Journal of Mathematics Research; Vol. 7, No. 1; 2015 ISSN 1916-9795 E-ISSN 1916-9809 Published by Canadian Center of Science and Education Some More Results on Root Square Mean Graphs S. S. Sandhya1, S. Somasundaram2 & S. Anusa3 1 Department of Mathematics, Sree Ayyappa College for Women, Chunkankadai 629003, India. 2 Department of Mathematics, Manonmaniam Sundaranar University, Tirunelveli 627012, India. 3 Department of Mathematics, Arunachala College of Engineering for Women, Vellichanthai 629203, India. Correspondence: S. Anusa, Department of Mathematics, Arunachala College of Engineering for Women, Vellichanthai 629203, India. E-mail: [email protected] Received: October 23, 2014 Accepted: November 6, 2014 doi:10.5539/jmr.v7n1p72 Online Published: February 17, 2015 URL: http://dx.doi.org/10.5539/jmr.v7n1p72 Abstract A graph πΊ = (π, πΈ) with π vertices and π edges is called a Root Square Mean graph if it is possible to label the vertices π₯ β π with distinct elements π(π₯) from 1,2, β¦ , π + 1 in such a way that when each edge π = π’π£ π(π’)2 +π(π£)2 is labeled with π(π = π’π£) = ββ 2 β or ββ π(π’)2 +π(π£)2 2 β , then the resulting edge labels are distinct. In this case π is called a Root Square Mean labeling of πΊ. The concept of Root Square Mean labeling was introduced by (S. S. Sandhya, S. Somasundaram and S. Anusa). We investigated the Root Square Mean labeling of several standard graphs such as Path, Cycle, Comb, Ladder, Triangular snake, Quadrilateral snake etc., In this paper, we investigate the Root Square Mean labeling for Double Triangular snake, Alternate Double Triangular snake, Double Quadrilateral snake, Alternate Double Quadrilateral snake, and Polygonal chain. Keywords: Mean graph, Root Square Mean graph, Cycle, Triangular snake, Double Triangular snake, Quadrilateral snake, Double Quadrilateral snake, Polygonal chain. 1. Introduction The graph considered here will be finite, undirected and simple. The vertex set is denoted by π(πΊ) and the edge set is denoted by πΈ(πΊ).For all detailed survey of graph labeling we refer to Gallian (2010). For all other standard terminology and notations we follow Harary (1988). A Triangular snake ππ is obtained from a path π’1 π’2 π’3 β― π’π by joining π’π and π’π+1 to a new vertex π£π for 1 β€ π β€ π β 1. A Double Triangular Snake π·(ππ ) consists of two Triangular snakes that have a common path. An Alternate Triangular snake π΄(ππ ) is obtained from a path π’1 π’2 β¦ π’π by joining π’π and π’π+1 (Alternatively) to new vertex π£π .An Alternate Double Triangular Snake π΄(π·(ππ )) consists of two Alternate Triangular snakes that have a common path. A Quadrilateral snake ππ is obtained from a path π’1 π’2 β¦ π’π by joining π’π and π’π+1 to new vertices π£π and π€π respectively