HEXAWARE PLACEMENT PAPER -1 WITH ANSWER
1. Kamal started a business with Rs.25000 and after 4 months, Kiran joined him with
Rs.60000. Kamal received Rs.58000 including 10% of profit as commission for managing
the business. What amount did Kiran receive?
A. 75000
B. 70000
C. 72000
D. 78000
Explanation:Ratio of the profits = 25000*12 : 60000*8
= 25*12 : 60*8 = 5*3 : 12:2 = 5 : 4*2
= 5:8
Let the total profit = x.
Then Kamal received 10x/100 = x/10 as commission for managing the business
Remaining profit = x- x/10 = 9x/10 which is shared in the ration 5:8
Kamal's share = x/10 + (9x/10) * (5/13) = 58000
=> x + 9x(5/13) = 580000
=> x(1 + 45/13) = 580000
=> x ( 58/13) = 580000
=> x ( 1/13) = 10000
=> x = 130000
Kiran's share = 130000 - 58000 = 72000
2. A, B and C jointly thought of engaging themselves in a business venture. It was agreed
that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3
months. A wants to be the working member for which, he was to receive 5% of the profits.
The profit earned was Rs. 7400. What is the share of B in the profit.
A. 2660
B. 1000
C. 2300
D. 4000
Answer : Option A
Explanation : A is a working member and for that, he receive 5% of the profit
= 5% of 7400 = 5*7400/100 = 370
Remaining amount = 7400-370 = 7030
Ratio of their investments = 6500*6 : 8400*5 : 10000*3
= 65*6 : 84*5 : 100*3 = 13*6 : 84 : 20*3 = 13*2 : 28 : 20
= 13 : 14 : 10
Share of B in the profit = 7030 * (14/37) = 190*14 = 2660Ages
3.. Ayisha's age is 1/6th of her father's age. Ayisha 's father's age will be twice the age of
Shankar's age after 10 years. If Shankar's eight birthdays was celebrated two years before,
then what is Ayisha 's present age.
A. 10 years
B. 12 years
C. 8 years
D. 5 years
Answer : Option D
Explanation :
Consider Ayisha's present age = x
Then her father's age = 6x
Given that Ayisha 's father's age will be twice the age of Shankar's age after 10 years
=> Shankar's age after 10 years = ½(6x + 10) = 3x + 5
Also given that Shankar's eight birthdays was celebrated two years before =>
Shankar's age after 10 years = 8 + 12 = 20
=> 3x + 5 = 20
=> x = 15/3 = 5
=> Ayisha 's present age = 5 years
4. My brother is 3 years elder to me. My father was 28 years of age when my sister was
born while my mother was 26 years of age when I was born. If my sister was 4 years of age
when my brother was born, then what was the age my father when my brother was born?
A. 35 years
B. 34 years
C. 33 years
D. 32 years
Answer : Option D
Explanation :
Let my age = x
Then
My brother's age = x + 3
My mother's age = x + 26
My sister's age = (x + 3) + 4 = x + 7
My Father's age = (x + 7) + 28 = x + 35
=> age my father when my brother was born = x + 35 – (x + 3) = 32
5. A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4
years. The sum is :
A. Rs. 700
B. Rs. 690
C. Rs. 650
D. Rs. 698
Answer : Option D
Explanation :
Simple Interest (SI) for 1 year = 854-815 = 39
Simple Interest (SI) for 3 years = 39 × 3 = 117
Principal = 815 - 117 = Rs.698
6. There is 80% increase in an amount in 8 years at simple interest. What will be the
compound interest of Rs. 14,000 after 3 years at the same rate?
A. Rs.3794
B. Rs.3714
C. Rs.4612
D. Rs.4634
Answer : Option D
Explanation :
Let P = Rs.100
Simple Interest = Rs. 80 ( ∵ 80% increase is due to the simple interest)
Rate of interest=100×SIPT=100×80100×8=10% per annum
Now let's find out the compound interest of Rs. 14,000 after 3 years at 10%
P = Rs.14000
T = 3 years
R = 10%
Amount after 3
years =P(1+R100)T=14000(1+10100)3=14000(110100)3=14000(1110)3=14×113=18634
Compound Interest = Rs.18634 - Rs.14000 = Rs.4634
7. A jogger is running at 9 kmph alongside a railway track in 240 meters ahead of the
engine of a 120 meters long train . The train is running at 45 kmph in the same direction.
how much time does it take for the train to pass the jogger?
A. 46
B. 36
C. 18
D. 22
Answer : Option B
Explanation :
Distance to be covered = 240+ 120 = 360 m
Relative speed = 36 km/hr = 36×10/36 = 10 m/s
Time = distance/speed = 360/10 = 36 seconds
8. A train overtakes two persons who are walking in the same direction to that of the train
at 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. What
is the length of the train?
