3. Electrolysis of aqueous sodium chloride solution. Some possible anode reactions: 1681 3. Electrolysis of aqueous sodium chloride solution. Some possible anode reactions: 2 Cl-(aq) Cl2(g) + 2e- (1) 1682 3. Electrolysis of aqueous sodium chloride solution. Some possible anode reactions: 2 Cl-(aq) Cl2(g) + 2e(1) 2 H2O(l) 4 H+(aq) + O2(g) + 4e- (2) 1683 3. Electrolysis of aqueous sodium chloride solution. Some possible anode reactions: 2 Cl-(aq) Cl2(g) + 2e(1) 2 H2O(l) 4 H+(aq) + O2(g) + 4e- (2) Some possible cathode reactions: 1684 3. Electrolysis of aqueous sodium chloride solution. Some possible anode reactions: 2 Cl-(aq) Cl2(g) + 2e(1) 2 H2O(l) 4 H+(aq) + O2(g) + 4e- (2) Some possible cathode reactions: Na+(aq) + eNa(s) (3) 1685 3. Electrolysis of aqueous sodium chloride solution. Some possible anode reactions: 2 Cl-(aq) Cl2(g) + 2e2 H2O(l) 4 H+(aq) + O2(g) + 4eSome possible cathode reactions: Na+(aq) + eNa(s) 2 H2O(l) + 2e2 OH-(aq) + H2(g) (1) (2) (3) (4) 1686 3. Electrolysis of aqueous sodium chloride solution. Some possible anode reactions: 2 Cl-(aq) Cl2(g) + 2e2 H2O(l) 4 H+(aq) + O2(g) + 4eSome possible cathode reactions: Na+(aq) + eNa(s) 2 H2O(l) + 2e2 OH-(aq) + H2(g) 2 H+(aq) + 2 eH2(g) (1) (2) (3) (4) (5) 1687 3. Electrolysis of aqueous sodium chloride solution. Some possible anode reactions: 2 Cl-(aq) Cl2(g) + 2e(1) 2 H2O(l) 4 H+(aq) + O2(g) + 4e- (2) Some possible cathode reactions: Na+(aq) + eNa(s) (3) 2 H2O(l) + 2e2 OH-(aq) + H2(g) (4) 2 H+(aq) + 2 eH2(g) (5) Experimentally it is found that Cl2(g) is liberated at the anode and H2 is liberated at the cathode. 1688 3. Electrolysis of aqueous sodium chloride solution. Some possible anode reactions: 2 Cl-(aq) Cl2(g) + 2e(1) 2 H2O(l) 4 H+(aq) + O2(g) + 4e- (2) Some possible cathode reactions: Na+(aq) + eNa(s) (3) 2 H2O(l) + 2e2 OH-(aq) + H2(g) (4) 2 H+(aq) + 2 eH2(g) (5) Experimentally it is found that Cl2(g) is liberated at the anode and H2 is liberated at the cathode. 1689 It is not immediately clear what the cathode reaction is. 1690 It is not immediately clear what the cathode reaction is. Can we exclude the following situation: Na(s) is formed which then reacts with water 1691 It is not immediately clear what the cathode reaction is. Can we exclude the following situation: Na(s) is formed which then reacts with water 2Na(s) + 2H2O(l) 2Na+(aq) + 2 OH-(aq) + H2(g) 1692 It is not immediately clear what the cathode reaction is. Can we exclude the following situation: Na(s) is formed which then reacts with water 2Na(s) + 2H2O(l) 2Na+(aq) + 2 OH-(aq) + H2(g) It turns out (from experiment) that the ease of reduction decreases in the order: reaction (5) > reaction (4) > reaction (3) 1693 It is not immediately clear what the cathode reaction is. Can we exclude the following situation: Na(s) is formed which then reacts with water 2Na(s) + 2H2O(l) 2Na+(aq) + 2 OH-(aq) + H2(g) It turns out (from experiment) that the ease of reduction decreases in the order: reaction (5) > reaction (4) > reaction (3) The pH of an aqueous solution of NaCl is 7, so that the concentration of H+(aq) is 1.0 x 10-7 M, which is too low to make reaction (5) reasonable. 1694 It is not immediately clear what the cathode reaction is. Can we exclude the following situation: Na(s) is formed which then reacts with water 2Na(s) + 2H2O(l) 2Na+(aq) + 2 OH-(aq) + H2(g) It turns out (from experiment) that the ease of reduction decreases in the order: reaction (5) > reaction (4) > reaction (3) The pH of an aqueous solution of NaCl is 7, so that the concentration of H+(aq) is 1.0 x 10-7 M, which is too low to make reaction (5) reasonable. Hence, reaction (4) is the cathode reaction. 1695 2 Cl-(aq) Cl2(g) + 2e- (1) 1696 2 Cl-(aq) 2 H2O(l) + 2e- Cl2(g) + 2e- (1) 2 OH-(aq) + H2(g) (4) 1697 2 Cl-(aq) 2 H2O(l) + 2eOverall reaction: 2 H2O(l) + 2 Cl-(aq) Cl2(g) + 2e- (1) 2 OH-(aq) + H2(g) (4) Cl2(g) + 2 OH-(aq) + H2(g) 1698 2 Cl-(aq) 2 H2O(l) + 2eOverall reaction: 2 H2O(l) + 2 Cl-(aq) Cl2(g) + 2e- (1) 2 OH-(aq) + H2(g) (4) Cl2(g) + 2 OH-(aq) + H2(g) This electrolysis would produce three very useful chemicals: chlorine gas, hydrogen gas, and sodium hydroxide. 