Chapter 7 Practice Exam Nicole, Valerie, Nat, Maryalice

7.1- Nicole
7.2- Valerie, Maryalice
7.3- Nathaniel (ME!)
7.4- Yasmeen
Nicole Stevenson
7.1 Review
#1:
Question:
Answer:
#2
Question:
Answer:
#3
Question:
Answer:
7.2 Review
Valerie
1. Question:
Find the area of the shaded region analytically: (refer to page 395 #5 for graph)
Solution:
𝐡
∫𝐴 𝑓(π‘₯) βˆ’ 𝑔(π‘₯)𝑑π‘₯
4 3
π‘₯
3
1
βˆ’ 5 π‘₯5
4
2
2
βˆ«βˆ’2 2π‘₯ 2 𝑑π‘₯ βˆ’ βˆ«βˆ’2 π‘₯ 4 βˆ’ 2π‘₯ 2 𝑑π‘₯
1
4
∫ 2π‘₯ 2 βˆ’ π‘₯ 4 + 2π‘₯ 2 𝑑π‘₯
1
[3 (2)3 βˆ’ 5 (2)5 ] βˆ’ [3 (βˆ’2)3 βˆ’ 5 (βˆ’2)5 ] =
∫ 4π‘₯ 2 βˆ’ π‘₯ 4
128
15
2. Question:
Find the area of the regions enclosed by the lines and curves: 𝑦 = π‘₯ 2 βˆ’ 2 π‘Žπ‘›π‘‘ 𝑦 = 2
Solution:
π‘₯2 βˆ’ 2 = 2
π‘₯2 βˆ’ 4 = 0
2
π‘₯ = 2, βˆ’2 First; Find the x-intercepts
2
∫ 2 βˆ’ π‘₯ 2 + 2𝑑π‘₯
βˆ’2
∫ 4 βˆ’ π‘₯ 2 𝑑π‘₯ = 4π‘₯ βˆ’
βˆ’2
π‘₯3
3
[4(2) βˆ’
(2)3
(βˆ’2)3
32
] βˆ’ [4(βˆ’2) βˆ’
]=
3
3
3
3. Question:
Find the area of the regions enclosed by the lines and curves: π‘₯ + 𝑦 2 = 0 π‘Žπ‘›π‘‘ π‘₯ + 3𝑦 2 = 2
Solution:
π‘₯ = βˆ’π‘¦ 2
π‘₯ = 2 βˆ’ 3𝑦 2 First; Solve equations for x
βˆ’π‘¦ 2 = 2 βˆ’ 3𝑦 2
1
𝑦 = 1, βˆ’1 Next; Set both equal and solve for y
βˆ«βˆ’1[(2 βˆ’ 3𝑦 2 ) βˆ’ (βˆ’π‘¦ 2 )]𝑑𝑦
1
2
βˆ«βˆ’1 2 βˆ’ 2𝑦 2 𝑑𝑦 = 2𝑦 βˆ’ 3 𝑦 3
2
2
8
[2(1) βˆ’ 3 (1)3 ] βˆ’ [2(βˆ’1) βˆ’ 3 (βˆ’1)3 ] = 3
7.2 Two
Maryalice Weed
AP Calculus
Period 6
Section 7.2 Review
1. Find the area of the region R in the first quadrant that is bounded above by 𝑦 = √π‘₯ and below
by the
x-axis and the line 𝑦 = π‘₯ βˆ’ 2
Solution: 10/3
2. Find the area between the x-axis and the function 𝑦 = √9 βˆ’ π‘₯ 2 over the interval [-3, 3]
Solution: 5/6 or 9πœ‹/2
3. Find the area of the region first quadrant bounded by the x-axis and the graphs of √π‘₯ βˆ’ 2 and
𝑦 = π‘₯ βˆ’ 10 by subtracting the area of the triangular region from the area under the square root
curve.
Solution: 19.88
7.3 Nathaniel Kreiman
Question:
Find the volume of the solid that lies between the planes perpendicular to the x-axis at x=0 and x=4. The
cross sections perpendicular to the axis on the interval [0,4] are squares whose diagonals run from
𝑦 = βˆ’βˆšπ‘₯ to 𝑦 = √π‘₯
Solution:
Question:
Find the volume of the solid created by rotating the given region about the x-axis. The region is bounded
by π‘₯ + 2𝑦 = 2, the x-axis and the y-axis.
Solution:
Question:
Find the volume of the solid generated by revolving the region bounded by the lines and curves about
the x-axis. 𝑦 = π‘₯ 2 + 1, 𝑦 = π‘₯ + 3.
Solution: (Following two pages.)
7.4
Question:
Solution:
Question:
Solution:
Question:
Solution: