SWBAT: Solve Consecutive Integer Word Problems by Factoring Quadratic Equations B D -40 -5 8 3 π₯ +3 π₯= π π(π + π) = ππ ππ +ππ = ππ ππ + ππ β ππ = 0 π+π πβπ =π π+π =π π = βπ Reject πβπ =π π=π SWBAT: Solve Consecutive Integer Word Problems by Factoring Quadratic Equations Homework SWBAT: Equations Solve Consecutive Integer Word Problems by Factoring Quadratic SWBAT: Equations Solve Consecutive Integer Word Problems by Factoring Quadratic SWBAT: Equations Solve Consecutive Integer Word Problems by Factoring Quadratic First x Second x + 1 -56 -7 8 1 πππππ × πΊπππππ = ππ π(π + π) = ππ ππ +ππ = ππ ππ + ππ β ππ = 0 π+π πβπ =π π+π =π πβπ =π π = βπ π=π x = -8 x=7 First Second x + 1 = -7 x + 1 = 8 SWBAT: Equations Solve Consecutive Integer Word Problems by Factoring Quadratic First x Second x + 2 -48 -6 8 2 πππππ × πΊπππππ = ππ π(π + π) = ππ ππ +ππ = ππ ππ + ππ β ππ = 0 π+π πβπ =π π+π =π πβπ =π π = βπ π=π x = -8 x=6 First Second x + 2 = -6 x + 2 = 8 SWBAT: Equations Solve Consecutive Integer Word Problems by Factoring Quadratic First x Second x + 1 F S x=0 x=5 x+1=1 x+1=6 π=π π β πΊ = π πππ β π π(π + π) = π(ππ + π) β π ππ + ππ = ππ + π β π ππ + ππ = ππ βππ = βππ 0 ππ β ππ = π -5 0 π πβπ =π -5 πβπ =π π=π SWBAT: Write a Quadratic Equation and Solve. First x Second x + 2 F S x = -1 x=3 x+2=1 x+2=5 π β πΊ = π πππ β π π(π + π) = π(ππ + π) β π ππ +ππ = ππ + π β π ππ +ππ = ππ + π βππ β π = βππ -3 ππ βππ β π = π π+π πβπ =π π+π =π πβπ =π π = βπ π=π -3 -3 1 -2 SWBAT: Write a Quadratic Equation and Solve. First x Second x + 1 x=4 F x = -2 S x + 1 = -1 x + 1 = 5 π β πΊ = π πΊπππππ + π π π+π =π π +π +π ππ + ππ = ππ + π + π ππ +ππ = ππ + π βππ β π = βππ β π ππ βππ β π = π π+π πβπ =π π+π =π πβπ =π π = βπ π=π -8 2 -4 -2 SWBAT: Write a Quadratic Equation and Solve. Example 5: Find three consecutive odd integers such that the product of the first and third is one more than four times the second. πΉπππ π‘ π₯ ππππππ Third π₯ + 2 π₯ + 4 F S T x = -3 x=3 x + 2 = -1 x+2=5 x+4= 1 x+4=7 π β π» = π πΊπππππ + π π π+π =π π +π +π ππ +ππ = ππ + π + π ππ +ππ = ππ + π βππ β π = βππ βπ ππ βπ = π π+π πβπ =π π+π =π πβπ =π π = βπ π=π ππ β π = π SWBAT: Write a Quadratic Equation and Solve. Practice: Solve. Find three consecutive integers such that the product of the first and second is 2 more than three times the third. πΉπππ π‘ ππππππ Third F x = -2 S x + 1 = -1 T x+2= 0 π β πΊ = π π»ππππ + π π π+π =π π +π +π π₯ +1 π π + ππ = ππ + π + π π₯ +2 π π +ππ = ππ + π x=4 βππ β π = βππ βπ x+1=5 x+2=6 ππ βππ β π = π 2 -8-4 -2 π+π πβπ =π π+π =π πβπ =π π = βπ π=π π₯ SWBAT: Write a Quadratic Equation and Solve. Homework Changes The product of two even consecutive integers is 120. Find the integers 1. The product of two consecutive integers is one less than their sum. Find the integers. 3. SWBAT: Write a Quadratic Equation and Solve. Challenge SWBAT: Write a Quadratic Equation and Solve. SWBAT: Write a Quadratic Equation and Solve. Exit Ticket π πππππ ππ ππ ππ π πΉπππ π‘ π₯ ππππππ Third π₯ + 2 π₯ + 4 = π»ππππ + ππ = π + π + ππ = π + ππ = ππ = ππ
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