A. 62 m
B. 54 m
C. 50 m
D. 55 m
Answer : Option C
Explanation :
Let x is the length of the train in meter and v is its speed in kmph
x/9 = ( v-2)(10/36) ---(1)
x/10 =( v-4) (10/36) --- (2)
Dividing equation 1 with equation 2
10/9 = (v-2)/(v-4)
=> 10v - 40 = 9v - 18
=> v = 22
Substituting in equation 1, x/9 = 200/36 => x = 9×200/36 = 50 m
9. Rahul went to a shop and bought things worth Rs. 25, out of which 30 Paise went on
sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax
free items?
A. Rs. 15
B. Rs. 12.10
C. Rs. 19.70
D. Rs. 16.80
Answer : Option C
Explanation :
Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (25−30100−x)6100=30100⇒6(25−0.3−x)=30⇒(25−0.3−x)=5⇒x=25−0.3−5=19.7
10.What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit?
A. 2023%
B. 20%
C. 21%
D. 2223%
Answer : Option B
Explanation :
Total numbers = 70
Total numbers in 1 to 70 which has 1 in the unit digit = 7
Total numbers in 1 to 70 which has 9 in the unit digit = 7
Total numbers in 1 to 70 which has 1 or 9 in the unit digit = 7 + 7 = 14
Required percentage = 1470×100=1407=20%
11. An observer 2 m tall is 103√ m away from a tower. The angle of elevation from his eye
to the top of the tower is 30º. The height of the tower is:
A. None of these
B. 12 m
C. 14 m
D. 10 m
Answer : Option B
Explanation :
SR = PQ = 2 m
PS = QR = 103√ mtan 30°=TSPS13√=TS103√TS=103√3√=10 m
TR = TS + SR = 10 + 2 = 12 m
12. Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation
of the top of the lighthouse is observed from the ships are 30º and 45º respectively. If the
lighthouse is 100 m high, the distance between the two ships is:
A. 300 m
B. 173 m
C. 273 m
D. 200 m
Answer : Option C
Explanation :
Let BD be the lighthouse and A and C be the positions of the ships.
Then, BD = 100 m,
BAD = 30° ,
BCD = 45°
tan 30° = BDBA⇒13√=100BA⇒BA=1003√
tan 45° = BDBC⇒1=100BC⇒BC=100
Distance between the two ships = AC = BA + BC
=1003√+100=100(3√+1)=100(1.73+1)=100×2.73=273 m
13. If a+b : b+c : c+a = 6 : 7 : 8 and a + b + c = 14, then the value of c is : . [C.B.I. 1993]
6
8
7
14
Answer & Explanation
Answer:
14
Explanation: (a/3) = (b/4) = (c/7) then a = 3k, b = 4k, c = 7k
a+b+c/c = 3k+4k+7k/7k = 14k/7k = 2
14.Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian
stamps is 5 to 2 and the ratio of Indian to British stamps is 5 to 1, what is the ratio of US to
British stamps?
A) 10 : 5
C) 20 : 2
Answer & Explanation Answer: D) 25 : 2
B) 15 : 2
D) 25 : 2
Explanation:
Indian stamps are common to both ratios. Multiply both ratios by factors such that the Indian
stamps are represented by the same number.
US : Indian = 5 : 2, and Indian : British = 5 : 1. Multiply the first by 5, and the second by 2.
Now US : Indian = 25 : 10, and Indian : British = 10 : 2
Hence the two ratios can be combined and US : British = 25 : 2
15.In the series 0,3,8,15,____ what is the next number?
a)24 b)25 c)23 d)18
Ans: 24
Explanation: 0*2=0; 1*3=3; 2*4=8; 3*5=15; 4*6=24;
16.Find next in series 31,29,31,30,31,?
a)30 b)31 c)29 c)32
Ans: 31
Explanation: leave the number 31 in the series,then note that the numbers increses
by 1, 29,30,31
hence 31 is the result
17.Find average of all nos. which lies b/w 1 and 100 & r divisible by 7
a)52 b)54 c)52.5 d)55
Ans: 52.5
Explanation: Numbers lies between 1 to 100 which divisible by 7 is,
7,14,21,28,35,42,49,56,63,70,77,84,91,98
735/14
or
By formula method:
Formula: (n/2)(a+l) where n=how many numbers, a=1st digit,l=last digit
so a=7,l=98 , n=14
hence
(14/2)(7+98)
=7*105
avg=(7*105)/14
=105/2
=52.5
18.The average age of boys in the class is twice the number of girls in the class. If the ratio
of boys and girls in the class of 36 be 5 : 1, what is the total of the ages (in years) of the boys
in the class.
a)490 b)420 c)196 d)360
Answer:
360
Explanation: Number of boys = 136 *(5/2) = 30,
Number of girls 6.
