The free wavicle: motivation for the Schrödinger Equation • Einstein showed that hitherto wavelike phenonomenon had distinctly particle-like aspects: the photoeffect • photon energy is E = hf = ħw (h = Planck’s constant; f = frequency; w = angular frequency = 2pf) • let f(x,t) be a wave’s amplitude at position x at time t 2 2 f 2 f • the Classical Wave Equation reads (v = phase speed) 2 v 2 t x • first pass at a solution is any function in the form f(± x – vt); a pattern that moves at speed v to R (+) or to L (–) with fixed shape • can build linear combinations that satisfy CWE with different phase speeds, too, so the pattern may in fact evolve as it moves • consider the simple harmonic solution [wavelength l; period T 2p 2p 2p f ( x, t ) A cos x t A cos kx wt x vt A cos T l l 2p 2p l w where wavenumber k ; angular frequency w ; phase speed v l T T k Going to a complex harmonic wave • sines are as good as cosines, so if we take a complex sum as follows, it also works (assume A is real): i(kx wt ) f ( x, t ) Acos kx wt i sin kx wt Ae so we see Re f A cos kx wt and Im f A sin kx wt • the real and imaginary parts are 90° out of phase • in the complex plane, for some x, f orbits at w CW on a circle of radius A much simpler than ‘waving up and down’ • this will be the frequency of the quantum oscillations Einstein on waves de Broglie on particles hw photon energy E hf : w 2p relativity E 2 p 2 c 2 m02 c 4 but mass is zero E pc w h h p k de Broglie wavelength l c l p Non-relativistic wavicle physics • free Non-Relativistic Massive Particle has • non-free NRMP has p 2 2k 2 EK 2m 2m p2 2k 2 E K V ( x) V ( x) V ( x) 2m 2m • we connect this energy to the photon energy 2k 2 V ( x) w 2m • let the wavicle amplitude function be written Y(x,t) and for a free wavicle we take the earlier complex form Y( x, t ) Aei(kx wt ) Y 2Y 2 note iwY (fails for sine/cosin e form) and k Y (works) 2 t x 2k 2 the NRMP energy equation, with Y inserted : 2m Y ( x, t ) V ( x ) Y ( x , t ) E Y ( x , t ) 2 2 Y ( x, t ) Y ( x, t ) Time - Dependent Schrodinge r Equation V ( x ) Y ( x , t ) i 2m t x 2 • compare to classical wave equation (order, reality..) What is this thing, the wavefunction Y(x,t)? • it contains information about physics: position, momentum, kinetic energy, total energy, etc. using operators pˆ i x xˆ x 2 2 2 ˆ p Kˆ 2m 2m x 2 2 2 Eˆ : Hˆ V ( x) 2 2m x • we assume that TDSE also works for a non-free particle if energy is conserved (V = V(x) so its operator is trivial) • Born (Max) interpretation of complex wavefunctionY(x,t) -- Y*Y = r(x,t) probability density at time t; Y = probability amplitude -- Y*Y dx = probability that, at time t, particle is between x and x + dx b Pab Y * Ydx probabilit y that particle is in interval a x b, at time t a 1 Y * Ydx wavefunction is said to be normalized at every time Q : Y * (Qˆ Y )dx one ' sandwiches' the operator and it acts to the right Some peculiarities of the free wavicle f(x,t) • it exists finitely everywhere so does not represent a ‘bound state’ 2mE k 2 i ( kxwt ) i ( kxwt ) f ( x, t ) Ae so f * ( x, t ) Ae where k ;w 2m f * f A2 so the probabilit y is constant at any time at any place!! f*f dx so the free wavicle is not normalizab le in this fashion! - vphase : vquantum w k k 2 2m k k 2 E k whereas vgroup : vclassical 2m m m • we will revisit these ideas again but we need a lot more insight into the subtle distinctions between bound states (which are discrete) and free states (which form a continuum) • for now, the normalization integral IS infinite but it will turn out that a free wavicle with any other wavenumber is orthogonal – so the infinity is really a dirac delta function in ‘k-space’ Mathematical attributes of Y • it must be ‘square-integrable’ over all space, so it has to die off sufficiently quickly as x ± ∞, to guarantee normalizability • the free wavicle fails this test! Normalizing it is tricky! • no matter how pathological V(x), Y is piecewise continuous in x • let’s check whether Yx,t ‘stays’ normalized as time goes by.. d dt Y * Ydx Y * Y dx [since the boundary is not changing with time ] t Y Y * Y Y * t dx t this thing should be zero!! 2 2 Y ( x, t ) Y ( x, t ) TDSE reads V ( x ) Y ( x , t ) i 2m t x 2 Y i 2 Y iV Y 2 t 2m x h 2 2 Y * ( x, t ) Y * ( x, t ) take c.c : V ( x ) Y * ( x , t ) i 2m t x 2 Y * i 2 Y * iV Y* 2 t 2m x h Finishing the normalization check of the solution to the TDSE postmultip ly first by Y*, premultipl y second by Y , and add... V terms cancel and one gets Y Y * i 2 Y 2 Y * Y * Y Y* Y 2 2 t t 2m x x compare to previous expression and x - integrate d dt i Y Y * i Y * Ydx Y * Y 2m x x 2m Y Y * Y * Y dx x x x x • First term is zero because Y has to die off at x = ±∞ • Second term is obviously zero • therefore, probability is conserved • a subtle point is that when a matter wave encounters a barrier that it can surmount, one must consider the probability flux rather than the probability… Elements of the Heisenberg Uncertainty Principle • uncertainty in a physical observable Q is standard deviation sQ • for the familiar example of position x and momentum p: a particle whose momentum is perfectly specified is an infinitely long wave, so its position is completely unknown: it is everywhere! • a particle which is perfectly localized, it turns out, must be made of a combination of wavicles of every momentum in equal amounts, so knowledge of its momentum is lost once it is ‘trapped’ • Heisenberg showed that the product of the uncertainties could not be less than half of Planck’s constant: s xs p 2 • it is amusing to confirm this inequality for well-behaved Y • there is also an energy-time HUP of the same form, and an angular momentum-angular position one of the same form • we’ll derive this soon much more rigorously
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