Algebra 1 Fundamentals
Summer Assignment 2017
The following packet contains topics and definitions that you will be required to know in order to
succeed in Algebra 1 Fundamentals this year. You are advised to be familiar with each of the
concepts and to complete the included problems by Thursday, August 31, 2017. All of these topics
were discussed in Math 8 and Algebra I, and will be used frequently throughout the year.
1
Section 1: Integer Computations
Integers: Any number from the set { β¦, -3, -2, -1, 0, 1, 2, 3, β¦}You can visually use a number line to find the answer to a problem:
Other patterns in adding integers the following:
Patterns in Multiplication:
Example 1:
βππ + π β (βπ) β π
Order of
operations
states to go left
to right.
Example 2:
(βπ β (βπ)) β (βπ)
βπ β (βπ) β π
βπ + π β π
βπ β π = βπ
(βπ + π) β (βπ)
Rememberβ¦
minus a negative
is the same as
addition.
(π) β (βπ) = βππ
2
Simplify the following expression:
1) (β4) + 6 + (β3)
2) 1 + (β4) + 10
3) (β5) + (β5) + 1
4) 1 + (β3) + 11
5) (β9) + 4 + 7
6) (β12) + 4 + 8
7) 3 + (β10) + 6
8) (β3) + 3 + 12
9) 3 + (β11) + 8
10) 5 β 3 β (β2)
11) 7 β (β6) β 7
12) (β4) β (β8) β 2
13) (β2) β (β1) β (β7)
14) 2 β (β5) β 3
15) (β7) β (β7) β 4
16) (β6) β 4 β (β4)
17) (β8) β (β8) β 5
18) (β5) β 6 β (β6)
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Section 2: Order of Operations
P arenthesis
E xponents
M ultiplication
D ivision
A ddition
S ubtraction
Example:
Simplify the following:
(18 + 4)
β 3(10 β 2 β 3 β 6)
2
οWork inside first set of parenthesis first
=
22
β 3(10 β 2 β 3 β 6)
2
οWork inside second set of parenthesis by multiplying first
=
22
β 3(20 β 18)
2
οContinue to work inside second set of parenthesis by subtracting
=
22
β 3(2)
2
οDivide the fraction
= 11 β 3(2)
οMultiply
= 11 β 6
οSubtract
=5
4
Now complete the following problems:
1)
4)
7)
10)
4 + 6(8)
14 + 6 ο΄ 23 β 8 οΈ 22
(3.4)(2.7) + 5
2.4+3.5
β
.7
2
2)
5)
4(8β2)
3)
3+9
3 + 4[13 β 2(6 β 3)]
8) (6.88 ÷ 2) β (9.3 β 9.03)
11)
4 ο΄ 32 + 2
2
3
13 β 4 β 4
5
6)
3(
6+12
2
)
9) (.9 + 1.1)2 β (112 β 117)
12)
3
4
1
1
÷ (2)2 + 2
Section 3: Real Number Comparison
An Inequality is a mathematical sentence that compares the value of two expressions using an
inequality symbol.
Inequality
Symbol
<
β€
>
β₯
β
Pronounced
Example
Less than
Less than or equal to
Greater than
Greater than or equal to
Not equal to
4<9
β3 β€ 2
β4 > β7
5β₯5
7 β 11
When comparing two numbers with an inequality symbol, it can be useful to plot both numbers
on a number line. By plotting both numbers on a number line, you can see which number is
greater simply by seeing which number is further to the right.
Example: Fill in the blank with the correct inequality symbol ( < , > )
βπ____ β π
First plot a point on each
number on a number line
βπ < β2
ο--------------------------------
Since -2 is further to the right, it
is the larger number, therefore
you use a less than sign because
-7 is less than -2
HINT: When comparing fractions you can either get a common denominator to compare, or
convert the fraction(s) to decimals then compare.
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Example:
Which is greater, or
?
Since the LCM of 9 and 12 is 36, the LCD of the fractions is 36.
Since
16
36
4
9
15
> 36,
5
> 12
Use <, =, > to compare the following sets of numbers:
1) 2 ____ 6
2) β12 ____ β 15
4) 0.63 ___ 0.6
5) π ____ 0.88
7)
2
3
____
1
6
π
8)
3
4
____
3) 2 ____ β 1
6) -1.45 ___ 1.45
12
9) β2
16
7
5
8
1
____ β 2 2
Section 4: Variables and Verbal Expressions
Write each phrase as an algebraic expression.
Phrase
Expression
nine increased by a number x
9+x
fourteen decreased by a number p 14 - p
seven less than a number t
t-7
the product of 9 and a number n
9 · n or 9n
thirty-two divided by a number y
32 ÷ y or
Write an algebraic expression for each phrase.