and then joining π£π and π€π . A Double Quadrilateral snake π·(ππ ) consists of two Quadrilateral snakes that have a common path. An Alternate Quadrilateral snake π΄(ππ ) is obtained from a path π’1 π’2 β¦ π’π by joining π’π and π’π+1 (Alternatively) to new vertices π£π and π€π respectively and then joining π£π and π€π .An Alternate Double Quadrilateral snake π΄(π·(ππ )) consists of two Alternate Quadrilateral snakes that have a common path.A Polygonal chain πΊπ,π is a connected graph all of whose π blocks are polygons on π sides. S. Somasundaram and R. Ponraj introduced the concept of mean labeling of graphs and investigated the mean labeling of some standard graphs. S. Somasundaram and S. S. Sandhya introduced the concept of Harmonic mean labeling of graphs. S. Somasundaram and P. Vidhya Rani introduced the concept of Geometric mean labeling of graphs. In this paper we prove that Double Triangular snake, Alternate Double Triangular snake, Double Quadrilateral snake, Alternate Double Quadrilateral snake and Polygonal Chains are Root Square mean graphs. We make frequent reference to the following results. Theorem 1.1: (S. Somasundaram & R. Ponraj) Triangular snakes and Quadrilateral snakes are mean graphs. 72 www.ccsenet.org/jmr Journal of Mathematics Research Vol. 7, No. 1; 2015 Theorem 1.2: (S. S. Sandhya, S. Somasundaram & S. Anusa) Double Triangular and Double Quadrilateral snakes are mean graphs. Theorem 1.3: (S. S. Sandhya & S. Somasundaram) Triangular snakes and Quadrilateral snakes are Harmonic mean graphs. Theorem 1.4: (C. Jaya Sekaran, S. S. Sandhya & C. David Raj) Double Triangular snakes and Alternate Double Triangular snakes are Harmonic mean graphs. Theorem 1.5: (C. David Raj, C. Jaya Sekaran & S. S. Sandhya) Double Quadrilateral and Alternate Double Quadrilateral snakes are Harmonic mean graphs. Theorem 1.6: (S. S. Sandhya & S. Somasundaram) Double Triangular snakes are Geometric mean graphs. Theorem 1.7: (S. S. Sandhya & S. Somasundaram) Double Quadrilateral snakes are Geometric mean graphs. 2. Root Square Mean Labeling Definition 2.1: A graph πΊ = (π, πΈ) with π vertices and π edges is called a mean graph if it is possible to label the vertices π₯ β π with distinct elements π(π₯) from 0,1,2, β¦ , π in such a way that when each edge π(π’)+π(π£) 2 π = π’π£ is labeled with π(π = π’π£) = {π(π’)+π(π£)+1 2 ππ π(π’) + π(π£) ππ ππ£ππ ππ π(π’) + π(π£) ππ πππ , then the edge labels are distinct. In this case π is called Mean labeling of πΊ. Definition 2.2: A graph with π vertices and π edges is called as Harmonic mean graph if it is possible to label the vertices π₯ β π with distinct elements π(π₯) from 1,2,3, β¦ , π + 1 in such a way that when each edge π = π’π£ is labeled with π(π = π’π£) = β 2π(π’)π(π£) π(π’)+π(π£) β