6.4.3 Lagrange's Theorem
Theorem 6.19: Let H be a subgroup of
the group G. Then {gH|gG} and
{Hg|gG} have the same cardinal
number
Proof:Let S={Hg|gG} and T={gH|gG}
: S→T, (Ha)=a-1H。
(1) is a function.
for Ha=Hb, a-1H?=b-1H
[a][b] iff [a]∩[b]=
(2) is one-to-one。
For Ha,Hb,if HaHb,then (Ha)=a-1H?(Hb)
=b-1H
(3)Onto
Definition 17:Let H is a subgroup of the
group G. The number of all right
cosets(left cofets) of H is called index of H
in G.
[E;+] is a subgroup of [Z;+].
E’s index??
Theorem 6.20: Let G be a finite group and
let H be a subgroup of G. Then |G| is a
multiple of |H|.
Example: Let G be a finite group and let
the order of a in G be n. Then n| |G|.
Example: Let G be a finite group and
|G|=p. If p is prime, then G is a cyclic
group.
a b a b
G {
0, a, b, c, d R}
|
c d c d
a b a b
|
H {
0, a, b, c, d Q}
c d c d
2 0
2a
0 1 H { c
2
H
0
2b
| a, b, c, d Q}
d
0 2a b
{
| a, b, c, d Q}
1 2c d
6.4.4 Normal subgroups
Definition 18:A subgroup H of a group is
a normal subgroup if gH=Hg for gG.
Example: Any subgroups of Abelian group
are normal subgroups
S3={e,1, 2, 3, 4, 5} :
H1={e, 1}; H2={e, 2}; H3={e, 3}; H4={e,
4, 5} are subgroups of S3.
H4 is a normal subgroup
(1) If H is a normal subgroup of G, then
Hg=gH for gG
(2)H is a subgroup of G.
(3)Hg=gH, it does not imply hg=gh.
(4) If Hg=gH, then there exists h'H such
that hg=gh' for hH
Theorem 6.21: Let H be a subgroup of G.
H is a normal subgroup of G iff g-1hgH
for gG and hH.
Exercise: P362 21, 22,23, 26,28,33,34
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