Continuous or not? If a curve is not continuous, then it

Continuous or not?
If a curve is not continuous, then it is discontinuous.
Decide whether each of the following is
continuous or not.
Explain your reasoning.
Continuous function because,
β€’ in theory, you could trace along the curve from left to
right without once having to lift your pencil.
β€’ There is a y-value for each π‘₯ ∈ 𝑅
This is not a continuous function because
β€’ if you were to attempt to trace the curve with your
pencil from left to right, you would have to lift your
pencil at β€œx=a” and then reposition your pencil on
the paper, and then also not be able to draw to
the right of β€œx = E”.
𝑓 π‘Ž π‘Žπ‘›π‘‘ 𝑓 𝐹 π‘‘π‘œ π‘›π‘œπ‘‘ 𝑒π‘₯𝑖𝑠𝑑
β€’ y-values do not exist for any x-value chosen.
𝑓 π‘₯ 𝑒π‘₯𝑖𝑠𝑑𝑠 π‘“π‘œπ‘Ÿ π‘₯ ∈ 𝑅
Condition #1 for a function to be continuous has been met.
This curve is continuous.
𝑓 π‘₯ π‘‘π‘œπ‘’π‘  π‘›π‘œπ‘‘ 𝑒π‘₯𝑖𝑠𝑑 π‘“π‘œπ‘Ÿ π‘₯ ∈ 𝑅
Condition #1 has not been met.
This curve is not continuous.
Infinite discontinuity
This function is not continuous
β€’ If you were to attempt to draw this function
from left to right, you would have to lift your
pencil at β€œx=a” reposition your pencil’s height
and then continue drawing the function out
to the right.
β€’ The limit of f(x) from the left does not
approach the same value as the limit of f(x)
from the right as β€œx approaches a”
This function is not continuous
β€’ If you were to attempt to draw this function from left to
right, you would have to lift your pencil at β€œx=3” and
reposition your pencil on the other side of the vertical
asymptote to continue drawing the function to the right.
β€’ The limits of f(x) from the left and the right approach infinity
which is not a specific value and therefor the limit of f(x) as
β€œx approaches 3” does not exist.
lim 𝑓 π‘₯ = +∞,
π‘₯β†’3
limβˆ’ 𝑓(π‘₯) β‰  lim+𝑓(π‘₯ ) ,
π‘₯β†’π‘Ž
π‘₯β†’π‘Ž
lim 𝑓(π‘₯ ) does not exist all π‘₯ ∈ 𝑅
π‘₯β†’π‘Ž
Condition #2 for a curve to be continuous has not been met.
This curve is not continuous.
lim 𝑓(π‘₯ ) does not exist for all π‘₯ ∈ 𝑅
π‘₯β†’π‘Ž
Condition #2 for a curve to be continuous has not been met.
This curve is not continuous.
This function is not continuous
β€’ If you were to attempt to draw this function from left to
right, you would have to lift your pencil at β€œx=a” reposition
your pencil’s height to plot (a, f(a) ) and lift your pencil again
and change its height again before being able to then
continue drawing the function out to the right.
β€’ The limit of f(x) as β€œx approaches a” exists, but this limit is
not equal to the at an instance value β€œf(a)”.
lim 𝑓 π‘₯ β‰  𝑓(π‘Ž) because b β‰ c and so this function is not continuous.
π‘₯β†’π‘Ž
Condition #3 has not been met.
Three algebraic conditions
for a function to be continuous.
All three conditions must be satisfied or met
in order for the function to be continuous.
1.
𝑓 π‘Ž 𝑒π‘₯𝑖𝑠𝑑𝑠 π‘“π‘œπ‘Ÿ π‘Žπ‘™π‘™ π‘₯ = π‘Ž,
π‘₯βˆˆπ‘…
2. lim 𝑓 π‘₯ 𝑒π‘₯𝑖𝑠𝑑𝑠 π‘“π‘œπ‘Ÿ π‘Žπ‘™π‘™ π‘₯ = π‘Ž,
π‘₯βˆˆπ‘…
π‘₯β†’π‘Ž
3.
lim 𝑓 π‘₯ = 𝑓(π‘Ž) ,
π‘₯β†’π‘Ž
π‘₯∈π‘