1699 2 Cl-(aq) 2 H2O(l) + 2eOverall reaction: 2 H2O(l) + 2 Cl-(aq) Cl2(g) + 2e- (1) 2 OH-(aq) + H2(g) (4) Cl2(g) + 2 OH-(aq) + H2(g) This electrolysis would produce three very useful chemicals: chlorine gas, hydrogen gas, and sodium hydroxide. Note that sodium chloride is cheap, but electrical energy is not, unless one is situated near a hydro-power source of electrical energy. 1700 Quantitative Aspects of Electrolysis The quantitative aspects of electrolysis were largely developed by Michael Faraday. 1701 Quantitative Aspects of Electrolysis The quantitative aspects of electrolysis were largely developed by Michael Faraday. He observed that the mass of product formed or reactant consumed at an electrode is proportional to both the amount of electricity transferred at the electrode and the molar mass of the substance in question. 1702 In the electrolysis of molten NaCl, Na+(l) + eNa(l) 1703 In the electrolysis of molten NaCl, Na+(l) + eNa(l) one Na atom is produced when one Na+ accepts one electron from the electrode. 1704 In the electrolysis of molten NaCl, Na+(l) + eNa(l) one Na atom is produced when one Na+ accepts one electron from the electrode. To react one mole of Na+ ions we must supply Avogadro’s number (6.02 x 1023) of electrons to the cathode. 1705 In the electrolysis of molten NaCl, Na+(l) + eNa(l) one Na atom is produced when one Na+ accepts one electron from the electrode. To react one mole of Na+ ions we must supply Avogadro’s number (6.02 x 1023) of electrons to the cathode. At the anode, the formation of one mole of Cl2(g) results in the transfer of two moles of electrons from the Cl- to the anode: 2 Cl-(aq) Cl2(g) + 2e1706 Faraday: The faraday is the electrical charge carried by one mole of electrons. 1707 Faraday: The faraday is the electrical charge carried by one mole of electrons. Symbol: F 1708 Faraday: The faraday is the electrical charge carried by one mole of electrons. Symbol: F Unit of charge is the Coulomb, symbol C. 1709 Faraday: The faraday is the electrical charge carried by one mole of electrons. Symbol: F Unit of charge is the Coulomb, symbol C. Unit of electrical current is the Ampere, symbol A. 1710 Faraday: The faraday is the electrical charge carried by one mole of electrons. Symbol: F Unit of charge is the Coulomb, symbol C. Unit of electrical current is the Ampere, symbol A. A coulomb is the quantity of electrical charge passing a point in a second when the current flowing is 1 ampere. 1711 Faraday: The faraday is the electrical charge carried by one mole of electrons. Symbol: F Unit of charge is the Coulomb, symbol C. Unit of electrical current is the Ampere, symbol A. A coulomb is the quantity of electrical charge passing a point in a second when the current flowing is 1 ampere. Q = It 1712 Faraday: The faraday is the electrical charge carried by one mole of electrons. Symbol: F Unit of charge is the Coulomb, symbol C. Unit of electrical current is the Ampere, symbol A. A coulomb is the quantity of electrical charge passing a point in a second when the current flowing is 1 ampere. Q = It where the charge Q is in coulombs, the time t is in seconds, and the current I is in amperes. 1713 Faraday: The faraday is the electrical charge carried by one mole of electrons. Symbol: F Unit of charge is the Coulomb, symbol C. Unit of electrical current is the Ampere, symbol A. A coulomb is the quantity of electrical charge passing a point in a second when the current flowing is 1 ampere. Q = It where the charge Q is in coulombs, the time t is in seconds, and the current I is in amperes. Unit wise: 1C=1As 1714 Now 1 F = 96485 C mol-1 That is, 1 mole e- carries a charge of 96485 C of charge. 1 mol e- = 96485 C 1715 Example: A current of 0.452 A is passed for 1.50 hours through an electrolytic cell containing molten MgCl2. Write the electrode reactions, the overall reaction, and calculate the amount of products formed at the electrodes. 1716 Example: A current of 0.452 A is passed for 1.50 hours through an electrolytic cell containing molten MgCl2. Write the electrode reactions, the overall reaction, and calculate the amount of products formed at the electrodes. The only ions present in molten MgCl2 are Mg2+ and Cl-. 