3.2 Rolles & Mean Value Theorem Rolleβs Theorem Let f be continuous on the closed interval [a,b] and differentiable on the open interval (a,b). If π π = π(π) Then there is at least one number c in (a,b) such that fβ(c)=0 What does Rolleβs Thrm do? ο΅ Rolleβs theorem states some x value exists (x=c) so that the tangent line at that specific x value is a horizontal tangent (fβ(c)=0) Horizontal Tangent Line ie: fβ(c)=0 f(a)=f(b) a c b Notes about Rolleβs Thrm ο΅ It is an EXISTENCE Theorem, it simply states that some c has to exist. It does NOT tell us exactly where that value is located. ο΅ In order to find the location x=c, we would take fβ(x)=0 and find critical numbers like in section 3.1 (Extrema on a closed Interval) Example 1 of Rolleβs Thrm ο΅ Determine whether Rolleβs thrm can be applied. If it can be applied, find all values of c such that fβ(c)=0 ο΅ Ex: π π₯ = π₯ 2 β 5π₯ + 4 , [1,4] ο΅ Since f is a polynomial, it is continuous on [1,4] and differentiable (1,4). ο΅ π 1 = 0 = π(4) ο΅ Therefore, Rolleβs Theorem can be applied and states there must be some x=c on [1,4] such that fβ(c)=0. ο΅ Lets find those x values! Example 1 Continued ο΅ π β² π₯ = 2π₯ β 5 ο΅ 0 = 2π₯ β 5 ο΅ π₯=2 ο΅ Therefore by Rolleβs Thrm, π β² 5 5 2 =0 Example 2 of Rolleβs Thrm ο΅ Determine whether Rolleβs thrm can be applied. If it can be applied, find all values of c such that fβ(c)=0 ο΅ Ex: π π₯ = π₯ + 1 ππ [β2,3] ο΅ f is continuous on [-2,3] ο΅ f is not differentiable on (-2,3) ο΅ ROLLEβs cannot be used! Example 3 of Rolleβs Thrm ο΅ Determine whether Rolleβs thrm can be applied. If it can be applied, find all values of c such that fβ(c)=0 ο΅ Ex: π π₯ = cos π₯ ο΅ f is continuous on [0,2π] ο΅ f is differentiable on (0,2π) ο΅ cos 0 = 1 = cos 2π ο΅ ROLLEβS APPLIES! [0,2π] Example 3 Continued ο΅ π β² π₯ = βsin(π₯) ο΅ β sin π₯ = 0 ο΅ π₯ = 0, π ο΅ Therefore π β² 0 = 0 πππ π β² π = 0 Mean Value Theorem ο΅ If f is continuous on [a,b] and differentiable on the open interval (a,b), then there exists a number c in (a,b) s.t. ο΅ πβ² π = π π βπ π πβπ πβ² π f(b) π π βπ π πβπ f(a) a b MVT Example pg 177 #37 parts a,b,c,d
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