CPT Mock Test
Test Booklet No. – 110011
(1)
2nd Session
Date: - 06.06.2016
Duration : 2 Hours
Total Marks : 100
Ans.d
Explanation:
Under Monopolistic Competition Market, there are so many varities of product
available for the consumer, because there is existence of product differentiation.
(2)
Ans.b
Explanation:
Under Partial Oligopoly, the industry is dominated by one large firm, which is
considered or looked upon as a leader of the group. The dominating firm will be
the price leader.
(3)
Ans. c
Explanation:
Rising portion of Marginal Cost curve is known as supply curve because marginal
cost increases with the increment in level of output.
(4)
Ans. a
(5)
Ans. b
(6)
Ans.c
(7)
Ans. d
Explanation:
As per law of DMU, MU diminishes with increased consumption and gradually can
become zero or negative
(8)
Ans. b
Explanation:
Since Elasticity between any two given points of a demand curve is called ARC
Elasticity.
(9)
Ans. a
(10)
Ans. a
(11)
Ans. d
(12)
Ans. c
(13)
Ans. b
Explanation:
TP increases at diminishing rate due to decrement in MP but positively.
(14)
Ans. a
(15)
Ans. b
Explanation:
MITTAL COMMERCE CLASSES
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Y
e= 1
O
X
At the mid point of demand curve elasticity is unitary elastic
(16)
Ans. b
Explanation:
Since MC is having an extreme behaviour than AC.
(17)
Ans. d
Explanation:
As when AR>AC (Super normal profit)(10>8)
(18)
Ans. c
Explanation:
since on the upper extreme point the elasticity is infinite and on the mid point the
elasticity is equal to 1. So in between the elasticity is >1 as per the graph shown
above.
(19)
Ans. a
Explanation:
Since labour doesn't have previous accumulated capital hence he has weak
bargaining power.
(20)
Ans. b
Explanation:
As shut down is the point where firm will not be able to recover even its average
variable cost.
(21)
Ans. d
MITTAL COMMERCE CLASSES
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Explanation:
Since the economist who gave cobb - douglas production function was an American.
(22)
Ans. c
Explanation:
LAC curve is also known as Planning Curve and Envelope Curve.
(23)
Ans. b
Explanation:
9
100  12.5%
72
Unemployed
100
Employed  Unemployed
(24)
Ans. a
Explanation:
Since the shape of TFC is horizontal.
(25)
Ans. b
TC
Q
800  400
MC =
20  10
Explanation: MC =
MC = 40
(26)
Ans.c
(27)
Ans. c
Explanation:
According to this theory- In the first stage both birth and death rate are very high. In
the second stage, birth rate comes down slightly but death rate comes down rapidly.
In the third stage, both birth and death rate are low.
(28)
Ans. a
Explanation:
Electricity generated from coal, oil and gas is called Thermal electricity.
(29)
Ans.b
Explanation:
For adult, the National Literacy Mission (NLM) was launched in 1998, as a
Technology Mission. It aimed at imparting functional literacy to non-literates in the
country in the age group of 15-35 in a time bound manner.
(30)
Ans. c
Explanation:
In the form of Stagflation, under which economic stagnation, in the form of a low
rate of growth combines with the rise in general price level.
(31)
Ans. c
Explanation:
Due to low CRR Commercial banks have to keep less amount of liquidity with reserve
bank. So that they can make available more credit to the public this will create more
MITTAL COMMERCE CLASSES
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liquidity in hands of public and which will generate more demand by the public.
(32)
Ans.c
Explanation:
Balance of payments is the sum of balance of payment on capital account and the
balance of current account. The sum of balance of goods, services and unrequited
transfers is known as "Balance of current account".
(33)
Ans. a
(34)
Ans.a
(35)
Ans. c
Explanation:
To improve generation of power, Ministry of Power has launched the ‘‘Partnership in
Excellence’’ programme. Under the programme, 26 thermal stations with PLF less
than 60 percent have been identified. Steps will be taken to improve their efficiency.
(36)
Ans. c
Explanation:
The Department of Posts has launched a pilot project ‘‘ Project Arrow’’ with the aim
of providing fast and reliable postal services to the consumers.
(37)
Ans. a
(38)
Ans. b
(39)
Ans. a
(40)
Ans. b
(41)
Ans. a
(42)
Ans. b
Explanation:
Cafeteria approach is related to Family Planning. Various contraceptive methods
were offered and the acceptors had the freedom to choose any of the methods
offered.
(43)
Ans. a
Explanation:
In India we use the concept of absolute poverty for measuring poverty. For this a
minimum level of consumption standard is laid down (known poverty line) and those
who fail to reach this minimum consumption level are regarded as poor.
(44)
Ans. a
Explanation:
The revenue is income elastic ; because of the progressive character revenue will
increase faster than the increase in income.
(45)
Ans. a
The tax which is levied on the income of individuals, Hindu Undivided family
unregistered Firms and other association of people is known as personal income tax
(46)
Ans. c
MITTAL COMMERCE CLASSES
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Explanation:
Since Kerala has the highest literacy ratio of 92%.
(47)
Ans. a
Explanation:
Since the creation of Indian Postal Department happened in 1837.
(48)
Ans. c
Explanation:
Since FCI provides crop storage facility in India.
(49)
Ans. a
Explanation:
Since devaluation means to reduce the value of home currency in other currency.
(50)
Ans. a
Explanation:
Since balance of payment is a systematic record of all transactions of a county in a
year.
(51)
Ans. b
Explanation:
Required sum
=
162  1 162  1 162  ....
2

