Cent. Eur. J. Math. • 11(2) • 2013 • 357-367 DOI: 10.2478/s11533-012-0051-5 Central European Journal of Mathematics Uniformly bounded composition operators in the Banach space of bounded (p, k)-variation in the sense of Riesz–Popoviciu Research Article Francy Armao1∗ , Dorota Głazowska2† , Sergio Rivas3‡ , Jessica Rojas1§ 1 Facultad de Ciencias, Departamento de Matemática, Universidad Central de Venezuela, Caracas, Venezuela 2 Faculty of Mathematics, Computer Science and Econometrics, University of Zielona Góra, Szafrana 4a, 65-516 Zielona Góra, Poland 3 Departamento de Matemática, Universidad Nacional Abierta, Caracas, Venezuela Received 11 October 2011; accepted 27 February 2012 Abstract: We prove that if the composition operator F generated by a function f : [a, b] × R → R maps the space of bounded (p, k)-variation in the sense of Riesz–Popoviciu, p ≥ 1, k an integer, denoted by RV(p,k) [a, b], into itself and is uniformly bounded then RV(p,k) [a, b] satisfies the Matkowski condition. MSC: 47H30, 26A45, 47B38 Keywords: Nemytskij (composition, superposition) operator • Uniformly bounded mapping • Uniformly continuous mapping • de la Vallée Poussin second-variation • Popoviciu k-th variation © Versita Sp. z o.o. 1. Introduction Let a, b ∈ R, a < b, be fixed. For a given function f : [a, b] × R → R the nonlinear composition operator (also called superposition operator, substitution operator or Nemytskij operator) F : R[a,b] → R[a,b] , generated by f, is defined by F x(t) = f(t, x(t)), ∗ † ‡ § E-mail: E-mail: E-mail: E-mail: x ∈ R[a,b] , t ∈ [a, b]. (1) [email protected] [email protected] [email protected] [email protected] 357 Unauthenticated Download Date | 7/28/17 10:27 PM Uniformly bounded composition operators in the Banach space of bounded (p, k)-variation in the sense of Riesz–Popoviciu Here R[a,b] denotes the family of all functions x : [a, b] → R. In spite of its simple form, the behaviour of this locally defined operator, cf. [19, 28–30, 43–46], exhibits many surprising and even pathological features in various function spaces. For instance, applying the Banach contraction principle (or one of its generalizations) to find the solutions x in a function Banach space (X , k · k), X ⊂ R[a,b] , of the nonlinear iterative functional equation x(t) = f(t, x(φ(t))), cf. for instance [17], it is necessary to guarantee that F is Lipschitzian, i.e. that kF x − F yk ≤ K kx − yk, x, y ∈ X . (2) It turns out, however, that sometimes this leads to a strong degeneracy: in some classical function spaces X , the operator (1) satisfies (2) if and only if the corresponding function f has the form f(t, u) = α(t) + β(t)u, α, β ∈ X . (3) This means, roughly speaking, that one may apply classical fixed point principles for contraction type maps only if the underlying problem is actually linear. To the best of our knowledge, the first who observed the kind of degeneracy phenomenon for composition operators described above was Janusz Matkowski. More specifically, Matkowski (in part with coauthors) proved that Lipschitz continuous operators (1) in X are generated only by affine functions (3), if X is the space Cm [a, b] of m times continuously differentiable functions [22], the Sobolev space W1p [a, b] of functions with distributional first derivative in Lp [a, b] [26], or the space BVp2 [a, b] of functions of bounded (p, 2)-variation [25]. Likewise, an analogous result was proved by Matkowska [21] for the space Cα [a, b] of Hölder continuous functions of order α < 1, by Lupa [20] for the space Cn,α [a, b] of functions with