Average age of boys = (2 * 6) = 12 years.
Total age of boys (30 * 12) years = 360 years.
19.Snehs age is1/6 th of her fathers age. Snehs fathers age will be twice of Vimals age after
10 years. If Vimals eighth birthday was celebrated two years before, then what is Snehs
present age?
a)24 years
b)6.66 years
c)30 years
d)5 years
Answer:
5 years
Explanation: Vimals age after 10 years = (8 + 2 + 10) years = 20 years.
Snehs father’s age after 10 years = 40 years.
Snehs father’s present age = 30 years.
Snehs age= 1/6 * 30 years = 5 years.
20.The age of father 10 years ago was thrice the age of his son. Ten years hence, the
father’s age will be twice that of his son. The ratio of their present ages is:
a)5 : 2
b)7 : 3
c)9 : 2
d)13 : 4
Answer:
7:3
Explanation: Let sons age 10 years ago = x.
Then, fathers age 10 years ago = 3x.
2(x+ 10+ 10) = (3x + 10 + 10)so x = 20.
Ratio of their present ages = (3x + 10) : Cx + 10) 70: 30 = 7 :3.
21.X, Y and Z share a sum of money in the ratio 7 : 8 : 16. If Z receives Rs. 27 more than X,
then the total money shared was:
a)Rs. 48
b)Rs. 279
c)Rs. 93
d)Rs. 558
Answer:
Rs. 93
Explanation: Let X = 7x, Y = 8x & Z = 16x. Then, total money = 31x.
Now, Z - X = 27 so 16x—7x = 27 that is why x = 3.
Total money 31*x = Rs.93.
22.If 15% of x is the same as 20% of y, then x : y is :
a)3 : 4 b)17 : 16
c)4 : 3
d)16 : 17
Answer:
4:3
Explanation: 15% of x = 2O% of y ⇒ 15x/100 = 20y/100 ⇒ x/y = 4/3
23. A bag contains 2 yellow, 3 green and 2 blue balls. Two balls are drawn at random.
What is the probability that none of the balls drawn is blue?
A. 12
B. 1021
C. 911
D. 711
Answer : Option B
Explanation :
Total number of balls = 2 + 3 + 2 = 7
Let S be the sample space.
n(S) = Total number of ways of drawing 2 balls out of 7 = 7C2
Let E = Event of drawing 2 balls , none of them is blue.
n(E) = Number of ways of drawing 2 balls , none of them is blue
= Number of ways of drawing 2 balls from the total 5 (=7-2) balls = 5C2
(∵ There are two blue balls in the total 7 balls. Total number of non-blue balls = 7 - 2 = 5)
P(E) = n(E)n(S)=5C27C2=(5×42×1)(7×62×1)=5×47×6=1021
24. There are 10 prizes and 25 blanks in a lottery. If John has taken a lottery, what is the
probability for him to get a prize?
A. 47
B. 37
C. 27
D. 17
Answer : Option C
Explanation :
Total number of outcomes possible, n(S) = 10 + 25 = 35
Total number of prizes, n(E) = 10
P(E) = n(E)n(S)=1035=27
25. How many bricks, each measuring 25 cm x 11.25 cm x 6 cm, will be needed to build a
wall of 8 m x 6 m x 22.5 cm?
A.5600
B. 6000
C.6400
D.7200
Answer: Option C
Explanation:
Volume of the wall
Number of
bricks =
800 x 600 x 22.5
=
Volume of 1 brick
25 x 11.25 x 6
The curved surface area of a cylindrical pillar is 264 m2 and its volume is 924 m3.
Find the ratio of its diameter to its height.
A.3 : 7
B. 7 : 3
C.6 : 7
D.7 : 6
26.
Answer: Option B
Explanation:
r2 h
2
= 6400.
rh
And, 2
924
=
264
924
r=
rh = 264
x2
= 7 m.
264
h=
7 1 1
x x
22 2 7
264 x
= 6m.
2r 14
= = 7 : 3.
Required ratio = h 6
27. 13 + 23 + 33 + ... + 63 = ?
A. 451
B. 441
C. 421
D. 401
Answer : Option B
Explanation :
(Reference : Power Series : Important formulas)
13+23+33+⋯+n3=∑n3=n2(n+1)24=[n(n+1)2]2
13+23+33+⋯+63=[n(n+1)2]2=[6(7)2]2=[3×7]2=212=441
28.. What is the remainder when 17200 is divided by 18 ?
