Chapter 6 Practice Test Group 3 with solutions Chapter 6

Lee Cantrell, Ben Arrants, Jack Blahouse, Marcus Lynch
Chapter 6 practice test
6.1
1. Find the general solution to the exact differential equation:
𝑑𝑦
1
= 5π‘₯ ln 5 + 2
𝑑π‘₯
π‘₯ +1
Solution:
𝑦 = 5π‘₯ + tanβˆ’1 π‘₯ + 𝑐
Find the anti-derivative
2. Solve the initial value problem explicitly:
𝑑𝑣
= 4 sec 𝑑 tan 𝑑 + 𝑒 𝑑 + 6𝑑 π‘Žπ‘›π‘‘ 𝑣 = 5 π‘€β„Žπ‘’π‘› 𝑑 = 0
𝑑π‘₯
Solution:
𝑣 = 4 sec 𝑑 + 𝑒 𝑑 + 3𝑑 2 + 𝑐
Find the anti-derivative
5 = 4 sec(0) + 𝑒 (0) + 3(0)2 + 𝑐
Plug in the points given
5= 4+1+0+𝑐
Simplify
0=𝑐
Solve for c
πœ‹
πœ‹
Answer: [𝑦 = 4 sec 𝑑 + 𝑒 𝑑 + 3𝑑 2 (βˆ’ 2 < 0 < 2 )]
3. Solve the initial value problem using the Fundamental Theorem. (Your answer will contain definite
integral.)
𝐹 β€² (π‘₯) = 𝑒 cos π‘₯ π‘Žπ‘›π‘‘ 𝐹(2) = 9
Solution:
π‘₯
𝐹(π‘₯) = ∫2 𝑒 cos 𝑑 𝑑𝑑 + 9
4. Use Euler’s method with increments of βˆ†π‘₯ = 0.1 to approximate the value of y when π‘₯ = 1.3.
𝑑𝑦
= 𝑦 βˆ’ π‘₯ π‘Žπ‘›π‘‘ 𝑦 = 2 π‘€β„Žπ‘’π‘› π‘₯ = 1
𝑑π‘₯
Solution:
(x, y)
(1, 2)
(1.1, 2.1)
(1.2, 2.2)
𝑑𝑦
=π‘¦βˆ’π‘₯
𝑑π‘₯
1
1
1
βˆ†π‘₯
𝑑𝑦
βˆ†π‘₯
𝑑π‘₯
0.1
0.1
0.1
βˆ†π‘¦ =
0.1
0.1
0.1
(π‘₯ + βˆ†π‘₯, 𝑦 + βˆ†π‘¦)
(1.1, 2.1)
(1.2, 2.2)
(1.3, 2.3)
Answer: [𝐹(1.3) = 2.3]
5. Use Euler’s method with increments of βˆ†π‘₯ = βˆ’0.1 to approximate the value of y when π‘₯ = 1.7
𝑑𝑦
= π‘₯ βˆ’ 𝑦 π‘Žπ‘›π‘‘ 𝑦 = 2 π‘€β„Žπ‘’π‘› π‘₯ = 2
𝑑π‘₯
Solution:
(x, y)
(2, 2)
(1.9, 2)
(1.8, 2.01)
𝑑𝑦
=π‘₯βˆ’π‘¦
𝑑π‘₯
0
-0.1
-0.21
βˆ†π‘₯
-0.1
-0.1
-0.1
𝑑𝑦
βˆ†π‘₯
𝑑π‘₯
0
0.01
0.021
βˆ†π‘¦ =
(π‘₯ + βˆ†π‘₯, 𝑦 + βˆ†π‘¦)
(1.9, 2)
(1.8, 2.01)
(1.7, 2031)
Answer: [𝐹(1.7) = 2.031]
Use the indicated substitution to evaluate the integral. Confirm your answer by differentiation
1.
sec(2x)tan(2x)dx, u=2x
Solution:
2.
sin(3x)dx, u=3x
Solution:
Use substitution to evaluate the integral
3.
Solution:
4.
Solution: