STEP THREE: CONVERT OBJECTIVE TO UNITS. STEP ONE: CONVERT KNOWN TO MOLES. CONVERT TO MASS RECOGNIZE: MASS CONVERT TO MOLES GIVEN IS A MASS IN GRAMS, ANY PHASE. MOLES = MASS/GFM RECOGNIZE: CONVERT TO MOLES GIVEN IS A GAS (g) VOLUME AT STP MOLES =VOL(L)/22.4L (ATOMS OR MOLECULES) RECOGNIZE: VOLUME AND MOLARITY GIVEN IS AN AQUIOUS SOLUTION (aq) RATIO MOLES GIVEN TO MOLES OBJECTIVE TO SOLVE FOR MOLES OF OBJECTIVE USE COEFFICIENT OF BALANCED REACTION VOL = MOLES * 22.4 CONVERT TO PARTICLES PARTICLES = MOLES * 6.02 * 1023 RECOGNIZE PARTICLES STEP TWO: MOLE RATIO CONVERT TO GAS VOL STP GAS GIVEN IS IN MASS = MOLES * GFM CONVERT TO MOLES MOLES = PARTICLES 6.02 * 1023 CONVERT TO MOLES VOLUME = MOLES/ M CONVERT TO MOLES MOLES =VOLUME * M CALCULATE THE YEILD OF NH3 in grams IF 8 GRAMS OF H2 REACTS COMPLETLEY WITH EXCESS NITROGEN. N2 + 3H2 2NH3 STEP THREE: CONVERT OBJECTIVE TO UNITS. STEP ONE: CONVERT KNOWN TO MOLES. RECOGNIZE: GIVEN IS A MASS IN GRAMS, ANY PHASE. RECOGNIZE GIVEN IS A GAS (g) VOLUME AT STP RECOGNIZE GIVEN IS IN PARTICLES (ATOMS OR MOLECULES) RECOGNIZE GIVEN IS AN AQUIOUS SOLUTION (aq) CONVERT TO MASS CONVERT TO MOLES STEP TWO: MOLE RATIO MASS = MOLES * GFM MOLES = MASS/GFM CONVERT TO GAS VOL CONVERT TO MOLES MOLES =VOL(L)/22.4L CONVERT TO MOLES MOLES = PARTICLES 6.02 * 1023 CONVERT TO MOLES MOLES =VOLUME * M RATIO MOLES GIVEN TO MOLES OBJECTIVE TO SOLVE FOR MOLES OF OBJECTIVE USE COEFFICIENT OF BALANCED REACTION VOL = MOLES * 22.4 CONVERT TO PARTICLES PARTICLES = MOLES * 6.02 * 1023 CONVERT TO MOLES VOLUME = MOLES/ M CALCULATE THE YEILD OF NH3 in grams IF 8.0 GRAMS OF H2 REACTS COMPLETLEY WITH EXCESS NITROGEN. N2 + 3H2 2NH3 STEP 1 Identify known (the substance that can be converted to moles), choose the correct equation to convert to moles. In this problem 8.0 grams of H2 is a given mass. MOLES = MASS/GFM MOLES = 8.00g/ 2.0 g/mol MOLES = 4.0 mol STEP 2 RATIO known to objective, use reaction coefficients to compare H2 known) to NH3 (objective). H2 = 3 = NH3 2 4.0 mol X , X = 2.66 mol NH3 STEP 3 Convert Objective to required units. Convert ammonia from MOLES to GRAMS. MOLES = MASS/GFM 2.66 = MASS/ 17.0 g/mol MASS = 45. g CALCULATE THE REQUIRED VOLUME OF H2 GAS AT STP TO PRODUCE 40 GRAMS OF NH3? N2 + 3H2 2NH3 STEP THREE: CONVERT OBJECTIVE TO UNITS. STEP ONE: CONVERT KNOWN TO MOLES. RECOGNIZE: GIVEN IS A MASS IN GRAMS, ANY PHASE. RECOGNIZE GIVEN IS A GAS (g) VOLUME AT STP RECOGNIZE GIVEN IS IN PARTICLES (ATOMS OR MOLECULES) RECOGNIZE GIVEN IS AN AQUIOUS SOLUTION (aq) CONVERT TO MASS CONVERT TO MOLES STEP TWO: MOLE RATIO MASS = MOLES * GFM MOLES = MASS/GFM CONVERT TO GAS VOL CONVERT TO MOLES MOLES =VOL(L)/22.4L CONVERT TO MOLES MOLES = PARTICLES 6.02 * 1023 CONVERT TO MOLES MOLES =VOLUME * M RATIO MOLES GIVEN TO MOLES OBJECTIVE TO SOLVE FOR MOLES OF OBJECTIVE USE COEFFICIENT OF BALANCED REACTION VOL = MOLES * 22.4 CONVERT TO PARTICLES PARTICLES = MOLES * 6.02 * 1023 CONVERT TO MOLES VOLUME = MOLES/ M CALCULATE THE REQUIRED VOLUME OF H2 GAS AT STP TO PRODUCE 40.0 GRAMS OF NH3? N2 + 3H2 2NH3 STEP 1 Identify known (the substance that can be converted to moles), choose the correct equation to convert to moles. In this problem 40 grams of NH3 is a given mass. MOLES = MASS/GFM MOLES = 40.0g/ 17.0 g/mol MOLES = 