Hölder continuous n-th derivative, by Sieczko [39] for the space ACn [a, b] of functions with absolutely continuous n-th derivative, by Knop [15] for the space Lipn [a, b] of functions with Lipschitz continuous n-th derivative, by Merentes and Rivas [33] for the space RVp [a, b] of functions of bounded generalized p-variation in the Riesz sense, and by Merentes [31, 32] for the space RVφ [a, b] of functions of bounded generalized φ-variation in the Riesz sense. The Nemytskij operator (1) appears frequently in connection with integral equations and iterative functional equations. Moreover, Nemytskij operators satisfying condition (2) are considered also in the study of systems with hysteresis [16] and difference equations [40]. Like in [2], we shall say that the composition operator (1) has Matkowski’s property if, whenever this operator maps the space X into the space Y and satisfies some additional condition like global Lipschitz continuity, uniform continuity or other, the generator function f has the form (3). In the case when X = Y = BV[a, b], where BV[a, b] is the Banach space of functions of bounded variation, the degeneracy one encounters when a Lipschitz condition is imposed is somewhat different. Recall that, given a function f : [a, b] × R → R, if for any fixed y, f(·, y) has the left-hand limit lims→x− f(s, y) at each point x ∈ (a, b], then the left regularization f − of f is defined by f − (x, y) = h(a, y) for x = a, lim h(s, y) for a < x ≤ b. s→x− (4) Similarly, we define the right regularization f + of f. These regularizations are different from f only if f(·, y) is discontinuous from the left or right, respectively. Matkowski and Miś in [27] showed that if the composition operator F maps the space BV[a, b] into itself and satisfies condition (2), then there exist two functions α, β ∈ BV[a, b] continuous from the left on (a, b], such that f − (x, y) = α(x)y + β(x), (x, y) ∈ (a, b] × R. (5) 358 Unauthenticated Download Date | 7/28/17 10:27 PM F. Armao et al. Clearly, an analogous result is true for the right regularization. From this fact, Appell, Guanda and Väth observed in [2] that this is a weaker form of the Matkowski property. We shall say that the composition operator (1) has the weak Matkowski property if, whenever this operator maps the space X into the space Y and satisfies some additional condition like globally Lipschitz, uniformly continuous or other, the left regularization (4) (or right regularization) of the generator function f has the form (5). The above result has been further extended to several spaces of functions of generalized bounded variation in one variable [7–9, 12] and two variables [10, 11]. Below we give an example from [2] which shows that the Matkowski condition and the weak Matkowski condition are not equivalent. Example 1.1. Let {r0 , r1 , . . .} be an enumeration of all rational numbers in [0, 1], r0 = 0, and let g : R → R be any function satisfying g(0) = 0 and |g(u) − g(v)| ≤ L|u − v|. We define f : [0, 1] × R → R by g(u) 2k f(t, u) = 0 if t = rk , otherwise. Denote by P[0, 1] the family of all partitions of the interval [0, 1]. For any partition P = {t0 , t1 , . . . , tm } ∈ P[0, 1] and x ∈ BV[0, 1] we then have m X |F x(tj ) − F x(tj−1 )| ≤ 2 j=1 ∞ X |f(rk , x(rk ))| = 2 k=0 ∞ X |g(x(rk ))| ≤ 2L, 2k k=0 which shows that F maps the space BV[0, 1] into itself. Furthermore, for any x, y ∈ BV[0, 1] and P ∈ P[0, 1], as above we obtain the following estimation: var(F x − F y, P, [0, 1]) = m m X X F x(tj ) − F y(tj ) − F x(tj−1 ) + F y(tj−1 ) ≤ 2 f(tj , x(tj )) − f(tj , y(tj )) j=1 j=1 ∞ ∞ X X |g(x(rk )) − g(y(rk ))| f(rk , x(rk )) − f(rk , y(rk )) ≤ 2 ≤ 2k k=0 k=0 ≤ 2L ∞ X |x(rk ) − y(rk )| ≤ 2Lkx − ykBV . 