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PHY 231 HW11 More constant acceleration and circular motio
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HW11 More constant acceleration and circular motio Begin Date: 4/10/2015 12:00:00 PM -- Due Date: 4/17/2015 11:59:00 PM End Date:
4/17/2015 11:59:00 PM
Problem 1:
Full solution not currently available at this time.
A ball is thrown from a rooftop with an initial downward velocity of
magnitude vo = 0.2 m/s. The rooftop is a distance above the ground, h
= 11 m. In this problem use a coordinate system in which upwards is
positive.
Variable Name
v0
h
Min
0.1
10
Max
7
50
Step
0.1
1
Sample Value
0.2
11
Part (a) Find the vertical component of the velocity, vfy, in meters per second, with which the ball hits the ground.
Correct Algorithm: vfy = -(v0^2+19.6*h)^0.5
Choice Info:
vfy = -(0.2^2+19.6*11)^0.5
vfy = -(0.2^2+19.6*11)^0.5
vfy = -14.685
Buffer + or - 0.44055
Hints:
4 hints available
• Gravitational acceleration, g, acts downward.
• Only one kinematic equation contains all the given
information according to the given coordinate
system. You don't know the time it took to reach the
final velocity.
• The displacement is negative.
• The initial velocity is not zero.
Part (b) If we wanted the ball's final speed to be exactly 27.3 m/s, from what height, hnew (in meters), would we need to
throw it with the same initial velocity?
Correct Algorithm: hnew = (745.3-v0^2)/19.6
Choice Info:
hnew = (745.3-0.2^2)/19.6
hnew = (745.3-0.2^2)/19.6
hnew = 38.023
Buffer + or - 1.14069
Hints:
2 hints available
• Height is the magnitude of the displacement. The
displacement is negative.
• Rearrange your expression from Part (a) and solve
for height.
Part (c) If the height is fixed at 11 m, but we wanted the ball's final speed to be 32.7 m/s, what would the vertical
component of the initial velocity viy need to be, in meters per second?
Correct Algorithm: viy = -(1069.3-19.6*h)^0.5
Choice Info:
viy = -(1069.3-19.6*11)^0.5
viy = -(1069.3-19.6*11)^0.5
viy = -29.218
Buffer + or - 0.87654
Hints:
3 hints available
• When you take a square root you must choose the
positive or negative solution.
• The final velocity is down.
• Rearrange your previous solution solving for vi.
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Problem 2:
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Problem 3:
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Problem 4:
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Problem 5:
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Problem 6:
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Problem 7:
Problem 8:
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Problem 9:
Problem 10:
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Problem 11:
Problem 12:
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Problem 13:
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Problem 14:
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Problem 15:
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