2.352 mol NH3 STEP 2 RATIO known to objective, use reaction coefficients to compare H2 known) to NH3 (objective). H2 = 3 = NH3 2 X , 2.352 X = 3.528 mol H2 STEP 3 Convert Objective to required units. Convert hydrogen from MOLES to STP gas Volume.. VOLUME = MOLES * 22.4L V = 3.528 mol H2 * 22.4L /mol V = 79.03 L CALCULATE THE MASS OF HYDROGEN REQUIRED TO PRODUCE 67.2 L OF AMMONIA AT STP. N2 + 3H2 2NH3 STEP THREE: CONVERT OBJECTIVE TO UNITS. STEP ONE: CONVERT KNOWN TO MOLES. RECOGNIZE: GIVEN IS A MASS IN GRAMS, ANY PHASE. RECOGNIZE GIVEN IS A GAS (g) VOLUME AT STP RECOGNIZE GIVEN IS IN PARTICLES (ATOMS OR MOLECULES) RECOGNIZE GIVEN IS AN AQUIOUS SOLUTION (aq) CONVERT TO MASS CONVERT TO MOLES STEP TWO: MOLE RATIO MASS = MOLES * GFM MOLES = MASS/GFM CONVERT TO GAS VOL CONVERT TO MOLES MOLES =VOL(L)/22.4L CONVERT TO MOLES MOLES = PARTICLES 6.02 * 1023 CONVERT TO MOLES MOLES =VOLUME * M RATIO MOLES GIVEN TO MOLES OBJECTIVE TO SOLVE FOR MOLES OF OBJECTIVE USE COEFFICIENT OF BALANCED REACTION VOL = MOLES * 22.4 CONVERT TO PARTICLES PARTICLES = MOLES * 6.02 * 1023 CONVERT TO MOLES VOLUME = MOLES/ M CALCULATE THE MASS OF HYDROGEN REQUIRED TO PRODUCE 67.2 L OF AMMONIA AT STP. N2 + 3H2 2NH3 STEP 1 Identify known (the substance that can be converted to moles), choose the correct equation to convert to moles. In this problem 67.2 L OF AMMONIA IS GIVEN(KNOWN) GAS VOLUME. VOLUME = MOLES * 22.4L 67.2 = mol NH3 * 22.4L /mol MOL NH3 = 3 STEP 2 RATIO known to objective, use reaction coefficients to compare H2 known) to NH3 (objective). H2 = 3 = NH3 2 X 3 , X = 4.50 mol H2 STEP 3 Convert Objective to required units. Convert hydrogen from MOLES to MASS. MOLES = MASS/GFM 4.5 MOLES = MASS/ 2.0 g/mol MASS = 9.00 GRAMS H2 CALCULATE THE REQUIRED VOLUME OF N2 GAS AT STP TO PRODUCE 12.04 * 1023 MOLECULES OF NH3? N2(g) + 3H2(g) 2NH3(g) STEP THREE: CONVERT OBJECTIVE TO UNITS. STEP ONE: CONVERT KNOWN TO MOLES. RECOGNIZE: GIVEN IS A MASS IN GRAMS, ANY PHASE. RECOGNIZE GIVEN IS A GAS (g) VOLUME AT STP RECOGNIZE GIVEN IS IN PARTICLES (ATOMS OR MOLECULES) RECOGNIZE GIVEN IS AN AQUIOUS SOLUTION (aq) CONVERT TO MASS CONVERT TO MOLES STEP TWO: MOLE RATIO MASS = MOLES * GFM MOLES = MASS/GFM CONVERT TO GAS VOL CONVERT TO MOLES MOLES =VOL(L)/22.4L CONVERT TO MOLES MOLES = PARTICLES 6.02 * 1023 CONVERT TO MOLES MOLES =VOLUME * M RATIO MOLES GIVEN TO MOLES OBJECTIVE TO SOLVE FOR MOLES OF OBJECTIVE USE COEFFICIENT OF BALANCED REACTION VOL = MOLES * 22.4 CONVERT TO PARTICLES PARTICLES = MOLES * 6.02 * 1023 CONVERT TO MOLES VOLUME = MOLES/ M CALCULATE THE REQUIRED VOLUME OF N2 GAS AT STP TO PRODUCE 12.04 * 1023 MOLECULES OF NH3? N2(g) + 3H2(g) 2NH3(g) STEP 1 Identify known (the substance that can be converted to moles), choose the correct equation to convert to moles. In this problem 12.04 * 1023 MOLECULES (PARTICLES) OF NH3 IS THE KNOWN. MOL= PART/6.02*1023 MOL=12.04*1023 / 6.02*1023 MOLES = 2.000 MOL NH3 STEP 2 RATIO known to objective, use reaction coefficients to compare N2 known) to NH3 (objective). N2 = 1 = NH3 2 X , 2.000 X = 1.000 mol N2 STEP 3 Convert Objective to required units. Convert hydrogen from MOLES to STP gas Volume.. VOLUME = MOLES * 22.4L V = 1.000 mol H2 * 22.4L /mol V = 22.40 L
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