4

= 16  1    ...
 2 4

2
1
1




1
2
 512 sq. cm
= 16  
1
1  
 2
(52)
Ans. b
Explanation:
By formula
n A  B  C   n A  nB  nC   n A  B  nB  C   n( A  C)  n A  B  C 
92%
= 42% + 51% + 68% – 30% – 28% – 36% +
n A  B  C  = 25%
MITTAL COMMERCE CLASSES
n A  B  C 
5|Page
U
B
A
5%
1%
18%
25%
3%
11%
29%
C
The percentage of persons who read only one paper
= 1% + 18% + 29% = 48%
(53)
Ans. c
Explanation:
81 x  41 x
 2 x dx
23 x 3  2 2 2 x
dx
=
2x
2 x 3
 2 23 x dx
= 2

=

2 2 x 3
2 2 3 x

c
2 log 2  3 log 2
2 2 x 3
2 2 3 x

c
=
2 log 2 3 log 2
(54)
(55)
Ans. c
Explanation:
SI for 5 years = 1020 – 720
= 300
300
x2
5
SI for years
=
Principal
= Rs.120
= Rs.720 – Rs.120
= Rs.600
Ans. d
Explanation:
An injective function means one-one. In option (d), f (x)  -x for every value of x ,
we get a different value of f . Hence, it is injective.
(56)
Ans. b
Explanation:
Required no. of ways = 2×4×3×2×1=48
(57)
Ans. b
Explanation:
MITTAL COMMERCE CLASSES
6|Page
S 
(58)
a
3
3 3


1
1 r 1
2
3
Ans. d
Explanation:
Present value  A(1  i )  n  10000 / (1  0.025) 4
 10000 / (1.025) 4
 10000 / (1.1038)
 Rs.9059.50
(59)
Ans. b
Explanation:
We know that perpendicular distance between the line ax  by  c  0 and the point
(x1 , y1 ) is
ax1  by1  c
a 2  b2
Therefore, required distance
12(2)  5(1)  9
122  ( 5) 2
=
28
24  5  9