2k k=0 This, together with the trivial estimate |F x(0) − F y(0)| ≤ L|x(0) − y(0)|, shows that F satisfies the global Lipschitz condition (2) with K = 2L, although f is not of the form (3). We can see that f − = f + = 0 for the function f in Example 1.1, in accordance with [2, Theorem 2]. Notice that there are important function spaces having neither the Matkowski property nor the weak Matkowski property. For example, Appell, Guanda and Väth proved in [2] that the condition (2) in the space C[a, b] equipped with the norm kukC = max |u(t)| a≤t≤b is equivalent to the Lipschitz condition |f(t, u) − f(t, v)| ≤ K |u − v|, a ≤ t ≤ b, u, v ∈ R, for the function f(x, ·) (with the same Lipschitz constant as in (2)); this is of course what one should expect in “reasonable” function spaces. A similar result holds for the Lebesgue space Lp [a, b], 1 ≤ p < ∞, equipped with the norm b Z kukLp = |u(t)|p dt 1/p . a 359 Unauthenticated Download Date | 7/28/17 10:27 PM Uniformly bounded composition operators in the Banach space of bounded (p, k)-variation in the sense of Riesz–Popoviciu The strong degeneracy described above, occuring also in many familiar functions spaces, emphasizes a need of proving Lipschitz condition (2) or weaker uniform continuity, Matkowski [23], in order to get the Matkowski property. Matkowski [23] proved that the uniformly continuous Nemytskij operator, acting between the Banach spaces of Hölder functions, has the Matkowski property. Uniform continuity of composition operators has been considered in other functional Banach spaces [1, 3–6, 13, 14, 23]. It turns out [24], Lipschitz continuity and uniform continuity of the composition operator can be replaced by a rather weak uniform boundedness of the Nemytskij operator, cf. Definition 4.2. This notion has been recently applied by Wróbel [47] to the space of functions of bounded k-th variation in the sense of Popoviciu, cf. also [42]. In this paper, following an idea of Wróbel [47], we show that for a fixed p > 1, any uniformly bounded composition operator, mapping RV(p,k) [a, b] into itself, has the Matkowski property. 2. Riesz–Popoviciu space of functions of bounded (p, k)-variation and some related Banach spaces Throughout we will consider several normed spaces endowed with the following norms. I. Let Lip[a, b] denote the Banach space of all Lipschitz continuous functions u : [a, b] → R, equipped with the natural norm kukLip = |u(a)| + Lba (u), where u(s) − u(t) : a≤s<t≤b Lba (u) = sup s−t is the smallest Lipschitz constant of u on [a, b]. II. Let k ≥ 1 be an integer, u ∈ R[a,b] and t1 , . . . , tk+1 be distinct points, not necessarily in linear order, of [a, b]. Define the k-th divided difference of u as u[t1 ] = u(t1 ), u[t1 , t2 ] = u(t2 ) − u(t1 ) , t2 − t1 t2 6= t1 , u[t1 , . . . , tk , tk+1 ] = u[t2 , . . . , tk+1 ] − u[t1 , . . . , tk ] , tk − t1 tk 6= t1 , see [37]. For a partition P : a = t1 < . . . < tn = b of the interval [a, b], we define σk (u, P) = n−k n−k X X u[tj+1 , . . . , tj+k ] − u[tj , . . . , tj+k−1 ] = (tj+k − tj ) u[tj , . . . , tj+k ]. j=1 j=1 In 1933–34, Popoviciu [35] defined the concept of function of bounded k-variation of u as Vk (u, [a, b]) = Vk (u) = sup σk (u, P). P If Vk (u) < ∞ we say that u has finite k-variation and we denote by BVk [a, b] the vector space of such functions. For k = 1, BV1 [a, b] is the classic space of functions of bounded variation. For k = 2, BV2 [a, b] is the space of functions of second bounded variation given by de la Vallée Poussin in 1908 [41]. In the general case, it is known [38] that BVk [a, b] has a structure of Banach space with respect to the norm kukk = |u(a)| + · · · + |u(k−1) (a)| + Vk (u, [a, b]), u ∈ BVk [a, b]. 