EXPECTED FROBENIUS NUMBERS
ISKANDER ALIEV, MARTIN HENK, AND AICKE HINRICHS
Abstract. We show that for large instances the order of magnitude of
the expected Frobenius number is given by its lower bound.
1. Introduction
Let π be a positive integral π-dimensional primitive vector, i.e., π =
(π1 , . . . , ππ )βΊ β β€π>0 with gcd(π) := gcd(π1 , . . . , ππ ) = 1. The Frobenius
number of π, denoted by F (π), is the largest number which cannot be represented as a non-negative integral combination of the ππ βs, i.e.,
F (π) = max{π β β€ : π β= β¨π, π§β© for all π§ β β€πβ₯0 },
where β¨β
, β
β© denotes the standard inner product on βπ . In other words, F (π)
is the maximal right hand side π, such that the well-known knapsack polytope
π (π, π) = {π₯ β βπβ₯0 : β¨π, π₯β© = π} does not contain an integral point. From
that point of view it is also apparent that the Frobenius number plays an
important role in the analysis of integer programming algorithms (see, e.g.,
[1, 16, 17, 19]) and, vice versa, integer programming algorithms are known
to be an eο¬ective tool for computing the Frobenius number (see, e.g., [9]).
There is a rich literature on Frobenius numbers, and for an impressive survey
on the history and the diο¬erent aspects of the problem we refer to the book
[2].
Here we just want to mention that only for π = 2 an explicit formula is
known, which was proven by Curran Sharp in 1884 answering a question by
Sylvester:
F (π) = π1 π2 β (π1 + π2 ).
There is a huge variety of upper bounds on F (π). They all share the property that in the worst case they are of quadratic order with respect to the
maximum norm of π, say, which will be denoted by β£πβ£β . For instance,
assuming π1 β€ π2 β€ . . . β€ ππ , a classical upper bound due to ErdoΜs and
Graham [13] says
[π ]
1
β π1 ,
F (π) β€ 2 ππ
π
and, in a recent paper, Fukshansky&Robins [14, (29)] gave an upper bound
which is also symmetric in the ππ βs
[
]
π
(π β 1)2 /Ξ( π2 + 1) β β
2
ππ (β£πβ£2 )2 β ππ + 1 ,
(1.1)
F (π) β€
π π/2
π=1
1
2
ISKANDER ALIEV, MARTIN HENK, AND AICKE HINRICHS
where β£ β
β£2 denotes the Euclidean norm. The worst case in all the known
upper bounds is achieved when the ππ βs are approximately of the same size,
and it is also known that in these cases the quadratic order of an upper
bound cannot be lowered (see [7, 13, 20]).
On the other hand, Aliev&Gruber [3] recently found an optimal lower
bound for the Frobenius number which implies that
(1.2)
1
1
F (π) > (π β 1)! πβ1 (π1 π2 β
. . . β
ππ ) πβ1 β (π1 + β
β
β
+ ππ ) .
Hence, if all the ππ βs are of the same size then the lower bound is only of order
1+1/(πβ1)
β£πβ£β
. In fact, taking the quotient of the (symmetric) upper bound
1β1/(πβ1)
(1.1) with (1.2), we see that there is always a gap of order β£πβ£β
.
Thus the next natural and important question is to get information on
the Frobenius number of a βtypicalβ vector π. This problem appears to be
hard, and to the best of our knowledge it has ο¬rstly been systematically
investigated by V. I. Arnold, see, e.g., [5, 7, 8]. In particular, he conjectured
that F (π) grows like π 1+1/(π β1) for a βtypicalβ vector π with 1-norm β£πβ£1 =
π [5], and in [6, 2003-5] he conjectures that the βaverage behaviorβ is
(1.3)
1
1
F (π) βΌ (π β 1)! πβ1 (π1 π2 β
. . . β
ππ ) πβ1 ,
i.e., it is essentially the lower bound. A similar conjecture for the 3-dimensional case was proposed by Davison [12] and recently proved by Shur, Sinai
and Ustinov [21]. Extensive computations support conjecture (1.3) (see [9]).
