SUPPLEMENTARY MATERIAL Solution of the complete Curtiss-Bird model for polymeric liquids subjected to simple shear flow Pavlos S. Stephanou,* and Martin Kröger Department of Materials, Polymer Physics, ETH Zurich, CH-8093 Zurich, Switzerland *Author to whom correspondence should be addressed; electronic mail: [email protected] A. Real basis of the spherical harmonics We define the real basis of the spherical harmonics (RSH) ylm based on the spherical harmonics Ylm as 1 * 2 Ylm Ylm if m>0 ylm Yl 0 if m=0 . 1 Ylm* Ylm if m<0 i 2 Note that here the spherical harmonics are defined without the Ylm u Alm Pl m cos eim , Alm (A1) 1 m factor: 2l 1 l m ! m where Pl x are the associated 4 l m ! Legendre polynomials and the asterisk denotes a conjugation (Ref. 1, p. 788). These definitions are identical with the following ones: 1 yl m 2 Al m Pl cos m m yl 0 Yl 0 . yl , m 2 Al , m Pl m (A2) sin m The RSH can be shown to obey the following orthogonality relations: duy y l m . (A3) lm As it will be made evident in Appendix B we need to consider the rotational operator defined as L u . u (A4) For the action of the rotational operator on the RSH we obtain the following: Lz ylm 1 myl , m m L y ylm Lx ylm , for m 1 alm yl , m1 alm yl , m1 1 alm yl ,m1 alm yl ,m1 2 1 2 m (A5a) whereas for m 1 1 L y yl , 1 u al1 yl , 2 ; 2 1 L y yl 0 al 0 yl1 ; 2 1 L y yl1 u al1 yl 2 2al1 yl 0 ; 2 where alm l Lx yl , 1 u 1 2 2al1 yl 0 al1 yl 2 1 al 0 yl , 1 2 1 Lx yl1 u al1 yl , 2 2 Lx yl 0 , (A5b) m l m 1 (also note that al , m alm ). The Laplacian is given as L L ylm L2 ylm l l 1 ylm . (A6) Finally, the following forth-rank matrix needs to be defined for Section B. Blm duylm u uz u y Ly y u u y2 Lz y u . 2 (A7) B. Methodology to obtain the RSH expansion of the single-link distribution function We consider the steady-state limit of Eq. (1) which we rewrite as: 2 f , u 3 (B1) N 2 f , u Γf , u κ : uu 0 , 2 u u u 4 1 f , u f , u , Γ δ uu κ u with κ κ , normalization 4 1 where 1 ds duf , u 0 and vanishing boundary conditions at chain ends for f , u . We 0 next consider the following expansion in spherical harmonics with an upper cut-off for the spherical harmonics index l equal to L: L l f , u alm cos blm sin ylm u . (B2) l 0 m l 0 where are yet unknown. By first considering normalization and the boundary conditions Eq. (B2) simplifies to: L l 1 f , u b00 sin blm sin ylm u . (B3) 2 0 l 1 m l 0 even Our next step is to use expansion (B3) in eq. (B1) to obtain: 1 2 L b sin 1 00 0 even l 2 b sin 1 l 1 m l 0 2 lm Γ u 3 N 2l l 1 ylm u Γylm u κ : uu 0 u 4 We then multiply with sin ynp u and integrate over u and to get 1 2 L l 1 b sin 1 duy 0 even 2 00 0 1 y duynp np 00 . (B4) Γy00 u 2 blm sin sin 1 N 2l l 1 duynp u ylm u , (B5) l 1 m l 0 0 duynp u 3 Γylm u sin duynp u κ : uu 0 u 4 0 1 or by using 3 Γylm u duynp u L u κ uylm u u , duylm u L u κ uynp u WiBnplm duynp u (B6) then, 1 , even 2 b00 1 n0 p 0 WiBnp 00 2 L l 1 3 2 1 1 N 2 n n 1 bnp Wi blm Bnplm 1 1 Wi duynp u xu y 0 2 2 2 l 1 ml 4 . (B7) Note that already in the last equation in Eq. (B6) and in Eq. (B7) we have specified our treatment to the case of shear flow. Now by taking cases separately we find