360 Unauthenticated Download Date | 7/28/17 10:27 PM F. Armao et al. There is another way to get this space using partitions of the interval [a, b] of the type P : a = t1 < . . . < tk ≤ tk+1 < . . . < t2k ≤ t2k+1 < . . . < tkn = b, (6) with at least 2k − 1 points considered and the functionals σbk defined as σbk (u, P) = σbk (u) = n−1 X u[tjk+1 , . . . , t(j+1)k ] − u[t(j−1)k+1 , . . . , tjk ]. j=1 Put bk (u, [a, b]) = V bk (u) = sup σbk (u, P). V P bk (u) < ∞ denote by BV c k [a, b]. In Lemma 3.1 we prove that BVk [a, b] = BV c k [a, b], The space of the functions u that satisfy V k ∈ N. III. In [34] Merentes, Sánchez and Rivas generalized the concept of functions of bounded variation introduced by Riesz in [36] as follows. Given a number p > 1, an integer k ≥ 1 and a function u ∈ R[a,b] , consider a partition of [a, b] by blocks of the type (6) and functions R σb(p,k) (u, P) n−1 X = j=1 !p u[tjk+1 , . . . , t(j+1)k ] − u[t(j−1)k+1 , . . . , tjk ] t(j+1)k − t(j−1)k+1 . t(j+1)k − t(j−1)k+1 Put b R (u, [a, b]) = V b R (u) = sup σbR (u, P). V (p,k) (p,k) (p,k) P b R (u) < ∞. The vector space of such It is said that u has bounded (p, k)-variation in the sense of Riesz–Popoviciu if V (p,k) functions is denoted by RV(p,k) [a, b]. For a function u ∈ RV(p,k) [a, b] we define the norm b R (u) kukR(p,k) = |u(a)| + |u0 (a)| + · · · + |u(k−1) (a)| + V (p,k) 1/p . One can show that RV(p,k) [a, b] with the norm k · kR(p,k) is a Banach space and it is called the space of functions of bounded (p, k)-variation in the sense of Riesz–Popoviciu. In [34] the following has been shown. Theorem 2.1 (generalization of the Riesz lemma). Let p > 1, k ∈ N. Then u ∈ RV(p,k) [a, b] if and only if u(k−1) ∈ AC[a, b] and u(k) ∈ Lp [a, b]. Moreover, Z b(p,k) (u, [a, b]) = V 1 ((k − 1)!)p b |u(t)|p dt, a u ∈ RV(p,k) [a, b]. From this result we immediately obtain that Ck [a, b] ⊂ RV(p,k) [a, b]. 361 Unauthenticated Download Date | 7/28/17 10:27 PM Uniformly bounded composition operators in the Banach space of bounded (p, k)-variation in the sense of Riesz–Popoviciu 3. Auxiliary results We begin this section with some lemmas. Lemma 3.1. If k ∈ N, then bk (u) ≤ Vk (u) ≤ 3k V bk (u), V u ∈ RV(p,k) [a, b], and c k [a, b]. BVk [a, b] = BV Proof. c k [a, b] and a ≤ t1 < . . . < tk+1 ≤ b. Choose arbitrarily b1 , . . . bk , c1 , . . . , ck so that Take u ∈ BV t1 < b1 < . . . < bk = t2 , tk < c1 < . . . < ck = tk+1 . Then u[t2 , . . . , tk+1 ] − u[t1 , . . . , tk ] ≤ u[t2 , . . . , tk+1 ] − u[b1 , . . . , bk ] + u[b1 , . . . , bk ] − u[c1 , . . . , ck ] bk (u, [t1 , tk+1 ]). + u[c1 , . . . , ck ] − u[t1 , . . . , tk ] ≤ 3 V Take arbitrary n ∈ N, n ≥ k + 1. Then for any partition P : a = t1 < . . . < tn = b of the interval [a, b] we have n−k n−k X X bk (u, [tj , tj+k ]) = u[tj+1 , . . . , tj+k ] − u[tj , . . . , tj+k−1 ] ≤ 3V j=1 j=1 bk (u, [t1 , t1+k ]) + · · · + V bk (u, [t1+k , t1+2k ]) + V bk (u, [t2+k , t2+2k ]) + · · · =3 V bk (u, [tn−2k , tn−k ]) + · · · + V bk (u, [tn−k , tn ]) bk (u, [t2+2k , t2+3k ]) + · · · + V +V bk (u, [t1 , t1+k ]) + V bk (u, [t2+k , t2+2k ]) + · · · + V bk (u, [tn−2k , tn−k ]) + · · · =3 V bk (u, [t1+k , t1+2k ]) + V bk (u, [t2+2k , t2+3k ]) + · · · + V bk (u, [tn−k , tn ]) , + V bk (u, [a, b]) and, consequently, whence σk (u, P) ≤ 3k V bk (u, [a, b]). Vk (u, [a, b]) ≤ 3k V c k [a, b] ⊂ BVk [a, b]. It follows that u ∈ BVk [a, b] which shows that BV Now assume that u ∈ BVk [a, b] and take n ∈ N and a partition P : a = t1 < . . . < tk ≤ tk+1 < . . . < t2k ≤ t2k+1 < . . . < tnk = b of the interval [a, b]. From the triangle inequality we get u[tjk+1 , . . . , t(j+1)k − u[t(j−1)k+1 , . . . , tjk ] ≤ u[tjk+1 , . . . , t(j+1)k ] − u[tjk , tjk+1 , . . . , tjk+k−1 ] + u[tjk , tjk+1 . . . , tjk+k−1 ] − u[tjk−1 , tjk , tjk+1 , . . . , tjk+k−2 ] + · · · + u[tjk−k+2 , tjk−k+3 , . . . , tjk, tjk+1 ] − u[t(j−1)k+1 , . . . , tjk ] = k−1 X u[tjk−i+1 , . . . , t(j+1)k−i ] − u[tjk−i , . . . , t(j+1)k−i−1 ], i=0 362 Unauthenticated Download Date | 7/28/17 10:27 PM F. Armao et al. for j = 1, . . . , n. Summing up these inequalities we obtain n−1 n−1 X k−1 X X u[tjk , . . . , t(j+1)k−1 ] − u[t(j−1)k+1 , . . . , tjk ] u[t(j−1)k+i+1 , . . . , t(j+1)k−i ] − u[tjk−i , . . . , t(j+1)k−ii−1 ] ≤ Vk (u, [a, b]), j=1 j=1 i=0 whence bk (u, [a, b]) ≤ Vk (u, [a, b]), V which completes the proof. c k [a, b], k ∈ N. This lemma guarantees that BVk [a, b] = BV Lemma 3.2 ([34, Proposition 2.1]). If p > 1 and k ∈ N, then 1/p bk (u) ≤ (b − a)1−1/p V b R (u) , V (p,k) u ∈ RV(p,k) [a, b]. Lemma 3.3. Let k ≥ 2 be a positive integer and 1 < p < ∞. Then there exists a positive constant s(k, p) > 0 such that kukLip ≤ s(k, p)kukR(p,k) , u ∈ RV(p,k) [a, b]. (7) Apply [47, Lemma 3] and the continuous embedding given in [34, Proposition 2.1] to get (7). 4. Main results We begin this section with the following Theorem 4.1. Let [a, b] ∈ R, a < b, be an interval, p > 1 a real number, k ≥ 2 a positive integer and let a function f : [a, b] × R → R be continuous with respect to the second variable. Suppose that the composition operator F generated by f acts from the space RV(p,k) [a, b] into itself and satisfies the following inequality: kF (u) − F (v)kR(p,k) ≤ γ ku − vkR(p,k) , u, v ∈ RV(p,k) [a, b], for some function γ : [0, ∞) → [0, ∞). Then there exist functions α, β ∈ RV(p,k) [a, b] such that f(t, x) = α(t)x + β(t), t ∈ [a, b], x ∈ R. (8) Proof. By hypothesis, for x ∈ R fixed, the constant function u(t) = x, t ∈ [a, b], is in RV(p,k) [a, b] and therefore F (u) = f(·, x) ∈ RV(p,k) [a, b], so f(·, x) is continuous for every x ∈ R. Let s, s ∈ [a, b], s < s, x1 , x2 , x 1 , x 2 ∈ R and consider the functions xi − x i (t − s) + xi , i = 1, 2. ui (t) = s−s These functions are straight lines that pass through the points (s, x1 ) and (s, x 1 ) in the case of u1 and points (s, x2 ) and (s, x 2 ) in the case of u2 . Thus, it follows that both functions have (p, k)-bounded variation. In addition, R x1 − x 1 − x2 + x 2 ku1 − u2 kR(p,k) = (t − s) + x − x 1 2 s−s = |x1 − x2 |. (p,k) 363 Unauthenticated Download Date | 7/28/17 10:27 PM Uniformly bounded composition operators in the Banach space of bounded (p, k)-variation in the sense of Riesz–Popoviciu On the other hand, as F (ui ) ∈ RV(p,k) [a, b], i = 1, 2, from Lemma 3.1 and Lemma 3.3, we get kF (u1 ) − F (u2 )kLip = |f(s, x1 ) − f(s, x2 ) − f(s, x 1 ) + f(s, x 2 )| ≤ K kF (u1 ) − F (u2 )kR(p,k) , |s − s| where K = 3s(p, k) max 1, (b − a)1−1/p . In this way, by hypothesis, it follows that |f(s, x1 ) − f(s, x2 ) − f(s, x 1 ) + f(s, x 2 )| ≤ K γ(|x1 − x2 |). |s − s| We set constants p, q ∈ R and let x1 = x 2 = (p + q)/2, x 1 = p, x2 = q in the above inequality. Then p + q p + q − f(s, q) − f(s, p) + f s, ≤ K γ(|x1 − x2 |)|s − s|. f s, 2 2 By continuity of f in the first variable, taking limit as s → s, we get p + q = f(s, p) + f(s, q), 2f s, 2 s ∈ [a, b], p, q ∈ R. Since the function f(t, ·) is continuous and satisfies the Jensen equation, see [18, p. 315], there are functions α, β : [a, b] → R satisfying (8), whence, for every x ∈ R the function f(·, x) ∈ RV(p,k) [a, b], we have β(t) = f(t, 0), α(t) = f(t, 1) − β(t), t ∈ [a, b], which implies that α, β ∈ RV(p,k) [a, b]. Matkowski [24] introduced the notion of a uniformly bounded operator and proved that any uniformly bounded composition operator acting between general Lipschitz function normed spaces must be of the form (3). Definition 4.2. Let Y and Z be two metric (or normed) spaces. We say that a mapping F : Y → Z is uniformly bounded if, for any t > 0, there exists a nonnegative real number γ(t) such that for any nonempty set B ⊂ Y we have diam B ≤ t =⇒ diam H(B) ≤ γ(t). Remark 4.3. Every uniformly continuous operator or Lipschitzian operator is uniformly bounded. Note that, under the assumptions of this definition, every bounded operator is uniformly bounded. Recently Wróbel [47] has shown that if the composition operator F , generated by f : [a, b] × R → R, maps the space BVk [a, b], k ≥ 2, into itself and is uniformly bounded, then the space BVk [a, b] satisfies the Matkowski condition; i.e., the function f has the form (3). Applying Theorem 4.1 we show the relevant result for the space RV(p,k) [a, b], which reads as follows: Theorem 4.4. Let a, b ∈ R, a < b, p > 1 a real number and k ≥ 2 a positive integer. Suppose that a function f : [a, b] × R → R is continuous with respect to the second variable. If the composition operator F generated by f acts from the space RV(p,k) [a, b] into itself and is uniformly bounded then there exist functions α, β ∈ RV(p,k) [a, b] with (8). 364 Unauthenticated Download Date | 7/28/17 10:27 PM F. Armao et al. Proof. Take any t ≥ 0 and u, v ∈ RV(p,k) [a, b] such that ku − vkR(p,k) ≤ t. Since diam {u, v} ≤ t, by uniform boundedness of F , we have diam F ({u, v}) ≤ γ(t), i.e., kF (u) − F (v)kR(p,k) = diam F ({u, v}) ≤ γ ku − vkR(p,k) , and the result follows from Lemma 4.1. Following the ideas developed in [47, Remark 1] we get the following corollary of this theorem, changing the condition that the function f is continuous in the second variable to the hypothesis of continuity from the right of the function γ and γ(0) = 0. Corollary 4.5. Let a, b ∈ R, a < b, p > 1 a real number and k ≥ 2 a positive integer. If the composition operator F , generated by f, acts from the space RV(p,k) [a, b] into itself and satisfies the following inequality: kF (u) − F (v)kR(p,k) ≤ γ ku − vkR(p,k) , u, v ∈ RV(p,k) [a, b], for some right continuous function γ : [0, ∞) → [0, ∞) such that γ(0) = 0, then there exist functions α, β ∈ RV(p,k) [a, b] satisfying (8). In a similar way as [23, Theorem 2] we get the following Corollary 4.6. Let a, b ∈ R, a < b, p > 1 a real number and k ≥ 2 a positive integer. If the composition operator F , generated by f, acts from the space RV(p,k) [a, b] into itself and is uniformly continuous with respect to the norm k · kR(p,k) , then there exist functions α, β ∈ RV(p,k) [a, b] satisfying (8). In addition, if we take γ(t) = ct, for some c > 0, we get [33, Theorem 1]. Acknowledgements This research has been partly supported by the Central Bank of Venezuela. We also want to give thanks to the library staff of B.C.V. for compiling the references. References [1] Acosta A., Aziz W., Matkowski J., Merentes N., Uniformly continuous composition operator in the space of φ-variation functions in the sense of Riesz, Fasc. 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