Welcome to
Everyday Mathematics
University of Chicago School
Mathematics Project
Why do we need a
new math program?
60% of all future jobs have not even
been created yet
80% of all jobs will require post
secondary education / training.
Employers are looking for candidates
with higher order and critical thinking
skills
Traditional math instruction does not
develop number sense or critical
thinking.
Research Based Curriculum
Mathematics is more meaningful when it is rooted in real
life contexts and situations, and when children are given
the opportunity to become actively involved in learning.
Children begin school with more mathematical
knowledge and intuition than previously believed.
Teachers, and their ability to provide excellent
instruction, are the key factors in the success of any
program.
Curriculum Features
Real-life Problem Solving
Balanced Instruction
Multiple Methods for Basic Skills Practice
Emphasis on Communication
Enhanced Home/School Partnerships
Appropriate Use of Technology
Lesson Components
Math Messages
Mental Math and Reflexes
Math Boxes / Math Journal
Home links
Explorations
Games
Alternative Algorithms
Learning Goals
Assessment
Grades primarily reflect mastery of secure
skills
End of unit assessments
Math boxes
Relevant journal pages
Slate assessments
Checklists of secure/developing skills
Observation
What Parents Can Do to Help
Come to the math nights
Log on to the Everyday Mathematics website or
the South Western Math Coach’s web site
Read the Family letters – use the answer key to
help your child with their homework
Ask your child to teach you the math games and
play them.
Ask your child to teach you
the new algorithms
Contact your child’s teacher
with questions or concerns
Partial Sums
An Addition Algorithm
Add the hundreds (200 + 400)
Add the tens (60 +80)
Add the ones (8 + 3)
Add the partial sums
(600 + 140 + 11)
268
+ 483
600
140
+ 11
751
Add the hundreds (700 + 600)
Add the tens (80 +40)
Add the ones (5 + 1)
Add the partial sums
(1300 + 120 + 6)
785
+ 641
1300
120
+
6
1426
329
+ 989
1200
100
+ 18
1318
An alternative subtraction algorithm
12
13
12
- 3
5
6
5
7
6
8
In order to subtract, the top
number must be larger than
the bottom number
Start by going left to right. Ask
yourself, “Do I have enough to take
away the bottom number?” In the
hundreds column, 9-3 does not need
trading.
9
3
2
Move to the tens column. I cannot subtract 5
from 3, so I need to trade.
Move to the ones column. I cannot subtract 6
from 2, so I need to trade.
Now subtract column by column in any order
11
12
15
- 4
9
8
2
2
7
Let’s try another one
together
Start by going left to right. Ask
yourself, “Do I have enough to take
away the bottom number?” In the
hundreds column, 7- 4 does not need
trading.
6
7
2
5
Move to the tens column. I cannot subtract 9
from 2, so I need to trade.
Move to the ones column. I cannot subtract 8
from 5, so I need to trade.
Now subtract column by column in any order
13
3
12
- 2
8
7
6
5
5
8
Now, do this one on
your own.
9
4
2
Last one! This
one is tricky!
9
10
13
- 4
6
9
2
3
4
6
7
0
3
Partial Products
Algorithm for
Multiplication
To find 67 x 53, think of 67 as 60
+ 7 and 53 as 50 + 3. Then
multiply each part of one sum by
each part of the other, and add
the results
Calculate 50 X 60
Calculate 50 X 7
Calculate 3 X 60
Calculate 3 X 7
Add the results
67
X 53
3,000
350
180
+ 21
3,551
Let’s try another
one.
Calculate 10 X 20
Calculate 20 X 4
Calculate 3 X 10
Calculate 3 X 4
Add the results
14
X 23
200
80
30
+ 12
322
Do this one on
your own.
Let’s see if
you’re right.
Calculate 30 X 70
Calculate 70 X 8
Calculate 9 X 30
Calculate 9 X 8
Add the results
38
X 79
2, 100
560
270
+ 72
3002
Partial Quotients
A Division Algorithm
The Partial Quotients Algorithm uses a series of “at least,
but less than” estimates of how many b’s in a. You might
begin with multiples of 10 – they’re easiest.
There are at least ten 12’s in
158 (10 x 12=120), but fewer
than twenty. (20 x 12 = 240)
There are more than three
(3 x 12 = 36), but fewer than
four (4 x 12 = 48). Record 3 as
the next guess
Since 2 is less than 12, you can stop
estimating. The final result is the sum
of the guesses (10 + 3 = 13) plus what
is left over (remainder of 2 )
12
158
Subtract - 120
38
Subtract - 36
2
10 – 1st guess
3 – 2nd guess
13
Sum of guesses
Let’s try another one
36
7,891
Subtract - 3,600
4,291
Subtract - 3,600
691
- 360
331
- 324
7
100 – 1st guess
100 – 2nd guess
10 – 3rd guess
9 – 4th guess
219 R7
Sum of guesses
Now do this one on your
own.
43
Subtract
Subtract
8,572
- 4,300
4272
-3870
402
- 301
101
- 86
15
100 – 1st guess
90 – 2nd guess
7 – 3rd guess
2 – 4th guess
199 R 15
Sum of guesses