NPTEL- Probability and Distributions
MODULE 1
PROBABILITY
PROBLEMS
1. Let πΊ = {1, 2, 3, 4}. Check which of the following is a sigma-field of subsets of
πΊ:
(i) β±1 = π, 1, 2 , 3, 4 ;
(ii) β±2 = π, πΊ, 1 , 2, 3, 4 , 1, 2 , 3, 4 ;
(iii) β±3 = π, πΊ, 1 , 2 , 1, 2 , 3, 4 , 2, 3, 4 , 1, 3, 4 .
2.
Show that a class β± of subsets of πΊ is a sigma-field of subsets of πΊ if, and only
if, the following three conditions are satisfied: (i) πΊ β β±; (ii) π΄ β β± β π΄πΆ = πΊ β
π΄ β β±; (iii) π΄π β β±, n = 1, 2, β― β β
π=1 π΄π β β±.
3. Let β±π : π β π¬ be a collection of sigma-fields of subsets of πΊ.
(i) Show that πβπ¬ β±π is a sigma-field;
(ii) Using a counter example show that βͺπβπ¬ β±π may not be a sigma-field;
(iii) Let π be a class of subsets of πΊ and let β±π : π β π¬ be a collection of all
sigma-fields that contain the class π. Show that π π = πβπ¬ β±π , where π π
denotes the smallest sigma-field containing the class π (or the sigma-field
generated by class π).
4. Let πΊ be an infinite set and let π = π΄ β πΊ: π΄ is finite or π΄πΆ is finite .
(i) Show that π is closed under complements and finite unions;
(ii) Using a counter example show that π may not be closed under countably
infinite unions (and hence π may not be a sigma-field).
5. (i) Let πΊ be an uncountable set and let
β± = π΄ β πΊ: π΄ is countable or π΄πΆ is countable .
(a) Show that β± is a sigma-field;
(b) What can you say about β± when πΊ is countable?
(ii) Let πΊ be a countable set and let π = { π : π β πΊ}. Show that π π = π« πΊ .
6. Let β± = π« πΊ =the power set of πΊ = 0, 1, 2, β¦ . In each of the following cases,
verify if πΊ, β±, π is a probability space:
Dept. of Mathematics and Statistics Indian Institute of Technology, Kanpur
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NPTEL- Probability and Distributions
(i) π π΄ = π₯βπ΄ π βπ ππ₯ π₯! , π΄ β β±, π > 0;
(ii) π π΄ = π₯βπ΄ π 1 β π π₯ , π΄ β β±, 0 < π < 1;
(iii) π π΄ = 0, if π΄ has a finite number of elements, and π(π΄) = 1 , if π΄ has
infinite number of elements, π΄ β β±.
7. Let (πΊ, β±, π) be a probability space and let π΄, π΅, πΆ, π· β β±. Suppose that π π΄ =
0.6, π π΅ = 0.5, π πΆ = 0.4, π π΄ β© π΅ = 0.3, π π΄ β© πΆ = 0.2, π π΅ β© πΆ =
0.2, π π΄ β© π΅ β© πΆ = 0.1, π π΅ β© π· = π πΆ β© π· = 0, π π΄ β© π· =
0.1 and π π· = 0.2.
Find:
(i) π π΄ βͺ π΅ βͺ πΆ and π π΄πΆ β© π΅ πΆ β© πΆ πΆ ;
(ii) π (π΄ βͺ π΅) β© πΆ and π π΄ βͺ (π΅ β© πΆ );
(iii) π (π΄πΆ βͺ π΅ πΆ ) β© πΆ πΆ and π (π΄πΆ β© π΅ πΆ ) βͺ πΆ πΆ ;
(iv) π π΅ β© πΆ β© π· and π π΄ β© πΆ β© π· ;
(v) π π΄ βͺ π΅ βͺ π· and π π΄ βͺ π΅ βͺ πΆ βͺ π· ;
(vi) π π΄ β© π΅ βͺ (πΆ β© π·) .
8. Let πΊ, β±, π be a probability space and let π΄ and π΅ be two events (i.e., π΄, π΅ β β±).
(i) Show that the probability that exactly one of the events π΄ or π΅ will occur is
given by π π΄ + π π΅ β 2π π΄ β© π΅ ;
(ii) Show that π π΄ β© π΅ β π π΄ π π΅ = π π΄ π π΅πΆ β π π΄ β© π΅ πΆ =
π π΄πΆ π π΅ β π π΄πΆ β© π΅ = π π΄ βͺ π΅ πΆ β π π΄πΆ π π΅πΆ .
9. Suppose that π β₯ 3 persons π1 , β¦ , ππ are made to stand in a row at random.
Find the probability that there are exactly π persons between π1 and π2 ; here
π β 1, 2, β¦ , π β 2 .
10. A point π, π is randomly chosen on the unit square π = π₯, π¦ : 0 β€ π₯ β€ 1, 0 β€
π¦ β€ 1 (i.e., for any region π
β π for which the area is defined, the probability that
π, π lies on π
is
area of π
area of π
). Find the probability that the distance from π, π to
1
the nearest side does not exceed 3 units.
11. Three numbers π, π and π are chosen at random and with replacement from the set
1, 2, β¦ ,6 . Find the probability that the quadratic equation ππ₯ 2 + ππ₯ + π = 0
will have real root(s).
12. Three numbers are chosen at random from the set 1, 2, β¦ ,50 . Find the
probability that the chosen numbers are in
(i) arithmetic progression;
Dept. of Mathematics and Statistics Indian Institute of Technology, Kanpur
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NPTEL- Probability and Distributions
(ii) geometric progression.
13. Consider an empty box in which four balls are to be placed (one-by-one)
according to the following scheme. A fair die is cast each time and the number of
dots on the upper face is noted. If the upper face shows up 2 or 5 dots then a
white ball is placed in the box. Otherwise a black ball is placed in the box. Given
that the first ball placed in the box was white find the probability that the box will
contain exactly two black balls.
14. Let 0, 1 , β±, π be a probability space such that β± is the smallest sigma-field
containing all subintervals of πΊ = 0, 1 and π( π, π ) = π β π, where 0 β€ π <
π β€ 1 (such a probability measure is known to exist).
(i) Show that π =
(ii) Show that π π
β
π=1
1
π β π +1 , π , βπ β 0, 1 ;
= 0, βπ β 0, 1
and π 0, 1
= 1 (Note that here
π π = 0 but π β π and π 0, 1 = 1 but 0, 1 β πΊ);
(iii) Show that, for any countable set π΄ β β±, π π΄ = 0;
1
(iv) For π β β, let π΄π = 0, π and π΅π =
1
2
1
+ π+2 , 1 . Verify that π΄π β, π΅π β,
π Limπββ π΄π = limπββ π π΄π and π Limπββ π΅π = limπ ββ π π΅π .
15. Consider four coding machines π1 , π2 , π3 and π4 producing binary codes 0 and
1
3
4
4
1. The machine π1 produces codes 0 and 1 with respective probabilities and .
The code produced by machine ππ is fed into machine ππ+1 π = 1, 2, 3 which
may either leave the received code unchanged or may change it. Suppose that
3
each of the machines π2 , π3 and π4 change the received code with probability 4.
Given that the machine π4 has produced code 1, find the conditional probability
that the machine π1 produced code 0.
16. A student appears in the examinations of four subjects Biology, Chemistry,
Physics and Mathematics. Suppose that probabilities of the student clearing
examinations in these subjects are
1 1 1
1
2 3 4
5
, , and
respectively. Assuming that the
performances of the students in four subjects are independent, find the probability
that the student will clear examination(s) of
(i) all the subjects;
(ii) no subject;
(iii) exactly one subject;
(iv) exactly two subjects;
(v) at least one subject.
