November 14, 2011 Check for understanding + + -10 Two protons are separated by a distance of 1 X 10 m. Find the gravitational attraction between the two particles. November 14, 2011 · · · · Exams returned Goals Card updated Universal Gravitation Intro to Work & Energy ***Mid Term next Tuesday! Review booklet handed out in class Booklet to be turned in on exam day November 14, 2011 Universal Gravitation d2 or r2 is fine Mass of Earth in Ref Table Radius of Earth in Ref Table CHECK THEM NOW! November 14, 2011 HW P. 90 QQ 4.2 P. 91 Q 4.3 & Ex 4.3 P. 109-110 MC #5 & 14 P. 122 Q 5.1 & EX 5.1 Quick Quiz 4.2 Which has a greater value, a newton of gold won on the Earth or a newton of gold won on the Moon? B -on the Moon P. 91 Q4.3 & Ex 4.3 Q 4.3: Mars is 1.5X as far from the sun as the Earth. What if Fsun on a 70kg man standing on Mars? Fsun = 0.2N for man on Mars Ex 4.3: Find the force exerted by the Moon on a 70kg man standing on Earth. Fmoon = 0.002N for man on Earth P. 109 & 110 MC #5 B & #14 B P.122 Q5.1 & Ex 5.1 Q 5.1: How does the work change if the load is doubled? Assuming dounble load produces doubled frictional force, BUT Ff is VERY small, doubling load probably will not change effort force or distance, thus keeping work approx the same as before. Ex 5.1: Suppose the sled is pushed instead on level terrain with a force of 50N. o a.) Force exerted at an angle of 0 to the horizontal, distance =? to do 400J of work 8m o b.) Force exerted at 45 angle to the horizontal, how much work for the same amount of distance? 283m using Fx as the force November 14, 2011 P. 91 Q4.3 & Ex 4.3 Q 4.3: Mars is 1.5X as far from the sun as the Earth. What if Fsun on a 70kg man standing on Mars? Ex 4.3: Find the force exerted by the Moon on a 70kg man standing on Earth. November 14, 2011 November 14, 2011 An object has a mass of 10.2kg. Find the weight of the object (force due to gravity) on the surface of the Earth, at one Earth radius above the surface, two Earth radii, and 3 Earth radii. November 14, 2011 Calculate the force of gravity between you and the person sitting next to you in class, assuming you both have masses of 60 kg and are sitting 1.2 m apart. Two tennis balls have a mass of 0.25 kg each and they are placed so that there is a distance of 42 cm between their centers. What is the gravitational force between the two tennis balls? Use the universal gravitation formula to find the weight of a 10 kg object on the surface of the earth. 2 At what altitude above the earth’s surface would the acceleration due to gravity be 4.9 m/s ? A 14.2 kg object weighs 6.55 N at a certain point above the earth’s surface. (a) What is the acceleration due to gravity at that point? (b) How far is the object from the earth’s surface? (c) What is the weight of the block on the earth’s surface? November 14, 2011 November 14, 2011 A certain hypothetical2 planet has a radius of 500 km and a surface gravitational acceleration of 3 m/s . (a) What is the mass of the planet? (b) What is the gravitational acceleration 100 km above the surface of the planet? How far from the surface of the earth must a satellite be in order to have a weight of only 1/3 of its weight at the earth’s surface? What is the weight of a 14 kg object when it is 300,000 m above the surface of Mars? November 14, 2011 1. It is the gravitational force that holds a planet in its orbit about the Sun. If it were zero, the planet would continue in a straight path rather than following an ellipse. Gravity is the string on the yo-yo when it is spun in a circle... 2. Fg = 81.26N 3. Fg= 81.7N 4. Fnew = 9 Fold 5. Fnew = 9/4 Fold 6. Fnew = 1/9 Fold 7. Fnew = 4/9 Fold 8. Fnew = 1/8 Fold 9. Fg = 1641 N a = 2.27 m/s2 and 10. Fg = 2 X 1020 N 11. Fg = 17354 N skip 11c, 12 a & b and and each pulls each other with 2 X 1020N a = 8.68 m/s2 November 14, 2011
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