ππ β 2π(π’)π(π£) π(π’)+π(π£) β , then the edge labels are distinct. In this case π is called Harmonic mean labeling of πΊ. Definition 2.3: A graph with π vertices and π edges is called as Geometric mean graph if it is possible to label the vertices π₯ β π with distinct elements π(π₯) from 1,2,3, β¦ , π + 1 in such a way that when each edge π = π’π£ is labeled with π(π = π’π£) = ββπ(π’)π(π£) β ππ ββπ(π’)π(π£) β , then the edge labels are distinct. In this case π is called Geometric mean labeling of πΊ. Definition 2.4: A graph with π vertices and π edges is called a Root Square mean graph if it is possible to label the vertices π₯ β π with distinct elements π(π₯) from 1,2,3, β¦ , π + 1 in such a way that when each edge π(π’)2 +π(π£)2 π = π’π£ is labeled with π(π = π’π£) = ββ 2 π(π’)2 +π(π£)2 β 0π ββ 2 β , then the edge labels are distinct. In this case π is called Root Square mean labeling of πΊ. Theorem 2.5: Double Triangular snakes π·(ππ ) are Root square mean graphs. Proof: Consider a path π’1 π’2 π’3 β― π’π .Join π’π and π’π+1 ,1 β€ π β€ π β 1 to two new vertices π£π , π€π , 1 β€ π β€ π β 1.Define a function π: π(π·(ππ )) β *1,2, β¦ π + 1+ by π(π’1 ) = 1 , π(π’2 ) = 5, π(π’π ) = 5π β 4, 3 β€ π β€ π, π(π£π ) = 5π β 3, 1 β€ π β€ π β 1, π(π€π ) = 5π β 2, 1 β€ π β€ π β 1. The edges are labeled as π(π’1 π’2 ) = 4, π(π’π π’π+1 ) = 5π β 2, 2 β€ π β€ π β 1 π(π’π π£π ) = 5π β 4, 1 β€ π β€ π β 1 π(π’2 π£1 ) = 3, π(π’π+1 π£π ) = 5π β 1, 2 β€ π β€ π β 1 π(π’π π€π ) = 5π β 3, 1 β€ π β€ π β 1 π(π’π+1 π€π ) = 5π, 1 β€ π β€ π β 1. Then the edge labels are distinct. Hence Double Triangular snakes are Root Square mean graphs. 73 www.ccsenet.org/jmr Journal of Mathematics Research Vol. 7, No. 1; 2015 Example 2.6: Root Square mean labeling of π·(π5 ) is given below. Figure 1 Theorem 2.7: Alternate Double Triangular snakes π΄(π·(ππ )) is a Root Square mean graph. Proof: Let πΊ be the graph π΄(π·(ππ )). Consider a path π’1 π’2 π’3 β― π’π .To construct πΊ, join π’π and π’π+1 (Alternatively) with two new vertices π£π and π€π , 1 β€ π β€ π β 1.There are two different cases to be considered. Case 1: If the Double Triangle starts from π’1 , then we consider two sub cases. Sub Case 1(a): If π is even, then Define a function π: π(πΊ) β *1,2, β¦ π + 1+ by π(π’1 ) = 1 , π(π’π ) = 3π β 1, 2 β€ π β€ π, π(π£1 ) = 2, π(π£π ) = 6(π β 1), 2 β€ π β€ π , 2 π π(π€1 ) = 3, π(π€π ) = 6π β 2, 2 β€ π β€ . 2 The edges are labeled as π(π’π π’π+1 ) = 3π , 1β€π β€πβ1 π(π’2πβ1 π£π ) = 6π β 5, 1 β€ π β€ π 2 π 2 π(π’2 π£1 ) = 4, π(π’2π π£π ) = 6π β 4, 2 β€ π β€ π(π’1 π€1 ) = 2, π(π’2πβ1 π€π ) = 6π β 2, 2 β€ π β€ π 2 π π(π’2π π€π ) = 6π β 1, 1 β€ π β€ . 