Relativistic Universe Relativistic stars Metric z Locally any curved manifold is characterized by its metric (interval), which tells the distance between a point and points in its neighborhood. ds 2 = g µν dx µ dxν µ ν ds = g µν dx dx 2 z Tangent vector xα(λ) dxα (λ ) v ( x) = dλ α vα(x) z We can rewrite the geodesic equation as d α v ( x(λ )) + Γα µν ( x) v µ ( x) vν ( x) = 0 dλ z But z d ≡ vµ ∂µ dλ So that we can write the geodesic eqn. as v µ ∂ µ vα ( x) + Γα µν ( x) v µ ( x) vν ( x) = 0, ( ) ( 0 = v µ ∂ µ vα ( x) + Γα µν ( x) vν ( x) = v µ ∇ µ vα ( x) ) Covariant derivative z The covariant derivative z Is the right derivative, replacing partial derivative of the flat space and preserving tensor character of objects ∇ µ vα ( x) = ∂ µ vα ( x) + Γα µν ( x) vν ( x) Covariant derivatives of tensors α α α ∇ µ v ( x) = ∂ µ v ( x) + Γ ∇ µ vα ( x) = ∂ µ vα ( x) − Γ ∇ µ tαβ ( x) = ∂ µ tαβ ( x) − Γ δ µα β ν µν ( x) v ( x) µα ( x) vβ ( x) ( x) tδβ ( x) − Γ δ µβ ( x) tαδ ( x) It can be easily checked z That the metric is covariantly constant ∇ µ gαβ ( x) ≡ 0 Geometrical meaning In flat space, partial derivative ∂µ is infinitesimal translation in direction µ. z Similarly, in curved space, covariant derivative ∇µ is infinitesimal parallel translation in direction µ. z !! z Parallel transport z If there is a curve with tangent vector vα(x) and we want to paralel transport a vector uα(x) along it we must solve the equation α β v ∇α u = 0 uα(x(1)) vα(x) uα(x(0)) Curvature If there is an infinitesimal closed curve (loop) and we parallel transport a vector along it z Then the difference is proportional to curvature z Riemann tensor z R Curvature is measured by Riemann tensor, defined in terms of Christoffel symbols µ ναβ = ∂α Γ µ νβ − ∂β Γ µ να +Γ µ σα Γ σ νβ −Γ µ σβ Γ σ να Symmetries of Riemann tensor Rµν ρσ = Rρσ µν Rµν ρσ = − Rνµ ρσ Rµν ρσ = − Rµν σρ Contracting we get z Ricci tensor Rνβ = R µνµβ = ∂µΓ z µ νβ − ∂β Γ µ νµ +Γ µ σµ Curvature scalar νβ R = g Rνβ σ Γ νβ −Γ µ σβ σ Γ νµ Vacuum Einstein equations Rµν = 0 Bianchi identity 1 ⎛ ⎞ ∇ ⎜ Rµν − g µν R ⎟ ≡ 0 2 ⎝ ⎠ µ z This important identity is analogous to the identity for the LHS of the second pair of Maxwell equations ε µνρσ ∂ν Fρσ ≡ 0 Coupling to matter Gravity tells matter how to move z Matter’s energy and momentum tells spacetime how to curve z In empty space Einstein equations have the form z Rµν = 0 z In the presence of matter the equation should be of the form Rµν + … = 8π G Tµν z Tµν is called energy-momentum tensor. Properties of e-m tensor Tµν is symmetric in µ, ν; z T00 is energy density, ρ; z Tii are pressures in direction i , pi ; z For perfect isotropic, relativistic fluid, in the system, in which it is at rest z Tµν ⎛ρ ⎜ 0 =⎜ ⎜0 ⎜ ⎝0 0 0 p 0 0 0 0 p 0⎞ ⎟ 0⎟ 0⎟ ⎟ p⎠ Equations of motion z In flat space matter equations of motion can be expressed with the help of Tµν as follows µ ∂ Tµν = 0 For perfect fluid z The general expression for energy momentum tensor of the fluid (gas) composed of particles is Tµν = pg µν + ( ρ + p )uµ uν Four velocity In flat space Componets of four velocity are uµ=(1,v i ), where v is much smaller than 1; z Pressure is much smaller from energy density; z T 00 = ( ρ + p )u u + pg 0 0 00 ≈ρ T 0 j = T j 0 = ( ρ + p )u 0u j ≈ ρ v j T jk = ( ρ + p )u u + pδ j k jk ≈ ρ v v + pδ j k jk Motion of the fluid z Continuity equation 0 = ∂ µT z µ0 ( ) = ∂0 ρ + ∂i ρ v = ρ + ∇ ( ρ v ) i Euler equation 0 = ∂ 0T 0j + ∂ iT = v + (v ⋅∇)v + ij 1 ρ ∇p Curved space generalization z To generalize our result to curved space we must only replace partial derivative by the covariant one ∇ µT µν =0 Einstein equations z We know that 1 ⎛ ⎞ ∇ ⎜ Rµν − g µν R ⎟ ≡ 0 2 ⎝ ⎠ µ z Thus (c=1) 1 Rµν − g µν R = 8π G Tµν 2 Consistency with vacuum eqns 1 Rµν − g µν R = 0 ⇒ 2 R − 2R = 0 ⇒ Rµν = 0 Metric of spherical relativistic star z It turns out that the most general spherically symmetric metric is of the form ds = −e 2 z 2Φ ( r ) dt + e 2 2Λ(r ) dr + r d Ω 2 2 2 Λ(r) and Φ(r) both go to zero at infinity (far away from the source the metric is flat.) Matter in star … z 1. 2. 3. 4. Is described by Energy density ρ (r), Isotropic pressure p (r), Barion number density n (r), with EOS; 4-velocity of the fluid uµ = uµ (r) : T µν µ ν = ( p + ρ )u u + pg µν 00 Einstein equation 1 R00 − g 00 R = 8π G T00 2 ( ) d ⎡ −2 Λ 2 ⎤ r 1 e 8 π Gr ρ − = ⎦ dr ⎣ z Denoting (m(r) is mass in radius r) ( r 1− e z −2 Λ ) = 2Gm(r ) ⇔e 2Λ ⎛ 2Gm(r ) ⎞ = ⎜1 − ⎟ r ⎝ ⎠ And solving the equation 2G dm(r ) = 8π G ρ ⇒ 2 r dr r m(r ) = ∫ 4π ρ dr 0 −1 rr Einstein equation 1 Rrr − g rr R = 8π G Trr 2 ( ) −2 Λ 1 2e −2 Λ − 2 1− e + r r dΦ = 8π G p dr dΦ 4π pr + m =G dr r ( r − 2Gm ) 3 z With Newtonian limit d Φ Gm = 2 dr r Oppenheimer – Volkov eqn. z It follows from energy conservation that dp dΦ = −( ρ + p ) dr dr z So that we get dp ( p + ρ )(4π pr 3 + m) = −G dr r ( r − 2Gm ) Nonrelativistic vs relativistic stars Solution of OV equation Assume that density of star is constant: ρ(r) =ρ0. z Then z r m(r ) = ∫ 4π ρ0 dr ⇒ 0 4πρ0 3 m( r ) = r 3 z Then the OV equation takes the form 4π Gr ρ02 (1 + p / ρ0 c 2 )(1 + 3 p / ρ 0 c 2 ) dp =− dr 3 1 − 8π G ρ0 r 2 / 3c 2 ( z To ) which we add the usual initial condition p(R)=0 Solution p(r ) = ρ0c 2 1 − 2GMr 2 / R 3c 2 − 1 − 2GM / Rc 2 3 1 − 2GM / Rc 2 − 1 − 2GMr 2 / R 3c 2 Central pressure z At r=0 p (0) = pc = ρ0 c 2 z 1 − 1 − 2GM / Rc 2 3 1 − 2GM / Rc 2 − 1 This is the pressure in the center of a stable star of mass M and radius R Condition of stability z The central pressure becomes infinite if 9 2GM 9 R= = Rs 2 8 c 8 z The star radius cannot be smaller if the star is to be stable. z A more reasonable limit on the central pressure would be to limit the speed of sound to be less than or equal to the speed of light. A sound speed in excess of the speed of light would suggest conditions where the gas would violate the principle of causality. Namely, sound waves could propagate signals faster than the velocity of light. Since P/ρ0 is the square of the local sound speed, pc = ρ0 c 2 1 − 1 − 2GM / Rc 2 3 1 − 2GM / Rc − 1 2 = ρ0 c 2 4 2GM 4 R= = Rs 2 3 c 3 Since causality will always dictate that the sound speed be less than the speed of light, we conclude that any stable star must have a radius R such that R > 4/3 Rs. z From the NICMOS image we have seen that behind the obscuring dust, inside the Centaurus A Galaxy, there are a hot gas disk and a twisted jet and disk around a feeding black hole. 1998-14-a-low_quicktime.mov Matter falling on black hole Black hole in globullar cluster
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