Tutorial 2 1. Evaluate the following discrete-time convolution sums: (i) y[n] = u[n+3] * u[n-3] (ii) y[n]= 3nu[-n+3] * u[n-2] Tutorial 2 EKT 230 Signals & Systems Tutorial 2 EKT 230 Signals & Systems (iii) y[n] = (1/4)n u[n] * u[n+2] (iv) y[n]= (-1)n * 2nu[-n+2] 2. Consider the discrete-time signals depicted in Figure 1(a), Figure 1(b) and Figure 1(c). Evaluate the following convolution sums: (a) m[n]= x[n] * y[n] Tutorial 2 Tutorial 2 (b) m[n]= x[n] * f[n] Tutorial 2 EKT 230 Signals & Systems Tutorial 2 (c) m[n]= y[n] * f[n] Tutorial 2 EKT 230 Signals & Systems Tutorial 2 Tutorial 2 EKT 230 Signals & Systems Tutorial 2 EKT 230 Signals & Systems Figure 1(a) Figure 1(b) Tutorial 2 Tutorial 2 EKT 230 Signals & Systems Figure 1(c) 3. A linear time invariant system has an impulse response, h(t) and input signal, x(t). Use convolution to find the response, y(t) for following signal: Cross multiplication method x[n] h[n] 1 2 3 -1 -1 -2 -3 -1 -1 -2 -3 2 2 4 6 1 1 2 3 1 1 2 3 Ans : y[n] = [-1 -3 -3 2 9 5 3] Tutorial 2 Tutorial 2 EKT 230 Signals & Systems h[-k] x[k] 1 0 n=0 2 1 1 3 2 3 4 5 h[0-k] 1 -2 2 -1 0 -1 2 1 -3 1 1 -1 y[0] = -1 -3 -2 -1 0 -1 n=1 1 -1 y[1] = -2-1 = -3 h[1-k] 1 -3 2 1 -2 -1 0 1 -1 n=2 y[2] = -3-2+2 = -3 h[2-k] 1 -3 n=3 -1 2 1 -2 -1 0 1 -1 h[3-k] 1 -3 1 -2 2 -1 0 1 -1 n=4 -1 h[4-k] 1 -3 -2 1 y[4] = 6+2+1 =9 2 -1 0 -1 Tutorial 2 y[3] = -3+4+1 =2 -1 1 -1 Tutorial 2 EKT 230 Signals & Systems h[k] x[k] 1 0 n=5 2 1 3 2 3 4 6 -3 2 1 -2 -1 0 -1 y[5] = 3+2 =5 1 -1 h[6-k] y[6] = 3 1 -3 2 1 -2 -1 0 1 -1 n=7 -1 y[7] = 0 h[7-k] 1 -3 -2 1 2 -1 0 -1 y[n]=[-1 -3 -3 2 9 5 3] Tutorial 2 7 h[5-k] 1 n=6 5 1 -1 Tutorial 2 EKT 230 Signals & Systems 4. According to Figure 2(a), (b), (c), (d), evaluate the following convolution integral: (a) m(t) = x(t) * y(t) (b) m(t) = x(t) * z(t) (c) m(t) = y(t) * w(t) (d) m(t) = y(t) * z(t) Figure 2 (a), (b), (c), (d) ANSWER: (a) m(t) = x(t) * y(t) Tutorial 2 Tutorial 2 (b) m(t) = x(t) * z(t) Tutorial 2 EKT 230 Signals & Systems Tutorial 2 (c) m(t) = y(t) * w(t) (d) m(t) = y(t) * z(t) Tutorial 2 EKT 230 Signals & Systems Tutorial 2 Tutorial 2 EKT 230 Signals & Systems
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