2 Then the edge labels are distinct. Hence in this case π is a Root Square mean labeling of πΊ. The labeling pattern is shown below. Figure 2 Sub Case 1(b): If π is odd then 74 www.ccsenet.org/jmr Journal of Mathematics Research Define a function π: π(πΊ) β *1,2, β¦ π + 1+ by π(π’1 ) = 1 , π(π’π ) = 3π β 1, 2 β€ π β€ π β 1, π(π’π ) = 3π β 2 , π(π£1 ) = 2, πβ1 , 2 π(π£π ) = 6(π β 1), 2 β€ π β€ π(π€1 ) = 3, π(π€π ) = 6π β 2, 2 β€ π β€ πβ1 2 . The edges are labeled as π(π’π π’π+1 ) = 3π , 1β€π β€πβ1 π(π’2πβ1 π£π ) = 6π β 5, 1 β€ π β€ πβ1 2 πβ1 2 π(π’2 π£1 ) = 4, π(π’2π π£π ) = 6π β 4, 2 β€ π β€ π(π’1 π€1 ) = 2, π(π’2πβ1 π€π ) = 6π β 2, 2 β€ π β€ π(π’2π π€π ) = 6π β 1, 1 β€ π β€ πβ1 2 πβ1 . 2 Then the edge labels are distinct. Hence in this case π is a Root Square mean labeling of πΊ . The labeling pattern is shown below. Figure 3 Case 2: If the triangle starts from π’2 , then we have to consider two sub cases. Sub case 2(a): If π is even , then Define a function π: π(πΊ) β *1,2, β¦ π + 1+ by π(π’1 ) = 1 , π(π’2 ) = 2, π(π’π ) = 3π β 3, 3 β€ π β€ π β 1, π(π’π ) = 3π β 4 , π(π£1 ) = 3, π(π£π ) = 6π β 5, 2 β€ π β€ π(π€π ) = 6π β 1, 1 β€ π β€ πβ2 2 πβ2 , 2 . The edges are labeled as π(π’π π’π+1 ) = 3π β 2 , 1β€π β€πβ1 π(π’2π π£π ) = 6π β 4, 1 β€ π β€ πβ2 2 π(π’3 π£1 ) = 5, π(π’2π+1 π£π ) = 6π β 3, 2 β€ π β€ π(π’2 π€1 ) = 3, π(π’2π π€π ) = 6π β 1, 2 β€ π β€ πβ2 2 πβ2 2 75 Vol. 7, No. 1; 2015 www.ccsenet.org/jmr π(π’2π+1 π€π ) = 6π, 1 β€ π β€ Journal of Mathematics Research Vol. 7, No. 1; 2015 πβ2 . 2 Then the edge labels are distinct. Hence in this case π is a Root Square mean labeling of πΊ . The labeling pattern is shown below. Figure 4 Sub Case 2(b): If π is odd Define a function π: π(πΊ) β *1,2, β¦ π + 1+ by π(π’1 ) = 1 , π(π’2 ) = 2, π(π’π ) = 3π β 3, 3 β€ π β€ π , π(π£1 ) = 3, π(π£π ) = 6π β 5, 2 β€ π β€ π(π€π ) = 6π β 1, 1 β€ π β€ πβ1 2 πβ1 , 2 . The edges are labeled as π(π’π π’π+1 ) = 3π β 2 , 1β€π β€πβ1 π(π’2π π£π ) = 6π β 4, 1 β€ π β€ πβ1 2 π(π’3 π£1 ) = 5, π(π’2π+1 π£π ) = 6π β 3, 2 β€ π β€ π(π’2 π€1 ) = 3, π(π’2π π€π ) = 6π β 1, 2 β€ π β€ π(π’2π+1 π€π ) = 6π, 1 β€ π β€ πβ1 2 πβ1 2 πβ1 . 2 Then the edge labels are distinct. Hence in this case π is a Root Square mean labeling of πΊ. The labeling pattern is shown below. Figure 5 From all the above cases, we conclude that Alternate Double Triangular Snakes π΄(π·(ππ )) are Root Square mean graphs. 76 www.ccsenet.org/jmr Journal of Mathematics Research Vol. 7, No. 1; 2015 Theorem 2.8: Double Quadrilateral snake graph π·(ππ ) is a Root Square mean graphs. Proof: Let ππ be the path π’1 π’2 π’3 β― π’π .To construct π·(ππ ), join π’π and π’π+1 to four new vertices π£π , π€π , π£πβ² and π€πβ² by the edges π’π π£π , π’π+1 π€π , π£π π€π , π’π π£πβ² , π’π+1 π€πβ² and π£πβ² π€πβ² , for 1 β€ π β€ π β 1. Define a function π: π(π·(ππ )) β *1,2, β¦ π + 1+ by π(π’1 ) = 1 , π(π’π ) = 7(π β 1), 2 