Linear and Multilinear Algebra 2012, 1–4, iFirst An eigenvalue majorization inequality for positive semidefinite block matricesyz Minghua Lin and Henry Wolkowicz* Department of Combinatorics and Optimization, University of Waterloo, Waterloo, ON N2L 3G1, Canada Downloaded by [University of Waterloo] at 07:59 16 January 2012 Communicated by R. Loewy (Received 26 July 2011; final version received 17 December 2011) Let H ¼ KM KN be a Hermitian matrix. It is known that the vector of diagonal elements of H, diag(H), is majorized by the vector of the eigenvalues of H, (H), and that this majorization can be extended to the eigenvalues of diagonal blocks of H. Reverse majorization results for the eigenvalues are our goal. Under the additional assumptions that H is positive semidefinite and the block K is Hermitian, the main result of this article provides a reverse majorization inequality for the eigenvalues. This results in the following majorization inequalities when combined with known majorization inequalites on the left: diagðHÞ ðM NÞ ðHÞ ððM þ NÞ 0Þ: Keywords: majorization; eigenvalue inequalities AMS Subject Classifications: 15A42; 06A06 1. Introduction An early result concerning eigenvalue majorization is the fundamental result due to I. Schur (see, e.g. [1,5,6]), which states that the diagonal entries of a Hermitian matrix A are majorized by its eigenvalues. i.e., diag(A) a (A). This result can be extended to block Hermitian matrices. For example, if H ¼ KM KN is Hermitian, then diagðHÞ ðM NÞ ðHÞ: To see the second inequality, let M ¼ U*D1U, N ¼ V*D2V, where D1, D2 are diagonal matrices, the spectral decomposition of M, N, respectively. Then ðHÞ ¼ D1 UKVbe VK ðD1 D2 Þ ¼ ðM NÞ. U D 2 Reverse majorization results are our goal. Here and throughout, K* denotes the conjugate transpose of K; M N denotes the direct sum of M and N, i.e., the block 0 diagonal matrix M 0 N and 0 is a zero block matrix of compatible size. *Corresponding author. Email: [email protected] yIn memory of Ky Fan. zResearch Report CORR 2011-04. ISSN 0308–1087 print/ISSN 1563–5139 online ß 2012 Taylor & Francis http://dx.doi.org/10.1080/03081087.2011.651723 http://www.tandfonline.com 2 M. Lin and H. Wolkowicz Majorization inequalities are useful and important; see, e.g. [6]. The main result of this article is the following reverse majorization inequality for a Hermitian positive semidefinite 2 2 block matrix. (We delay the proof until Section 2.) THEOREM 1.1 Let H ¼ KM KN be a Hermitian positive semidefinite matrix. If, in addition, the block K is Hermitian, then the following majorization inequality holds: Downloaded by [University of Waterloo] at 07:59 16 January 2012 ðHÞ ððM þ NÞ 0Þ: ð1:1Þ 1.1. Preliminary results Let Mmn(C) be the space of all complex matrices of size m n with Mn(C) ¼ Mnn(C). For A 2 Mn(C), the vector of eigenvalues of A is denoted by (A) ¼ (1(A), 2(A), . . . , n(A)). If A is Hermitian, we arrange the eigenvalues of A in nonincreasing order: 1(A) 2(A) n(A). For two sequences of real numbers arranged in nonincreasing order, x ¼ ðx1 , x2 , . . . , xn Þ, y ¼ ð y1 , y2 , . . . , yn Þ, we say that x is majorized by y, denoted by x a y (or y x), if k X j¼1 xj k X yj ðk ¼ 1, . . . , n 1Þ, and n X j¼1 j¼1 xj ¼ n X yj : j¼1 We make use of the following lemmas in our proof of Theorem 1.1. LEMMA 1.2 If A, B 2 Mn(C) are Hermitian, then 2ðAÞ ðA þ BÞ þ ðA BÞ: ð1:2Þ Proof The lemma is equivalent to Ky Fan’s eigenvalue inequality, i.e., (A þ B) a (A) þ (B), [2]. A proof can