Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. 1/20/2016 Sinusoidal Wave Theory II CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D., Professor Emeritus Presentation Content • Part II of predicting behavior of water waves • Algebraic solutions • Modeled with sinusoidal wave profiles Interpreting • Applying • Professor Tom Ravens, UAA College of Engineering, contributed graphics and information to this presentation CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. CE A676 Coastal Engineering Spring 2016 Sinusoidal Wave Theory 2 1 Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. 1/20/2016 Solutions • Velocity potential ∅ , , as affected by wave height (H), wave period (T), wave length (L), and depth (d) • Hg cosh k ( d z ) sin( kx t ) 2 cosh kd ∅ =− ∅ k 2 L Dispersion Equation: relating period, wavelength, and depth 2 gk tanh kd • =− For water surface profile: L ( , )= 2 T gT 2 2d tanh 2 L 2 cos( − CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. ) Sinusoidal Wave Theory 3 Sinusoidal wave profile • Two wave profile modes: • • Progressive profiles at times t1 = 0 and t2 = T/2 Standing wave profiles at times t1 = 0 and t2 = T/2 CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. CE A676 Coastal Engineering Spring 2016 1 2 1 0.5 0 0.5 1 1 2 0 100 200 100 200 x 300 400 500 300 400 500 1 0.5 0 0.5 1 0 x Sinusoidal Wave Theory 4 2 Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. 1/20/2016 Hyperbolic tangent • Dispersion Equation: 2 gk tanh kd • Deep water (large kd, d > L/2): • Lo = 1.56T2 (m) Lo = 5.12T2 L0 (ft) CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. gT 2 2 Sinusoidal Wave Theory 5 Intermediate and shallow depths • Depths between L/2 and about L/20 • Must apply the full Dispersion Equation C L 2d tanh C0 L0 L • L L0 tanh kd C L0 tanh kd T Shallow water (small kd, d < L/20): 2 gk 2 d CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. CE A676 Coastal Engineering Spring 2016 C gd Sinusoidal Wave Theory 6 3 Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. 1/20/2016 Water particle velocities • Velocity potential: Hg cosh k (d z ) sin( kx t ) 2 cosh kd u H cosh k (d z ) cos( kx t ) x 2 sinh kd w • • H sinh k (d z ) sin( kx t ) z 2 sinh kd /2 out of phase • • u is maximum when w is zero w is maximum when u is zero Maximum at surface (z = 0); diminish with depth (-z) CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. Sinusoidal Wave Theory 7 Sinusoidal Wave Theory 8 Water particle paths • Integrate u and w with respect to time: • Horizontal displacement relative to mean: • Vertical displacement relative to mean: • H cosh k ( d z ) sin( kx t ) 2 sinh kd H sinh k (d z ) cos( kx t ) 2 sinh kd Deep water: circular path radius = CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. CE A676 Coastal Engineering Spring 2016 H kz e 2 4 Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. 1/20/2016 Water particle motion decay with depth cosh k d z sinh k d z e kz sinh kd sinh kd • • Exponential decay with increasing depth (-z) Radii reduced to ~4% of surface at z = -L/2 CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. Sinusoidal Wave Theory 9 Motion in intermediate and shallow depths • Elliptical, diminishing with depth • Flattening to only horizontal motion at bottom (z = -d) • w = 0 at z = -d CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. CE A676 Coastal Engineering Spring 2016 Sinusoidal Wave Theory 10 5 Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. 1/20/2016 Water particle accelerations • • Important for estimating wave-induced forces Neglect 2nd two terms of full differential: ax az • u H 2 cosh k d z sin kx t t 2 sinh kd ax u u u u w t x z w H sinh k d z 2 coskx t z 2 sinh kd /2 out of phase with each other and with velocities CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. Sinusoidal Wave Theory 11 Potential Energy • Vertical displacement of water from SWL (PE = 0) • Integrate mgz over a wavelength (m = mass) • • Consider a small column of water beneath a wave Average potential energy due to waves: PE 1 gH 2 Equals potential energy per unit area • Depends only on wave height • CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. CE A676 Coastal Engineering Spring 2016 16 Sinusoidal Wave Theory 12 6 Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. 1/20/2016 Kinetic and total energy • Integrate + KE • over L and z: 1 gH 2 PE 16 Total average energy per unit surface area: KE PE 1 gH 2 8 CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. Sinusoidal Wave Theory Group velocity • Water particle orbits Waves transport energy • • Average rate at which work is done on fluid (or by fluid) Energy flux for one wave period: = • no net mass transport n Group velocity: • • 1 2 kh 1 2 sinh 2 kh C g nC d dk H1 + H2 • 13 time Speed at which energy is transported by waves Deep water, n = ½; shallow water, n = 1 CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. CE A676 Coastal Engineering Spring 2016 Sinusoidal Wave Theory 14 7 Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. 