EmDrive Basic Theory 1 EmDrive Theory Fg1 T = Q(Fg1-Fg2) Microwave energy is fed to a specially tapered resonator,which produces a net thrust from the large number of EM reflections in the high Q structure. (typically 5x104) Fg1>Fg2 as guide velocity Vg1>Vg2 Fg2 Static Thrust given by: Magnetron 2 P QS T 0 0 c 0 0 g1 g 2 2 Derivation of Basic Thrust Equation From principle of operation T QFg1 Fg 2 now Fg 2 P 0 c g Ref: A. L. Cullen Thus force is inversely proportional to guide wavelength Then 0 2 PQS 0 0 T c g1 g 2 where 02 S 0 1 g1g 2 1 S0 corrects for Einstein’s equation for the addition of relativistic velocities Relationship between guide wavelength and waveguide geometry is non-linear 3 Axial Component of Sidewall Force F Area A2 F2 1 At first sight it might appear that because A1= A2+A3 then F1= F2+F3 F3 Area A1 However as the relationship between F and A is highly non-linear,the cavity can be designed to maximise F1/F2 and minimise F3/F1 Area A3 Detail design requires software developed by SPR Ltd and is included in IPR Guide Wavelength for Circular TM01 at 2GHz 5500 However intuitively it can be seen that at cut-off : 5000 4500 Guide wavelength (mm) 4000 Guide wavelength is infinity 3500 3000 Group velocity and force is zero 2500 Area A2 is clearly not zero 2000 1500 1000 500 0 0 50 100 150 200 250 300 350 400 450 500 Waveguide Diam eter (m m ) 4 Conservation of Momentum Vg = 0.99c Waveguide velocity = 0.5c Vg measured inside waveguide = 0.99c Vg measured outside waveguide = 0.99c (not 1.49c !) This applies if the open end wall is now closed An EM wave propagated inside a CLOSED waveguide is an OPEN system Momentum can therefore be exchanged between the EM wave and the waveguide end walls Momentum is therefore conserved 5 Conservation of Momentum Assume that at velocity c, the EM wave has momentum At initial propagation 1 = 0.4 and 2 = - 0.4 Then 1 + 2 = 0 w At end plates 1 = 0.9 and 2 = - 0.1 1 2 Then momentum lost by EM wave at end plates = 2( 1 + 2 ) = 1.6 Momentum gained by waveguide w = - 1.6 Then w +2( 1 + 2 ) = 0 Vg2 = .1c Vg0 = .4c Vg1 = .9c 6 Conservation of Energy Doppler Shift for Fo =4GHz, Qu = 5x107 40 35 Ff 30 Fr 25 20 Vg2 15 Vg1 Doppler Shift (Hz) 10 Vr Vf 5 m otor 0 generator -5 -10 -15 Cavity Acceleration -20 -25 -30 -35 Cavity acceleration produces unequal Doppler Shifts in Ff and Fr during each wavefront transit. Doppler Mathematical model illustrates Doppler shift for both Motor and Generator modes. -40 0 5 10 15 20 25 30 35 40 45 50 Transit Num ber x 107 +ve acceleration gives a frequency decrease and hence an energy loss (motor) -ve acceleration gives a frequency increase and thus an energy increase (generator) 7
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