Trapezoid Convex Proof Definition: A quadrilateral ο¨ABCD is a trapezoid if π΄π΅ β₯ πΆπ· or π΄π· β₯ π΅πΆ. Statement: A trapezoid is convex. Proof: [WLOG, assume that π΄π΅ β₯ πΆπ·. We need to prove that each point is in the interior of the angle formed by the other three vertices. Since the proof is similar for each vertex, we will prove that D is in the interior of β ABC, with the understanding that the same proof can be used for the other D three vertices.] [To show that D is in the interior of β ABC, we have to C show that C and D on the same side of π΄π΅ and A and D on A the same side of π΅πΆ.] C and D on the same side of π¨π©: B 1. Suppose C and D are on opposite sides of π΄π΅. 2. Then πΆπ· intersects π΄π΅. 3. This is a contradiction. A and D on the same side of π©πͺ: 4. Suppose that A, D are on opposite sides of π΅πΆ. D 5. Let E be the point of intersection between π΄π· and π΅πΆ. C 6. π΄π· and π΅πΆ cannot intersect. B 7. E * B * C or B * C * E. Case 1: Suppose that E * B * C. [See second figure.] E 8. Note that because B is between E and C, then B is an interior A point of β CAE. 9. But D is collinear with A and E, which implies that B is an interior point of β CAD. 10. π΄π΅ intersects πΆπ·. 11. This is a contradiction. Case 2: Suppose that B * C * E. [See third figure.] 12. Then ο²AEB is a triangle. A E 13. πΆπ· intersects the interior of πΈπ΅. 14. πΆπ· must intersect π΄πΈ or π΄π΅. D C 15. But πΆπ· cannot intersect π΄πΈ. 16. So πΆπ· must intersect π΄π΅. B 17. This is a contradiction.
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