In [10], Bourgain and Sinai proved a statement in the spirit of these
conjectures, which says, roughly speaking, that
(
)
Prob F (π)/π 1+1/(πβ1) β₯ π· β€ π(π·),
where Prob (β
) is meant with respect to the uniform distribution among all
points in the set
πΊ(π ) = {π β β€π>0 : gcd(π) = 1, β£πβ£β β€ π }.
Here the number π(π·) does not depend on π and tends to zero as π· approaches inο¬nity. The paper [4] gives more precise information about the
order of decay of the function π(π·). Their main result [4, Theorem 1.1]
implies that
(
)
(1.4)
Prob F (π)/β£πβ£1+1/(πβ1)
β₯ π· βͺπ π·β2 ,
β
where βͺπ denotes the Vinogradov symbol with the constant depending on
π only. In particular, from that result the authors get a statement about
the average Frobenius number, namely [4, Corollary 1.2]
β
1+1/(πβ1)
πβG(π ) F (π)/β£πβ£β
βͺπ 1.
sup
#G(π )
π
EXPECTED FROBENIUS NUMBERS
3
So the order of the average Frobenius number is (essentially) not bigger than
1+1/(πβ1)
β£πβ£β
, which is close to the sharp lower bound (1.2), but there is still
a gap.
The main purpose of this note is to ο¬ll that gap. We will show that
Theorem 1. Let π β₯ 3. Then
(
)
πβ1
1
Prob F (π)/ (π1 π2 β
. . . β
ππ ) πβ1 β₯ π· βͺπ π·β2 π+1 .
From this result we will derive the desired statement
Corollary 1. Let π β₯ 3. Then
1
β
πβ1
πβG(π ) F (π)/ (π1 π2 β
. . . β
ππ )
sup
βͺπ 1.
#G(π )
π
These statements ο¬t also perfectly to recent results on the limit distribution of Frobenius numbers due to Shur, Sinai and Ustinov [21] and Marklof
[18]. For instance, in our setting, [18, Theorem 1] says that
(
)
1
lim Prob F (π)/ (π1 π2 β
. . . β
ππ ) πβ1 β₯ π· = Ξ¨(π·),
π ββ
where Ξ¨ : ββ₯0 β ββ₯0 is a non-increasing function with Ξ¨(0) = 1.
The proof of Theorem 1 is based on a discrete inverse arithmetic-geometric
mean inequality which might be of some interests in its own. It will be stated
and proved in Section 2. Finally, Section 3 contains the proofs of Theorem
1 and Corollary 1.
2. Reverse discrete AGM-inequality
For π₯ β βπβ₯0 the Arithmetic-Geometric-Mean (AGM) inequality states
β
β
that ( ππ=1 π₯π )1/π β€ π1 ππ=1 π₯π . It is known that the βreverseβ AGM inequality holds with high probability. More precisely, Gluskin&Milman [15]
have shown that
ββ β
β
π
1
2
π₯
π=1 π
1
π
Prob π πβ1 β βπ
= β βπ
> πΌβ β€ ππ πΌβπ/2 ,
1/π
1/π
( π=1 β£π₯π β£)
π ( π=1 β£π₯π β£)
where π is an absolute constant and Prob π πβ1 () is meant with respect
to standard rotationβinvariant measure on the π-dimensional unit sphere
π πβ1 = {π₯ β βπ : ππ=1 π₯2π = 1}. Here we show an analogous statement
with respect to the primitive lattice points in the set πΊ(π ).
With respect to the uniform distribution on πΊ(π ), let πΏπ : πΊ(π ) β β>0
be the random variable deο¬ned by
1 βπ
ππ
π
πΏπ (π) = βπ π=1 1/π .
( π=1 ππ )
4
ISKANDER ALIEV, MARTIN HENK, AND AICKE HINRICHS
Theorem 2. Let πΌ > 1 and let π β {1, . . . , π β 1}. Then there exists a
constant π(π, π) depending only on π, π, such that
Prob (πΏπ β₯ πΌ) β€ π(π, π) πΌβπ .
By Markovβs inequality the theorem is an immediate consequence of the
next statement about the expectation πΌ(πΏππ ) of higher moments of πΏπ .
Lemma 1. Let π β {1, . . . , π β 1}. Then there exists a constant π(π, π)
depending on π, π, such that
πΌ(πΏππ ) β€ π(π, π).