β€ π β€ π , π(π£1 ) = 2, π(π£π ) = 7π β 2, 2 β€ π β€ π β 1, π(π€1 ) = 5, π(π€π ) = 7π β 1, 2 β€ π β€ π β 1 , π(π£1β² ) = 3, π(π€1β² ) = 4, π(π£πβ² ) = 7π β 5, 2 β€ π β€ π β 1, π(π€πβ² ) = 7π β 3, 2 β€ π β€ π β 1. The edges are labeled as π(π’1 π’2 ) = 5, π(π’π π’π+1 ) = 7π β 3 , 2 β€ π β€ π β 1 π(π’1 π£1 ) = 1, π(π’π π£π ) = 7π β 5, 2 β€ π β€ π β 1 π(π’π+1 π€π ) = 7π, 1 β€ π β€ π β 1, π(π£1 π€1 ) = 4, π(π£π π€π ) = 7π β 2, 2 β€ π β€ π β 1 π(π’1 π£1β² ) π(π’π π£πβ² ) = 7π β 6 , 2 β€ π β€ π β 1 = 2, π(π’π+1 π€πβ² ) = 7π β 1, 1 β€ π β€ π β 1, π(π£πβ² π€πβ² ) = 7π β 4, 1 β€ π β€ π β 1. Then the edge labels are distinct. Hence in this case π is a Root Square mean labeling of πΊ. Example 2.9: The Root Square mean labeling of π·(π5 ) is given below. Figure 6 Theorem 2.10: Alternate Double Quadrilateral snake graphs π΄(π·(ππ )) are Root Square mean graphs. Proof: Let πΊ be the Alternate Double Quadrilateral snake π΄(π·(ππ )) .Consider a path π’1 π’2 π’3 β― π’π .Join π’π and π’π+1 (Alternatively) with to four new vertices π£π , π£π+1 , π€π and π€π+1 .Here we consider two different cases. Case 1: If the Double Quadrilateral starts from π’1 , then we consider two sub cases. Sub Case 1(a): If π is even then Define a function π: π(πΊ) β *1,2, β¦ π + 1+ by π(π’1 ) = 1 , π(π’π ) = 4π β 2, 2 β€ π β€ π, π(π£1 ) = 2, π(π£π ) = 4π β 3, 2 β€ π β€ π β 1, π(π€1 ) = 3, π(π€π ) = 4π β 1, 2 β€ π β€ π β 1 . The edges are labeled as π(π’π π’π+1 ) = 4π , 1β€πβ€π π(π’π π£π ) = 4π β 3, π = 1,3,5, β¦ , π β 1 π(π’π π£π ) = 4π β 2, π = 2,4,6, β¦ , π π(π’π π€π ) = 4π β 2, π = 1,3,5, β¦ , π β 1 π(π’π π€π ) = 4π β 1, π = 2,4,6, β¦ , π 77 www.ccsenet.org/jmr Journal of Mathematics Research π(π£π π£π+1 ) = 8π β 5, 1 β€ π β€ πβ1 2 π(π€π π€π+1 ) = 8π β 3, 1 β€ π β€ πβ1 2 Then the edge labels are distinct. Hence in this case π is a Root Square mean labeling of πΊ. The labeling pattern is shown below. Figure 7 Sub Case 1(b): If π is odd then Define a function π: π(πΊ) β *1,2, β¦ π + 1+ by π(π’1 ) = 1 , π(π’π ) = 4π β 2, 2 β€ π β€ π β 1, π(π’π ) = 4π β 3 , π(π£1 ) = 2, π(π£π ) = 4π β 3, 2 β€ π β€ π β 1, π(π€1 ) = 3, π(π€π ) = 4π β 1, 2 β€ π β€ π β 1 . The edges are labeled as π(π’π π’π+1 ) = 4π , 1β€πβ€π π(π’π π£π ) = 4π β 3, π = 1,3,5, β¦ , π π(π’π π£π ) = 4π β 2, π = 2,4,6, β¦ , π β 1 π(π’π π€π ) = 4π β 2, π = 1,3,5, β¦ , π π(π’π π€π ) = 4π β 1, π = 2,4,6, β¦ , π β 1 π(π£π π£π+1 ) = 8π β 5, 1 β€ π β€ πβ1 2 π(π€π π€π+1 ) = 8π β 3, 1 β€ π β€ πβ1 2 Then the edge labels are distinct. Hence in this case π is a Root Square mean labeling of πΊ. The labeling pattern is shown below. Figure 8 Case 2: If the Double Quadrilateral starts from π’2 , then we have to consider two sub cases. Sub case 2(a): If π is even , then Define a function π: π(πΊ) β *1,2, β¦ π + 1+ by π(π’1 ) = 1 , π(π’2 ) = 2, π(π’π ) = 4π β 5, 3 β€ π β€ π β 1, π(π’π ) = 4π β 6 , π(π£1 ) = 3, π(π£π ) = 4π β 2, 2 β€ π β€ π β 2, π(π€π ) = 4π , 1 β€ π β€ π β 2. 