Galton box Problem 14 Reporter: Krasikov Aleksey Team: Voronezh One Belgrade, Serbia 2015 Problem In the Galton box, a regular 2D lattice of obstacles disperses a thin flow of falling particles. When falling on the bottom of the box, the particles show a normal distribution. Use various types or particles and different arrangements of the obstacles to find the conditions when the distribution is no longer normal Investigation goals 1. Explain the occurrence the normal distribution in Galton box 2. Find numerical border between normal and binomial distribution 3. Identify the normal distribution break parameter 4. Set an experiment and investigate this phenomenon What is a Galton box? 1123 Balls are thrown in the center of the box The obstacles are arranged in a checkerboard pattern Balls fall in the cell at the bottom 4 How does it work? 1123 The ball falls at the first obstacle Ball Turn left Turn right First obstacle 1 π= 2 1 π= 2 It can bounce in the right and left side If conditions are ideal, the probability of a bounce in different directions will be equal 5 Check it Modelling our experiments in Algodoo 6 Check it 1123 Modelling in Algodoo Physics 20 18 16 The number of balls 14 12 10 8 6 4 2 0 Columns 7 How does it work? 1123 Turn left (1/2) The ball is involved in two independent trials Turn right (1/2) First series Turn left (1/2) Turn right (1/2) Second series In each such test ball can bounce to the right side or to the left side Second series 1 π= 4 1 π = 2 1 π= 4 Binomial distribution 8 Check it 1123 Modelling in Algodoo Physics 20 18 16 The number of balls 14 12 10 8 6 4 2 0 Columns 9 How does it work? First series Second series If π β β, the distribution tends to normal Second series ... N series 10 Binomial vs normal distribution The binomial distribution is a distribution of the numbers of "successes" in n independent experiments (probability is constant) 11 Binomial vs normal distribution The binomial distribution is discrete, because it is concentrated at several points. E.g.: The number of heads (or tails) has binomial distribution 12 Binomial vs normal distribution The normal distribution is continuous. It coincides with the Gaussian function 13 Normal distribution Binomial distribution turns to normal for certain values of the parameters. E.g.: This occurs when the Galton box has a large number of series with obstacles (n>10) Binomial distribution β Normal distribution 14 Check it n=1 n=3 n=6 40 30 50 35 30 20 30 The number of balls The number of balls The number of balls 25 40 25 20 15 20 15 10 10 10 5 5 0 0 Columns 0 Columns Columns Modelling in βGalton boxβ Binomial distribution β Normal distribution 15 Check it n=12 n=9 45 30 40 35 The number of balls The number of balls 25 20 15 10 30 25 20 15 10 5 5 0 0 Columns Columns Modelling in βGalton boxβ Binomial distribution β Normal distribution 16 When does Galton box work? R β1πΏ βπ π - expected value π 1πΏ πΏ - standard deviation Modelling in Algodoo. We can see normal distribution If πΏ β₯ π , Galton box works 17 When doesnβt Galton box work? R Modelling in Algodoo. We donβt see normal distribution If πΏ < π , Galton box doesnβt work β1πΏ βπ π - expected value πΏ - standard deviation π 1πΏ 18 Experimental investigation π(π₯) = 1 πΏ 2π (π₯βπ)2 β π 2πΏ2 Gaussian function: πΏ- standard deviation π- expected value 19 Experimental investigation βπ‘ πΏ= π=β1 βπ₯2 βπ₯1 β1 ππ 2 π₯π + π 0 1 π‘ π=1 π₯1 ππ 2 π₯π π πΏ- standard deviation 2π‘ + 2- number of columns π₯π - coordinate of i-column ππ - the number of balls in the i-column ππ - the total number of balls π₯2 20 Experimental investigation Variable parameters: 1. the ratio between the distance from one pin to another and the radius of the ball; 2. the shape of particles; 3. the shape of obstacles If πΏ < π , Galton box doesnβt work Find out the πΏ If πΏ β₯ π , plot the Gaussian functions Experiments 21 1) Ratio between distance and radius πΏ π= π Ball First series d Second series Second series L S=1 S=6 S=20 22 1) Ratio between distance and radius S=1 R=1 β1 πΏ = 1,54 0 1 23 1) Ratio between distance and radius S=1 practice line theoretical line 0.3 πΏ>π 1,54 > 1 Probability 0.25 0.2 0.15 0.1 0.05 0 -5 -4 -3 -2 -1 0 Column 1 2 3 4 5 There for we can see, that the Galton box works 24 1) Ratio between distance and radius S=6 S=20 R R πΏ < π , thatβs why Galton box doesnβt work 25 Real experiment setup L=5 mm Changing the frequency of obstacles L=10 mm 26 1) Ratio between distance and radius πΏ>π 1,75 > 1 πΏ>π 1,43 > 1 theoretical line theoretical line practise 0.3 0.25 0.25 0.2 Probability Probability 0.2 0.15 0.1 0.15 0.1 0.05 0.05 0 0 -6 -4 -2 0 Columns practise 2 4 6 -6 -4 -2 0 Columns 2 4 6 27 1) Ratio between distance and radius πΏβπ πΏβ1 πΏ<π πΏ = 0,85 Galton box doesnβt work 28 Explanation Small particles pass through without collision, so particles concentrate in the central column First series Second series Second series 29 2) Shape of particles Oval Triangle Square Star Triangle with a displaced center of mass 30 2) Shape of particles Modelling in Algodoo Physics 31 2) Shape of particles Modelling in Algodoo Physics 32 Explanation Despite the fact that we change the shape of the particles, the possibility of deviation to the right and left side persists. Thatβs why we can see the normal distribution 33 3) Shape of obstacles Obstacles in the shape of triangles 34 3) Shape of obstacles Explanation: we change the shape of obstacles, so the probability of deviation to the left side become bigger. Therefore, the normal distribution was broke 35 Conclusion 1. We explained how Galton box works 2. Modelled and made an experiment in reality 3. Explained difference between normal and binomial distribution 4. If the number of series strive to infinity, the distribution tends to normal Conclusion 5. If standard deviation smaller then distance between columns, Galton box doesnβt work, in another way it works. If particles is very small, normal distribution will be break 6. Distribution doesnβt depends on the shape of particles (and center of mass of the one particle) 7. If we change the probability of deviation (change shape of obstacles), normal distribution will be break Thanks for attention! 38
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