11.1 Chemical Reactions > Chapter 11 Matter and Change 11.1 Describing Chemical Reactions 11.2 Types of Chemical Reactions 11.3 Reactions in Aqueous Solution 1 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Introduction to Chemical Equations Do Now: Work with your table mates to come up with a list of 10 chemical reactions that you have seen or heard of. 2 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Introduction to Chemical Equations How do you know if a chemical reaction is taking place? https://www.youtube.com/watch?v=FofPjj7v414 3 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Introduction to Chemical Equations Signs of a Chemical Reaction • Transfer of energy • Change in color • Production of a gas • Formation of a precipitate 4 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Introduction to Chemical Equations How do you describe what is happening in a chemical reaction? 5 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Introduction to Chemical Equations Word Equations Reactants → Products • Reactants are on the left, products on the right. • An arrow separates them. • You read the arrow as yields, gives, or reacts to produce. 6 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Introduction to Chemical Equations Word Equations Iron + oxygen → iron(III) oxide • Rusting of Iron • You could say, “Iron reacts with oxygen to produce iron(III) oxide (rust).” 7 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Introduction to Chemical Equations Skeleton Equations Equations that show just the formulas of the reactants and products. Fe + O2 → Fe2O3 The first step in writing a complete chemical equation is to write the skeleton equation. 8 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Interpret Data Symbols Used in Chemical Equations Symbol + → Explanation Separates two reactants or two products “Yields,” separates reactants from products Use in place of → for reversible reactions (s), (l), (g) (aq) Designates a reactant or product in the solid state, liquid state, or gaseous state; placed after the formula Designates an aqueous solution; the substance is dissolved in water; placed after the formula Δ heat Pt 9 Indicates that heat is supplied to the reaction A formula written above or below the yields sign indicates its use as a catalyst (in this example, platinum). Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Introduction to Chemical Equations Chemical Equations Indicate the physical states of substances by putting a symbol after each formula. • • • • (s) for solid (l) for liquid, (g) for gas, (aq) for a substance in an aqueous solution (a substance dissolved in water). Fe(s) + O2(g) → Fe2O3(s) 10 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Introduction to Chemical Equations Chemical Equations Catalyst: substance that speeds up the reaction but is not used up in the reaction. • A catalyst is neither a reactant nor a product, so its formula is written above the arrow in a chemical equation. H2O2(aq) 11 MnO2 H2O(l) + O2(g) Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Sample Problem 11.1 Write a Skeleton Equation Hydrochloric acid reacts with solid sodium hydrogen carbonate. The products formed are aqueous sodium chloride, water, and carbon dioxide gas. Write a skeleton equation for this chemical reaction. 12 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Sample Problem 11.1 Write a Skeleton Equation Hydrochloric acid reacts with solid sodium hydrogen carbonate. The products formed are aqueous sodium chloride, water, and carbon dioxide gas. Write a skeleton equation for this chemical reaction. NaHCO3(s) + HCl(aq) → NaCl(aq) + H2O(l) + CO2(g) 13 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Balancing Chemical Equations Law of Conservation of Mass • During any chemical reaction, the mass of the products always equals the mass of the reactants. • Atoms are neither created nor destroyed in ordinary chemical reactions. • The same number of atoms of each element must be present on both sides of the equation. 14 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Balancing Chemical Equations What does that mean for you? • The same number of atoms of each element must be present on both sides of the equation. • Add coefficients to balance the reactants and products. Do not add subscripts! 15 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Balancing Chemical Equations Coefficients— small whole numbers that are placed in front of the formulas in an equation in order to balance it. 16 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Balancing Chemical Equations Balanced equation: each side of the equation has the same number of atoms of each element and mass is conserved. 17 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Balancing Chemical Equations To write a balanced chemical equation 1. Write the skeleton equation. 2. Use coefficients to balance the equation so that it obeys the law of conservation of mass. 18 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Balancing Chemical Equations Carbon burns in the presence of oxygen to produce carbon dioxide. C(s) Carbon + O2(g) Oxygen Reactants 1 carbon atom, 2 oxygen atoms CO2(g) Carbon dioxide Product 1 carbon atom, 2 oxygen atoms • This equation is balanced. • You do not need to change the coefficients. – They are all understood to be 1. 19 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Balancing Chemical Equations When hydrogen and oxygen are mixed, the product is water. • The formulas for all the reactants and the product are correct, but this equation is not balanced. – As written, the equation does not obey the law of conservation of mass. 20 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Balancing Chemical Equations When hydrogen and oxygen are mixed, the product is water. • If you put the coefficient 2 in front of H2O, oxygen will be balanced. – Now twice as many hydrogen atoms are in the product as are in the reactants. 21 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Balancing Chemical Equations When hydrogen and oxygen are mixed, the product is water. • To correct this equation, put the coefficient 2 in front of H2. – The equation is now balanced. 22 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > CHEMISTRY & YOU The reaction between oxygen and hydrogen in fuel cells produces the energy to power a car. What are the products of the reaction in a fuel cell that make the fuel-cell car a zero-emission car? 23 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > CHEMISTRY & YOU The reaction between oxygen and hydrogen in fuel cells produces the energy to power a car. What are the products of the reaction in a fuel cell that make the fuel-cell car a zero-emission car? Water is the product of the reaction between oxygen and hydrogen in a fuel cell. Water is not a pollutant, and so fuel-cell cars are considered “zero-emission” cars. 24 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Interpret Data Rules for Writing and Balancing Equations 1. Determine the correct formulas for all the reactants and products. 4. Balance the elements one at a time by using coefficients. When no coefficient is written, it is assumed 2. Write the skeleton equation by to be 1. Begin by balancing placing the formulas for the elements that appear only once on reactants on the left and the each side of the equation. Never formulas for the products on the balance an equation by changing right with a yields sign (→) in the subscripts in a chemical formula. between. If two or more reactants or Each substance only has one products are involved, separate their correct formula. formulas with plus signs. 5. Check each atom or polyatomic ion 3. Determine the number of atoms of to be sure that the number is equal each element in the reactants and on both sides of the equation. products. Count a polyatomic ion as a single unit if it appears unchanged 6. Make sure all the coefficients are in on both sides of the equation. the lowest possible ratio. 25 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Sample Problem 11.2 Balancing a Chemical Equation Students suspended copper wire in an aqueous solution of silver nitrate. They noticed a deposit of silver crystals on the copper wire when the copper reacted with the silver nitrate. They recorded the equation for this reaction but didn’t balance it. Balance their equation: AgNO3(aq) + Cu(s) → Cu(NO3)2(aq) + Ag(s) 26 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Sample Problem 11.2 2 Solve Apply concepts to this situation. Balance the nitrate ion. • Put a coefficient 2 in front of AgNO3(aq). 2AgNO3(aq) + Cu(s) → Cu(NO3)2(aq) + Ag(s) Remember that a coefficient must always go in front of a compound’s formula, not in the middle of it. 27 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Sample Problem 11.2 2 Solve Apply concepts to this situation. Balance the silver. • Put a coefficient 2 in front of Ag(s). 2AgNO3(aq) + Cu(s) → Cu(NO3)2(aq) + 2Ag(s) 28 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Sample Problem 11.3 Balancing a Chemical Equation Aluminum is a good choice for outdoor furniture because it reacts with oxygen in the air to form a thin protective coat of aluminum oxide. Balance the equation for this reaction. Al(s) + O2(s) → Al2O3(s) 29 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Sample Problem 11.3 1 Analyze Identify the relevant concepts. Apply the rules for balancing equations. • Notice the odd number of oxygen atoms in the product. Al(s) + O2(s) → Al2O3(s) 30 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Sample Problem 11.3 2 Solve Apply concepts to this situation. First balance the aluminum by placing the coefficient 2 in front of Al(s). 2Al(s) + O2(s) → Al2O3(s) 31 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Sample Problem 11.3 2 Solve Apply concepts to this situation. Multiply the formula with the odd number of oxygen atoms (on the right) by 2 to get an even number of oxygen atoms on the right. 2Al(s) + O2(s) → 2Al2O3(s) Any whole-number coefficient placed in front of O2 will always give an even number of oxygen atoms on the left. 32 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Sample Problem 11.3 2 Solve Apply concepts to this situation. Balance the oxygens on the left by placing a 3 in front of O2. 2Al(s) + 3O2(s) → 2Al2O3(s) 33 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Sample Problem 11.3 2 Solve Apply concepts to this situation. Then rebalance the aluminum by changing the coefficient of Al(s) from 2 to 4. 4Al(s) + 3O2(s) → 2Al2O3(s) 34 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > https://www.youtube.com/watch?v=2S6e11NB wiw 35 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Balance the following equation. C3H8(g) + O2(g) → CO2(g) + H2O(l) 36 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > Balance the following equation. C3H8(g) + O2(g) → CO2(g) + H2O(l) C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l) 37 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11.1 Chemical Reactions > END OF 11.1 38 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved.
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