Name ________________________________________ Date __________________ Class__________________ LESSON 2-5 Reading Strategies Building Vocabulary When you look into a mirror, you see your reflect ion. You see your exact, identical self. Similarly, when you use the Reflexive Property of Equality, a quantity is equal to its exact, identical self. 5=5 2 x + 3 = 2x + 3 m∠C = m∠C The two halves of a football field are symmetrical to each other. When two football teams change sides, the second side of the field is the same as the first side. In the same way, the Symmetric Property of Equality allows equal quantities to be written on either side of the equal sign. If x = 2, then 2 = x. If m∠A = 40°, then 40° = m∠A. Just as the cars on a train link the engine to the caboose, the Transitive Property of Equality links equal quantities to each other. If two expressions are equal to the same thing, they are equal to each other. If AB = 8 and 8 = CD, then AB = CD. AB = CD Sometimes, at school, a substitute teacher may replace your teacher for a day. Similarly, the Substitution Property of Equality allows equal expressions to be used interchangeably. If b = 5 and a + b = 9, then a + 5 = 9. Which properties do the following situations describe? 1. butterfly wings _________________________________ 2. removing the quarterback of the football team and replacing him with another quarterback _________________________________ 3. the reflection of clouds on a still pond _________________________________ 4. There are four quarters in one dollar and ten dimes in one dollar, so four quarters have the same value as ten dimes. _________________________________ Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 2-42 Holt McDougal Geometry Reading Strategies Statements 1. Symmetric Property of Equality Reasons 2. Substitution Property of Equality 1. a. ∠HKJ is a straight angle. 1. Given 3. Reflexive Property of Equality 2. m∠HKJ = 180° 2. b. Def. of straright ∠ 4. Transitive Property of Equality JJG 3. c. KI bisects ∠HKJ 3. Given 4. ∠IKJ ≅ ∠IKH 4. Def. of ∠ bisector 5. m∠IKJ = m∠IKH 5. Def. of ≅ 6. d. m∠IKJ + m∠IKH = m∠HKJ 6. ∠ Add. Post. 7. 2m∠IKJ = 180° 7. e. Subst. (Steps 2, 5, 6) 8. m∠IKJ = 90° 8. Div. Prop. of = 9. ∠IKJ is a right angle. 9. f. Def. of right ∠ 2-6 GEOMETRIC PROOF Practice A 1. B 2. A 3. B 4. C 5. two-column 6. Statements 1. a. ∠1 and ∠2 are straight angles. Reasons Practice C 1. Given 1. 2. m∠1 = 180°, m∠2 = 180° 2. b. Def. of straight ∠ 3. m∠1 = m∠2 3. Subst. Prop. of = 4. c. ∠1 ≅ ∠2 4. Def. of ≅ ∠s Statements 7. Statements Reasons 1. ∠1 and ∠2 form a linear pair, and ∠3 and ∠4 form a linear pair. 2. ∠1 and ∠2 are supplementary, and ∠3 and ∠4 are supplementary. 1. a. Given Reasons 1. m∠2 + m∠3 + m∠4 = 180° 1. Given 2. ∠1 and ∠2 are supplementary. 2. Linear Pair Thm. 3. m∠1 + m∠2 = 180° 3. Def. of supp. ∠s 4. m∠1 + m∠2 = m∠2 + m∠3 m∠4 4. Subst. Prop. of = 5. m∠1 = m∠3 + m∠4 5. Subtr. Prop. of = 2. b. Linear Pair Thm. 3. c. m∠1 + m∠2 = 180°, and m∠3 + m∠4 = 180° 3. Def. of supp. 4. m∠1 + m∠2 + m∠3 + m∠4 = 360° 4. d. Add. Prop. of = 2. Possible answer: Statements ∠s Practice B 1. Given ∠s 2. Def. of mdpt. 3. Def. of ≅ segments Reasons 1. ∠1 is a right angle. 1. Given 2. ∠1 and ∠2, ∠1 and ∠4, ∠2 and ∠3 are supplementary. 2. Linear Pair Thm. 3. ∠1 ≅ ∠3 3. Congruent Supps. Thm. 4. ∠3 is a right angle. 4. Rt. ∠ ≅ Thm. 5. Def. of supp. ∠s 4. Seg. Add. Post. 5. Subst. 5. m∠1 + m∠2 = 180°, m∠1 + m∠4 = 180° 6. Given 7. Mult. Prop. of = 6. m∠1 = 90° 6. Def. of rt. ∠ 7. 90° + m∠2 = 180°, 90° + m∠4 = 180° 7. Subst. 8. m∠2 = 90°, m∠4 = 90° 8. Subtr. Prop. of = 9. ∠2 and ∠4 are right angles. 9. Def. of rt. ∠ 8. Subst. Prop. of = 9. Def. of ≅ segments 10. Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. A17 Holt McDougal Geometry
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