be found in [4, Theorem 4.3.27] and [7, Theorem 7.15]. g LEMMA 1.3 Let A 2 Mmn(C) with m n, then we have ðAA Þ ¼ ðA A 0Þ: ð1:3Þ 2. Proof of main result: corollaries Before we prove Theorem 1.1, we show by an example that the requirement K being Hermitian is necessary. Example 2.1 Let M ¼ 10 04 , N ¼ 21 11 and K ¼ 12 02 . Then pffiffiffi pffiffiffi ððM þ NÞ 0Þ ¼ ð4 þ 2, 4 2, 0, 0Þ, pffiffiffi pffiffiffi M K ¼ ð4 þ 5, 4 5, 0, 0Þ: K N M K Therefore K N ˛ ðM þ NÞ 0Þ. 3 Linear and Multilinear Algebra K Proof of Theorem 1.1 Since H :¼ M is positive semidefinite, we may write K N H ¼ P*P, where P ¼ [X Y ], for some X, Y 2 M2nn(C). Therefore, we have M ¼ X*X, N¼ Y*Y and K ¼ X*Y ¼ Y*X. Note that by Lemma 1.3, we have K ¼ ðPP Þ. The conclusion (1.1) is then equivalent to showing M K N fX Y ¼ Y Xg ¼) ððX X þ Y YÞ 0Þ ðXX þ YY Þ : ð2:1Þ First, note that ðX þ iYÞ ðX þ iYÞ ¼ X X þ Y Y þ iðX Y Y XÞ Downloaded by [University of Waterloo] at 07:59 16 January 2012 ¼ X X þ Y Y ðX iYÞ ðX iYÞ ¼ X X þ Y Y iðX Y Y XÞ ¼ X X þ Y Y ðX þ iYÞðX þ iYÞ ¼ XX þ YY iðXY YX Þ ðX iYÞðX iYÞ ¼ XX þ YY þ iðXY YX Þ: Therefore we see that 1 ððX þ iYÞ ðX þ iYÞ 0Þ þ ððX iYÞ ðX iYÞ 0Þ 2 1 ¼ ðððX þ iYÞðX þ iYÞ Þ þ ððX iYÞðX iYÞ ÞÞ 2 ðXX þ YY Þ, ððX X þ Y YÞ 0Þ ¼ where the second equality is by Lemma 1.3 and the majorization follows from applying Lemma 1.2 with A ¼ (XX* þ YY*), B ¼ i(XY* YX*). g As we can see from the above proof, a special case of Theorem 1.1 can be stated as follows. COROLLARY 2.2 Let X, Y 2 Mn(C) with X*Y Hermitian. Then we have ðXX þ YY Þ ðX X þ Y YÞ: COROLLARY 2.3 ð2:2Þ n Let k 1 be an integer. If A, B 2 M (C) are Hermitian, then we have ðA2 þ ðABÞk ðBAÞk Þ ðA2 þ ðBAÞk ðABÞk Þ: k ð2:3Þ k Proof Let X ¼ A and Y ¼ (BA) . Then XY ¼ A(BA) is Hermitian. The result now follows from Corollary 2.2. g COROLLARY 2.4 Let k 1 be an integer, p 2 [0, 1); and let A, B 2 Mn(C) be Hermitian. Then we have (1) trace[(A2 þ (AB)k(BA)k)p] trace[(A2 þ (BA)k(AB)k)p], for p 1; (2) trace[(A2 þ (AB)k(BA)k)p] trace[(A2 þ (BA)k(AB)k)p], for 0 p 1. Proof Since f(x) ¼ xp is a convex function for p 1 and concave for 0 p 1, Corollary 2.4 follows from Corollary 2.3 and a general property of majorization [5, p. 56]. g Remark 2.5 The case where k ¼ 1 in Corollary 2.4 was proved in [3]. 4 M. Lin and H. Wolkowicz Acknowledgements The authors thank the anonymous referees for valuable suggestions that improved the presentation of this article. This research was supported by The Natural Sciences and Engineering Research Council of Canada. Downloaded by [University of Waterloo] at 07:59 16 January 2012 References [1] R. Bhatia, Matrix Analysis, Springer-Verlag, New York, 1997. [2] K. Fan, On a theorem of Weyl concerning eigenvalues of linear transformations. I, Proc. Natl. Acad. Sci. USA 35 (1949), pp. 652–655. [3] S. Furuichi and M. Lin, A matrix trace inequality and its application, Linear Algebra Appl. 433 (2010), pp. 1324–1328. [4] R.A. Horn and C.R. Johnson, Matrix Analysis, Cambridge University Press, Cambridge, 1990. Corrected reprint of the 1985 original. [5] A.W. Marshall and I. Olkin, Inequalities: Theory of Majorization and its Applications, Academic Press, New York, 1979. [6] A.W. Marshall, I. Olkin, and B.C. Arnold, Inequalities: Theory of Majorization and its Applications, Springer Series in Statistics, 2nd ed., Springer, New York, 2011. [7] F. Zhang, Matrix Theory: Basic Results and Techniques, Universitext, Springer-Verlag, New York, 1999.
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