NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 4 8β’4 Lesson 4: Solving a Linear Equation Classwork Exercises For each problem, show your work, and check that your solution is correct. 1. Solve the linear equation π₯ + π₯ + 2 + π₯ + 4 + π₯ + 6 = β28. State the property that justifies your first step and why you chose it. 2. Solve the linear equation 2(3π₯ + 2) = 2π₯ β 1 + π₯. State the property that justifies your first step and why you chose it. Lesson 4: Solving a Linear Equation This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M4-TE-1.3.0-09.2015 S.10 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 4 8β’4 3 5 3. Solve the linear equation π₯ β 9 = π₯. State the property that justifies your first step and why you chose it. 4. Solve the linear equation 29 β 3π₯ = 5π₯ + 5. State the property that justifies your first step and why you chose it. 5. Solve the linear equation π₯ β 5 + 171 = π₯. State the property that justifies your first step and why you chose it. 1 3 Lesson 4: Solving a Linear Equation This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M4-TE-1.3.0-09.2015 S.11 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 4 NYS COMMON CORE MATHEMATICS CURRICULUM 8β’4 Lesson Summary The properties of equality, shown below, are used to transform equations into simpler forms. If π΄, π΅, πΆ are rational numbers, then: ο§ If π΄ = π΅, then π΄ + πΆ = π΅ + πΆ. Addition property of equality ο§ If π΄ = π΅, then π΄ β πΆ = π΅ β πΆ. Subtraction property of equality ο§ If π΄ = π΅, then π΄ β πΆ = π΅ β πΆ. Multiplication property of equality ο§ If π΄ = π΅, then π΄ πΆ = π΅ πΆ , where πΆ is not equal to zero. Division property of equality To solve an equation, transform the equation until you get to the form of π₯ equal to a constant (π₯ = 5, for example). Problem Set For each problem, show your work, and check that your solution is correct. 1. Solve the linear equation π₯ + 4 + 3π₯ = 72. State the property that justifies your first step and why you chose it. 2. Solve the linear equation π₯ + 3 + π₯ β 8 + π₯ = 55. State the property that justifies your first step and why you chose it. 3. Solve the linear equation π₯ + 10 = 1 1 2 4 π₯ + 54. State the property that justifies your first step and why you chose it. 1 4. Solve the linear equation π₯ + 18 = π₯. State the property that justifies your first step and why you chose it. 5. Solve the linear equation 17 β π₯ = 6. Solve the linear equation 4 π₯+π₯+2 Lesson 4: 4 1 β 15 + 6. State the property that justifies your first step and why you chose it. 3 = 189.5. State the property that justifies your first step and why you chose it. Solving a Linear Equation This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M4-TE-1.3.0-09.2015 S.12 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 4 NYS COMMON CORE MATHEMATICS CURRICULUM 7. 8β’4 Alysha solved the linear equation 2π₯ β 3 β 8π₯ = 14 + 2π₯ β 1. Her work is shown below. When she checked her answer, the left side of the equation did not equal the right side. Find and explain Alyshaβs error, and then solve the equation correctly. 2π₯ β 3 β 8π₯ = 14 + 2π₯ β 1 β6π₯ β 3 = 13 + 2π₯ β6π₯ β 3 + 3 = 13 + 3 + 2π₯ β6π₯ = 16 + 2π₯ β6π₯ + 2π₯ = 16 β4π₯ = 16 β4 16 π₯= β4 β4 π₯ = β4 Lesson 4: Solving a Linear Equation This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from G8-M4-TE-1.3.0-09.2015 S.13 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
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