7.1- Nicole 7.2- Valerie, Maryalice 7.3- Nathaniel (ME!) 7.4- Yasmeen Nicole Stevenson 7.1 Review #1: Question: Answer: #2 Question: Answer: #3 Question: Answer: 7.2 Review Valerie 1. Question: Find the area of the shaded region analytically: (refer to page 395 #5 for graph) Solution: π΅ β«π΄ π(π₯) β π(π₯)ππ₯ 4 3 π₯ 3 1 β 5 π₯5 4 2 2 β«β2 2π₯ 2 ππ₯ β β«β2 π₯ 4 β 2π₯ 2 ππ₯ 1 4 β« 2π₯ 2 β π₯ 4 + 2π₯ 2 ππ₯ 1 [3 (2)3 β 5 (2)5 ] β [3 (β2)3 β 5 (β2)5 ] = β« 4π₯ 2 β π₯ 4 128 15 2. Question: Find the area of the regions enclosed by the lines and curves: π¦ = π₯ 2 β 2 πππ π¦ = 2 Solution: π₯2 β 2 = 2 π₯2 β 4 = 0 2 π₯ = 2, β2 First; Find the x-intercepts 2 β« 2 β π₯ 2 + 2ππ₯ β2 β« 4 β π₯ 2 ππ₯ = 4π₯ β β2 π₯3 3 [4(2) β (2)3 (β2)3 32 ] β [4(β2) β ]= 3 3 3 3. Question: Find the area of the regions enclosed by the lines and curves: π₯ + π¦ 2 = 0 πππ π₯ + 3π¦ 2 = 2 Solution: π₯ = βπ¦ 2 π₯ = 2 β 3π¦ 2 First; Solve equations for x βπ¦ 2 = 2 β 3π¦ 2 1 π¦ = 1, β1 Next; Set both equal and solve for y β«β1[(2 β 3π¦ 2 ) β (βπ¦ 2 )]ππ¦ 1 2 β«β1 2 β 2π¦ 2 ππ¦ = 2π¦ β 3 π¦ 3 2 2 8 [2(1) β 3 (1)3 ] β [2(β1) β 3 (β1)3 ] = 3 7.2 Two Maryalice Weed AP Calculus Period 6 Section 7.2 Review 1. Find the area of the region R in the first quadrant that is bounded above by π¦ = βπ₯ and below by the x-axis and the line π¦ = π₯ β 2 Solution: 10/3 2. Find the area between the x-axis and the function π¦ = β9 β π₯ 2 over the interval [-3, 3] Solution: 5/6 or 9π/2 3. Find the area of the region first quadrant bounded by the x-axis and the graphs of βπ₯ β 2 and π¦ = π₯ β 10 by subtracting the area of the triangular region from the area under the square root curve. Solution: 19.88 7.3 Nathaniel Kreiman Question: Find the volume of the solid that lies between the planes perpendicular to the x-axis at x=0 and x=4. The cross sections perpendicular to the axis on the interval [0,4] are squares whose diagonals run from π¦ = ββπ₯ to π¦ = βπ₯ Solution: Question: Find the volume of the solid created by rotating the given region about the x-axis. The region is bounded by π₯ + 2π¦ = 2, the x-axis and the y-axis. Solution: Question: Find the volume of the solid generated by revolving the region bounded by the lines and curves about the x-axis. π¦ = π₯ 2 + 1, π¦ = π₯ + 3. Solution: (Following two pages.) 7.4 Question: Solution: Question: Solution: Question: Solution:
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