HOW TO PREPARE DIFFERENT CONCENTRATIONS OF GLUCOSE BAGS
DESIRED FINAL
CONCENTRATION
10%
12.5%
15%
17.5%
20%
25%
30%
35%
40%
50%
AMOUNT OF 10% GLUCOSE REQUIRED
AMOUNT OF 20% GLUCOSE REQUIRED
AMOUNT OF 50% GLUCOSE REQUIRED
TOTAL FINAL
VOLUME
PRE-PREPARED BAGS ARE COMMERCIALLY AVAILABLE AT THIS CONCENTRATION
487.5ml
N/A
32.5ml
520ml
437.5ml
N/A
62.5ml
500ml
422.5ml
N/A
97.5ml
520ml
PRE-PREPARED BAGS ARE COMMERCIALLY AVAILABLE AT THIS CONCENTRATION
N/A
425ml
85ml
510ml
N/A
340ml
170ml
510ml
N/A
250ml
250ml
500ml
N/A
170ml
340ml
510ml
PRE-PREPARED VIALS ARE COMMERCIALLY AVAILABLE AT THIS CONCENTRATION
HOW TO PREPARE DIFFERENT CONCENTRATIONS OF GLUCOSE BAGS
Calculation for making different glucose concentrations:
1. Use a grid like the one below and write the two concentrations of the glucose you are mixing in the column on the left. The highest available concentration
should be in cell A in the top left of the grid
2. Put the desired final concentration of glucose in the column in the middle
3. Write the difference between the number in cell A and the number in the middle column in cell D (follow the arrow)
4. Write the difference between the number in cell B and the number in the middle column in cell C (follow the arrow)
Concentration of glucose solutions to be mixed to
make the desired final concentration of glucose (put
highest value at top left)
Desired final concentration
50%
Number of parts (this is the difference between the
number in the left column and the middle column –
follow the arrows)
2.5
A
C
12.5%
10%
B
37.5
D
5. Calculate the volume of solution A required by dividing the number in cell C by the total number of parts (C+D) and multiply this by the total volume of your final
solution (you can choose this volume but it should not exceed 550mls as you will not be able to fit this in the bag of fluid)
In the example above = 2.5/40 x 520ml = 32.5mls of 50% glucose required
(50% glucose = 50grams in 100ml = 0.5g in 1ml so there are 16.25grams in 32.5ml of 50% glucose)
6. Calculate the volume of solution B required by dividing the number in cell D by the total number of parts (C+D) and multiply this by the total volume of your final
solution
In the example above = 37.5/40 x 520ml = 487.5mls of 10% glucose required
(10% glucose = 10g in 100ml = 0.1mg in 1ml so there are 48.75grams in 487.5ml)
7. Final check = the final mixed solution will have 48.75grams + 16.25 grams = 65grams in 520ml = 12.5grams in 100ml = 12.5% glucose