3 1 0 2 3 0 2 1 3 1 0 3 1 is a linear combination of 2 0 3 1 3 2 depends upon 3 1 0 1 and and 0 1 0 0 1 0 3 1 0 is called a DEPENDENT set. 2 0 1 3 , 1 , 0 When one vector in a set is a linear combination of other vectors in the set, then the set is said to be DEPENDENT. Suppose w, x, y, z is dependent. One of the vectors, x , is a linear combination of the others: x aw by cz Let’s say x aw by cz 0 A nontrivial linear combination of the vectors produces the zero vector. At least one coefficient is not 0. When one vector in a set is a linear combination of other vectors in the set, then the set is said to be DEPENDENT. Suppose w, x, y, z is dependent. One of the vectors, x , is a linear combination of the others: x aw by cz Let’s say x aw by cz 0 A nontrivial linear combination of the vectors produces the zero vector. At least one coefficient is not 0. Is the set 1 0 0 0 , 1 , 0 0 0 1 dependent? 1 0 0 0 c1 0 c2 1 c3 0 0 0 0 1 0 Is the set 1 0 0 0 , 1 , 0 0 0 1 1 0 0 0 0 0 1 0 0 dependent? 0 0 0 0 1 0 This is TRIVIAL. All coefficients are 0’s. Is the set 1 0 0 0 , 1 , 0 0 0 1 dependent? NO 1 0 0 0 c1 0 c2 1 c3 0 0 0 0 1 0 Is there any way to do this without using ALL ZEROS? NO 1 0 0 0 , 1 , 0 is an INDEPENDENT SET 0 0 1 definition: v1 , v2 , v3 ,....vn is an INDEPENDENT set iff c1v1 c2 v2 c3v3 .... cn vn 0 ONLY IF c1 c2 c3 ....... cn 0 The ONLY linear combination of the vectors to produce the zero vector is the TRIVIAL one. Suppose one of these is not 0. Let’s say c2 0 c1v1 c2 v2 c3v3 .... cn vn 0 c2 v2 c1v1 c3v3 .... cn vn c3 cn c1 v2 v1 v3 .... vn c2 c2 c2 v2 DEPENDS on the other vectors in the set! 1 1 2 Is the set 1 , 2 , 5 independent? 1 1 2 1 1 2 0 c1 1 c2 2 c3 5 0 1 1 2 0 1c1 1c 2 2c3 0 1c1 2c 2 5c3 0 1c1 1c 2 2c3 0 1 1 2 1 , 2 , 5 1 1 2 Is the set independent? 1 1 2 0 c1 1 c2 2 c3 5 0 1 1 2 0 1c1 1c 2 2c3 0 1c1 2c 2 5c 3 0 1c1 1c 2 2c3 0 2 0 1 1 1 2 5 0 1 1 2 0 Reduces to 1 0 1 0 0 1 3 0 0 0 0 0 1 1 2 1 , 2 , 5 1 1 2 Is the set independent? 1 1 2 0 c1 1 c2 2 c3 5 0 1 1 2 0 1c1 1c 2 2c3 0 1c1 2c 2 5c 3 0 1c1 1c 2 2c3 0 c1 = 1 c1 = c 3 c2 = -3 c2 = -3c3 Let c3 = 1 1 0 1 0 0 1 3 0 0 0 0 0 1 1 2 1 , 2 , 5 1 1 2 NO independent? Is the set 1 1 2 0 c 11 1 c -3 2 2 c 1 3 5 0 1 1 2 0 1c1 1c 2 2c3 0 1c1 2c 2 5c 3 0 1c1 1c 2 2c3 0 c1 = 1 c1 = c 3 c2 = -3 c2 = -3c3 Let c3 = 1 1 0 1 0 0 1 3 0 0 0 0 0 1 1 2 1 , 2 , 5 1 1 2 NO independent? Is the set 1 1 2 0 c 11 1 c -3 2 2 c 1 3 5 0 1 1 2 0 1 1 2 c11 1 c 32 2 c -13 5 1 1 2 1 1 2 Is the set 1 , 2 , 5 independent? 1 1 3 1 1 2 0 c1 1 c 2 2 c3 5 0 1 1 3 0 1c1 1c 2 2c3 0 1c1 2c 2 5c3 0 1c1 1c 2 3c3 0 1 1 , 1 Is the set 1 c1 1 c 2 1 1 2 , 1 2 5 3 1 2 c3 1 independent? 2 0 5 0 3 0 1c1 1c 2 2c 3 0 1c1 2c 2 5c 3 0 1c1 1c 2 3c 3 0 1 1 2 0 1 2 5 0 1 1 3 0 Reduces to 1 0 0 0 0 1 0 0 0 0 1 0 1 1 , 1 Is the set 1 2 , 1 2 5 3 independent? YES 1 1 2 0 c1 1 c 2 2 c3 5 0 1 1 3 0 1c1 1c 2 2c 3 0 1c1 2c 2 5c 3 0 1c1 1c 2 3c 3 0 ONLY IF c1 = 0 c2 = 0 c3 = 0 1 0 0 0 0 1 0 0 0 0 1 0
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