78 Vol. 7, No. 1; 2015 www.ccsenet.org/jmr Journal of Mathematics Research The edges are labeled as π(π’π π’π+1 ) = 4π β 3, 1β€πβ€π π(π’π+1 π£π ) = 4π β 2, π = 1,3,5, β¦ , π β 1 π(π’π+1 π£π ) = 4π β 1, π = 2,4,6, β¦ , π π(π’π+1 π€π ) = 4π β 1, π = 1,3,5, β¦ , π β 1 π(π’π+1 π€π ) = 4π, π = 2,4,6, β¦ , π π(π£π π£π+1 ) = 8π β 4, 1 β€ π β€ πβ2 2 π(π€π π€π+1 ) = 8π β 2, 1 β€ π β€ πβ2 2 Then the edge labels are distinct. Hence in this case π is a Root Square mean labeling of πΊ. The labeling pattern is shown below. Figure 9 Sub Case 2(b): If π is odd , then Define a function π: π(πΊ) β *1,2, β¦ π + 1+ by π(π’1 ) = 1 , π(π’2 ) = 2, π(π’π ) = 4π β 5, 3 β€ π β€ π, π(π£1 ) = 3, π(π£π ) = 4π β 2, 2 β€ π β€ π β 1, π(π€π ) = 4π , 1 β€ π β€ π β 1. The edges are labeled as π(π’π π’π+1 ) = 4π β 3, 1β€πβ€π π(π’π+1 π£π ) = 4π β 2, π = 1,3,5, β¦ , π π(π’π+1 π£π ) = 4π β 1, π = 2,4,6, β¦ , π β 1 π(π’π+1 π€π ) = 4π β 1, π = 1,3,5, β¦ , π π(π’π+1 π€π ) = 4π, π = 2,4,6, β¦ , π β 1 π(π£π π£π+1 ) = 8π β 4, 1 β€ π β€ πβ1 2 π(π€π π€π+1 ) = 8π β 2, 1 β€ π β€ πβ1 2 Then the edge labels are distinct. Hence in this case π is a Root Square mean labeling of πΊ. The labeling pattern is shown below. Figure 10 Theorem 2.11: Polygonal chain πΊπ,π are Root Square mean graphs for all π and π. 79 Vol. 7, No. 1; 2015 www.ccsenet.org/jmr Journal of Mathematics Research Vol. 7, No. 1; 2015 Proof: In πΊπ,π , let π’1 π’2 π’4 π’6 β― π’πβ6 π’πβ4 π’πβ2 π’π+1 π’πβ1 π’πβ3 π’πβ5 β― π’9 π’7 π’5 π’3 π’1 be the first cycle. The second cycle is connected to the first cycle at the vertex π’π+1 . Let π’π+1 π’π+2 π’π+4 β― π’2π+1 π’2πβ1 π’2πβ3 β― π’π+7 π’π+5 π’π+3 π’π+1 be the second cycle.In general the rth connected to the (r-1) cycle at the vertex π’ππ+1 .Let the r th th cycle is cycle be π’ππ+1 π’ππ+2 π’ππ+4 π’ππ+6 β― π’(π+1)πβ4 π’(π+1)πβ2 π’(π+1)π+1 π’(π+1)πβ1 π’(π+1)πβ3 π’(π+1)πβ5 β― π’ππ+5 π’ππ+3 π’ππ+1 .The figure of the rth cycle is given below. Figure 11 Let the graph has π cycles . Define a function π: π(πΊ) β *1,2, β¦ π + 1+ by π(π£π ) = π , 1 β€ π β€ ππ β 1 , π(π£π ) = ππ + 1. Then the label of the edges is given below.π(π’ππ+1 π’ππ+2 ) = ππ + 1 , π(π’ππ+π π’ππ+π+2 ) = ππ + π + 1, π(π’(π+1)πβ2 π’(π+1)π+1 ) = (π + 1)π β 1, π(π’(π+1)π+1 π’(π+1)πβ1 ) = (π + 1)π. Hence the graph πΊπ,π has distinct edge labels, hence πΊπ,π is a Root Square mean graph. Example 2.12: Root Square mean labeling of πΊ4,6 chain is given below. Figure 12 80 www.ccsenet.org/jmr Journal of Mathematics Research Vol. 7, No. 1; 2015 Reference David Raj, C., Jayasekaran, C., & Sandhya, S. S. (2013). 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