that b00 0, and bnp 0, even,n, p . For the rest, L l b A l 1 m l lm nplm , for odd Cnp Anplm 1 N 2 n n 1 nl mp 1 nl mp WiBnplm , 2 Cnp 6 Wi (B8) 1 n 2 p 2 15 where nl is Kronecker's delta (if n=l nl 1 , otherwise nl 0 ). By solving this we actually find that for odd l then blm 0 , and by making a choice for the upper cut-off of the spherical harmonics, L we may obtain the expansion, with regards to the dimensionless shear rate Wi, up to Wi L / 2 . Without further ado we give here the final expression up to fourth order in Wi obtained using Mathematica: 4 1 4 f , u 4Wi 3 4Wi 4 1 5 3 5 g1 y2,2 4Wi 2 y20 y22 g3 y40 y44 1 4Wi g 2 15 15 21 7 7 3 2 1 7 5 5 3 35 g 5 y4 4 g 6 y4 2 5 g 7 y6 2 y6 6 g 4 y2 2 15 49 539 286 21 11 26 2 3 2 30 3 15 5 g8 y20 g9 y22 g10 y42 g11 y40 g12 y44 15 3773 147 539 1618617 231231 g13 1 175 1 15 1 35 y60 y64 g14 y62 5 y66 121 91 7 286 11 234 21 15 6 105 75 g15 y80 y84 21 y88 O Wi 5 13 187 2431 143 17 ,(B8) where 6 sin 6 sin 6 sin ; g 2 ; g 3 2 K2 K2 K2 K4 1 1 1 g1 odd odd odd 6 12 K 2 23K 4 sin 6 2 K 2 K 4 sin ; g 5 3 K2 K4 K 22 K 42 1 1 g 4 odd odd 6 10 K 2 11K 4 sin 6 sin ; g 7 2 2 K2 K4 1 1 K 2 K 4 K 6 g 6 odd odd 6 50 K 187 K 2 K 4 253K sin K 24 K 42 1 g 8 2 2 2 4 odd 2 2 6 70 K 2 71K 2 K 4 69 K 4 sin 6 4 K 2 3K 4 sin g 9 ; g 10 4 2 K2 K4 K 22 K 43 1 1 odd odd 2 6 48020 K K 4 17550 K K 6 18447 K 2 K 4 K 6 72358 K 4 K 6 sin g11 K 23 K 43 K 6 1 2 2 2 2 odd 5 2 2 2 6 113876 K 2 K 4 307138K 2 K 6 190619 K 2 K 4 K 6 72358K 4 K 6 sin g12 ; K 23 K 43 K 6 1 odd 6 49 K 2 K 4 50 K 2 K 6 55K 4 K 6 sin ; K 22 K 42 K 62 1 g13 odd 6 3K 2 K 4 2 K 2 K 6 K 4 K 6 sin 6 sin ; g 15 2 2 2 K2 K4 K6 1 1 K 2 K 4 K 6 K 8 g14 odd odd , (B9) where we have used the shorthand notation K j 1 N 2 j j 1 . 2 It would be instructive to check whether we obtain eq. (19.5-17) in Ref. 4 when 0 ; up to third order we have the simplifications g1 34 E2 , g2 g3 161 E4 , and 7 1 1 g4 967 E6 , g5 160 E6 , g6 160 E6 , g7 480 E6 where E2n are the even Euler polynomials (see Ref. 2 p. 2024, and Ref. 3 p., 805) defined via, E2 n 1 4 2n ! n 1 odd sin 2 n 1 . (B10) . (B11) The first three are expressed as [Ref. 3 p., 809] E2 1 E4 2 3 4 E6 3 5 3 3 5 6 With this in mind we obtain for 0 6 1 Wi 2 f , u 1 y2,2 u 2 3 4 1 3Wi 4 15 4 15 3 Wi 3 1 5 5 y y y y 3 5 3 3 5 6 , 20 22 40 44 7 3 21 120 15 7 (B12) 10 3 15 3 5 7 35 y4 2 y62 5 y6 6 y 2 2 5 y4 4 7 77 11 26 286 7 which is the same as (19.5-17) in Ref. 4 (the third order term given in Eq. (7.18) in Ref. 2) in the case of shear flow. C. Results of the BD simulations In this section we provide the results of the BD simulations for the material functions without making them dimensionless with the zero-shear-rate values. This is done for the following two reasons: a) the fidelity of our BD algorithm is thus verified, and b) the capability of the theoretical results, Eq. (6) in the main text, to capture both the zero-shearrate values at Wi=0 and the downturn at larger Wi is also verified. This comparison is provided in Figs. S1-S4. 7 FIG. S1: Predictions for the shear viscosity (a), first (b) and second viscometrc function (c) when 0 and N 0.5 . FIG. S2: Predictions for the shear viscosity; parameter values same as in Fig. 1. 