Chapter 10 Graphing Equations and Inequalities Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. 10.7 Graphing Linear Inequalities in Two Variables Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Linear Inequalities in Two Variables Linear inequality in two variables • Written in the form Ax + By < C • A, B, C are real numbers, A and B are not both 0 • Could use (>, ≥, ≤) in place of < An ordered pair is a solution of the linear inequality in x and y if replacing the variables with the coordinates of the ordered pair results in a true statement. Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 3 Linear Inequalities in Two Variables To Graph a Linear Inequality Step 1: Graph the boundary line found by replacing the inequality sign with an equal sign. If the inequality sign is > or <, graph a dashed boundary line (indicating that the points on the line are not solutions of the inequality). If the inequality sign is ≥ or ≤, graph a solid boundary line (indicating that the points on the line are solution of the inequality). Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e continued 4 Linear Inequalities in Two Variables Step 2: Choose a point not on the boundary line as a test point. Substitute the coordinates of this test point into the original inequality. Step 3: If a true statement is obtained in Step 2, shade the half-plane that contains the test point. If a false statement is obtained, shade the half-plane that does not contain the test point. Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e continued 5 Example y Graph: 7x + y > –14. Step 1: First graph the boundary line 7x + y = –14 as a dashed line because the inequality symbol is >. Step 2: Choose a test point not on the boundary line. We choose (0,0), and substitute the coordinates into 7x + y > –14. 7(0) + 0 > –14 True Step 3: Since the result is a true statement, (0, 0) is a solution of 7x + y > –14, so shade the side containing (0,0). (0, 0) x Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 6 Example Graph: 3x + 5y ≤ –2. Step 1: First graph the boundary line 3x + 5y ≤ –2 as a solid line because the inequality is ≤. Step 2: Choose a test point not on the boundary line. We choose (0,0), and substitute the coordinates into 3x + 5y ≤ –2. 3(0) + 5(0) ≤ –2 False Step 3: Since the result is a false statement, shade the side that doesn’t contain (0,0). Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 7 Example y Graph 3x < 15. Step 1: First graph the boundary line 3x < 15 as a dashed line. Step 2: Choose a test point not on the boundary line. We choose (0,0), and substitute the coordinates into 3x < 15. 3(0) < 15 True Step 3: Since the result is a true statement, shade the side that contains (0,0). (0, 0) x Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 8 Helpful Hint When graphing an inequality, make sure the test point is substituted into the original inequality. Also, note that although all of our examples allowed us to select (0, 0) as our test point, that will not always be true. If the boundary line contains (0,0), you must select another point that is not contained on the line as your test point. Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 9
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