MCR3UI
Date: ________________________
1.
Given the following ordered pairs, π = {(β1, β3), (1, β2), (3, 4), (5, 0), (6, 1)}, find the inverse, and graph the
function and its inverse.
2.
Given the ordered pairs of each function, find the inverse, and state whether the inverse is a function.
a) π = {(β2, 3), (β1, 2), (0, 0), (4, β2)}
b) π = {(4, β2), (2, 1), (1, 3), (0, β2), (β3, β3)}
3.
Sketch the inverse of each function.
a)
b)
π¦ = π(π₯)
π¦ = π(π₯)
c)
d)
π(π₯) = 3π₯
π¦ = π(π₯)
e)
f)
π(π₯) = 2π₯ β 1
π(π₯) = 3 β π₯
4.
Find the inverse of each function.
a)
π(π₯) = π₯ β 1
π(π₯) = π₯ + 3
b)
c)
π(π₯) = 2π₯ + 1
d)
5.
Find the inverse function of π(π₯) = π₯ + 2. Graph the function and its inverse.
6.
Find the inverse of π(π₯) =
7.
Determine if the functions in each pair are inverses of each other.
a)
π₯+3
4
and determine whether the inverse is a function.
π(π₯) = 2π₯ β 1 and π(π₯) =
π₯+1
b)
2
Answers:
1) πβπ = {(βπ, βπ), (βπ, π), (π, π), (π, π), (π, π)}
2a) πβπ = {(π, βπ), (π, βπ), (π, π), (βπ, π)}, πβπ is a function
4a) πβπ (π) = π + π
4b) πβπ (π) = π β π
5
π(π₯) = 2 π₯ β 4
π₯
π(π₯) = 3 β 5 and β(π₯) = 3π₯ + 5
2b) πβπ = {(βπ, π), (π, π), (π, π), (βπ, π), (βπ, βπ)}, πβπ is not a function
π
π
π
π
4c) πβπ (π) = π β
π
π
π
π
4d) πβπ (π) = π +
5) πβπ (π) = π β π
6) πβπ = ππ β π, πβπ (π) is a function
7a) π(π) & π(π) are inverse functions 7b) π (π) π(π) are not inverse functions
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