Proof. First we note that there is an absolute constant π such that
#πΊ(π ) β₯ π π π .
(2.1)
This follows easily from well-known relations between integration and counting primitive lattice points (see e.g. [11, p. 183, (1)]), but in order to keep
the paper self-contained we give a short argument here: Let π β₯ 2 and let
πΊ2 (π ) = {(π, π)βΊ β β€2β₯1 : 1 β€ π, π β€ π, gcd(π, π) = 1}.
Since πΊ2 (π ) × {1, . . . , π }πβ2 β πΊ(π ) it suο¬ces to prove the statement for
π = 2, i.e., πΊ2 (π ). There are at most (π /π)2 pairs (π, π)βΊ β {1, . . . , π } with
gcd(π, π) = π. Thus
(
)
β
β
#πΊ2 (π ) β₯ π 2 1 β
πβ2 = (2 β π 2 /6) π 2 ,
π=2
which gives (2.1).
Now we have
(2.2)
( β
)π
π
1
β
β
π
1
1
π
π=1
π
πΏπ (π)π =
πΌ(πΏππ ) =
1
βπ
#πΊ(π )
#πΊ(π )
π
πβπΊ(π )
πβπΊ(π ) ( π=1 ππ )
(
) π1 π2
β 1
β
1
π
π1 π2 β
. . . β
ππππ
=
π
β
#πΊ(π )
π1 , π2 , β
β
β
, ππ
ππ
( π π )π
πβπΊ(π )
β€
=
1
#πΊ(π )
1
#πΊ(π )
π1 +π2 +β
β
β
+ππ =π
β
π1 +π2 +β
β
β
+ππ =π
β
π1 +π2 +β
β
β
+ππ =π
)
(
)β
π β
π
1
π
π
π π1 , π2 , β
β
β
, ππ
1
π
π
π π1 , π2 , β
β
β
, ππ
π
π=1
π
β
(
π
β
π βπ/π
πππ
π1 ,π2 ,...,ππ =1 π=1
π=1 ππ =1
π βπ/π
πππ
.
EXPECTED FROBENIUS NUMBERS
5
β
Since for π < π the sum ππ=1 πβπ/π is bounded from above by π(π, π) π 1βπ/π ,
where π(π, π) is a constant depending only on π and π, we ο¬nd
(2.3)
π
β
π βπ/π
πππ
β€ π(π, π)π 1+ππ βπ/π .
ππ =1
Thus, for π1 + π2 + β
β
β
+ ππ = π we obtain
π β
π
β
π βπ/π
πππ
β€ π(π, π)π π π .
π=1 ππ =1
Hence we can continue (2.2) by
β
1
πΌ(πΏππ ) β€
#πΊ(π )
= π(π, π)π
π1 +π2 +β
β
β
+ππ =π
ππ
#πΊ(π )
(
)
π
1
π(π, π)π π π
ππ π1 , π2 , β
β
β
, ππ
.
Finally, with (2.1) we get the assertion.
β‘
Remark 1. With a little more work one can prove Lemma 1 for any positive
number π < π, not only for integers.
Next we want to point out that the arguments in the proof of Lemma 1
lead to the following lower bound on the random variable ππ : πΊ(π ) β β>0
given by
F (π)
ππ (π) = β
1 .
π
( π=1 ππ ) πβ1
Proposition 1. Let π β₯ 2. Then there exists a constant depending only on
π such that
(
)
1
1
πΌ(ππ ) β₯ (π β 1)! πβ1 1 β π(π) π β πβ1
Proof. On account of the lower bound (1.2) on F (π) it remains to show that
βπ
β
1
1
π=1 ππ
β€ π(π) π β πβ1 .
