for i=1, 2, …, n.(Ti is a star union a leg) Proof : Similar to Theorem 1.2 and consider four cases according to Δ(G) =n-1, n, n+1 or n+2 we could have an ASD with each member a Ti. … ... T1 T2 … Tn 10 Case 1 Δ(G) =n-1 G’ . . . Sn-1 11 Case 2 Δ(G) =n G’ . . . Sn (i) S n Gn' 1 Gn Gn 1 (ii ) (iii ) 12 Case 3 Δ(G) =n+1 (assume ' is in G l ) G’ . . . Sn+ 1 (i) ' S n 1 Gl Gn Gl (ii ) (iii ) 13 Case 4 Δ(G) =n+2 (i) x s.t. n 1 deg( x) n 1 then go back to Case 1, 2, 3 (ii ) (i) failed and x s.t. deg( x) n k Then similar to Case 1, 2, 3 G\Tn-k+1 can be decomposed into Gn, Gn-1, …, G1 except Gn-k+1 14 Theorem 2.1 If a graph G has G has an ASD. n 1 edges, 2 and Δ(G)< n 1 Theorem 2.2 If a graph G has 2 edges, and Δ(G) ≤ (2 2, )then n (n 1) / 2, then G has an ASD with each a member a matching. Proof : Step 1 : Partitioned the edge set of G into k matchings (k=n/2 or (n+1)/2 according to k is even or odd) M1, M2, …,Mk where |M1|=|M2|= … =|Mk| Step 2 : Split Mi into Gi and Gn+1-i for i=1, 2, …, n/2 when n is even. Split Mi into Gi and Gn-i for i=1, 2, …, (n-1)/2 when n is odd. 15 Example : |E(G)|= G10 G5 11=1+10 10 1 and then 2 G9 G8 G4 11=2+9 G3 11=3+8 G is 5 edge-colorable. G7 G6 G2 11=4+7 G1 11=5+6 Gi=a matching of size i for i=1, 2, …, 10 16 Theorem 3.1 Any split graph n 1 on 2 edges has an ASD. v Null graph Complete graph . . . . . . Proof : Delete a star of n edges from the edges from the edges incident to v (the edges between null graph and complete graph first) and the by induction. 17 Example : 5 1 |E(G)|= 2 18 n 1 tedges where t < n, has an ASD. Theorem 3.2 Any r-regular graph G on 2 Proof : Case 1. r ≤ n/2, then by Thm 2.2 with each member a matching. Case 2. n/2<r ≤2n/3 : Case 3. 2n/3<r<v/2: Case 4. r≥v/2. Peel off Hamiltonian cycles from the graph until the remaining 19 valency r’<v/2 and the members Gi would be linear forest. . . . . . . . . . . . . . . . 20 Theorem 3.3 Any forest on on n 1 edges has an ASD with each member a star forest. 2 21 Case 1 exists small branches with at least n edges Example : n=10 22 Case 2 exists a big star with more than n 2 edges }1 23 Case 3 exists at least two stars with size at least n } k 24 Theorem 3.4 Any complete multipartite graph has an ASD with each member a star or a double star or a pregnant star. Double star Pregnat star 25 26 27
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