See T&K Chapter 9 “Unsteady” MassTransfer Models ChEn 6603 Wednesday, April 4, 12 1 Outline Context for the discussion Solution for transient binary diffusion with constant ct, Nt. Solution for multicomponent diffusion with ct, Nt. Film theory revisited (surface renewal models) Transient diffusion in droplets, bubbles Wednesday, April 4, 12 2 Context Film theory - so far we assumed steady state, no reaction in bulk (only potentially at interface) • Mass Transfer Coefficients used to simplify problem - don’t fully resolve diffusive fluxes. • Bootstrap problem solved (via definition of [β]) to obtain total species fluxes. Unsteady cases? • What if we want to know the transient concentration profiles? • What if we want to consider the effects of transient (perhaps turbulent) mixing near the interface? Here we consider unsteady film-theory approaches... Hung Le and Parviz Moin. http://www.stanford.edu/group/ctr/gallery/003_2.html Wednesday, April 4, 12 3 Solution Options ci = t ⇤ · Ni + r i Describes evolution of ci at all points in space/time, but requires Ni, which may involve solution of the momentum equations... Solve the problem numerically • Allows us to incorporate “full” description of the physics ‣ may be quite complex (particularly if we must solve for a non-trivial velocity profile...) • Could also simplify portions (constant [D], ct, etc.) • Can solve this for a variety of BCs, ICs Make enough assumptions/simplifications to solve this analytically • Different BC/IC may require different form for analytic solution • We already did this for effective binary and linearized theory for a few simple problems (2-bulb problem, Loschmidt tube) ‣ T&K chapters 5 & 6. • Here we show a few more techniques, based on unsteady film theory ‣ Don’t resolve mass transfer completely - get a coarser description of the diffusive fluxes... (J) (N ) Wednesday, April 4, 12 = = ct [k • ]( x) [ ](J) Approximation for diffusive flux (total flux). 4 See T&K 9.2 Binary Formulation (1/3) ci = t ⇤ · Ni + r i What are the assumptions? ct xi = t ⇤ · Ni What happened here? ct xi + Nt · ⇤xi = t ⇤ · Ji One-dimensional... ct xi xi + Nt = t z z Ji 2 x1 N t x1 x1 + =D 2 t ct z z Wednesday, April 4, 12 Problem statement: semi-infinite diffusion (binary) z ≥ 0, t =0, z = 0, t >0, z → ∞, t >0, BCs & ICs xi=xi∞. (Initial condition) xi=xi0. (Boundary condition) xi=xi∞. (Boundary condition) valid for “short” contact times (more later) 5 Binary Formulation (2/3) 2 x1 N t x1 x1 + =D 2 t ct z z ct ✓ ◆ ✓ ◆ dx dx + Nt 2t d z d ✓ ◆ Nt z dx 2 + ct d d2 x dx D 2 + 2( ⇥) d d Nt p ⌘ t ct x1 = x1,0 =0 x1 = x1,1 =1 Wednesday, April 4, 12 Observation: since x is dimensionless, z, t, D must appear in a dimensionless combination in the solution. z =p 4t chosen for convenience, ⇥ d ⇥ = = ζ2/D is dimensionless ⇥t d ⇥t 1 d 2td ⇥ d ⇥ d = = ⇥z d ⇥z zd ✓ ◆2 2 2 2 ⇥ ⇥ d d = 2 = 2 ⇥z 2 d ⇥z z d 2 d2 x = ct Di 2 2 z d d2 x = D 2 d = 0 Solve using order reduction 1 erf ⇣ p ⇥ D ⌘ x1 x1,0 ⇣ ⌘ = x1,1 x1,0 1 + erf p⇥D Note that this is a function of both z and t. 6 Binary Formulation (3/3) ⇣ p ⇥ D ⌘ 1 erf x1 x1,0 ⇣ ⌘ = x1,1 x1,0 1 + erf p⇥D Calculate J1 at z=0, J1,0 = ct What happens to J1 as z→∞? r ⇣ 2 ⌘ D exp D ⇣ ⌘ (x1,0 t 1 + erf p x1,1 ) D Mass Transfer Coefficients (binary system): Low-flux limit (as Nt→0) r D J1,0 = ct (x1,0 t Wednesday, April 4, 12 x1,1 ) J1,0 = ct k (x1,0 N1,0 = ct • k (x1,0 0 k= r D t x1, ) = ct k • (x1,0 exp = ⇣ 1 + erf 2 D ⇣ p ⌘ D ⌘ x1, ) x1, ) 7 See T&K 9.3.1-9.3.2 Multicomponent