1
βπ
#πΊ(π )
πβ1
πβπΊ(π ) ( π=1 ππ )
Following the argumentation in (2.2) we ο¬nd
βπ
π
π
β
β
β
β
ππ β 1
π=1 ππ
β€
ππ πβ1
1
βπ
πβ1
π1 +π2 +β
β
β
+ππ =1 π1 ,π2 ,...,ππ =1 π=1
πβπΊ(π ) ( π=1 ππ )
π
β
=π
1
1β πβ1
β 1
π2 πβ1
π1
β
π1 ,π2 ,...,ππ =1
=π
π
β
π1 =1
1β 1
π1 πβ1
(
π
β
π2 =1
β 1
π2 πβ1
1
β
. . . β
ππ πβ1
)πβ1
6
ISKANDER ALIEV, MARTIN HENK, AND AICKE HINRICHS
Thus, analogously to (2.3), and on account of (2.1) we obtain
βπ
(
)πβ1
β
1
1
1
1
2β πβ1
1β πβ1
π=1 ππ
π
π
β€
π
Λ
(π)
1
β
#πΊ(π )
#πΊ(π )
( π ππ ) πβ1
πβπΊ(π )
π=1
1
β€ π(π)π β πβ1 .
β‘
3. Proof of Theorem 1 and Corollary 1
We keep the notation of the previous section. First we note that (1.4) is
certainly also true for any other norm larger than the β£ β
β£β in the denominator, in particular for the 1-norm β£ β
β£1 . Thus
β
β
F (π)
β₯ π·β βͺπ π·β2 .
(3.1)
Prob β
1
1+ πβ1
β£πβ£1
Secondly, we observe that
(3.2)
β
Prob β
1
1+ πβ1
β
β£πβ£1
(π1 β
. . . β
ππ )
1
πβ1
π
(
( π1 β£πβ£1 ) πβ1
β₯ πΎ β = Prob
(π1 β
. . . β
ππ ) πβ1
(
( ) π
π
1 πβ1
πβ1
= Prob πΏπ β₯
πΎ
π
)
(
(πβ1)2
1 πβ1
π
βͺπ πΎ β π ,
= Prob πΏπ β₯ πΎ
π
where in the last inequality we have
Together with (3.1) we obtain
β
F (π)
Prob (ππ (π) β₯ π½) = Prob β
1+ 1
β£πβ£1 πβ1
β
F (π)
β€ Prob β
1+ 1
β£πβ£1 πβ1
βͺπ π½ β2 π‘ + π½
1
applied Theorem 2 with π = π β 1.
1
1+ πβ1
β
β£πβ£1
β
1
(π1 β
. . . β
ππ ) πβ1
β
β
β₯ π½ π‘ β + Prob β
(πβ1)2
β π (1βπ‘)
β₯ π½β
1
1+ πβ1
(π1 β
. . . β
ππ )
,
πβ1
Prob (ππ (π) β₯ π½) βͺπ π½ β2 π+1 ,
β
β£πβ£1
for any π‘ β (0, 1). With π‘ = (π β 1)/(π + 1) we ο¬nally get
which shows Theorem 1.
( ) π )
1 πβ1
β₯
πΎ
π
)
1
πβ1
β₯ π½ 1βπ‘ β
EXPECTED FROBENIUS NUMBERS
7
For the proof of Corollary 1 we note that
β« β
β« β
πΌ(ππ ) =
Prob (ππ > π₯) dπ₯ β€ 1 +
Prob (ππ > π₯) dπ₯
0
1
β« β
πβ1
π₯β2 π+1 dπ₯.
βͺπ 1 +
1
For π β₯ 4, the last integral is ο¬nite and so we have
(3.3)
πΌ(ππ ) βͺπ 1.
For the case π = 3 we just note that on account of Remark 1 one can also
bound Prob (ππ (π) β₯ π½) by a function like π½ β(1+π) and so we also get (3.3)
in this case. Together with Proposition 1, Corollary 1 is proven.
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8
ISKANDER ALIEV, MARTIN HENK, AND AICKE HINRICHS
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School of Mathematics and Wales Institute of Mathematical and Computational Sciences, Cardiff University, Senghennydd Road, Cardiff, Wales,
UK
E-mail address: [email protected]
Institut fuΜr Algebra und Geometrie, Otto-von-Guericke UniversitaΜt Magdeburg, UniversitaΜtsplatz 2, D-39106-Magdeburg
E-mail address: [email protected]
Friedrich Schiller UniversitaΜt Jena, FakultaΜt fr Mathematik und Informatik, Ernst-Abbe-Platz 2, D-07743 Jena
E-mail address: [email protected]
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