Modern Control System EKT 308 Time Response Transient and Steady-State Response Analysis Typical Test Signals • • • • • • Step functions (*) Ramp functions (*) Impulse functions (*) Parabolic functions Sinusoidal functions (Later in frequency analysis) White noise Test signals Transient and Steady-State Response Time response has two parts: 1) Transient Response: System response from initial state to final state 2) Steady-state Response: System response when t approaches infinity. c(t ) Ctr (t ) Css (t ) First Order Systems R(s) + - E(s) 1 Ts 1 C ( s) 1 R( s) Ts 1 C(s) Unit step response of first order systems C ( s) G ( s) R( s) 1 C ( s) Lu (t ) Ts 1 1 1 A B Ts 1 s s Ts 1 1 T 1 1 s Ts 1 s s (1 / T ) c(t ) 1 e t T for t 0 From Eq (1), At t 0, c(t ) 0 At t , c(t ) 1 (1) c(t ) 1 e t / T Slope, dc(t ) 1 t / T 0 e dt t 0 T t 0 1 T Unit ramp response of first order systems C ( s) G ( s) R( s) 1 C (s) Lr (t ) Ts 1 1 1 1 T T2 2 2 Ts 1 s s s Ts 1 c(t ) t T Te t / T for t 0 t Error signal e(t ) r (t ) c(t ) T (1 e t / T ) At t , e() T Unit impulse response of first order systems C ( s) G ( s) R( s) 1 C (s) L (t ) Ts 1 1 1 1 .1 Ts 1 T s 1/ T 1 t / T c(t ) e for t 0 T 1 t /T c(t ) e T Example of first order system Second Order System Let us start with an example Second Order System (Contd…) Transfer function of a second order system (K=1) …. (1) From equation (1), we can write n2 Y ( s) 2 R( s) 2 s 2n s n For unit step n2 1 Y (s) 2 s 2n s n2 s Y ( s ) s 2n ( s n ) n 2 y (t ) 1 y (t ) 1 1 n 2 1 2 1 1 2 1 2 2 1 s 1/ 2 2 2 1 2 2 e nt sin( n n n e nt sin( n 1 2 t ) 1 t ) 2 Assuming 1 - y (t ) 1 1 e n t 2 sin( n t ) n 1 1 - where, tan tan n 1 tan 1- 2 sec 1 2 cos 1 1 2 2 1 2 2 Signal flow and block diagram of the system Transient response Unit Impulse response of a second order system Y ( s) 2 R( s) 2 s 2n s n 2 n 2 .1 2 s 2n s n 2 n n t y (t ) e sin( n t ). n Unit Impulse response (contd…)
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