17. Let π΄ and π΅ be independent events. Show that
Dept. of Mathematics and Statistics Indian Institute of Technology, Kanpur
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NPTEL- Probability and Distributions
max π π΄ βͺ π΅
π
, π π΄ β© π΅ , π π΄Ξπ΅
4
β₯ ,
9
where π΄Ξπ΅ = π΄ β π΅ βͺ π΅ β π΄ .
18. For independent events π΄1 , β¦ , π΄π , show that
π
π΄ππ β€ π β
π
π
π=1 π
π΄π
.
π=1
19. Let πΊ, β±, π be a probability space and let π΄1 , π΄2 , β¦ be a sequence of events
β
i. e. , π΄π β β±, π = 1, 2, β¦ . Define π΅π = β
π=π π΄π , πΆπ =
π=π π΄π , π = 1,2, β¦ , π· =
β
β
π=1 π΅π and πΈ = π=1 πΆπ . Show that:
(i) π· is the event that all but a finite number of π΄π s occur and πΈ is the event that
infinitely many π΄π s occur;
(ii) π· β πΈ;
π
(iii) π πΈ π = limπ ββ π πΆππ = limπββ limπ ββ π π
π=π π΄π and π πΈ =
limπββ π πΆπ ;
(iv) if β
π=1 π π΄π < β then, with probability one, only finitely many π΄π s will
occur;
(v) if π΄1 , π΄2 , β¦ are independent and β
π =1 π π΄π < β then, with probability one,
infinitely many π΄π π will occur.
20. Let π΄, π΅ and πΆ be three events such that π΄ and π΅ are negatively (positively)
associated and π΅ and πΆ are negatively (positively) associated. Can we conclude
that, in general, π΄ and πΆ are negatively (positively) associated?
21. Let πΊ, β±, π be a probability space and let A and B two events i. e., π΄, π΅ β β± .
Show that if π΄ and π΅ are positively (negatively) associated then π΄ and π΅ π are
negatively (positively) associated.
22. A locality has π houses numbered 1, β¦ . , π and a terrorist is hiding in one of these
houses. Let π»π denote the event that the terrorist is hiding in house numbered
π, π = 1, β¦ , π and let π π»π = ππ β 0,1 , π = 1, β¦ , π. During a search operation,
let πΉπ denote the event that search of the house number π will fail to nab the
terrorist there and let π πΉπ |π»π = ππ β 0,1 , π = 1, β¦ , π . For each π, π β
1, β¦ , π , π β π, show that π»π and πΉπ are negatively associated but π»π and πΉπ are
positively associated. Interpret these findings.
Dept. of Mathematics and Statistics Indian Institute of Technology, Kanpur
4
NPTEL- Probability and Distributions
23. Let π΄, π΅ and πΆ be three events such that π π΅ β© πΆ > 0. Prove or disprove each of
the following:
(i) π π΄ β© π΅|πΆ = π π΄|π΅ β© πΆ π π΅|πΆ ;
(ii) π π΄ β© π΅|πΆ = π π΄|πΆ π π΅|πΆ if π΄ and π΅ are independent events.
24. A π-out-of-π system is a system comprising of π components that functions if, and
only if, at least π π β 1,2, β¦ , π of the components function. A 1 -out-of- π
system is called a parallel system and an π-out-of-π system is called a series
system. Consider π components πΆ1 , β¦ , πΆπ that function independently. At any
given time π‘ the probability that the component πΆπ will be functioning is ππ π‘ β
0,1 and the probability that it will not be functioning at time π‘ is 1 β ππ π‘ , π =
1, β¦ , π.
(i) Find the probability that a parallel system comprising of components
πΆ1 , β¦ , πΆπ will function at time π‘;
(ii) Find the probability that a series system comprising of components πΆ1 , β¦ , πΆπ
will function at time π‘;
(iii) If ππ π‘ = π π‘ , π = 1, β¦ , π, find the probability that a π -out-of- π system
comprising of components πΆ1 , β¦ , πΆπ will function at time π‘.
Dept. of Mathematics and Statistics Indian Institute of Technology, Kanpur
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