13 units
= 144  25
(60)
Ans. b
Explanation:
x  x  ...
f(x) =
 f(x) =
x  f (x)
On squaring both sides, we get
 f x 2  x  f x 
differentiation both sides
2f(x) f'(x) = 1+f'(x)
f'(x) [2f(x)–1]=1
f'(x)=
(61)
1
2 f ( x)  1
Ans. c
Explanation:
4
5
6
3
4
5
81
log 3 ( ) + log 3 ( ) + log 3 ( ) +-------------------+log 3 ( )
=
4 5
log 3 ( x
3 4
6
x5
x−−−−−−−
80
81
)
80
= log 3 27 = 3
MITTAL COMMERCE CLASSES
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(62)
Ans. c
Explanation:
Let us denote by x, the number of bags of fertilizers of grade I and by y, the number
of bags of fertilizers of grade II produced in a week. We are given that grade I
fertilizer requires 6 hours in plant A and grade II fertilizer requires 3 hours in plant A
and plant A has maximum of 120 hours available in a week. Thus 6x + 3y ≤ 120.
Similarly grade I fertilizer requires 4 hours in plant B and grade II fertilizer requires
10 hours in Plant B and Plant B has maximum of 180 hours available in a week.
Hence, we get the inequality 4x + 10y ≤ 180.
(63)
Ans. c
Explanation:
lim
n
=
(64)
n 2  n  6  3n 2  6
2n  5
1 3
2
Ans. b
Explanation:
E1 E2 E3 E4 E5
1
2
3
4
5
5 4  321
Total ways = 120
There is only 1 way to put all in directed envelopes.
So Remaining = 120 – 1 = 119
(65)
Ans. c
Explanation:
Equation of the line through the points (7, 5)
and (2, 9) is given by
y−5
x−7
=
9−5
2−7
⇒ 4x + 5y − 53 = 0
Equation of the line parallel to 4x + 5y − 53 = 0 is
4x + 5y + k = 0
It passes through (3, −4) we have 12 − 20 + k = 0
∵k=8
Thus the required line is 4x + 5y + 8 = 0
(66)
Ans. a
Explanation:
Income
Expenditure
100
75
120
82.5
MITTAL COMMERCE CLASSES
Saving
25
37.5
8|Page
12.5
x100 = 50%
25
His savings are increased by =
(67)
Ans. d
Explanation:
(a, a), (b, b), (c, c) ℇ R
So R is a reflexive relation
But (𝑎, 𝑏)ℇ R and (b, a) ∉ R
Thus, R is not a symmetric relation.
Also, (a, b), (b, c) ℇ R ⇒ (a, c) ∉ R
Hence R is not a transitive relation
(68)
Ans. b
Explanation:
The no. of ways
=
11

C6  7 C6  4 C0  7 C5  4 C1

= 462 – (7+84) = 371
(69)
(70)
Ans. d
Explanation:
2x + 3y = 17 → (i)
2x+2 − 3y+1 = 5
4.2x − 3. 3y = 5 → (ii)
From equations (i) and (ii)
2𝑥 = 8, 3y = 9
⇒ 𝑥 = 3 and 𝑦 = 2
Ans. d
Explanation:
exh  e x  0 
lim
 
h 0
h
0
2
2
Using D'L Hospital Rule
= lim e
( x h)2
h 0
=
(71)
2 xex
2 x  h 
2
Ans. a
Explanation:
Here A = 2000,
i
6
 0.005 , n = 24
100  12
Let Rs. P be the each payment.
 (1  i)n  1 
 (1  0.005) 24  1 
 (1.005) 24  1 

2000

P

P





i
0.005




 0.005 
2000  0.005
10
10
or P 
= Rs. 78.61
 P

24
1.1272  1 0.1272
(1.005)  1

(72)
Amount : A = P 
Ans. c
Explanation :
MITTAL COMMERCE CLASSES
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Since the cost curve is linear we consider cost curve as y=Ax+B where y is total
cost. Now for x=80, y=2,20,000. ∴ 2,20,000 = 80A+B…….(i)
and for x = 125; y=2,87,500 ∴ 2,87,500 = 125A+B………(ii)
Subtracting (i) from (ii) 45A=67,500 or A=1500
From (i) 2,20,000 – 1500 (80) = B or B =2,20,000-1,20,000=1,00,000
Thus equation of cost line is y = 1,500x+1,00,000.
For x=95, y=1,42,500+1,00,000=Rs. 2,42,500.
∴ Cost of 95 T.V. set will be Rs. 2,42,500.
(73)
(74)
Ans. d
Explanation:
By options putting the value n = 9
9c2 − 9 = 27
Ans. c
Explanation:
37, 39, ... 119
l = a + (n–1)d
119 = 37 + (n–1)(2)
n = 42
Sn =
(75)
n
a  l   42 37  119  3276
2
2
Ans: c
Explanation:
Let the no. of deer and peacocks are 𝑥 and 𝑦
𝑥 + 𝑦 = 80.......................(i)
4𝑥 + 2𝑦 = 200.......................(i)
By solving the eqn (i) and eqn (ii)
y = 60
(76)
Ans. c
(77)
Ans. b
(78)
Ans. c
Explanation:
X=
LCL  UCL L  UCL

M
2
2
UCL = 2m - L
(79)
Ans. b
Explanation:
2
We Know Q.D = 𝑆. 𝐷
Q.D.<S.D
(80)
3
Ans. c
Explanation : Average age of 10 students = 20 yrs
MITTAL COMMERCE CLASSES
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The sum of age of 10 students = 20 x 10 = 200 yrs
If two boys are increased
The total no of students = 10+2=12
And average increased by 4 yrs
Then new average = 20 + 4 = 24
The sum of age of 12 student = 24 x 12 = 288
The sum of age of two boys = 288 – 200 = 88
88
Average age of two boys =
= 44
2
(81)
Ans. b
Explanation:
n= 32, =5, x=80
x 2
2
 x 
=
n
2
x
 6.25
=
32

52
x2
(82)
= 1000
Ans. b
Explanation:
Assumed mean formula for arithmetic mean is
x
=
A
x  4
d
n
72
n
x 7
….(i) and
by (i) and (ii), we get
(3)
n …(ii)
72
3
 7
n
n
4n  72 7n  3

n
n
72  4n  7n  3
4
75 = 3n
n = 25

(83)
72
 6.88
25
Ans. a
Explanation:
Gm =
(84)
Arithmetic mean =
4
2  2
2
 2 3  ....2 n

1
n
 2 n1 / 2
Ans. b
Explanation:
Cov (X, Y)
=
1
1  n  n  
n

x
y

yi  
  xi 
 i i



n
n  i 1  i 1  
 i 1

MITTAL COMMERCE CLASSES
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=
=
(1/5)(110  (1/5)  15  36)
(1/5)(110  108)  (2/5)  0.4
(85)
Ans. a
(86)
Ans.c
(87)
Ans. a
Explanation:
bvu 
=
(88)
p
 byx
q
3
 1.2  1.8
2
Ans. c
2 3
1
Explanation : P(A1). P(A2 ) = x = = 𝑃(𝐴1⋂𝐴2 )
3
8
4
So, A1 and A2 are Independent but not mutually exclusive
(89)
Ans. c
Explanation : Event A: Person aged 50 years will remain alive after 20 years
Event B: Person aged 60 years will remain alive after 20 years
 P(A) 
5
95
 P(A  B) 

5
14
5
14

and P(B) 
6
14

5
6
6
86

6
14
31


14 14 49
(90)
Ans. a
Explanation:
x
300
–80
p
0.57
0.43
Expected value = 300×0.57–80×0.43 = 136.6
(91)
Ans. c
Explanation:
P A'B' 1  P A  B 

 5/8
P  B '
1  P B 
P(A'/B') =
(92)
Ans. d
(93)
Ans. c
Explanation:
5
np − npq =
1
2
3
3
𝑝 = ,𝑞 =
9
2
1 5
3
3
Distribution is ( + )
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12 | P a g e
(94)
Ans. b
Explanation:
1
p=
, n = 10000, m = np = 2
5000
p(x = 0) =
e−2 (2)0
0!
= e−2
(95)
Ans. c
(96)
Ans. c
(97)
Ans. d
Explanation : Here, n=10, N= 85, x = 9, s=4
S. E. (x) =
=
=
(98)
(99)
4
√10−1
4
√9
s
√n−1
N−n
x√N−1
85−10
x√ 85−1
75
4
x√84 = 3 x √0.893 = 1.26
Ans. b
Explanation : The index 1970 on base 1960 will be =
150 x 200
100
= 300
Ans. b
(100) Ans. b
Explanation:
Chain index number for
1993
:
1994
:
1995
:
1996
:
103  100
 103
100
103  105
 108.15
100
108.15  112
 121.13
100
121.13  108
 130.82
100
***
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