LIMITS AND CONTINUITY An introduction to Limits and how we will be using them LIMIT We say the limit of f (x) as x approaches a is L and write lim f ( x) L x a y f ( x) L a EXAMPLES OF LIMITS f (x) = 3x+10 Given Find lim+ f (x) x®3 lim f (x) = lim 3x+10 = lim 3(3) +10 =19 x®3 x®3 x®3 THE - DEFINITION OF LIMIT We say lim f ( x) L if and only if x a for every positive number e , there exists a positive number d such that if 0 <| x- a |< d , then | f (x) - L |< e. L L y f ( x) L a a a ONE-SIDED LIMITS The right-hand limit of f (x), as x approaches a, equals L written: lim f (x) = L x®a+ when we can make f (x) arbitrarily close to L by taking x to be sufficiently close to the right of a. y f ( x) L a EXAMPLES ì x+ 2, if x > 0 Let f (x) = í î3x -1, if x £ 0. Find the limits: a) lim+ f (x) = lim (x+ 2) = 0 + 2 = 2 x®0 b) x®0+ lim f ( x) = lim- (3x-1) = 3(0) -1= -1 x 0 x®0 c) lim f ( x) = lim- (x+ 2) =1+ 2 = 3 x 1 x®1 d) lim f ( x) = lim(x+ 2) =1+ 2 = 3 x 1 x®1+ A THEOREM lim f (x) = L iff lim+ f (x) = L and lim- f (x) = L. x®a x®a x®a We can use this theorem to show a limit does not exist For the function ì x+ 2, if x > 0 f (x) = í î3x -1, if x £ 0. lim f (x) DNE because lim+ f (x) = 2 and lim- f (x) = -1. x®0 x®0 x®0 HW 2 Problems 2.3, 2.5, 2.7, 2.8, 2.13, 2.18
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