1/20/2016 Shoaling • • Period treated as constant L shortens, leading to slower phase speed (C = L/T) Wave height first diminishes, then increases • Shoaling Coefficient: = = = 2 CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. 5 4.5 Shoaling: Ho = 4 ft; T = 8 s H L 328 4 3.5 400 300 4 200 200 150 100 depth (ft) 50 100 0 wave length (ft) • Wave characteristics change with decreasing depth (shoaling), following change in energy flux, i.e., Cg wave height (ft) • Sinusoidal Wave Theory 15 Refraction • • • • • Consider straight wave crests approaching shallow water at an angle Part of crest slows before rest Crest bends in toward shore Snell’s Law: sin sin 0 C C0 cos cos 0 C C0 Refraction Coefficient: Kr cos 0 CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. CE A676 Coastal Engineering Spring 2016 cos H H0Ks Kr H0 Sinusoidal Wave Theory C0 2 Cg cos 0 cos 16 8 Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. 1/20/2016 Pressure under progressive waves • Substitute in Bernoulli Equation, neglecting u2 and w2 terms, and applying the DFSBC: =− • • + ∅ includes a hydrostatic part and a time-varying part due to water particle accelerations. Applying solution for : =− + 2 + − =− CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. + Sinusoidal Wave Theory + 17 Pressure • In deep water: • • + Exponential decay of dynamic pressure + In shallow water: • ≅ ≅1 Pressure is purely hydrostatic beneath the wave form = CE A676 Coastal Engineering Spring 2016 − 9 Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. 1/20/2016 Pressure (continued) Consider dynamic pressure variation under crest and under trough: o • o Vertical acceleration, equations of motion (conservation of momentum): =− − or =− − -g term is always negative o < 0 under crest; particles are accelerating downward; reduced |dP/dz| o > 0 under trough; particles are accelerating upward; increased |dP/dz| o |dP/dz| is less under the crest than under the trough CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. Sinusoidal Wave Theory 19 long waves [shallow Water Waves] short waves [or deep water waves] CE A676 Coastal Engineering Spring 2016 10 Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. d = 100 m, T = 10 s, H = 2 m 1/20/2016 Ex. 2.3-1 in Sorenson What is c, L, H/L, and water particle speed at crest? Solution: • Assume the wave is a deep water wave (we will check this assumption later). • If deep water wave, • Check deep water wave assumption: • Celerity: • Steepness: (Otherwise, we would need to use the full Dispersion Equation) Ho / Lo = 2 / 156 = 0.013 (small wave steepness) h = 100 m, T = 10 s, H = 2 m; c = 15.6 m/s Water is particle speed at crest? Solution: • • For deep water waves, particle orbits are circular; at the surface the diameter of the circles is the wave height. So, what is the nominal velocity? CE A676 Coastal Engineering Spring 2016 11 Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. 1/20/2016 d = 100 m, T = 10 s, H = 2 m in deep water • Suppose the wave has propagated to a depth of 2.3 m • Calculate the celerity and wavelength Solution: assume the wave is in shallow water at d = 2.3 m. L = C T = 47.5 m Check shallow water assumption: d/L = 2.3/47.5 = 0.048 < 0.05 the wave is in shallow water Note: computing L by applying the full Dispersion Equation will also confirm the assumption Calculating wave character from pressure data Given: the pressure data below from a bottom pressure transducer in a lake. Find: water depth, wave height 42500 42000 pressure, Pa 41500 41000 40500 40000 39500 39000 38500 38000 37500 CE A676 Coastal Engineering Spring 2016 0 0.5 1 1.5 2 2.5 time (sec) 3 3.5 4 4.5 12 Sinusoidal Wave Theory II Presented by Orson Smith, PE, Ph.D. Solution: 43000 42000 pressure, Pa d =?, H = ? 1/20/2016 41000 40000 39000 38000 37000 • Pavg = 40,000 Pa 0 1 2 time (sec) 3 4 5 (with P = ρgd & ρg 9800 N/m3), d ~ 4 m • By inspection, T = 4 sec (time between successive crests • Find d/Lo = .183 = transitional wave (< ½, not deep water) • • • • Lo = g/2π T2 = 21.9 m, for deep water From sinusoidal wave table, d/L = 0.208, so L = 19 m. k = 2 π/L = 0.33 m-1 ∆P between crest and SWL (2000 Pa) • • solve for H = 0.8 m H = (2 ∆P / ρg) cosh(kd) = Conclusion CE A476/676 Coastal Engineering Orson P. Smith, PE, Ph.D. CE A676 Coastal Engineering Spring 2016 Sinusoidal Wave Theory 26 13
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