State the property that justifies your first step and why

NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 4
8β€’4
Lesson 4: Solving a Linear Equation
Classwork
Exercises
For each problem, show your work, and check that your solution is correct.
1.
Solve the linear equation π‘₯ + π‘₯ + 2 + π‘₯ + 4 + π‘₯ + 6 = βˆ’28. State the property that justifies your first step and
why you chose it.
2.
Solve the linear equation 2(3π‘₯ + 2) = 2π‘₯ βˆ’ 1 + π‘₯. State the property that justifies your first step and why you
chose it.
Lesson 4:
Solving a Linear Equation
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This file derived from G8-M4-TE-1.3.0-09.2015
S.10
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Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 4
8β€’4
3
5
3.
Solve the linear equation π‘₯ βˆ’ 9 = π‘₯. State the property that justifies your first step and why you chose it.
4.
Solve the linear equation 29 βˆ’ 3π‘₯ = 5π‘₯ + 5. State the property that justifies your first step and why you chose it.
5.
Solve the linear equation π‘₯ βˆ’ 5 + 171 = π‘₯. State the property that justifies your first step and why you chose it.
1
3
Lesson 4:
Solving a Linear Equation
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from G8-M4-TE-1.3.0-09.2015
S.11
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 4
NYS COMMON CORE MATHEMATICS CURRICULUM
8β€’4
Lesson Summary
The properties of equality, shown below, are used to transform equations into simpler forms. If 𝐴, 𝐡, 𝐢 are rational
numbers, then:
ο‚§
If 𝐴 = 𝐡, then 𝐴 + 𝐢 = 𝐡 + 𝐢.
Addition property of equality
ο‚§
If 𝐴 = 𝐡, then 𝐴 βˆ’ 𝐢 = 𝐡 βˆ’ 𝐢.
Subtraction property of equality
ο‚§
If 𝐴 = 𝐡, then 𝐴 β‹… 𝐢 = 𝐡 β‹… 𝐢.
Multiplication property of equality
ο‚§
If 𝐴 = 𝐡, then
𝐴
𝐢
=
𝐡
𝐢
, where 𝐢 is not equal to zero. Division property of equality
To solve an equation, transform the equation until you get to the form of π‘₯ equal to a constant (π‘₯ = 5, for
example).
Problem Set
For each problem, show your work, and check that your solution is correct.
1.
Solve the linear equation π‘₯ + 4 + 3π‘₯ = 72. State the property that justifies your first step and why you chose it.
2.
Solve the linear equation π‘₯ + 3 + π‘₯ βˆ’ 8 + π‘₯ = 55. State the property that justifies your first step and why you
chose it.
3.
Solve the linear equation π‘₯ + 10 =
1
1
2
4
π‘₯ + 54. State the property that justifies your first step and why you chose
it.
1
4.
Solve the linear equation π‘₯ + 18 = π‘₯. State the property that justifies your first step and why you chose it.
5.
Solve the linear equation 17 βˆ’ π‘₯ =
6.
Solve the linear equation
4
π‘₯+π‘₯+2
Lesson 4:
4
1
β‹… 15 + 6. State the property that justifies your first step and why you chose it.
3
= 189.5. State the property that justifies your first step and why you chose it.
Solving a Linear Equation
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from G8-M4-TE-1.3.0-09.2015
S.12
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 4
NYS COMMON CORE MATHEMATICS CURRICULUM
7.
8β€’4
Alysha solved the linear equation 2π‘₯ βˆ’ 3 βˆ’ 8π‘₯ = 14 + 2π‘₯ βˆ’ 1. Her work is shown below. When she checked her
answer, the left side of the equation did not equal the right side. Find and explain Alysha’s error, and then solve the
equation correctly.
2π‘₯ βˆ’ 3 βˆ’ 8π‘₯ = 14 + 2π‘₯ βˆ’ 1
βˆ’6π‘₯ βˆ’ 3 = 13 + 2π‘₯
βˆ’6π‘₯ βˆ’ 3 + 3 = 13 + 3 + 2π‘₯
βˆ’6π‘₯ = 16 + 2π‘₯
βˆ’6π‘₯ + 2π‘₯ = 16
βˆ’4π‘₯ = 16
βˆ’4
16
π‘₯=
βˆ’4
βˆ’4
π‘₯ = βˆ’4
Lesson 4:
Solving a Linear Equation
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from G8-M4-TE-1.3.0-09.2015
S.13
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.