1. 7 increased by x
2.
p multiplied by 3
3. 10 decreased by m
4.
n less than 7
5. the product of 2 and q
6.
3 more than m
7. the difference of 8 and a number
8.
the sum of 4 and a number
9. the product of 2 and a number
10.
3 increased by a number
11. 10 plus the quotient of a number and 15
12.
12 less than a number
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Section 5: Evaluating Algebraic Expressions
A variable is a letter, for example x, y or z, that represents an unspecified number.
To evaluate an algebraic expression, you have to substitute a number for each variable and
perform the arithmetic operations.
Example:
Calculate the following expression for x = 3 and z = 2
6π§ + 4π₯ = ?
Solution: Replace x with 3 and z with 2 to evaluate the expression. (Be sure to use parenthesis
when you substitute!)
6π§ + 4π₯ = ?
6(2) + 4(3) = ?
12 + 12 = 24
Evaluate each expression for the given values.
1) π₯π¦ πππ π₯ = 3 πππ π¦ = 5
2) 2 + π πππ π = 3
3) 10 β π + 5 πππ π = 9
4) π + π ÷ 6 πππ π = 12 πππ π = 18
5) 4π + 3 πππ π = 5
6) 35 β 3π₯ πππ π₯ = 10
7) 3ππ β π πππ π = 4, π = 2, π = 5
8)
9
ππ
2
+ 4π πππ π = 6, π = 5, π = 3
Section 6: Solving One- Step Equations
A one-step equation is as straightforward as it sounds. You will only need to perform one step
in order to solve the equation. The goal in solving an equation is to only have a variable on one
side of the equal sign and numbers on the other side of the equal sign.
The strategy for getting the variable by itself involves using opposite operations. The most
important thing to remember in solving a linear equation is that whatever you do to one side of
the equation, you MUST do to the other side. So if you subtract a number from one side, you
MUST subtract the same value from the other side. You will see how this works in the examples.
Example:
Solve β2 = k β 14.
Example:
Solve
π₯
β7
= 15.
Example:
Solve
816 = 8c.
Solve the following one-step equations:
1) π β π = π
2) π + π. π = π. π
4)
π
π = ππ
π
5)
π
π
π=π
π
10
3) ππ = ππ
6)
π
π
=π
Section 7: Solving Two-Step Equations
When solving a two-step equation, you will need to perform two steps in order to solve the
equation.
The goal in solving a two step equation is the same as in solving a one step: to only have a
variable on one side of the equal sign and numbers on the other side of the equal sign.
The strategy for getting the variable by itself with a coefficient of 1 involves using opposite
operations. The most important thing to remember in solving a linear equation is that whatever
you do to one side of the equation, you MUST do to the other side. So if you subtract a number
from one side, you MUST subtract the same value from the other side. You will see how this
works in the examples.
In solving two-step equations you will make use of the same techniques used in solving one-step
equation only you will perform two operations rather than just one. (Note: you should always
add or subtract first, then multiply or divide)
Example:
Solve
π
5
β 7 = β9.
Example:
Solve 125 + 3b = 154.97.
Solve the following two-step equations:
π
2) βπ = π + ππ
1) π + π = βπ
4)
π
π
π
π+π=π
5)
π
π
π
π
πβπ=π
11
3)
π
π
βπ=π
6) π. ππ + π. π = ππ
Section 8: Plotting on the Coordinate Plane
You can graph a point on a coordinate plane. Use an ordered pair (x, y) to record the coordinates.
The first number in the pair is the x-coordinate. The second number is the y-coordinate.
To graph a point, start at the origin, O. Move horizontally according
to the value of x. Move vertically according to the value of y.
Example 1: Plot the ordered pair (4, -2)
Start at O, move right 4, then down 2.
Example 2: Plot the ordered pair (-5, 4)
Start at O, move left 5, then up 4.
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List the ordered pair for each letter, then name
the Quadrant the point lies in.
1) P = ( , ) Quadrant _______
2) B = ( , ) Quadrant _______
3) K = ( , ) Quadrant _______
4) A = ( , ) Quadrant _______
5) F = ( , ) Quadrant _______
6) D = ( , ) Quadrant _______
Plot the following ordered pairs on the
coordinate plane at right and label with the
corresponding letter:
7) H = ( -2 , 2 )
8) W = ( 0 , 0 )
9) S = (-2, -2 )
10) J = ( 2 , 2 )
11) P = ( -1 , -3 )
12) C = ( 1 , -3 )
13) V = ( 2 , -2 )
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