Math Tech IIII, Feb 26 Mean, Standard Deviation, and Expected Value of Discrete Probability Distributions Book Sections: 4.1 Essential Questions: How can I compute the probability of any event? How do I compute and interpret mean, standard deviation and expected value of a discrete probability distribution? Standards: DA-5.10, DA-4.3, S.MD.1, .2, .3 Discrete Probability Distributions • Discrete probability distribution – a table list all possible values of a random variable and the probability of that value occurring, and satisfying the following conditions: 0 ≤ P(x) ≤ 1 P(x) 1 Computing Statistics • We can compute the mean and standard deviation of a random variable, using the distribution table. • This is a distribution and not a sample, we will now call mean by another name, μ, and standard deviation by σ (mu and sigma). In here, we’re just going to let Texas handle this end of it. Discrete Probability Distributions • In a discrete probability distribution the mean is equal to the expected value of the distribution. • Often, these terms are used interchangeably. Calculator Computations • We load all x values into L1 and all P(x) values in L2, and do 1-var stat computations on both lists. Looks like: 1-Var Stats L1, L2 Using Calculator statistics Name Symbol Mean μ Standard Deviation σ Look for on Calculator X σx Example 1 Compute the mean and standard deviation of the following discrete probability distribution: x 0 P(x) 0.69 μ= σ= 1 0.20 2 3 0.08 0.02 4 5 0.01 0.01 Example 2 Find the mean and standard deviation of the following discrete probability distribution: x 4 P(x) 0.31 μ= σ= 6 0.10 8 10 0.22 0.07 12 15 0.18 0.12 Interpreting Statistics + 1 • The mean of a random variable is what you would expect to happen over thousands of trials • The Expected value of a distribution is equal to the mean of the distribution • In a game situation, an expected value of 0 implies a fair game • In a profit-loss analysis (or situation), an expected value of 0 is the break even point • A negative value gives you an expected loss • A positive value gives you an expected gain Creating a Distribution for a Situation • To accomplish a gain-loss scenario, you can create a probability distribution for the gains and compute the mean. From this, you will know expected gain (or loss if negative) • Follow the next example, it is a template for all such examples: Example At a raffle, 1500 tickets are sold at $2 each for four prizes of $500, $250, $150, and $75. If you buy 1 ticket, what is your expected gain. (Ans: The expected value of some distribution) Example At a raffle, 1500 tickets are sold at $2 each for four prizes of $500, $250, $150, and $75. If you buy 1 ticket, what is your expected gain. (Ans: The expected value of some distribution) Here is the discrete probability distribution for this situation. We will load it into the calculator, as is. Gain, x P(x) $498 1 1500 $248 $148 $73 1 1500 1 1500 1 1500 -$2 1496 1500 μ= Gain-Loss – Another Spin • You can also compute the mean directly in a gain-loss situation. This technique is especially good if there are only 2 possible outcomes. It will work for more, but gets more cumbersome. • Expected value = x1·P(x1) + x2 ·P(x2) Another Pivotal Example A ball club makes $450,000 when it does not rain. It also loses $250,000 when there is a rain out. If the probability of it raining is .32, find the expectation of profit? Classwork: Handout CW 2/26, 1-6 Homework – None
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