8 FIG. S3: Predictions for the first viscometric function; parameter values same as in Fig. 2. FIG. S4: Predictions for the second viscometric function; parameter values same as in Fig. 3. 9 D. Thermodynamic admissibility of the complete CB model Here we provide the GENERIC framework5-7 for the complete CB model. It actually stands as an extension of the GENERIC framework for the simplified CB model (with 0 ) provided by Öttinger [Ref. 7, Section 4.3.2]. Concerning the total energy E, total entropy S, and the Poisson matrix L they need not be modified and we immediately adopt expressions (4.141), (4.142), and (4.145 to 6), respectively. Adopting the T factorization for the friction matrix proposed by Edwards,8 M f CM DM CM , we here consider 0 0 0 0 0 CM 0 v 0 0 0 0 0 0 T 0 , CM 0 0 0 1 0 0 v 0 0 0 0 0 , 0 1 (D1) where XT is the transpose of X. Here v is the velocity gradient tensor. This particular T form for C M , and thus CM , is the one dictated by the degeneracy requirement CMT E x 0 . Next we make the choice 0 0 0 2 I CB DM 0 0 0 A 0 A , 0 0 0 M f ,44 0 0 (D2) which leads to the following form for the friction matrix (note that we use Einstein’s implicit summation convention for repeated Greek indices) 10 0 0 0 0 A 0 2 I CB I CB . Mf 1 0 I CB I CB v A 2 0 A v A M f ,44 (D3) Here 1 I CB 3 nk BT 2 N 1 d du f u, , t uuuu , 2 0 (D4) M f ,44 , u, , u , (D5) 2 1 f , u N f , u u u nkB N u u 1 A 1 N 2 1 f u, , t u u u , u (D6) Expression (D4) is simply eq. (4.150) of Ref. 7, (D5) is a special case of eq. (8.169) of Ref. 7 when s 2 s 1 2 and x s u s u x 2 s N 2 I , whereas expression (D6) is proposed here for the first time and is needed to obtain the extra terms in the stress tensor missing from (4.151) of Ref. 7. Using the above the evolution equation for the single-link distribution function and the stress tensor expression reads f 1 2 N 2 v f κ I uu uf f f, t u 2 u u (D7) and 1 1 τ nk BTN 1 d d 2uf u, , t I 3uu N 2 1 d d 2uf u, , t I 3uu , 0 0 1 3 κ : 1 d du f u, , t uuuu 0 (D8) 11 which is the same as Eqs. (19.3-26) of Bird et al. (for a strictly monodisperse system) and eq. (19.4-18), respectively4. Finally, requiring that DM is positive semi-definite (a property inherited to Mf as well) requires that the two averages above have to be non-negative or that 0 1 and 0 . References 1. G. B. Arfken, and H. J. Weber, Mathematical Methods for Physicists, 6th Ed., Elsevier Academic Press, (2005) 2. C. F. Curtiss and R. B. Bird, J. Chem. Phys., 74, 2016 (1981). 3. M. Abramowitz, and I. A. Stegan, Handbook of Mathematical Functions with Formulas, Graphs, and Mathematical Tables; 9th ed. (Dover Publications, 1965). 4. R. B. Bird, R. C. Armstrong, and O. Hassager, Dynamics of Polymeric Liquids; Vol. 2, Kinetic Theory, 2nd ed. (John Wiley & Sons, New York, 1987). 5. M. Grmela, and H. C. Öttinger, Phys. Rev. E, 56, 6620 (1997) 6. H. C. Öttinger, and M. Grmela, Phys. Rev. E, 56, 6633 (1997) 7. H. C. Öttinger, Beyond Equilibrium Thermodynamics (Wiley-Interscience, 2005). 8. B. J. Edwards, J. Non-Equilib. Thermodyn., 23, 301 (1998). 12
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