System (x) Nt (x) + = [D] t ct z 2 (x) z2 Nt p ⌘ t ct z =p 4t This has the analytic solution (see T&K 9.3.1-9.3.2): ii h h ii h h 1 1 [I] + erf ⇥ [D] 2 (x x1 ) = [I] erf ( ⇥) [D] 2 h ih h ii 1 1 1 1 ct (J0 ) = p [D] 2 exp [D] 2 [I] + erf [D] 2 (x0 ⇡t Low-flux limit (as Nt→0) 1 ct J0 = p [D] 2 (x0 t [k] = ( t) 1 2 [D] 1 2 (J0 ) = ct [k][ ](x0 x⇥ ) = ct [k • ](x0 (N0 ) = ct [ 0 ][k • ](x0 x⇥ ) Wednesday, April 4, 12 x1 ) [ ] = exp x⇥ ) h 1 [D] (x0 x1 ) 1 2 x1 ) remember that these are matrix functions! ih [I] + erf[ [D] Possible approaches: 1 2 i 1 • Solve the transient problem (beware of the “short” time assumption) • Use this information to formulate other steady-state models (e.g. turbulent mixing from bulk to surface) 8 See T&K §9.1 Surface Renewal Models (J0 ) = ct [k][ ](x0 x⇥ ) = ct [k • ](x0 (N0 ) = ct [ 0 ][k • ](x0 x⇥ ) x⇥ ) [k] = ( t) 1 2 [D] 1 2 Idea: develop a model for k that approximates the effects of transients near the surface. (J), (N) are functions of time since [k] is a function of time. How would we handle this problem? Concept: “Fresh” fluid from bulk is transported to the interface, where diffusion occurs for some time, t. Then this is transported back to the bulk and replaced by more “fresh” fluid. Initial & Boundary conditions: z = 0, z 0, z ⇥ ⇤, xi = xi0 xi = xi xi = xi t>0 t=0 t>0 Assumes that the “bulk” is unaffected by mass transfer (“short” contact times) Age distribution function, ψ(t), determines how long a fluid parcel is at the interface. (will affect expression for [k]) Wednesday, April 4, 12 9 See T&K §9.1 Surface-Renewal Models Age distribution function, ψ(t), determines how long a fluid parcel is at the interface. (will affect expression for [k]) kij (t) = Higbie model (1935) (t) = Danckwerts model (1951) Dij t kij = kij (t) (t)dt 0 Attempts to model a statistically stationary process (fast mixing, no saturation to bulk) by a steady state [k]. Assumes that all fluid parcels stay at the interface for a fixed amount of time, te. 1/te 0 t te t > te → [k] = 2 1/2 [D] te Note typo in T&K 9.3.33 (t vs. te) Fluid parcels have a greater chance of being replaced the longer they are at the interface. (t) = s exp( st) → [k] = s[D]1/2 s - rate of surface renewal (1/sec) (fraction of surface area replaced by fresh fluid in unit time) Wednesday, April 4, 12 10 See T&K §9.4 Bubbles, Drops, Jets δ δ δ Spheres Channels [Fo] = Cylinders [D]t 2 For “small” Fo (Fo«1), we are safe to use surface renewal concepts. What happens at “large” Fo (Fo→1)? xi = xiI Wednesday, April 4, 12 ⇥xi ⇤ 〈xi〉 - “mixing cup” average 11 See T&K §9.4 Fractional Approach to EQ (J0 ) = ct [k][ ](x0 x⇥ ) = ct [k • ](x0 (N0 ) = ct [ 0 ][k • ](x0 x⇥ ) ⇥ F (x0 (x10 (x10 ⌅x1 ⇧) x1I ) ⇤ ⌅x⇧) = [F ](x0 xI ) x∞ is changing! x⇥ ) (this solution is not valid) For a spherical droplet/particle: Binary [F ] = ⇤ ⇥ ⇧ 6 [I] 2 exp 1 m2 x0 - initial/boundary composition (t=0) xI - interface composition (constant in time) 〈x〉 - average composition (changing in time), use in place of x∞. m m=1 1 [D ] = [D] Dref Multicomponent 2 2 Foref ⇥ 6 note: 2 m 2 ⇥ Foref [D ] ⌅ Dref rt2 0 =1 m=1 [Sh] = 2 3 2 ⇤ ⇤ ⇧ Sh ⇥ [k] · 2r0 [D] exp m=1 Limiting cases: m 2 2 ⇥ Foref [D ] ⇤ ⇧ Sherwood number related to ∂F/∂Fo. 1 m2 exp m 2 2 m=1 Foref ⇥ ⌅ =⇤ Sh = Foref Wednesday, April 4, 12 ⇥ ⌅⇤ 1 2 3 2 ⇥ Foref [D ] [I] ⇤ [k] = ⇥ 2 3r0 ⌅ [D] 1 remember that these are matrix functions! See fig. 9.7 (L’Hopital’s rule) 2 1 =⇤ [k] = ⇧ [D]1/2 t 12
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