MCR3UI Date: ________________________ 1. Given the following ordered pairs, π = {(β1, β3), (1, β2), (3, 4), (5, 0), (6, 1)}, find the inverse, and graph the function and its inverse. 2. Given the ordered pairs of each function, find the inverse, and state whether the inverse is a function. a) π = {(β2, 3), (β1, 2), (0, 0), (4, β2)} b) π = {(4, β2), (2, 1), (1, 3), (0, β2), (β3, β3)} 3. Sketch the inverse of each function. a) b) π¦ = π(π₯) π¦ = π(π₯) c) d) π(π₯) = 3π₯ π¦ = π(π₯) e) f) π(π₯) = 2π₯ β 1 π(π₯) = 3 β π₯ 4. Find the inverse of each function. a) π(π₯) = π₯ β 1 π(π₯) = π₯ + 3 b) c) π(π₯) = 2π₯ + 1 d) 5. Find the inverse function of π(π₯) = π₯ + 2. Graph the function and its inverse. 6. Find the inverse of π(π₯) = 7. Determine if the functions in each pair are inverses of each other. a) π₯+3 4 and determine whether the inverse is a function. π(π₯) = 2π₯ β 1 and π(π₯) = π₯+1 b) 2 Answers: 1) πβπ = {(βπ, βπ), (βπ, π), (π, π), (π, π), (π, π)} 2a) πβπ = {(π, βπ), (π, βπ), (π, π), (βπ, π)}, πβπ is a function 4a) πβπ (π) = π + π 4b) πβπ (π) = π β π 5 π(π₯) = 2 π₯ β 4 π₯ π(π₯) = 3 β 5 and β(π₯) = 3π₯ + 5 2b) πβπ = {(βπ, π), (π, π), (π, π), (βπ, π), (βπ, βπ)}, πβπ is not a function π π π π 4c) πβπ (π) = π β π π π π 4d) πβπ (π) = π + 5) πβπ (π) = π β π 6) πβπ = ππ β π, πβπ (π) is a function 7a) π(π) & π(π) are inverse functions 7b) π (π) π(π) are not inverse functions
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