1717 Example: A current of 0.452 A is passed for 1.50 hours through an electrolytic cell containing molten MgCl2. Write the electrode reactions, the overall reaction, and calculate the amount of products formed at the electrodes. The only ions present in molten MgCl2 are Mg2+ and Cl-. Cathode reaction: Mg2+(l) + 2eMg(l) 1718 Example: A current of 0.452 A is passed for 1.50 hours through an electrolytic cell containing molten MgCl2. Write the electrode reactions, the overall reaction, and calculate the amount of products formed at the electrodes. The only ions present in molten MgCl2 are Mg2+ and Cl-. Cathode reaction: Mg2+(l) + 2eMg(l) Anode reaction: 2 Cl-(l) Cl2(g) + 2e- 1719 Example: A current of 0.452 A is passed for 1.50 hours through an electrolytic cell containing molten MgCl2. Write the electrode reactions, the overall reaction, and calculate the amount of products formed at the electrodes. The only ions present in molten MgCl2 are Mg2+ and Cl-. Cathode reaction: Mg2+(l) + 2eMg(l) Anode reaction: 2 Cl-(l) Cl2(g) + 2eOverall reaction: Mg2+(l) + 2 Cl-(l) Mg(l) + Cl2(g) 1720 The number of coulombs of electricity is obtained from 1721 The number of coulombs of electricity is obtained from Q = It 1722 The number of coulombs of electricity is obtained from Q = It 3600s x 1C (0.452 A)(1.50 hours) x = 1 hour 1 As 1723 The number of coulombs of electricity is obtained from Q = It 3600s x 1C (0.452 A)(1.50 hours) x = 1 hour 1 As = 2.44 x 103 C 1724 The number of coulombs of electricity is obtained from Q = It 3600s x 1C (0.452 A)(1.50 hours) x = 1 hour 1 As = 2.44 x 103 C mass of Mg formed 1 mol e 1mol Mg 24.3g Mg = (2.44x 103 C) 96485 C 2mol e - 1mol Mg 1725 The number of coulombs of electricity is obtained from Q = It 3600s x 1C (0.452 A)(1.50 hours) x = 1 hour 1 As = 2.44 x 103 C mass of Mg formed 1 mol e 1mol Mg 24.3g Mg = (2.44x 103 C) 96485 C 2mol e - 1mol Mg = 0.307 g Mg 1726 mass of Cl2 formed 1727 mass of Cl2 formed - 1mol Cl 70.9 g Cl 1 mol e 2 2 = (2.44x 103 C) 96485 C 2mol e - 1mol Cl2 1728 mass of Cl2 formed - 1mol Cl 70.9 g Cl 1 mol e 2 2 = (2.44x 103 C) 96485 C 2mol e - 1mol Cl2 = 0.896 g Cl2 1729 Example: What current would have to be passed for 2.250 x 103 s to produce 0.500 g Mg in the electrolysis of molten MgCl2? 1730 Example: What current would have to be passed for 2.250 x 103 s to produce 0.500 g Mg in the electrolysis of molten MgCl2? First calculate the number of coulombs needed. 1731 Example: What current would have to be passed for 2.250 x 103 s to produce 0.500 g Mg in the electrolysis of molten MgCl2? First calculate the number of coulombs needed. 1 mol Mg 2 mol e 96485 C Q = 0.500 g Mg 24.3g Mg 1mol Mg 1 mol e- 1732 Example: What current would have to be passed for 2.250 x 103 s to produce 0.500 g Mg in the electrolysis of molten MgCl2? First calculate the number of coulombs needed. 1 mol Mg 2 mol e 96485 C Q = 0.500 g Mg 24.3 g Mg 1 mol Mg 1 mol e = 3.97 x 103 C 1733 Example: What current would have to be passed for 2.250 x 103 s to produce 0.500 g Mg in the electrolysis of molten MgCl2? First calculate the number of coulombs needed. 1 mol Mg 2 mol e 96485 C Q = 0.500 g Mg 24.3 g Mg 1 mol Mg 1 mol e = 3.97 x 103 C Now from Q = I t, we have 1734 Example: What current would have to be passed for 2.250 x 103 s to produce 0.500 g Mg in the electrolysis of molten MgCl2? First calculate the number of coulombs needed. 1 mol Mg 2 mol e 96485 C Q = 0.500 g Mg 24.3 g Mg 1 mol Mg 1 mol e = 3.97 x 103 C Now from Q = I t, we have 3 3.97 x 10 C 1 As Q I = t 2.250 x 103 s 1C 1735 Example: What current would have to be passed for 2.250 x 103 s to produce 0.500 g Mg in the electrolysis of molten MgCl2? First calculate the number of coulombs needed. 1 mol Mg 2 mol e 96485 C Q = 0.500 g Mg 24.3 g Mg 1 mol Mg 1 mol e = 3.97 x 103 C Now from Q = I t, we have 3 3.97 x 10 C 1 As Q I = t 2.250 x 103 s 1C = 1.76 A 1736 Galvanic Cells Galvanic Cell (Voltaic Cell): A cell in which energy released from a spontaneous chemical reaction is used to generate electricity. 1737 1738 A + B B+ + A- 1739 A + B B+ + A- 1740
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