A. 3
B. 2
C. 1
D. 4
Answer : Option C
Explanation :
(xn−an) is completely divisible by (x+a) when n is even
Read More...
(17200 - 1200) is completely divisible by (17 + 1) as 200 is even.
=> (17200 - 1) is completely divisible by 18.
Hence, when 17200 is divided by 18, we will get 1 as remainder.
29. Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation
of the top of the lighthouse is observed from the ships are 30º and 45º respectively. If the
lighthouse is 100 m high, the distance between the two ships is:
A. 300 m
B. 173 m
C. 273 m
D. 200 m
Answer : Option C
Explanation :
Let BD be the lighthouse and A and C be the positions of the ships.
Then, BD = 100 m,
BAD = 30° ,
BCD = 45°
tan 30° = BDBA⇒13√=100BA⇒BA=1003√
tan 45° = BDBC⇒1=100BC⇒BC=100
Distance between the two ships = AC = BA + BC
=1003√+100=100(3√+1)=100(1.73+1)=100×2.73=273 m
30.. A man standing at a point P is watching the top of a tower, which makes an angle of
elevation of 30º with the man's eye. The man walks some distance towards the tower to
watch its top and the angle of the elevation becomes 45º. What is the distance between the
base of the tower and the point P?
A. 9 units
B. 33√ units
C. Data inadequate
D. 12 units
Answer : Option C
Explanation :
tan 45°=SRQRtan 30°=SRPR=SR(PQ + QR)
two equations and 3 variables. Hence we can not find the required value with the given data.
(Note that if one of SR, PQ, QR is known, this becomes two equations and two variables and if
that was the case, we could have found out the required value)
31. P is able to do a piece of work in 15 days and Q can do the same work in 20 days. If they
can work together for 4 days, what is the fraction of work left?
A. 8/15
B. 7/15
C. 11/15
D. 2/11
Answer : Option A
Explanation :
Amount of work P can do in 1 day = 1/15
Amount of work Q can do in 1 day = 1/20
Amount of work P and Q can do in 1 day = 1/15 + 1/20 = 7/60
Amount of work P and Q can together do in 4 days = 4 × (7/60) = 7/15
Fraction of work left = 1 – 7/15= 8/15
32. P can lay railway track between two stations in 16 days. Q can do the same job in 12
days. With the help of R, they completes the job in 4 days. How much days does it take for
R alone to complete the work?
A. 9(3/5) days
B. 9(1/5) days
C. 9(2/5) days
D. 10 days
Answer : Option A
Explanation :
Amount of work P can do in 1 day = 1/16
Amount of work Q can do in 1 day = 1/12
Amount of work P, Q and R can together do in 1 day = 1/4
Amount of work R can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48
=> Hence R can do the job on 48/5 days = 9 (3/5) days
33. Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12
hours. If all the three pipes are opened together, then the tank will be filled in:
A. 3917 hours
B. 11317 hours
C. 2811 hours
D. 412 hours
Answer : Option A
Explanation :
Pipes A and B can fill a tank in 5 and 6 hours respectively
=>Part filled by pipe A in hour = 1⁄5
and Part filled by pipe B in hour = 1⁄6
Pipe C can empty it in 12 hours
=> Part emptied by pipe C in 1 hour = 1⁄12
Net part filled by Pipes A,B and C together in 1 hour = 15+16−112=1760i.e, the pipe can be
filled in 6017=3917 hours
34. Two pipes A and B can fill a cistern in 371⁄2 minutes and 45 minutes respectively. Both
pipes are opened. The cistern will be filled in just half an hour, if pipe B is turned off after:
A. 5 min
B. 9 min
C. 10 min
D. 15 min
Answer : Option B
The following questions are based on the information given below:
All the opposite faces of a big cube are coloured with red, black and green colours.
After that is cut into 64 small equal cubes.
35. How many small cubes are there where one face is green and other one is either
black or red ?
A.28
B. 8
C.16
D.24
Answer: Option C
36. How many small cubes are there whose no faces are coloured ?
A.0
B. 4
C.8
D.16
Answer: Option C
3 How many small cubes are there whose 3 faces are coloured ?
7.A
B
4
8
.
.
C
D
16
24
.
.
Answer: Option B
38. How many small cubes are there whose only one face is coloured ?
A.32
B. 8
C.16
D.24
Answer: Option D
39. How many small cubes are there whose at the most two faces are coloured ?
A.48
B. 56
C.28
D.24
Answer: Option B
40. A rhombus has area 432 sq m, one diagonal is 36 cm. find other diagonal ?
a)2400m b)2350m c)2375m d)2250m
Explanation:
Ans:2400 m
area of rhombus =1/2*d1*d2
432=1/2*d1*.36
d1=2400m